tinh thiet bi nha may bia nguyen dang hung

8/6/2019 Tinh Thiet Bi Nha May Bia Nguyen Dang Hung

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3.2. Tnh v chn thit b

3.2.1 Phn xng nu.

3.2.1.1. Thit b phn xng nghin.

Nguyn liu c cn ring r tng loi, mi my nghin dng mt cn.

+ Cn go:

- Lng go ln nht trong 1 m l: 1796,4kg.

- Lng go ln nht trong 1 ngy l: 8982kg.

+ Cn malt:

- Lng malt ln nht nht trong 1 m l: 5392,8kg.

- Lng malt ln nht trong 1 ngy l: 26964 kg.Chn cn.

- Chn cn in t ch th s digital.

- Chn cn cho ton b dy chuyn nng sut ca cn m ln nht 5000.5

kg.

- Cc thit b cm bin ca cn, h thng khuych i tn hiu c tnh

ton m bo chng nhiu cn hot ng chnh xc.

Chn my nghin.- My nghin malt.

+ Lng malt ti a cho 1 m l: 5392,8kg. Thi gian lm vic ca my l 4h/ ca,

ngy lm vic 3 ca, ngy nghin 6 m, thi gian nghin mi m l 3h, h s s

dng my l: 0,75. Vy lng malt nghin trong 1 h l:

5392,8/ ( 3x 0,75) = 1997,3 kg/h

=>Vy ta chn:

- Loi my nghin 2 cp trc, nng sut 3000 kg/h.

- Kch thc trc nghin: ng knh 250mm, di 600 mm.

- khong cch gia 2 trc: 1,25 mm

- C mt phu cha malt cha nghin.

- Vt liu ch to: thp CT3 dy 3mm.


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- Cng sut ng c 11 kw.

- S lng: chn 1 my nghin.

- My nghin go.

Tng t: ta c lng go nghin trong 1 h l:1796.4 / ( 3 x 0,75) = 798,4 kg/h

Loi my nghin ba, cng sut 1000 kg/h.Kch thc bung nghin:

ng knh 500mm, rng 200 mm.

- C mt phu cha go cha nghin, c h thng tch lng bi.

- Vt liu ch to: thp khng r dy 3mm.

- Cng sut ng c 6 kw.

3.2.1.2. Tnh ton v chn thit b h ho.

Tnh kch thc ni:

+ Chn thit b h ho:

Chn thit b h ho l thit b thn tr, y chm cu v np hnh nn c cc

kch thc nh sau

- ng knh D.

- Chiu cao tr H = 1,4D.

- chiu cao y h1=0,2D

- chiu cao np h2= 0,15D.

- S lng: 2 thit b.

+ Tnh ton:


3/35

- Lng nguyn liu a vo ni nu go, gm c bt v malt lt bng 10%

lng bt go l:

1796.4 0,995 + 10% 1796.4 0,995 =1966.2 (kg)

- Lng nc a vo ni h ho 7864.56 lt, vy tng khi lng dch h hol:

7864.56 + 1966.2 = 9830.7(kg)

- Khi lng ring ca dch l 1,08 tn/ m3, vy th tch dch nu l:

)(1,908,1

9,8307 3mVd ==

- H s cha y ca ni l 0,75, dng 1 ni, vy th tch ca 1 ni l:

V = 75.0Vd

= 75.01.9

= 12,1m3

- Vy th tch ni l:

Vt = )68

(4

3

11

22

hhD

HD

++ = 12,1

Vt = 322

)2,0(6

2,084

DDD

HD

++ = 12,1

Vt= 1,18D3 = 12,1 ( m3)

D =3

18,1

12,1

= 2,17(m)

- Chn ng knh ni l D = 2200mm.

Lp v o hi dy 100mm

ng knh ngoi: Dn = 2200 + 2 x 100 = 2400mm

Chiu cao tr: H = 2200 x 1,4 = 3080mm.

Chiu cao y: h1 = 2200 x 0,2 = 440mm.

Chiu cao np: h2 = 2200 x 0,15= 330mm.

Chn cnh khuy cong c dng hnh m neo.

d =0,8D = 2200 x0,8 = 1760 mm.

Tnh din tch truyn nhit.


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Ly din tch b mt truyn nhit: 0,5 m2/ m3 dch, th tch dch trong 1 ni h

ha l: 4,55 m3 , vy tng din tch b mt truyn nhit tnh cho 1 ni l:

F = 0,5 x 4,55 = 2,275 m2

c tnh k thut ca ni h ho:- Ni thn tr, y chm cu v np hnh nn c ch to bng vt liu thp

khng r.ng knh ni 2200mm, chiu cao phn thn trn 3080mm, tc

khuy 32v/pht

3.2.1.3. Tnh ton v chn thit b ng ho

Tnh kch thc ni.

+ Chn thit b ng ho:

Chn thit b ng ha c 2 v, thn hnh tr, y hnhchm cu v np hnh nn c cc kch thc nh sau

- ng knh D.


- Chiu cao y h1 =0,2 D

- Chiu cao np h2= 0,15D.

- S lng: 2 thit b.

+ Tnh kch thc ni- Tng lng dch em ng ho 1 m nu l: 982,23 x36 = 35360,28 kg.

