l10 roof dsgn
DESCRIPTION
L10 Roof DsgnTRANSCRIPT
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< Types of Roof
< Bracing of Truss
< Loading on Truss & Purlin
< Secondary Truss
Timber and Steel DesignTimber and Steel Design
Lecture Lecture 1010 Roof Design
Mongkol JIRAVACHARADETS U R A N A R E E INSTITUTE OF ENGINEERINGUNIVERSITY OF TECHNOLOGY SCHOOL OF CIVIL ENGINEERING
Types of RoofTypes of Roof
(a) Flat roof
(d) Gable
(b) Lean to
(e) Hip
(c) Butterfly
(f) Curve
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RoofRoof RafterRafter
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(RUN)
(SPAN)
(RISE)
-
..
1.0 1.2 .15 ../..10, 15, 20 ()
0.32 0.34 .50 ../..30 - 35 ()
1.0 2.0 .5 ../..MIN. 1 - 2 (Metal sheet)
(RUN) (SPAN)
(RISE)
P/2P
PP
P/2 RR
RL
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10-1
4 m0.8 m 0.8 m
1.2 m
= 30 ../. = 50 ../. = 80 ../.
0.8 m
0.8 m
2 m
2 m
1 .
1 .
1.0 1.0 = 801.0 = 80 ../. = 10 ../. = 90 ../.
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2 . 0.8 .
0.8 m RL RR2 m
w = 90 kg/m
72 kg 75.6 kg
104.4 kg
0.84 m
31.8 kg-m
28.8 kg-m
RL = (1/2) (90) (2.8)2 / 2.0 = 176.4 ..RR = (90) (2.8) 176.4 = 75.6 ..
Mmax = 31.8 ..-.Fb = 0.60(2,500) = 1,500 ../.2
S = Mmax/Fb = 31.8(100)/1,500 = 2.12 .3
5025 .. 1.6 .. (Sx = 2.81 .3)
10-2 1
4 m
4 m
0.5 m
0.5 m
4 m 4 m0.5 m
0.5 m
90 ../..
L
L
45
2 24 4= + = 5.66
2 20.5 0.5= + = 0.707 L = 4.0/2 = 2.0
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wmax = 2L() = 2(2.0)(90)= 360 ../.
= 3(0.5)2(90) = 67.5 ..= (0.5)2(90) = 22.5 ..
:
:
RRRL5.66 m0.707 m
wmax = 360 kg/m67.5 kg
RRRL5.66 m0.707 m
wmax = 360 kg/m22.5 kg
RoofRoof TrussTruss
Truss
Free Support
Purlins
Top chord
Bottom chord
Sag rod
Truss
Fixed Support
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Types of TrussesTypes of Trusses
King Post Truss Pratt Truss
Howe Truss
Fink Truss
Fan Truss
Howe TrussPratt Truss
King Post This is the most basic truss type. Primarily used for simple structures with short spans.
Fink Capable of longer spans than the King Post, adding further design flexibility.
Flat - Using this truss can reduce the amount of wall area that needs to be sheathed.
Double Pitch or Dual Pitch An asymmetrical truss used where the designer wants a change in roof appearance.
Gambrel This truss is often used in agricultural buildings and barns.
Hip This is one section of a hip roof system.
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T-2
Sag rodPurlins Bracing
T-1
Bracing of TrussesBracing of Trusses
Roof Plan
1 25.00
35.00
45.00
55.00
65.00
75.00
85.00
95.00
105.00
A
B
10.0
0M
C
10.0
0M
Loading on TrussesLoading on Trusses
Purlins
Prim
ary
Trus
sS
econ
dary
Tru
ss
Trib
utar
y A
rea
=5
x 20
=10
0S
q.M
.
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Loading on Loading on PurlinPurlin
s s
Primary Truss
C Purlins
L
s
s
s
Tributary Area
+ = ./.
s L
= x s ./.
= 6 ./.
q
q
sin,8
,
cos,8
,
2
0
2
wwlwMSM
f
wwwlw
MSMf
xx
yy
yby
yy
xx
xbx
===
+===
0.175.066.0
+=+y
by
y
bx
by
by
bx
bx
Ff
Ff
Ff
Ff
q
wwy
wx
Design of Design of PurlinsPurlins
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Secondary TrussSecondary Truss
Primary Truss under Loading
Lower chordin Tension
Upper chordin Compression Lateral Buckling of upper
chord in primary trussLa
tera
l win
d lo
ad
Secondary Truss helps Primary Truss for
- Lateral wind load
- Lateral buckling of upper chord
- StabilityL
L
L/r
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: = 30 ./.
= 14 ./.
= 44 ./.
1.0 5.0
= 44 x 1.0 = 44 ./.
= 6 ./.
