11 taguchi technique ii
TRANSCRIPT
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Materials Engineering 14Taguchi Technique II
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defined as mean divided by the standard deviation
a response variable that takes both the mean and the variation into consideration
Signal-to-Noise Ratio (S/N ratio)
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Signal-to-Noise Ratio (S/N ratio) made up of the mean level and the variation
around this mean
helps find a setting of the control factors thatgive the best mean level while keeping variationunder control
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Larger the Better
S/N Formulas
)1
(1
log10 / 2i yn
N S
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Nominal is Best
S/N Formulas
e
em
V V Sn N S )(
1
log10 /
)(1
1
)(1
2
2
mie
im
S yn
V
yn
S where:
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A manufacturer of resistors wants to improve yield on substrate chips, many of which have been rejected for thickness problems (tolerance204). They decided to run an experimentaldesign on the following factors:
Example
Factor Level 1 Level 2 Level 3
A Ceramic Material Paraffin Paste Mixture
B Machine Pressure 300 375 450
C Mixing Time 60 90 120
D Temperature 275 350 425
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ResultL9 (3 4 ) A B C D Thickness Totals
1 1 1 1 1 27 31 28 862 1 2 2 2 16 18 20 54
3 1 3 3 3 19 14 21 54
4 2 1 2 3 23 20 25 68
5 2 2 3 1 25 24 26 75
6 2 3 1 2 19 18 20 57 7 3 1 3 2 29 25 27 81
8 3 2 1 3 15 19 18 52
9 3 3 2 1 16 17 18 51
Response Table (Totals)Factor A B C D
Level 1 194 235 195 212
Level 2 200 181 173 192
Level 3 184 162 210 174
Total 578 578 578 578
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Solution
CF n
A
n
A
n
ASS
SS
CF
factor
total
23
22
21
222
2
)()()(5.5685.373,12)18...1627(
5.373,1227
)18...1627(
1.78
5.149184
9200
9194 222
DC B Atotalerror
A
SSSSSSSSSSSS
CF SS
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Source of variation dof SS MS f SS P(%)
A 2 14.5 7.25 1.67 5.82 1
B 2 318.72 159.36 36.72 310.04 55
C 2 76.94 38.47 8.86 68.26 12
D 2 80.28 40.14 9.25 71.16 13error 18 78.06 4.34 112.86 20
Total 26 568.5
Solution
Reponse Table, Averages
Factor A B C D
Level 1 21.6 26.1 21.7 23.6
Level 2 22.2 20.1 19.2 21.3
Level 3 20.4 18 23.3 19.3
OptimumSettings A 3 B2 C2 D3
target thickness valuesnearest 20
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Compute for the corresponding S/N Ratios Nominal is Best (as required by the problem)
Solution
e
em
V
V Sn N S
)(1
log10 /
)(1
1
)(1
2
2
mie
im
S yn
V
yn
S
76.2234.4
)34.433.465,2(31
log10 / N S
34.4]33.465,2)283127[(2
1
33.465,2)283127(31
222
2
e
m
V
S
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Solution
Response Table (S/N Totals)
Factor A B C D
Level 1 55.8 64.5 66.8 75.4Level 2 72.7 65.5 62.8 67.3
Level 3 65.6 64.1 64.5 51.4
Total 194.1 194.1 194.1 194.1
Original Settings A 3 B2 C2 D3
Revised Settings A 2 B2 C1 D1
choose highest S/N ratio
L9 (3 4 ) A B C D S/N Ratio
1 1 1 1 1 22.82 1 2 2 2 19.1
3 1 3 3 3 13.9
4 2 1 2 3 19.1
5 2 2 3 1 28.0
6 2 3 1 2 25.6
7 3 1 3 2 22.68 3 2 1 3 18.4
9 3 3 2 1 24.6
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Source of Variation SS dof MS f
SS P(%)
A 48.0 2 24.0 30.0 46.4 30.9
B 0.3 (2)
C 2.7 (2)D 99.4 2 49.7 62.1 97.8 65
error 3.0 4 0.8 6.2 4.1
Total 150.4 8 100
Solution
Therefore, choosing the correct settings for the ceramic material and the heat treat temperature will reduce the variation in the thickness of the substrate chips. Machine pressure and mixing time will be adjusted tomove the process mean to the target value.
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Identify control factors
Determine optimum levels for control factors
Identify signal factors using raw data ANOVA
Determine optimum levels for signal factors
Perform confirmation run
Control critical control and signal factors
Summary of Steps for Analysis
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Additional Notes The first ANOVA table is used to determine the
signal factors while the second ANOVA table isused to identify the control factors.
Factor settings that will be considered in theprocess line would depend on the revised
setting, and the signal factors may be adjusted toproduce results close to the desired value.
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Exercise A manufacturer of rubber hosing wants toincrease the strength of his product. Hedetermines four factors that could influence hisprocess. He sets them at the following levels:
Factor Level 1 Level 2 Level 3
A Machine Temperature 300 350 400
B Reaction Time 5 10 15
C Agitation Speed 100 150 200
D Silicon Excess Rate 10 20 30
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