- Khi lng ring d = 1,08 tn/ m3 nn th tch ca dch ng ho l:

)(741,3208,1

35,36028 3mVd ==

- H s s dng ni l = 0,75 vy th tch thc ca 1 ni l:

Vt =75,02

741,32

= 21,82 m3

- Vy th tch ni l:

Vt = )68

(4

3

11

22

hhD

HD

++ = 21.82

Vt = 322

)2,0(6

2,084

DDD

HD

++ = 21.82


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Vt= 1,18D3 = 21.82( m3)

D = 3272,1

82,21= 2,64(m)

- Chn ng knh ni l D = 2700mm.

Lp v o hi dy 100mm

ng knh ngoi: Dn = 2700 + 2 100 = 2900mm

Chiu cao tr: H = 2700 1,4 = 3780mm

Chiu cao y: h1 = 2700 0,2= 540mm.

Chiu cao np: h2 = 2700 0,15 = 405 mm

Chn cnh khuy cong c dng hnh m neo. Tra s tay ho cng 1 c ng

knh cnh khuy l:

d = 0,8D =2160 mm.

- Tnh din tch truyn nhit.

Ly din tch b mt truyn nhit: 0,5 m2/ m3 dch, th tch dch trong 1 ng ha

l: 16,2 m3 , vy din tch b mt truyn nhit l:

F = 0,5 x 16,2 = 8,18 m2.

c tnh k thut ca mi ni ng ho:

- Thit b ng ha l thit b gia nhit loi hai v thn tr, y chm cu v nphnh nn c lm bng vt liu thp khng r.

- ng knh ni 2700mm, chiu cao phn thn tr 3780mm, ng knh cnh

khuy 2160 mm, tc khuy 32 v/ pht.

2.2.1.4. Tnh v chn thit b lc dch ng

+ Chn thng lc y bng.

Thn hnh tr, lm bng thp khng g, c cc thng s k thut sau:

- Khong cch t y tht n y gi l 20 cm.- H s y thn tr l 0,85.

- ng knh D.

- Chiu cao nh h = 0,15D.

- To gc nghing y gi l 1,50


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- S lng: 2 thit b.

+ Tnh ton

Hnh 2.3: Thit b lc y bng

- Khi lng b malt v go sau 1 m nu l: 6215,4kg = 6,2154tn, khi lngring ca b: 0,75 tn/ m3.

Suy ra th tch b:75,0

2154,6= 8,28 m3

Chn chiu cao lp b l 0,6 ( v chiu cao thch hp l 0,4 0,6).

- Din tch y lc mi thit b:6,02

28,8

= 6,9 m2

ng knh mi thng lc l: D = 49,6

= 2,9m , chn D = 2,9 m, ng knh

ngoi: 3,1 m, chiu cao np: 0,15 D = 0,44m.

- Khi lng dch cn li sau ng ha l:1000

36000027,950 = 34,2tn. Khi

lng ring dch ng sau ng ha l: 1,06 tn/ m3.

- Th tch dch trong 1 thng l:06,12

2,34

= 16,1 m3

Chiu cao dch: hd = sV

d

= 67,71,16

= 2,1m3

. Th tch s dng ca thng 85%, chiu

cao thn tr ca thng: Ht=85,0

dh

= 2,47m. y gi cch y tht 2 cm, chiu cao

phn hnh tr thng: H = 2,47 + 0,02 =2,49 m,


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Vy th tch thc ca mi thng l: Vt =4

2HD

= 16,3 m3

3.2.1.5. Tnh v chn thit b nu hoa.

Tnh kch thc ni.

+ Chn thit b nu hoa:

Chn thit b nu hoa c thn hnh tr, y chm cu v np hnh

nn c cc kch thc nh sau

- ng knh D.


- chiu cao y h1 =0,2 D

- chiu cao np h2= 0,15D.

- S lng: 2 thit b.

+ Tnh kch thc

- H s y ca ni phi thp v dch khi si nhit cao s tro ln

chim mt th tch ln, chn h s y l 0,70.

- Lng dch ng trc khi a vo nu hoa l 1274,97 l tnh cho 1000 l bia

thnh phm Vy 1 m s l:V = 1274,97 36 = 45898,8(l) =46 (m3)

Vy tnh cho 1 thit b th: Vt =7,02

46

= 32,8m3

- Vy th tch ni l: Vt = )68

(4

3

11

22

hhD

HD

++ = 32,8m3

Vt = 322

)2,0(6

2,084

DDD

HD

++ = 32,8m3

Vt= 1,18D3 = 32,8m3 ( m3)

D = 318,1

8,32= 3,03(m3)

Chn ng knh ni l D = 3100mm.

Hnh 2.4: Thit b nu


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Lp v o hi dy 100mm

ng knh ngoi: Dn = 3100 + 2 x 100 = 3300mm

Chiu cao tr: H = 3100 x 1,4 = 4340mm

Chiu cao y: h1 = 3100 x 0,2 = 620mm.Chiu cao np: h2 = 3100 x 0,15 = 465mm.


Ly din tch b mt truyn nhit: 0,5 m2/ m3 dch, th tch dch trong 1 ni nu

hoa l: 23 m3 , vy din tch b mt truyn nhit l:

F = 0,5 x 23 = 11.5 m2.

c tnh k thut ca ni nu hoa:

- Thit b nu l loi thit b hnh tr, gia nhit kiu ng chm, dung tch32,8m3, chiu cao 4340mm, ng knh tr 3100mm lm bng thp khng r.

3.2.1.6. Tnh v chn thng lng xoy.

Tnh kch thc thng.

