third analogue electronics
TRANSCRIPT
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Operational Amplifiers (Op Amps)
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What is an op amp?
An inexpensive, versatile, integrated
circuit that is anotherbasic buildingblock to electronics (made of resistorsand transistors)
Amplifier that hasLarge open loop gain (intrinsic)
Differential input stage, inverting input (-)and non-inverting input (+)
One output
Uses components in the feedback networkto control the relationship between theinput and output
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What does an Op-Amp do?
Performs operations on an input
signal
Amplification
Buffering
Integration/Differentiation
Addition/Subtraction
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Open Loop/Closed Loop and
Feedback
Open loop
Very high gain (intrinsic gain)
Poor stability
Open loop gain assumed to be infinite for ideal op amps
Closed loop
Uses feedback to add stability
Reduces gain of the amplifier
Output is applied back into the inverting (-) input Most amplifiers are used in this configuration
Open loop
gain
Feedback
VinVout
-
+
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Golden Rules of Op-Amp Analysis
Rule 1: VA = VB The output attempts to do whatever is necessary to
make the voltage difference between the inputs zero.
The op-amp looksat its input terminals and swings
its output terminal around so that the externalfeedback network brings the input differential to zero.
Rule 2: IA= IB= 0
The inputs draw no current
The inputs are connected to what is essentially an
open circuit
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1) Remove the op-amp from the circuit and
draw two circuits (one for the + and one for
theinput terminals of the op amp).
2) Write equations for the two circuits.
3) Simplify the equations using the rules for opamp analysis and solve for Vout/Vin
Steps in Analyzing Op-Amp Circuits
Why can the op-amp be removed from the circuit?
There is no input current, so the connections at the
inputs are open circuits.
The output acts like a new source. We can replace it
by a source with a voltage equal to Vout.
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Operational Amplifiers (Op Amps)
Ideal Op Amp
Non-inverting Amplifier
Unity-Gain Buffer
Inverting Amplifier
Differential Amplifier Current-to-Voltage Converter
Non-ideal Op Amp
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Ideal Op Amp
1) 0 vv A v v
The open-loop gain,Av
, is very large, approaching infinity.
2) 0i i
The current into the inputs are zero.
+
-
i
ov
v
vi
DDV
SSV
0SS DDV v V
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Ideal Op Amp with Negative Feedback
+
- ov
v
v
Network
Golden Rules of Op Amps:
1. The output attempts to do whatever is necessary to
make the voltage difference between the inputs zero.
2. The inputs draw no current.
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Operational Amplifiers (Op Amps)
Ideal Op Amp
Non-inverting Amplifier
Unity-Gain Buffer
Inverting Amplifier
Differential Amplifier Current-to-Voltage Converter
Non-ideal Op Amp
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Non-inverting Amplifier
+
-
1R
2R
ivov
v
v oF
i
vA
v
2
1
1oF
i
v RA
v R
1
1 2
i oRv v v vR R
Closed-loop voltage gain
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Operational Amplifiers (Op Amps)
Ideal Op Amp
Non-inverting Amplifier
Unity-Gain Buffer
Inverting Amplifier
Differential Amplifier Current-to-Voltage Converter
Non-ideal Op Amp
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Unity-Gain Buffer
+
- ov
v
viv
oF
i
vA
v
1oFi
vA
v
i ov v v v
Closed-loop voltage gain
Used as a "line driver" that transforms a high input impedance
(resistance) to a low output impedance. Can provide substantial
current gain.
