Simplest Formula

Prepared by: Stephen Boylan

October 20, 2009

Simplest Formula .

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A. Combustion in Excess oxygen

12.795 g. HC ----> 32.689 g. CO2 + 13.377 g. H2O

B. 5 Step Calculation

C. The Simplest Formula

. Cx Hy Oz

Molar Mass CO2

Element Number Atomic Mass Formula

n Units, amu Mass,

C 1 12.01 12.01

O 2 16.00 32.00

44.01grams per mole CO2

• Molar Mass H2O•

• Element Number Atomic Mass Formula• n Units, amu Mass, n(amu)•

• H 2 1.008 2.016•

• O 1 16.00 16.00• 18.02 grams per• mole H2O•

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• 2.0 Calculate the grams of carbon, hydrogen and oxygen.•

• 12.795g. HC --> 32.689 g CO2 + 13.377 g. H2O•

• C:• 32.689 grams CO2 12.01 grams C = 8.921 g. C• 44.01 grams CO2• H:• 13.377 grams H2O 2x1.008 grams H = 1.497 g H• 18.02 grams H2O• O:• 12.795 g HC - 8.921g C - 1.497 g H= 2.377 g O•

• Moles of carbon, hydrogen and oxygen.•

• C: 8.921 g. C 1 mole C = 0.7429 moles C• 12.01 grams C •

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• H: 1.497 g. H 1 mole H = 1.485 mole H• 1.008 grams H•

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• O: 2.377 g. O 1 mole O = 0.1485 mole O• 16.00 grams O

• Ratios Divide by smallest•

• C: 0.7429 moles C 1 = 5.003 ~ 5 moles C • 0.1485•

• H: 1.485 mole H 1 = 10 moles H • 0.1485•

• O: 0.1485 mole O 1 = 1 moles O • 0.1485•

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• C5 H10 O1

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• The End •