oily water seperator

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Design of Oily Water Seperator 1.097 m3/s Flow rate Q 3949.2 m3/hr Use Stokes law for rising velocitVt g*d^2*(1-S)/18v Where acceleration due to gravity g 9.81 m/s2 diameter of the oil particle d 0.00015 m specific gravity for the oil dropS 0.83 kinematic viscosity of water v 1.38E-06 m2/s Therefore Rise velocity of the oil particleVt 0.001511 m/s 5.438152 m/hr Horizontal Velocity Vh= <=15xVt 81.57228 m/hr Cross sect area of Oilwater seperAc 48.4135 m2 Minimum area should Depth D 0.75 m Width W 1.5 m Minimum area 1.125 m2 Based on the above minimum area Horizontal Velocity Vh 3510.4 m2 Calculat ethe actula area by using the F factor for short ci For Vh/Vt 645.5134 Factor "F" (See tabel) 1.26 Hence Horizontal Area Ah 915.0152 m2 Length L 610.0101

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Design of Oily Water Seperator1.097 m3/s

Flow rate Q 3949.2 m3/hr Vh/VtUse Stokes law for rising velocity Vt g*d^2*(1-S)/18vWhere 3acceleration due to gravity g 9.81 m/s2 6diameter of the oil particle d 0.00015 m 10specific gravity for the oil droplet S 0.83 15kinematic viscosity of water v 1.38E-06 m2/s 20ThereforeRise velocity of the oil particle Vt 0.001511 m/s

5.438152 m/hrHorizontal Velocity Vh= <=15xVt

81.57228 m/hrCross sect area of Oilwater seperator Ac 48.4135 m2Minimum area should Depth D 0.75 mWidth W 1.5 mMinimum area 1.125 m2Based on the above minimum areaHorizontal Velocity Vh 3510.4 m2Calculat ethe actula area by using the F factor for short ciructing and trubulenceFor Vh/Vt 645.5134Factor "F" (See tabel) 1.26Hence Horizontal Area Ah 915.0152 m2Length L 610.0101

TurbulenceF=1.2FtFactor,Ft

1.07 1.2841.14 1.3681.27 1.5241.37 1.6441.45 1.74