regularity, moments, and wavelet system design
TRANSCRIPT
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7/29/2019 Regularity, Moments, And Wavelet SYSTEM DESIGN
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N2 1 N
h (n)
h1 (n) (t) (t) (t)
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h (n)
n
h (n) =
2k
h (k) h (k + 2m) = (m) .
K K z = ei
H(z) =
1 + z1
2
KQ (z)
H(z) =
nh (n) zn h (n) Q (z)
z = ei h (n) (t) (t)
K = 1N H(z) N1
z = 1 K Q (z) N1K (t)2
N/2
1 K N2
.
N
N
h (n)H(z)
z = 1 = (t) (t)
kth (t) (t)
m (k) =
tk
(t) dt
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m1 (k) = tk (t) dtkth h (n) h1 (n)
(k) =n
nk h (n)
1 (k) =n
nk h1 (n) .
h (n)
(k, ) = n
(2n + )k h (2n + ) .
(k) = (k, 0) + (k, 1)
m (k) =1
(2k 1) 2k
=1
k
() m (k )
m1 (k) =1
2k
2
k=0
k
1 () m (k ) .
M
(t)K
1 (k) = 0 k = 0, 1, , (K 1)m1 (k) = 0 k = 0, 1, , (K 1)
k = 0, 1, , (K 1)
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= kth = 0
k = 1, 2, , 2K 1(K 1)
(K 1)
(t) K K 1
dk
dtk (t)
< , 0 k K
m1 (k) = 0. 0 k K (t)
L m1 (k) = 0 0 k K 1 dPdtP (t) <
LP > K (t)
h1 (n) (t) H() = 0
(t) (t)
h (n) K =
H() =
1 + ei
2
KL ()
|H() |2 + |H( + ) |2 = 2L () = |L () |2
L () = P
sin2 (/2)
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K N/2
P(y) =
K1k=0
K1 + k
k
yk
+ yK
R1
2 yR (y) P(y) 0 0 y 1R = 0 N K = N/2 N > 2 K
R y
H() = h (n) (t)
h (n) =
H() h (n) |H() |2
|H() |2 =1 + ei2
2K
|L () |2.
M() = |H() |2 L () = |L () |2
M() = |cos2(/2) |K L () .M() L () cos ()
cos () = 1
2 sin2 (/2)
M
sin2 (/2)
= |cos2 (/2) |K Psin2 (/2)y = sin2 (/2) = 1 cos2 (/2)
M(y) = (1 y)K P(y)P(y) (N K)
H()
|H() |2 + |H( + ) |2 = 2
M() + M( + ) = (1 y)K P (y) + yK P(1 y) = 2.
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(N/2 1)K = N/2
P(y) =K1k=0
K 1 + k
k
yk
h (n)
K < N/2 P (y)
P(y) =K1k=0
K 1 + k
k
yk + yK R1
2 y
R (y) NP (y) 0h (n) N
h (n) |H() |2H()
yz cos () = 1 2 y isin () =
cos2 () 1 ei = cos () isin ()
z = ei
H(z) H(1/z) N
1
H(z) N1M
h (n)h (n)
h (n) h (n)
K = N/2 =
K = (N/2) 2
h (n) h1 (n)
N/2 = 4 (0) =
2
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n h (n) h1 (n) (k) 1 (k) k
(t) (t)
N = 6
n h (n) h1 (n) (k) 1 (k) k
N = 4
n h (n) h1 (n) (k) 1 (k) k
N = 2
n h (n) h1 (n) (k) 1 (k) k
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N = 6
k (k) 1 (k) m (k) m1 (k)
N = 4
k (k) 1 (k) m (k) m1 (k)
(0) =
21 (0) = m1 (0) = 0
h (n) h1 (n) m (0) = 1N/2 1 m1 (k)
N/2 1 m1 (0) = 0 N/2m (2) = m(1)
2
N = 4, 6, 8, 10, 12, 16, 20, 40
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h (n)N
N = 2 N = 4 N = 6N = 14 h (n)
h (n)
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N = 4, 6, 8, ...,40
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(t)
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N = 4, 6, 8, ...,40
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|H() |2
N > 2 KR (y)
H() = /2 =
H() = 0
M(0) = 0d M()
d
=0
= 0
h (n)
H()
h (n)
o
o
o : IR < < o
| | | | x, y IR > 1
> 1 or > 0
o : R C r = P +
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r o L2
Hs+1/2 Cr Hs
oo
limN
NN
=
1 log (3)
2 log (2)
= (0.2075 )
o
oo
o
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o +
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= +
=
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N = 26 SH = 4.005SH = 5.06
M = 2 M
H() (t) (t) h (n)
nh (n) = 2 (t) dt = 1 K 2
m (2) = m2 (1) .
