pd mechanical dsgn

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    Step 1: Specification

    Material T in C T out C

    34o API Crude oil 40 67

    42o API Kerosene 200 90

    T in T out

    Shell 200 90

    Tube 40 67

    T mean 145 C

    Cp (145C) 2.47 kJ/KgC

    Duty 754.7222222 kW 754722.222

    Step 2: Physical Properties

    Kerosene Inlet Mean Outlet

    Temperature 200 145 90

    Specific Heat 2.72 2.47 2.26

    Thermal Conductivity 0.13 0.132 T

    Density 690 730 770

    Viscosity 0.22 0.43 0.8

    Step 3: Overall Coefficient

    For an exchanger for this type, the overall coefficient will be in the range of 300-500 w/mC

    See figure 12.1 and table 12.1; so start with 300

    Step 4: Exchanger Type Dimension

    Tlm = (Thi - Tco) - (Tho -

    ln [(Thi - Tco)/(Th

    Tlm = 81.89229794

    R = Thi - Tho

    Tco - Tci

    = 4.074074074

    S = Tco - Tci

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    Thi - Tci

    = 0.16875

    From figure 12.19, Ft = 0.92

    Tm = 75.34091411

    Step 5: Heat Transfer Area

    Uo = q

    AoTm

    Ao = q

    UoTm

    = 33.39142841

    Step 6: Layout and Tube Size

    Using a split ring floating head exchanger for efficiency and ease of cleaning

    Outer Diameter 19.05 mm 0.01905

    Internal Diameter 14.83 mm 0.01483Triangular 23.81 mm 0.02381

    Long Tubes 5 m 5000

    Pitch/ Diameter 1.25

    Step 7: Number of Tubes

    Area of one tube (neglecting thickness of tube sheet)

    = 0.2992367 m

    Number of tubes = 111.5886801 Say

    So, 2 passes, tube per pass = 55.5 Say

    Check the tube-side velocity at this stage to see if it look reasonable

    Tube cross sectional area = 0.000172732 m

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    Area per pass = 0.009672978 m

    Volumetric Flow Rate = Flow of Crude x

    3600

    = 0.016818708 m/s

    Tube Side Velocity, Ut = 1.738731069 m/s

    Hence, the velocity is satisfactory, between 1 and 2 m/s.

    Step 8: Bundle and Shell Diameter

    From Table 12.4, for tube passes, K1 = 0.249

    n1 = 2.207

    Bundle Diameter, Db = Outer Diameter x (Nt/K1)^(1/n1)

    Pt = 1.25do

    do = 0.019048 m

    Db = 302.150182 mm

    For a spliting floating head exchanger the typical shell clearance from figure 12.10 is 53 mm,

    Ds = 355.150182 mm

    Step 9: Tube Side Heat Transfer Coefficient

    Re = xUtxDi

    = 6049.309164

    Pr = CpxThermal Conductivity

    = 53.5880597

    L/D = 337.1544167

    From figure 12.23, jh = 0.0038

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    Nu = jh x Re x Pr^0.33

    Nu = 85.52278363

    hi = Nu x (Thermal Conductivity/ Internal Di

    = 772.7614974

    Step 10: Shell-side heat transfer coefficient

    As a first trial take the baffle spacing = Ds/5

    = 71.03003641

    As = 5041.014512

    Equilateral triangular pitch

    de = 1.1 (Pt - 0.917do)

    do

    = 13.51957786 mm

    Volumetric flow rate on shell side = 0.003805175

    Shell side velocity = 0.754845276

    Re = 17325.63009

    Pr = 8.046212121

    Use segmental baffles with a 25% cut. This should give a reasonable heat transfer coefficient