- Lng dch sau un hoa cho mi m l: 1202,6 x 36= 43293,6(kg).khi

lng ring ca dch l: 1.08 kg/lt

=> Vd =43293,6/ 1.08 = 40086.6 (l) = 41 (m3)

- S dng thng lng xoy lng cn v lm lnh nhanh s b vi h s

y 0,75.

- Chn 2 thng.

- Th tch thc ca 1 thng l:

Vt =75,02

41

= 27,3 m3

- Thng lng xoy y bng khi lp t phi nghing (8-10%) dch

c tho ra ht, cc thng s k thut ca ni:

ng knh D, y bng hi nghing 3 - 50

Chiu cao tr H = D.

Np hnh nn, chiu cao np h2 = 0,15 D


9/35

- Th tch thng tnh theo cng thc:

Vt = HD

4

2

= 27,3 m3

Vt= 0,785D3 = 27,3 m3 ( m3)

D = 3785,0

3,27= 3,2(m3)

Vy ng knh ni lng xoy D = 3,2 m,

Chiu cao tr H = 1 x 3,2 = 3,2 m.

Chiu cao np h = 0,15 x 3,2 = 0,48m.

c tnh k thut ca thit b.

- Thit b ny rt n gin ch l mt thit b hnh tr c dung tch 27,3 m3,

ng knh 3200mm, chiu cao 3200mm.

3.2.1.7. Thit b lm lnh nhanh.


- My trao i nhit tm bn 1 cp lm bng thp khng r, c kt cu

khung vi c cu p bc thp khng r, tm bn bng thp khng r dy

0,1mm, giong bng cao su, cc bch ni bng thp khng r.- C b iu chnh lu lng nc tan m bo nhit ra lun n

nh theo yu cu.

- My c th h nhit ca dch ng nng t 960C xung 80C bng cch

trao i nhit vi nc tan t 20 ln 800C vi cng sut 200hl/h.

- C ch th o nhit dch n h thng ln men.


- Cng thc tnh din tch b mt truyn nhit l:

)(2m

tk

QF

tb=

+ Q: tng lng nhit dng nng nhit dch cho ln cc im dng nhit

.


10/35

+ K: h s truyn nhit t hi n dch, kcal/m2.h..

+ tb: hiu s nhit trung bnh.

)/( hkcalT

QQQ ttm

+=

T : thi gian

Qm : lng nhit cn cung cp cho dch cho trong giai on nht nh.

Qtt = 5% Qm : lng nhit tn tht ra mi trng xung quanh.

Tnh Q:

- Q c xc nh bi chu k ti nhit ln nht, l chu k gim nhit

khi dch t 960C xung 80C trong 120 pht.

Q = m C t+ m : khi lng dch ng sau lng xoy ca 1 m, coi qu trnh bay hi khng

ng k,

= 1,08 kg/ lt m =1118,8 1,08 x 36= 43498,9 kg

+ C: nhit dung ring ca khi dch, kcal/kg0C. Tra s tay ho cng I c:

C = 0,95 (kcal/m2.h.)

Qm = 43498,9 0,95 (96 -8) = 3636511.7 (kcal)

- Nhit tn tht:Qtt = 5% Qm = 0,05 3636511.7 = 181825.5 (kcal)

Vy lng nhit cn cung cp l:

Tnh K:

- Cng thc tnh h s trun nhit k

2

21

1

11

1

++++

=

rr

k

+ 1: h s cp nhit t hi nc nng vo v thit b.

)/(6,1909168

60

120

181825.53636511.7hkcal

T

QQQ ttm =

+=

+=


11/35

1 = 6000 kcal/m2.h.

+ 2: h s cp nhit ca dch

p20002 = \ p: p p sut ca hi nc

m bo vn hnh sn xut cn p sut hi p = 2at 2 = 2000 2 = 2828,4( (kcal/m2.h.)

+ = 5mm = 0,005m: b dy ca v thit b.

+ : h s dn nhit ca v thit b, v thit b lm bng thp khng r nn: =

300 kcal/m2.h.

+21

1,

1

rr: h s dn nhit trung bnh ca cn bn bm vo 2 pha v thit b.

500011 =r i vi hi nc

5000

12=r i vi cht hu c, dung dch mui

)..kcal/m(363,1067

42,2828

1

5000

1

300

005,0

5000

1

6000

1

1

2dohk

k

=

++++

=

Tnh t:

Thc cht hnh thc trao i nhit y l hnh thc trao i nhit kiu gin tip.

Cng thc tnh:

21

1

21

lnt

t

ttttb

=

- t1: hiu s ln nhit gia hi lnh v khi dch.

t1 = 96 2 = 94(C)

- t2: hiu s gia nhit gia nc v khi dch.t2 = 80 8 = 72 (C)

Vy ta c:

Cttb

=

= 81

72

94ln

7294

96 80

82


12/35

Tnh F:

- Din tch b mt truyn nhit:

)(1,2281363,1067

6,1909168 2m

tk

QF

tb

=

=

=

- Chn din tch mi tm truyn nhit l 0,6 0,8 (m2)

- S tm l :48,0

1.22= 47 tm

3.2.1.8. Thit b un nc nng.

Tnh kch thc ni.

Nc nng trong qu trnh nu bao gm:

- Nc v sinh: nc ra thit b. Khong 8% thit b ln nht

- Nc cng nghip: nc dng nu v ra b.