f(t) Vj
Pj{f(t)} =k
< f (t) , j,k (t) > j,k (t)
f(t) Vj f(t)Vj
th (t)
m1 () =
t (t) dt.
f(t)
m1 () = 0 = 0, 1,
, L L2
1 = f(t) Pj{f(t)}2 C2j(L+1),C j L f(t)
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f(t)f(t)
Sj{f(t)} =k
2j/2 f
k/2j
j,k (t)
m () =
t (t) dt
m () = 0 = 1, 2, , L L2
2 = Sj{f(t)} Pj{f(t)}2 C2 2j(L+1),
C2 j L f(t)
f(t) j
f(t)
Vjf(t) L2 Vj
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m () = m1 () = 0 = 1, 2, , L m1 (0) = 0 L2
3 = f(t) Sj{f(t)}2 C3 2j(L+1),C3 j L f(t)
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f(t)
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tk (t) dt = m (k) = 0, k = 1, 2, , L 1
tk (t) dt = m1 (k) = 0, k = 1, 2, , L 1.
L 1L 1 m1 (0)
Lh (n) N
N/2 1
h =3 + 7
16
2, 1 7
16
2, 7 7
8
2, 7 + 7
8
2, 5 + 7
16
2, 1 7
16
2
,
h =
3 7
16
2,
1 +
7
16
2,
7 +
7
8
2,
7 78
2,
5 716
2
,1 +
7
16
2
,
h =
3 + 15
16
2,
1 1516
2
,3 15
8
2,
3 +
15
8
2,
13 +
15
16
2,
9 1516
2
,
h =
3 15
16
2,
1 + 1516
2
,3 + 15
8
2,
3 158
2,
13 1516
2
,9 + 15
16
2
,
(k) 1 (k) k = 0, 1, 2, 3
1 (0) = 0
m (2) = m(1)2
N = 6 = 1, 2, 3,
H() h (n)
= /3
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o
K 1h (n) H() =
nh (n) e
in 2K 1 = 0 kth k 1 < k < 2K 1
k
=0
k
(1)
() (k ) = 0.
(k) (0) =
2 k
(k) =1
2
2
k1=1
k
(1) () (k )
k = 2, 4, , 2K 2
(2) = 12
2 (1)
(4) = 122
8 (1) (3) 34 (1)
k=0
k
(1)km () m (k ) = 0
0 < k < 2K K 1 m (k)k
m (k) =12
k1=1
k
(1)m () m (k )
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k = 2, 4, , 2K 2
m (2) = m2 (1)
m (4) = 4 m (3) m (1) 3 m4 (1)m (6) = 6 m (5) m (1) + 10 m2 (3) + 60 m (3) m3 (1) + 45 m6 (1)
m (8) = 8 m (7) m (1) + 56 m (5) m (3) 168 m (5) m3 (1)+2520 m (3) m5 (1) 840 m (3) m2 (1) 1575 m8 (1)
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N = 6 L = 2
n h (n) h1 (n) (k) 1 (k) k
N = 8 L = 3
n h (n) h1 (n) (k) 1 (k) k
N = 12 L = 4
n h (n) h1 (n) (k) 1 (k) k
k = K 1 m (1) = m (3) = 0m (2) = m (4) = m (6) = m (8) = 0
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m (8)
N = 6 L = 2k (k) 1 (k) m (k) m1 (k)
N = 8 L = 3
k (k) 1
(k) m (k) m1
(k)
m (4) = (4) = 0
N = 6 + 2 (t) (t)
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N = 6 + 2
N = 6N
N = 6 2
N = 6 2
N = 4 L = 1
n h (n) h1 (n) (k) 1 (k) k
N = 10 L = 3
n h (n) h1 (n) (k) 1 (k) k
N = 10, 16, 22, 28
N = 6 + 2 N = 6
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N L m = 0 m1 = 0 m = 0 m1 = 0 o
N Lm1 (0) = 0
m1 (0) = 0N = 6 + 2
o N L
NN h (n) (t)
N/2 N/2 1N/2 1
(N/2 1) /2
2N/3N/2
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N = 6 + 2N = 6
N = 6 2
o
N m = 0 m1 = 0
N = 6 + 2 (N 2) /3 (N 2) /3 (2/3) (N 2)N = 6 N/3 (N 3) /3 (2/3) (N 3/2)N = 6
2 (N + 2) /3 (N
4) /3 (2/3) (N
1)
= 1, 2, 1 (0) = 0
N = 6 2
o
N/2
1
o
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