= 44 + 6 = 50 ./.
m-kg1538
549kg/m,4904.14cos50
m-kg388
512kg/m,1204.14sin50
20
20
=
===
=
===
xy
yx
Mw
Mw
3cm27.9)500,2(66.0
)100(153===
bx
xx F
MS
C125x50x20x2.3 . (Sx = 21.9.3, Sy = 6.22.3, Ix =137.4, Iy=20.6.4, 4.51./.)
x :
y :
2kg/cm 6.6989.21
)100(153===
x
xbx S
Mf
2kg/cm 9.61022.6
)100(38===
y
yby S
Mf
OK( ) ( ) 0.175.0500,275.0
9.610500,266.06.698
75.066.0=+=+
y
by
y
bxF
fF
f
:)137)(101.2(384
)500)(100/49(53845
6
44
max
==DEI
wl
OK
==
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= 60 x 5 x 0.5 = 150 .
T-1:
T-1 = 5
= 30 ../.
= 14 ../.
(+) = 6 ../.
() = 10 ./.
= 60 ../.
= 60 60 1 = 300 .. 150 ..
300 ..
(.) (.)L1L2 = L12L13 0 1.00L2L3 = L11L12 2200(T) 1.00L3L4 = L10L11 3000(T) 1.00L4L5 = L9L10 3240(T) 1.00L5L6 = L8L9 3200(T) 1.00L6L7 = L7L8 3000(T) 1.00
U1U2 = U12U13 2267(C) 1.03U2U3 = U11U12 3092(C) 1.03U3U4 = U10U11 3339(C) 1.03U4U5 = U9U10 3298(C) 1.03U5U6 = U8U9 3092(C) 1.03U6U7 = U7U8 2783(C) 1.03
Lower Chord:
Upper Chord:
-
VerticalBracing:
DiagonalBracing:
(.) (.)
L1U1 = L13U13 1800(C) 0.50L2U2 = L12U12 1100(C) 0.75L3U3 = L11U11 600(C) 1.00L4U4 = L10U10 240(C) 1.25L5U5 = L9U9 50(T) 1.50L6U6 = L8U8 300(T) 1.75
L7U7 1050(T) 2.00
L2U1 = L12U13 2460(T) 1.12L3U2 = L11U12 1000(T) 1.25L4U3 = L10U11 339(T) 1.41L5U4 = L9U10 64(C) 1.60L6U5 = L8U9 360(C) 1.80L7U6 = L7U8 604(C) 2.02
L4L5 L9L10 = 3240 . (T) 1.0
, Ft = 0.60Fy = 0.60(2,500) = 1,500 ./.2
, Ag = 3240/1500 = 2.16 .2
L50 x 50 x 4 . (Ag = 3.89 .2, rmin = 0.98 .)
A307 12 .
, Ae = 0.85Ag = 0.85(3.89) = 3.31
= 0.5FuAe = 0.5(4,000)(3.31)
= 6,620 . > 3,240 . OK
, L/r = 100/0.98 = 102 < 300 OK
:
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U3U4 U10U11 = 3,339 ..() 1.03
, Fa = 1,000 ../.2
, A = 3,339/1,000 = 3.34 .2
L50 x 50 x 4 . (A = 3.89 .2, rmin = 0.98 .)
, L/r = 103/0.98 = 105
, Fa = 876.2 ../.2
= (3.89)(876.2) = 3,408 .. > 3,339 .. OK
:
L2U1 L12U13 = 2,460 .. 1.12
, Ft = 0.60Fy = 0.60(2,500) = 1,500 ../.2
, Ag = 2460/1500 = 1.64 .2
L40 x 40 x 3 . (A = 2.35 .2, rmin = 0.78 .)
:
A307 12 ..
, Ae = 0.85Ag = 0.85(2.35) = 2.00
= 0.5(4,000)(2.00) = 4,000 .. > 2,460 .. OK
, L/r = 112/0.78 = 143.6 < 300 OK
1) :
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L7U6 L7U8 = 604 . 2.02
L65 x 65 x 6 . (A = 7.53 .2, rmin = 1.27 .)
= (4.70)(387.7) = 1,822 . > 600 . OK
L/r = 202/0.78 = 259 > 200 NG
2 L40 x 40 x 3 . (A = 2(2.35) = 4.70 .2)y
y
x x
Ix = 2 ( 3.45 ) = 6.90 .4
Iy = 2 ( 3.45 ) + 4.70 ( 1.07 )2 = 12.28 .4Control
min 6.90 / 4.70 1.21 cmr = =
L/r = 202/1.21 = 167 < 200 OK
, Fa = 387.7 ./.2
2) :
150 kg300 kg
300 kg300 kg
300 kg300 kg
300 kg
150 kg300 kg
300 kg300 kg
300 kg300 kg
12 m
FIXFREE
Max. Deflection:
From analysis,
Dmax = 1.64 cm
< [1200/300 = 4.0 cm] OK
Free (Roller) Support Design:
slot
= 12
a = 1210-6 /oc DT = 40 oCaDTL = 1210-6401,200 = 0.576 cm
Slot length = 2 0.576 + 1.6 = 2.75 cm USE 5 cm
BOLT 16 MM
5 cm
2 cm