+ Tnh nc v sinh:

- Ni ln nht l ni nu hoa. Th tch nc cn v sinh khong:

0,08 x 2( Vni nu hoa) = 0,08 x 2x32,8= 5,24m3

+ Tnh nc cho dy chuyn nu:

Lng nc dng cho ra b l: N1 = 546,6 x 36 = 19677,6 (l). =19,7 m3

- Lng nc dng nu v ng ho:

N2 = 7864.56+ 20748,24= 28612,8 (l)

Vy lng nc dng cho cng nghip l:

Ncn = N1 + N2 = 19,7 + 28,61= 48,31(m3)

Vy tng lng nc cn dng l:

N = 5,24 + 48,31 = 53,55(m3)

+ Chn thit b.

- Thit b c chn dng thn tr,y bng, np hnh chm cu c cc thng s

k thut:

- S lng l: 2 thit b

ng knh D, chiu cao tr H = 1,5D.

Chiu cao np: h = 0,1D.


13/35

H s y ca thng: 0,85.

Vy th tch thc ca 1 thng l:

Vt =85,02

53,55

= 31,5 m3

- Ta c cng thc:

Vt = HD

4

2

= 31,5

D = 3178,1

5,31= 2,99(m)

Vy ng knh thng D = 3 m.

Chiu cao tr: H = 4,5 m; chiu cao np h = 0,3 m.

3.2.1.9. Tnh v chn h thng CIP cho nh nu bia.H thng CIP cho nh nu bia c 3 thng gm:

- 1 thng cha NaOH 2%.

- 1 thng cha axit HNO3 0,1%.

- 1 thng cha nc.

Mi m nu xong thng c v sinh vi th tch cht lng bng 8% th tch

thng nu (v lng CIP ra bng 5 8% th tch thng nu). C 5 m trong 1

ngy, tuy nhin ch tnh cho mt m nu. V ni nu hoa ln nht nn tnh th tch

mi thng CIP theo th tch ni nu hoa.

Th tch 1 ni nu hoa: V = 32,8 m3. 1 m nu s dng 2 ni nu hoa

H s s dng ca thng CIP l 0,8, vy th tch ca mi thng CIP l:

Vt = 8,008,028,32

= 6,56 m3

Chn cu to thng:

- ng knh D.- Chiu cao tr H = 1,5D.

- Np hnh cu, chiu cao h2 = 0,1 D.

- y hnh chm cu, chiu cao h1 = 0,1 D.

Cng thc tnh th tch thng:


14/35

- Vy th tch ni l: Vt = )68

(4

3

11

22

hhD

HD

++ = 6,56m3

D = 3218,1

56,6= 1,75(m)

Vy ng knh mi thng CIP: D = 1,8 m.

Chiu cao tr H = 1,8 1,5 = 2,7 m.

Chiu cao y h1 = 0,1 1,8 = 0,18 m.

Chiu cao np h2 = 0,1 1,5 = 0,18 m.

- Trn np thng c ca a ho cht vo thng theo tng m, c ng ng

dn nc x l ho tan v pha long ho cht.

- Nhc im ca thng l khng t ng ho, phi pha ho cht theo tng

m.

- u im l thit b gn, khng cng knh, d vn hnh thao tc.

3.2.2. Phn xng ln men.

3.2.2.1. Tnh v chn thng ln men.

D H

h3

h4

h1

D: ng knh thit b (m)

h1: chiu cao phn nn (m)

H: chiu cao phn tr cha dch ng (m)


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h3: chiu cao phn tr khng cha dch ng (m)

h4: chiu cao phn tr phn np (m)

Th tch dch ln men trong 1 ngy: Vd = 201384(lt) 201,384 (m3) (c 5 m

trong ngy u cho vo 1 tank ln men). y cng chnh l th tch hu ch cathit b.

Chn:

H = 1,5D

h1 =2

1 D tg60o 0,866D

Ta c:

Vd = 4

2D

H + 31

4

2D

h1 0,447 D3

Vy:

D = 3447,0

dV = 3447,0

384,201

5,3 (m)

h1 = 0,866 5,3 = 4,589 (m)

H = 1,5 5,3 = 7,95 (m)

Th tch phn khng cha dch (15% th tch hu ch):

Vtrng = 0,15 Vd = 31,36 (m3)

Th tch thc ca thit b:

Vthc = Vd + Vtrng = 201,384+ 31,36 = 232,74 (m3)

h3 = 24

D Vtrng 1,42(m)

h4 = 0,2D = 1,06 (m)

Chiu cao thit b:

H1 = h1 + H + h3 + h4 = 15,01 (m)

Chn khong cch t y thit b n sn nh l 0,8 (m). Chiu cao ton b thit b

l:

Ht = H1 + 0,8 = 15,81 (m)

Tnh s thng ln men:


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- S thng ln men tnh theo cng thc:

1+

=

tV

TVN

T: chu k ln men, ngy.

Chn thi gian ln men chnh: 6 ngy.

Chn thi gian ln men ph: 10 ngy.

Chu k ln men: T = 6 + 10 + 1 = 17 (ngy)

- Mi thng ln men cha lng dch ln men bng lng dch ng nu

c trong mt ngy nn coi Vt = V.

Vy s thng l N = 17 + 1 = 18 (thng).

c tnh k thut ca thit b.- Tank ln men l thit b hnh tr nn gm 18 chic, c t ngoi tri

trn sn b tng cao > 1m, m bo chu c ti trng, gi bo.