    From figure 12.29, jh = 0.0048

    hs = 1615.795011 W/mC

    Step 11: Overall coefficient

    Kw = 55

    1/hi = 0.00129406

    1/hid = 0.00035

    ln do/di = 0.250414945

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    1/ho = 0.00061889

    1/hod = 0.0002

    1/Uo = 0.002930853

    Uo = 341.1975878

    Step 12: Pressure Drop

    Re = 6049.309164

    Ut = 1.738731069

    From figure 12.24, jf = 0.0053

    Pt = 41930.37008 N/m

    = 0.42 bar

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    Pressure in (bar) Permissible Pressure drop (bar) Fouling Factor (W/m2C)

    6.5 1 0.0003

    5 1 0.0002

    Hours Second

    1 3600

    W

    Crude oil Outlet

    C Temperature 67

    kJ/kgC Specific Heat 2.07

    W/mC Thermal Conductivity 0.134

    kg/m Density 812

    mNsm- Viscosity 2.86

    w/mC

    Tci)

    o - Tci)]

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    m

    mm

    mm

    111 tubes

    56

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    1

    density

    19.05 mm

    0.302 m

    o the shell inside diameter

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    meter)

    say 71

    mm 0.005041 m

    0.01352 m

    m/s

    without too large a pressure drop.

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    Mass Flowrate (kg/h)

    50000

    10000

    Mean Inlet

    53.5 40 C

    2.04 2.01 kJ/kgC

    0.134 0.135 W/mC

    825.8 840 kg/m

    3.52 4.3 mNsm-

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    cost estimation

    guthrie method

    K1 4.8306 log10Cp= 4.274003

    K2 -0.8509 Cp= 2033986

    K3 0.3187

    A 33.4

    Fm 1 Cbm= 6691816

    Fp 1

    b1 1.63

    B2 1.66

    Cp 2033986

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    1

    2

    3

    45

    6

    7

    8

    9

    10

    11

    12

    13

    14

    15

    16

    17

    18

    19

    20

    21

    22

    23

    24

    2526

    27

    28

    29

    30

    31

    32

    33

    34

    35

    3637

    38

    39

    40

    41

    42

    43

    44

    Heat Exchanged

    Transfer Rate, Service

    Tube Type

    CONSTRUCTION OF ONE S

    Corrosion Allowance mm

    Tube No.

    Tubesheet-Stationary

    Channel or Bonnet

    Shell Steel

    Rating

    Size

    Connection

    Intermediate

    Out

    In

    No. Passes per Shell

    Design Temperature C

    Design/ Test Pressure kPa (ga)

    Latent Heat kJ/kg @ C

    Inlet Pressure kPaVelocity m/s

    Pressure Drop, Allow./Calc kPa

    Fouling Resistance (Min.)/Calc mC/W

    Temperature (In/Out) C

    Density kg/m

    Viscosity/ Liquid mPa.s

    Molecular Mass, Vapor

    Molecular Mass, Noncondensable

    Specific Heat Capacity kJ/(kgC)

    Vapor (In/Out)

    Liquid

    Steam

    Water

    Noncondesable

    Fluid Name

    Surf/ Unit (Gross/Eff)

    Thermal Conductivity J/(s.m.C/m)

    Service of Unit Oil to Oil Exchange

    Size

    Fluid Quantity, Total kg/h

    Plant Location

    Customer

    Fluid Allocation

    PERFORMANCE OF ONE U

    Address

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    45

    46

    47

    48

    49

    50

    5152

    53

    54

    55

    56 Remark

    Weight/ Shell

    Code Requirement

    Floating Head

    Expansion Joint: Carbon Steel

    Gasket-Shell Sidev- Inlet Nozzle

    Bypass Seal Arrangement

    Support: Tube

    Baffles: Long

    Type: SegmBaffles: Cross

    Floating Head Cover

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    Material: Carbon Steel

    Tubesheet: Floating

    Channel Cover

    Shell Cover

    ELL

    ODID

    Tube Side

    3

    2

    Shell Side

    3

    2

    0.0003

    100

    650

    0.0002

    100

    500

    Sketch (Bundle/ Nozzle Orien

    150#

    4.3

    840

    40

    2.26

    0.135

    Crude Oil

    50 000

    In

    10 000

    0.135

    2.012.72

    0.13

    Out

    90

    770

    0.8

    In

    200

    690

    0.22

    Kerosene

    r Item No. E-4

    Connected In Parallel

    Reference No.

