Trang 1/4 KHOA KHOA HC C BN THI HC K II, NM HC 2010-2011 Bc/H:Lin thng i hc Mn thi:Ton B3 (STT v Gii tch) M mn hc:40134006. S TC: 4 Ngy thi:31/5, 3/6, 8/6, 11/6/2011Thi gian lm bi:60 pht (c s dng ti liu) Cu 1.Gi s A l ma trn vung cp n. Mnh no sau y l SAI? A.det(A)=0 khi v ch khi cc vect dng ca A l h c lp tuyn tnh trong n . B.Khng gian nghim ca h phng trnh AX =u l { u} khi v ch khi det(A) =0.C.r(A) < n khng gian con sinh bi h vect ct ca A c s chiu nh hn n. D.det(A)= 0 th cc vect ct ca Al c s ca n . Cu 2.Cho A l ma trn cp6 7 . Gi M l h vect dng ca A, N l h vect ct ca A. Bit rng hng ca A bng 5. Khng nh no di y l NG? A. N c lp tuyn tnh, M ph thuc tuyn tnh. B.M v N u c lp tuyn tnh. C.M v N u ph thuc tuyn tnh. D.M c lp tuyn tnh, N ph thuc tuyn tnh. Cu 3.Cho A l ma trn cp5 6 . Gi M l h vect dng ca A, N l h vect ct ca A. Bit rng hng ca A bng 5. Khng nh no di y l NG? A. N c lp tuyn tnh, M ph thuc tuyn tnh. B. M v N u c lp tuyn tnh. C. M v N u ph thuc tuyn tnh. D. M c lp tuyn tnh, N ph thuc tuyn tnh. Cu 4.Trong khng gian vct3 trn cho khng gian vct con W= 1 2 331 2 3 1 2 31 2 32 0( , , ) / 2 3 4 03 4 0x x xx x x x x xx x mx + = e + = ` + + = ) . Tm m dimW = 1 A . m= 4 B. m = 5 C. m = 6D. m = 6 Cu 5. Trong3 cho vct v= (0,8, 4) v c s S= ( ) ( ) ( ) { }1, 0, 0 ; 1, 4, 0 ; 0, 0, 4 . Hy tm[v] ?S A. 0[v] 24S =

B.

2[v] 21S =

Trang 2/4 C. 0[v] 84S =

D.

1[v] 22S = Cu 6. Cho T l nh x tuyn tnh t 3 3R R ,( )1 2 3 1 2 1 3 3T x , x , x (x x , x x , x 3) = + + . Chn cu tr li ng nht trong cc cu sau: A. T khng l nh x tuyn tnh v T(x+y)= Tx+Ty 3x, y R eB. T l nh x tuyn tnh vT( x) Tx o = o3x R , R e oeC. T khng l nh x tuyn tnh D. T l nh x tuyn tnh Cu 7. Cho T l nh x tuyn tnh t 3 3R R , ( )1 2 3 1 2 3 1 2 3 1 2 3T x , x , x (x 2x x , 2x 3x 4x , 3x 5x 5x ) = + + + + + +C s v s chiu ca KerT l: A. (-5,2,1); dimKerT=1 B. (5,-2,1); dimKerT=1 C. (5,2,-1); dimKerT=1 D. (5,2,1); dimKerT=1 Cu 8. Tm tt c cc vct ring tng ng vi tr ring0 = ca ma trn A =2 0 00 0 0 .0 0 0 A. v = ( 0, , o | ), o | e B. v=( 0, , o | ), o | e { } \ 0C. v = ( 0, , o | ), o | e2 2, 0 o | + > D.v = ( , , o | ), , o | e Cu 9. Dng ton phng no sau y xc nh m? A.f(x1,x2, x3 ) = 21x + 222x -323x

B. f(x1,x2, x3 ) = 21x + 422x +723x. C. f(x1,x2, x3 ) =521x + 22x +523x

+1 2 1 3 2 34 8 4 x x x x x x D. f(x1,x2, x3 ) = -321x -222x -23x1 2 1 32 2 x x x x + Cu 10.Cho A l ma trn vung cp 2 c tng cc phn t trn mi dng v mi ct u bng k. Nhng vctno trong cc vct v1 = (1,0); v2= (1,1); v3= (0,1) l vct ringca A? A. Ch c v1

B. Ch c v2

Trang 3/4 C. Ch c v3 D. v1 v v3 Cu 11.Chuyn tch phn sau sang ta cu v xc nh cn tch phn ( )2 2 2, I x y z dxdydzO= + + trong O l min 2 2 21 4. x y z s + + sA. 2 220 1 0sin . I d r dr dt tm u u = B. 2 2 230 1 0. I d r drdttm u = C. 2 240 1 0sin . I d r dr dt tm u u = D. 2 4 240 1 0sin . I d r dr dttm u u = Cu 12.Tnh tch phn 3, I y dxdydzO= trong O l hnh hp{ } 1 0, 1 0, 1 0 . O = s s s s s s x y zA.0. I =B.1. I = C. 1.4I = D. 1.4I =Cu 13.Tnh tch phn ng ( ), = CI x y dStrong C l on thng ni cc im ( ) 0, 0 Ov( ) 2, 2 . AA.2. = IB.0. = IC.2. = ID.2. = ICu 14.Cho im( ) 0,1 Av( ) 1, 0 B , tnh tch phn ng( ) ( ) 2 1 1ABy x dx y dy + + + ly theo ng1 y x = +i t im A n B. A.4 I = B.4. I =C.3. I =D.3. I = Cu 15.Cho C l ellipse 2 21.4 9x y+ =Tnh tch phn ng loi hai ( ) ( ) sin 1 cos .CI y x dx x x dy = + + Trang 4/4 A.0. I =B.. I t =C.6 . I t =D.36 . I t =Cu 16. Tnh 2 2,CI xy dy x dx = trong C l ng trn 2 2 2. x y R + = A. 3.3R tB. 4.4R t C. 3.3R t D. 4.4R tCu 17.Tnh tch phn mt loi mt,SI dS = trong S l mt2 0, x y z + + =2 26. z y + sA.6. I t =B.3 6. I t =C.6 6. I t =D.9 6. I t =Cu 18.Tnh tch phn mt,SI dxdy = trong S l mt trn ca mt 2 22, 4. x y z + s =A.0. I =B.8 . I t =C.2 . I t =D.4 . I t = Cu 19.Chui 211nno= ( ol mt tham s) hi t khi v ch khi A.3 o > B.3 o > C.1 o > D.1 o >Cu 20.Chui nnx ) 1 2 (1+ = c min hi t lA. (-1,0). B. [-1,0). C. (-1,0]. D. [-1,0]. HT