- Nhit mi trng khng nh hng n cng ngh ln men, tn tht

nhit t nht, kn tuyt i, khng nc ma, nc v sinh ngm vo lp

bo n.

- Vt liu ch to cc tank bng thp khng r. Dung tch s dng 201,384

m3; y 60;+ng knh thng D = 5 m.

+ h1 = 4,589 m.

+ H = 7,95 m.

+ h3 = 1,36 m.

+ h4 =1,06 m,

3.2.2.2. Tnh v chn thng nhn men cp 2.

Thit b gy men ging cp 2

Chn thng c y v np hnh chm cu to iu kin cho men phn tn u

trong dch, khng b kt lng di y cn


17/35

D

h4

h3

H

h1

Th tch hu ch ca thit b:

V2 =10

1 Vd = 201,384 (lt) 20,1384 (m3).

Chn:

H = D

h1 = 0,2D

Ta c:

V2 =4

2D H +

2

18

Dh

+ 316h

0,276 D3

Vy:

D =276,0

3 2V

= 3276,0

1384,20

2,853 (m) = 2853 (mm)

h1 = 0,2 2,853 0,57(m)

H = 2,853 (m)


Vtrng = 0,15 x V2 = 3,02 (m3)


Vthc = V2 + Vtrng = 23,159 (m3)

h3 = 24

D Vtrng = 2

4

.2,485x 3,02= 0,62 (m)

h4 = 0,2D = 0,57 (m)

Chiu cao thit b:

H1 = h1 + H + h3 + h4 = 4,613 (m)


l:


18/35

H2 = H1 + 0,8 = 5,413(m)


- Thng nhn men cp 2 hnh tr, np hnh chm cu, y cn.

+ Dung tch 23,19 m3

.+ng knh thng D = 2,853 m.

+ h1 = 0,57 m.

+ H = 2,853m.

+ h3 = 0,62 m.

+ h4 = 0,57 m,

- V lm lnh: p lc vn hnh 2 bar, nhit vn hnh l 2 -4C.

- Thng c bo n bng polyurethane 100 mm, ngoi bc inox.- Trang b phn nh: c 1 ca v sinh; 1 ng vi vi u phun CIP; c

van an ton, van chn khng.

- Trang b phn tr: 1 van ly mu; c u vo v ra glycol lm lnh.

- Trang b phn y: 1 u vi cho sc kh; mt u cho cp nhit Pt 100; 1

u van x b.

3.2.2.3. Thng nhn men cp 1.

Tnh kch thc thng.

D

h4

h3

H

h1


V1 =3

1 V2 6,71 (m3).

Chn:


19/35

H = D h1 = 0,2D

Ta c:

V1 =4

2D H +

2

18

Dh

+ 316h

0,276 D3

Vy:

D = 130,276

V

=276,0

3 1V

1,98(m) = 1980 (mm)

h1 = 0,39(m)

H = 1,98 (m)


Vtrng = 0,15 V1 = 1,1 (m3

)Th tch thc ca thit b:

Vthc = V1 + Vtrng = 7,81 (m3)

h3 = 24

D Vtrng 0,36 (m)

h4 = 0,2D = 0,39 (m)

Chiu cao thit b:

H1 = h1 + H + h3 + h4 = 3,12 (m)Chn khong cch t y thit b n sn nh l 0,8 (m). Chiu cao ton b thit b

l:

H0 = H1 + 0,8 = 3,92 (m)


- Thng gy men cp 2 hnh tr, np hnh chm cu, y cn.

+ Dung tch 7,81m3.

+ng knh thng D = 1,98 m.+ h1 = 0,39 m.

+H= 1,98 m.

+ h3 = 0,36 m.

+ h4 = 0,39 m,


20/35

3.2.2.4 . Thng ra men v bo quan men dng li, thit b hot ho men.

Thit b hot ho men.

D

h4

h3

H

h1


Vh =3

1 V1 2,24 (m3).

Chn:H = D

h1 = 0,2D

Ta c:

Vh =4

2D H +

2

18

Dh

+ 316h

0,276 D3

Vy:

D = 30,276

hV

= 3276,0

24,2

1,373(m) = 1373 (mm)

h1 = 0,274 (m)

H = 1,373(m)


Vtrng = 0,15 Vh = 0,336(m3)


Vthc = Vh + Vtrng = 2,576 (m3)

h3 = 24

D Vtrng 0,22 (m)

h4 = 0,2D = 0,274 (m)

Chiu cao thit b:


21/35

H1 = h1 + h2 + h3 + h4 = 2,14 (m)


l:

H = H1 + 0,8 = 2,94 (m)Thit b ra menSau khi ln men nm men c th b nhim tp nn cn phi x l bng axit H3PO4

0,6% hoc bng kim nh,

Do vy vt liu lm bng thp khng r chu c pH dao ng t 4-8.

Kch thc thn tr (ng knh D, chiu cao H), y chm cu.

D

h4

h3

H

h1

Tnh ton.Lng men thu c thng vo khong 2% so vi dch ln men.