    Date: Rev:

    Proposal No.

    NIT

    Shell Side Tube Side

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    Type: Flanged

    Impingement Protection

    InletSpacing: 75 mm%Cut (Diameter/ Area): 25%ented

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    ation)

    2.86

    812

    67

    Out

    0.134

    2.07

    Series

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    MECHANICAL DESIGN

    specification

    shell 355.15 mm

    tubes 14.83 mm id

    19.05 mm od

    length 5000 mm

    kerosene in the shell, operating pressure 5 bar

    crude in the tubes, operating pressure 6.5 bar

    material of construction, semi-killed or silicon killed crbon steel

    a) Design Pressure: takes 10% greater than operating pressure

    shell = 4.4 = 440000 N/m2

    tubes= 6.05 =650000 N/m2

    design temperature: 200 oC

    take this design temperature both shell and tubes. The tubes could reach the kerosene

    temperature if there was no flow of crude oil

    b) corrosion allowance

    kerosene= 2 mm

    crude oil= 4 mm

    c) end covers used torispherical, header-cover flat plate

    d) stressing

    from table 13.2, design stress is 105 N/mm2 at 200oC

    shell: e= 0.0008 m = 0.8 mm

    add corrosion allowance= 2.8 mm

    thiss is less than the minimum recommended thickness so round up to 5 mm

    header: e= 0.0011 m = 1.1 mm

    add corrosion allowance = 5.1 mm

    shell end cover, torispherical,

    take Rc = 0.3

    Rk/Rc = 0.1

    Cs = 2.37 take joint factor as 1 formed he

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    e = 0.00148 m = 1.5 mm

    add corrosion allowance = 3.5 mm

    floating head torispherical:

    from figure 12.10 bundle to shell clearance, take as split ring

    Db = 53.15 mm = 53

    take Rc = 0.3

    Rk/Rc = 0.1

    Cs= 2.37

    e= 0.00206 m = 2.1 mm

    add corrosion allowances = 6.1 mm

    flat plate (header cover) type e,

    Cp= 0.55

    Di= 355 mm = 0.35 m

    De= 0.4 m

    e= 0.167 m = 16.7 mm

    add corrosion allowance = 20.7 mm

    all thickness will be rounded to the nearest standard size

    e) Tube rating

    tube id= 14.83 mm

    tube od= 19.05 mm

    design stress = 105000000 N/m2

    design pressure = 6.05 N/m2

    thickness required , e = 0.0000053 m = 0.005

    actual wall thickness = 2.11 mm

    f) tube sheet thickness should not be less than tube diameter

    take thickness as 20 mm

    shell od= 365.15 mm say 370 mm

    design pressure= = 440000 N/m2

    design temperature 200 oC

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    refer to table 13.5, 6 bar rating will be satisfactory

    floating head od 350 mm

    design pressure 6.05 N/m2

    design temperature 200 oC

    based on the table 13.5 use 10 bar rated flanged

    h) supports

    use saddle supports

    diameter 0.4 m

    length 10 m

    shell and header volume of steel 0.063 m3volume of shell head, take as flat 0.0004

    volume of floating head, take as flat 0.0005

    volume of flat plate end cover 0.0026

    volume of tube-sheet 0.0026 ignoring the holes

    volume of tube 0.115

    number of baffles 77

    taking baffles as 3 mm thick and ignore the baffle cut

    volume = 0.027

    total volume of steel

    shell 0.063

    shell head 0.0004

    floating head 0.0005

    end cover 0.0026

    tube sheet 0.0026

    tubes 0.115

    baffles 0.027

    total 0.2111 m3

    taking density of steel as 7800 kg/m3

    mass of HE= 1646.58 kg

    weight HE= 16152.9498 N

    mass of water, ignore volum of tube 1257 kg

    weight= 12331.17 N

    maximum load on supports= 28484.12 N

    29 kN