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Operational Amplifiers (Op Amps)
Ideal Op Amp
Non-inverting Amplifier
Unity-Gain Buffer
Inverting Amplifier
Differential Amplifier Current-to-Voltage Converter
Non-ideal Op Amp
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Inverting Amplifier
0v v
1 1
0i ii v viR R
Current into op amp is zero
+
-
1R
2R
iv
ovv
vii i
i
0 0
2 2
0i
v vi
R R
2
1
oF
i
v RA
v R
0
1 2
iv v
R R
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Operational Amplifiers (Op Amps)
Ideal Op Amp
Non-inverting Amplifier
Unity-Gain Buffer
Inverting Amplifier
Differential Amplifier Current-to-Voltage Converter
Non-ideal Op Amp
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Differential Amplifier
v v
11
1
v viR
Current into op amp is zero
01
2
v vi
R
+
-1R
2R
1v
ov
v
v1i
1
i
2v
1R
2R
22
1 2
Rv v
R R
01
1 2
v vv v
R R
2 21 2 2 0
1 2 1 2
1 2
R Rv v v v
R R R R
R R
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Differential Amplifier
+
-1R
2R
1v
ov
v
v1i
1
i
2v
1R
2R
2 21 2 2 0
1 2 1 2
1 2
R Rv v v vR R R R
R R
2
2 2 20 1 2 2
1 1 2 1 1 2
R R Rv v v vR R R R R R
2 2 20 1 2
1 1 2 1
1R R R
v v v
R R R R
20 2 1
1
Rv v v
R
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Operational Amplifiers (Op Amps)
Ideal Op Amp
Non-inverting Amplifier
Unity-Gain Buffer
Inverting Amplifier
Differential Amplifier
Current-to-Voltage Converter
Non-ideal Op Amp
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Current-to-Voltage Converter
i fi i
0v v
00 f Fv i R
0 i Fv i R
0Transresistance
i Fv i R
+
- o
vv
v
ii
FR fi
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Photodiode Circuit
25 A per milliwatt of incident radiationii
650 25 10 1.25mAii
Assume 3.2kF
R
3 3
0 1.25 10 3.2 10 4Vi Fv i R
+
- ov
v
v
ii
FR fi
h At 50 mW
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Operational Amplifiers (Op Amps)
Ideal Op Amp
Non-inverting Amplifier
Unity-Gain Buffer
Inverting Amplifier
Differential Amplifier
Current-to-Voltage Converter
Non-ideal Op Amp
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Non-ideal Op Amp
Output voltage is limited by supply voltage(s) Finite gain (~105)
Limited frequency response
Finite input resistance (not infinite)
Finite output resistance (not zero)
Finite slew rate
Input bias currents
Input bias current offset Input offset voltage
Finite common mode rejection ratio (CMRR)
0slew rate ( )
MAXdv t dt
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Ref:080114HKN Operational Amplifier 24
Non-ideal case (Inverting Amplifier)
+
~
Rf
Ra
VinVo
3 categories are considering
Close-Loop Voltage Gain
Input impedanceOutput impedance
Equivalent CircuitRf
Ra
Vin Vo+
+
R RV
-AV
+
AVinVin Vout
Zout
~
Zin
Practical op-amp
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Ref:080114HKN Operational Amplifier 25
Close-Loop GainRf
RaVin
Vo+
+
R R
-AV
Ra Rf
R
V
V
Vin Vo
Applied KCL at Vterminal,
0
f
o
a
in
R
VV
R
V
R
VV
By using the open loop gain,
AVVo
0f
o
f
oo
a
o
a
in
AR
V
R
V
AR
V
AR
V
R
V
fa
aafaf
o
a
in
RRAR
RARRRRRRRV
R
V
The Close-Loop Gain,Av
RARRRRRRR
RAR
V
VA
aafaf
f
in
ov
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Ref:080114HKN Operational Amplifier 26
Close-Loop Gain
When the open loop gain is very large, the above equation become,
a
f
vR
RA
~
Note : The close-loop gain now reduce to the same formas an ideal case
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Closed-Loop Gain
2 1
1
1 1
1 2
1
2
1
0
0
1
o
I I
Io I I
o
I
vv v
A
v vi R R
vv v i R v R
R
v R
v R
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Ref:080114HKN Operational Amplifier 28
Input ImpedanceRf
Ra
VinVo
+
+
R
-AV
R'
RV
Rf
+
R
-AV
if
V
Input Impedance can be regarded as,
RRRR ain //
whereRis the equivalent impedance
of the red box circuit, that is
fi
VR
However, with the below circuit,
A
RR
i
VR
RRiAVV
of
f
off
1
)()(
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Ref:080114HKN Operational Amplifier 29
Input ImpedanceFinally, we find the input impedance as,
1
11
of
ainRR
A
RRR
RARR
RRRRR
of
of
ain)1(
)(
Since,
RARR of )1( , Rinbecome,
)1(
)(~
A
RRRR
of
ain
Again with )1( ARR of
ain RR ~
Note: The op-amp can provide an impedance isolated from
input to output
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Ref:080114HKN Operational Amplifier 30
Output ImpedanceOnly source-free output impedance would be considered,
i.e. Viis assumed to be 0 Rf
Ra
Vo+
R
-AV
RV
io
VV
Rf
Ra R+
R
-AV
V
i2 i1
(a)(b)
Firstly, with figure (a),
o
fafa
ao
af
a VRRRRRR
RRVV
RRR
RRV
//
//
By using KCL,io
= i1
+ i2
o
o
faf
oo
R
AVV
RRR
Vi
)(
//
By substitute the equation from Fig. (a),
RRARRRRRRRRRRRRRR
iV
R
afafao
fafao
o
o
out
)1())(1()(
isimpedance,outputThe
RandAcomparably large,
a
fao
outAR
RRRR
)(~