Dch ln men ca mt thng 201,384(m3)

100

201384 2 4027,6 (lt) = 4,027 (m3)

Chn:

H = D

h1 = 0,2D

Ta c:

Vr =4

2D H +

2

18

Dh

+ 316h

0,276 D3

Vy:


22/35

D = 30,276

rV

= 3276,0

027,4

1,668 (m) = 1668 (mm)

h1 = 0,33 (m)

H = 1,668 (m)Th tch phn khng cha dch (15% th tch hu ch):

Vtrng = 0,15 Vr = 0,604 (m3)


Vthc = Vr + Vtrng = 4,63 (m3)

h3 = 24

D Vtrng 0,276 (m)

h4 = 0,2D = 0,33(m)Chiu cao thit b:

H1 = h1 + H + h3 + h4 = 2,604(m)


l:

H = H1 + 0,8 =3,404 (m)

3.2.2.5. Tnh v chn h thng CIP lnh.

- CIP lnh c 3 bn cha: NaOH 2%, Trimeta HC 2% v P3 Oxonia 0,5%.Th tch ca ho cht ra thit b bng 5% th tch dch ln men, h s cha ca

thng bng 0,9. Th tch thng ln men V = 232,74m3/ m, vy th tch ca thng

cha l:

( )393,129,0

05,074,232mVt =

=

+ Chn cu to thng:

- ng knh D.


- y hnh chm cu, chiu cao h1= 0,1D

- Np hnh nn, chiu cao h2= 0,1D

+ Cng thc tnh th tch thng:


23/35

( )

( )mD

mDV

mhhD

HD

V

t

t

19,2

93,12218,1

93,12)68

(4

33

3

3

11

22

=

==

=++=

Vy ng knh ni lng xoy D = 2,2m.- Chiu cao tr H = 1,5 2,1 =3,3 m.

- Chiu cao y h1 = 0,1 2,2 = 0,22 m.

- Chiu cao np h2 = 0,1 2,2 = 0,22 m.

3.2.3. Phn xng hon thin

3.2.3.1. Tnh v chn my lc bia.

Chn my lc kiu bn c bt tr lc DIATOMIT tng cng cht lng lc

bia.

Tnh my lc bn.

- T bng cn bng vt liu: trong 1 ngy lng bia cn lc cho c dy chuyn l:

1062,8 x 5 x 36 = 191304lt. Trn thc t theo b tr dy truyn cng ngh chn

bin php lc nh sau:

- Tin hnh lc mi thng bia trong 1 ngy, 2 ca lm vic thi gian hot ng ca

my 16 h, h s s dng ca my l 0,8. Vy nng sut lc l:N =

8.016

191304

= 14,945(m3/h)

- Tnh s bn:

+ My khung bn thc t ch lc khong 1000 l/ m2 b mt lc. Vy din tch b

mt lc tng s l:

1000

945,14= 14,495 m2

+ Chn bn lc c kch thc l D R = 600 600 (mm), b dy 40 mm. Vy sbn cn c l:

6,06,0

945,14

= 41,5 ly 42 bn.


24/35

tng cng cht lng thnh phm b tr thm phn lc tinh gm c khong

45bn c b dy 10 mm.

Chiu di ca my: 42 x 0,04 + 45 x 0,01 + 1,2 = 3.33

Cc thng s k thut:+ Lc th 42 bn, lc tinh 45 bn.

+ Chiu di 3,33 m, chiu cao 1 m.

+ Nng sut lc : 14.945 m3/ h.

+ Thi gian lc 16 h.

Tnh thng ho bt tr lc.

- Bt tr lc DIATOMIT vi cht lng thng dng khong 1kg/1000lt

bia lc. Vy lng bt dng lc l:

1000

191304= 191,304 (kg)

- Lng bt c ho trn vi nc dng cho mi ln lc: chn t l

ho trn l 5 kg bt/ 30 lt nc. Lng nc cn dng l:

( )l824,11475

30304,191=

- Do bt dng rn nn th tch dch sau ho trn gim ch cn khong: 0,8

1147,824 = 918,25 (l).

- thun tin cho qu trnh lm vic lin tc kt hp vi khuy trn cn

chn 3 thng lm vic, mi thng c th tch: Vt = 310 (l).

+ Kch thc ca thng c chn l thng hnh tr c:

- ng knh 620 mm.

- Chiu cao: 930 mm.

- Thng c ch to bng thp khng r, b tr cnh khuy dng rng co,

ng knh cnh khuy 496 mm (cng sut 0,4kw, vn tc khuy 90

vng/pht), b dy thng 3 mm.

- Chn cao khong 800 mm.

3.2.3.2. Chn thng cha bia v bo ho CO2


25/35

Chn thng cha.

Chn thng cha bia cha c ton b lng bia trong cho mt ln lc bia, mi

ngy cha vo 2 thng v chn thm 2 thng d tr. Vy s lng c 4 thng

cha, h s cha y mi thng l 0,8. th tch 1 thng cha l:( )39,62

8,04

384,201m

xV == .

Cc thng s k thut ca thng l:

- Thn tr, ng knh D.

- Chiu cao H = 1,5D.

- y, Np hnh chm cu, chiu cao h = 0,1D.

- Ta c:

( )

( )mDD

mhhD

HD

V

72,39,62218,1

9,62)68

(43

3

3

11

22

==

=++=

Vy ng knh thng D = 3,72m.

+ Chiu cao thng H = 3,72 1,5 = 5,58 m.

+ Chiu cao y,np: h = 0,1 3,72= 0,372 m.

c tnh k thut ca thng.

S lng gm 4 thng, mi thng gm:

- Vt liu bng thp khng r, p sut lm vic l 1,5 bar; p sut th l 3 bar.

- ng knh trong 3720 mm, chiu cao thng 5580 mm.

- Np trn dng vm, thn tr, tt c cc mi ni u c bo v, bn trong c

mi mn cc mi hn bng kh argon, mi phng nh bng cc mi ghp pha

trong mt tip xc vi dch.

- phn thn tr c 2 vng lm lnh c cc ng hnh xon c l cc ng nglm lnh.

- Ngoi ra thng cn c 1 ng ng ty ra CIP, 1 cp nhit , 1 van ly mu, 1

ng bo mc bia trong thng, van an ton


26/35

3.2.3.3. Chn my chit chai.

- Th tch bia chai cn chit trong ngy cao nht l:

187506l .S dng chai dung tch 450 ml vy s chai s dng trong 1

ngy l:( )chai416680

45,0

187506=

- Mi ngy lm vic 24h, h s s dng my l 0,8. vy nng sut my

chit l:

1,217028,024

416680=

(chai/h)

* Chn my ra chai c thng s k thut:

Nng sut:25000 chai/h

Kch thc: 6,5m 3,44m 2,8m

Th tch b cha kim: 8m3

ng knh van xi kim: 35mm

Chu k mt vng: 12,9 pht

Thi gian ngh: 1,9 pht

S bm: 2 chic

Nng sut bm: 10 m3/h

Cng sut ng c: 7 kW

* Chn my chit chai c thng s k thut:

Nng sut: 30000 chai/h

Kch thc: 3,5m 2m 3,2m

p sut kh nn: 2,5 bar

p sut nc cp ca bm cao p: 1 2 bar

p sut CO2 vo: 2,5 3 bar

chn khng: 0,85 0,97 bar

* Chn thit b thanh trng l hm thanh trng (tunel) c thng s k thut:



27/35

Kch thc 18m 2,7m 2,2m

Cng sut lp t 4,1 kW, s dng in p 3 pha: 400V, 50Hz

p sut kh nn: 6 7 bar, 150 l/ph

Hi 3 4 bar, 6 8 m

3

/hTing n: < 70db

Thng s hot ng:

Tc bng ti chnh: 0,339 m/ph

Nhit u vo: 4C

Nhit nc cp: 18C

Nhit nc u ra: 25 36C

Chu k chai vo ra khi my l: 62 phtChu k hot ng: 60 pht.Trong thi gian gia nhit 27 pht, gi nhit 10 pht,

h nhit 23 pht.

Hm thanh trng c 8 khoang, mi khoang phun nc nng mt nhit khc

nhau.

Gia nhit 419C bng nc 28C

Gia nhit 1933C bng nc 42C

Gia nhit 3347C bng nc 48CGia nhit 4764C bng nc 64C

Gi nhit 64C bng nc 68C

H nhit 6459C bng nc 62C



* Chn my dn nhn c thng s k thut:


Kch thc my: 3,56m 1,2m 1,5m

Tc quay: 15 v/ph

Cng sut ng c: 0,8 kW

Trng lng my: 300 kg


28/35


29/35

Trn c s chn gu ti:

- Nng sut thc t: 6000 (kg/h).

- S gu mc l 30 gu cho mi thit b, 1 xch ko chu lc, tc quay ca

xch l 4 vng/pht.- Khi lng 1 ln mc l 50 kg/1gu.

- Cng sut ng c: 2kw.

+ Gu ti vn chuyn go.

Lng nguyn liu cn vn chuyn 1 m l 998 kg v cn vn chuyn trong 30

pht. Vy nng sut ca thit b l:

( )hkg/199630

60998=

Trn c s chn gu ti:

- Nng sut thc t: 2000 (kg/h).

- S gu mc l 10 gu cho mi thit b, 1 xch ko chu lc, tc quay ca

xch l 4 vng/pht.

- Khi lng 1 ln mc l 50 kg/1gu.

- Cng sut ng c: 0,8 kw.

- Vn tc ko: 1,2 1,4 m/s2.2.4.2. Chn vt ti.

+ Vt ti malt.

- vn chuyn malt nghin vo ni nu.

- Cng sut: 6 tn/h.

- Vt liu thp khng r.

- ng c: 0,5 kw, c hp gim tc.

+ Vt ti go.- vn chuyn go nghin vo ni nu.

- Cng sut: 2 tn/h.

- Vt liu thp khng r.

- ng c: 0,5 kw, c hp gim tc.


30/35

2.2.4.3. La chn bm.

Cc loi bm: bm cho v dch ng ho cng sut 75m3/h, Pdm= 7,5 kw; bm

dch lc cng sut 20 m3/h, Pdm= 3 kw; bm dch ng i lng xoy cng sut

50m

3

/h, Pm = 5,5 kw; bm dch ng sau lng xoy i lnh nhanh cng sut20m3/h, Pm= 3 kw; bm dch i ln men cng sut 25 m3/ h, Pm = 5 kw. Bm

nc lnh cng sut 25 m3/h, Pm 4 kw; bm nc sch cng sut 30 m3, Pm = 5

kw, bm tun hon nc lnh cng sut 25m3/h, Pm = 4 kw, bm y CIP cng

sut 20m3/h, Pm = 3 kw; bm CIP hi cng su 20 m3/h, Pm = 3 kw, bm dch ln

men cng sut 500l/ h, Pm = 0,5 kw.

3.2.5. Ho cht v sinh .

2.2.5.1. Ho cht v sinh cc ni nu:

Cc ho cht v sinh cc ni nu l: dung dch Na0H 2%, dung dch HN03 0,1%,

dung dch nc clo 10%, cn c theo nhp nu : gia cc m nu trong 1 ngy

ch cn v sinh cc ni nu bng nc nng. Trong cc khong ngh di v sinh

cc ni nu bng ho cht ty ra, kh trng. Th tch ho cht cn dng cho 1 ln

v sinh nh k khong 8% th tch ni nu ln nht l ni hoa, theo th tch

cc dung dch v sinh l : 0.08 x 36,43 x 2 = 5,83 m3

, tc khi lng 5830 kg,lng ho cht s dng tng ng l: Na0H dng khan: 2% x 5830=116,6 kg,

dung dch axit nitric m c 63%: 0,1% x 5830/63% = 9,25 kg, bt cloramin;

10% x 5830 = 583kg, nh k 1 tun v sinh cc ni nu 1 ln th theo lch sn

xut 1 nm cn v sinh khong 50 ln khi lng ho cht cn tiu hao l:

Na0H : 50 x 116,6 =5830 kg

HN03 : 50 x9,25 = 462,5 kg

Clorami : 50 x 583 = 29150 kg.2.2.5.2. Ho cht v sinh cc thit b ln men:

Cc ho cht dng v sinh cc thit b ln men l: dung dch Na0H 2%, dung

dch trimeta HC 2%, dung dch P3 oxonia 0,5%, theo nhp sn xut 1 ngy sn

xut v sinh 1 tank ln men, ngoi ra cn v sinh h thng ln men hay ti s dng


31/35

men kt lng v cc tank tng tr, th tch cc CIP cn s dng 1 ngy bng 8%

th tch tank ln men: 8% x209,4 = 16,75 m3.

Lng ho cht cn v sinh h thng ln men 1 ngy l:

Na0H : 2% x 16750 =335 kgTrimeta HC: 2% x 16750 = 335 kg

P3 oxonia: 0,5% x 16750 = 8375 kg

Mt nm tng ng 300 ngy sn xut cn 1 lng ho cht v sinh l:

Na0H : 300 x 335 = 100500 kg

Trimeta HC: 300 x335 = 100500kg

P3 oxonia: 300 x 83,75 = 2512,5 kg

Tng lng Na0H cn v sinh nh ny l: 106330 kg

Bng 2.3: Tng hp thit b


32/35

TT Tn thit b S

lng

ng c c im k

thut

Cng sut


33/35

1 Cn 2 cn in t ch

th s

500

0,5kg/ln cn2 My nghin malt 1 11 kw My nghin trc 3000kg/h3 My nghin go 1 6kw My nghin ba 1000kg/h

4 Ni h ho 2 ng c cnh

khuy

d=1,6 m

tc

32 v/p

D=2,0m; h1=0,4;H=2,0 m

h2=0,3 m

F= 2,275m2

6,06 m3

5 Ni ng ho 2 ng c

cnhkhuy

d=2,4 m

tc

32 v/p

D=3,0m; h1=0,6;

H= 3,0h2=0,45m

F= 8,18 m2

21,82 m3

6 Thng lc y

bng

2 D=2,9

H=2,49m

16,3 m3

7 Ni nu hoa 2 D=3,5m; h1=0,7;

H= 3,5

h2=0,525m

32,8m3

8 Thit b un nc

nng

2 D=3

H=4,5

h=0,3m

31,5m3

9 Ni lng xoy 2 D=3,2m

H=3,2

h=0,48m

27,3m3

10 CIP cho nh nu 3 D=1,8

H=2,7

h1=0,18

h2=0,18m

6,56m3

11 My lnh nhanh 1 47 tm


34/35

12 Thng ln men 18 D=5,3m

h1=4,589m

H=7,95m

h3=1,36mh4=1,06m

231,6m3

13 Thng nhn men

cp 2

1 D=2,853m

h1=0,57m

H=2,853m

h3=0,62m

h4=0,57 m

23,159m3

14 Thng nhn men

cp 1

1 D=1,98m

h1=0,39m

H=1,98m

h3=0,36m

h4=0,39 m

7,81m3

15 Thng ra men 1 D=1,668m

h1=0,33m

H=1,668m

h3=0,276m

h4=0,33 m

4,63m3

16 Thit b hot ho

men

1 D=1,373m

h1=0,274m

H=1,373mh3=0,22m

h4=0,274 m

2,57 m3

17 CIP lnh 3 D=2,2

H=3,3 m

12,8 m3

18 My lc bia 1 D x R =600 14,495 m3


35/35

x60019 Thng cha bia 4 D=3,72 m

H=5,58 m

62,9 m3

20 My chit chai 1 416680 chai 30000chai/h

21 My ra chai 1 7kw 25000chai/h22 My dp nt chai 1 30000np/h23 My thanh trng 1 4,1kw 30000chai/h24 My dn nhn 1 0,8kw 30000chai/h25 Gu ti 4 0,8kw 6000kg/h(ma

lt)

2000kg/h(g

o)26 Vt ti 2 0,5kw ti malt

ti go

6 tn/h

2 tn/h27 Bm Nhiu

loi

max

=7,5kw

max =75m3/h

tinh thiet bi nha may bia nguyen dang hung

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