regularity, moments, and wavelet system design

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  • 7/29/2019 Regularity, Moments, And Wavelet SYSTEM DESIGN

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    N2 1 N

    h (n)

    h1 (n) (t) (t) (t)

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    h (n)

    n

    h (n) =

    2k

    h (k) h (k + 2m) = (m) .

    K K z = ei

    H(z) =

    1 + z1

    2

    KQ (z)

    H(z) =

    nh (n) zn h (n) Q (z)

    z = ei h (n) (t) (t)

    K = 1N H(z) N1

    z = 1 K Q (z) N1K (t)2

    N/2

    1 K N2

    .

    N

    N

    h (n)H(z)

    z = 1 = (t) (t)

    kth (t) (t)

    m (k) =

    tk

    (t) dt

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    m1 (k) = tk (t) dtkth h (n) h1 (n)

    (k) =n

    nk h (n)

    1 (k) =n

    nk h1 (n) .

    h (n)

    (k, ) = n

    (2n + )k h (2n + ) .

    (k) = (k, 0) + (k, 1)

    m (k) =1

    (2k 1) 2k

    =1

    k

    () m (k )

    m1 (k) =1

    2k

    2

    k=0

    k

    1 () m (k ) .

    M

    (t)K

    1 (k) = 0 k = 0, 1, , (K 1)m1 (k) = 0 k = 0, 1, , (K 1)

    k = 0, 1, , (K 1)

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    = kth = 0

    k = 1, 2, , 2K 1(K 1)

    (K 1)

    (t) K K 1

    dk

    dtk (t)

    < , 0 k K

    m1 (k) = 0. 0 k K (t)

    L m1 (k) = 0 0 k K 1 dPdtP (t) <

    LP > K (t)

    h1 (n) (t) H() = 0

    (t) (t)

    h (n) K =

    H() =

    1 + ei

    2

    KL ()

    |H() |2 + |H( + ) |2 = 2L () = |L () |2

    L () = P

    sin2 (/2)

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    K N/2

    P(y) =

    K1k=0

    K1 + k

    k

    yk

    + yK

    R1

    2 yR (y) P(y) 0 0 y 1R = 0 N K = N/2 N > 2 K

    R y

    H() = h (n) (t)

    h (n) =

    H() h (n) |H() |2

    |H() |2 =1 + ei2

    2K

    |L () |2.

    M() = |H() |2 L () = |L () |2

    M() = |cos2(/2) |K L () .M() L () cos ()

    cos () = 1

    2 sin2 (/2)

    M

    sin2 (/2)

    = |cos2 (/2) |K Psin2 (/2)y = sin2 (/2) = 1 cos2 (/2)

    M(y) = (1 y)K P(y)P(y) (N K)

    H()

    |H() |2 + |H( + ) |2 = 2

    M() + M( + ) = (1 y)K P (y) + yK P(1 y) = 2.

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    (N/2 1)K = N/2

    P(y) =K1k=0

    K 1 + k

    k

    yk

    h (n)

    K < N/2 P (y)

    P(y) =K1k=0

    K 1 + k

    k

    yk + yK R1

    2 y

    R (y) NP (y) 0h (n) N

    h (n) |H() |2H()

    yz cos () = 1 2 y isin () =

    cos2 () 1 ei = cos () isin ()

    z = ei

    H(z) H(1/z) N

    1

    H(z) N1M

    h (n)h (n)

    h (n) h (n)

    K = N/2 =

    K = (N/2) 2

    h (n) h1 (n)

    N/2 = 4 (0) =

    2

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    n h (n) h1 (n) (k) 1 (k) k

    (t) (t)

    N = 6

    n h (n) h1 (n) (k) 1 (k) k

    N = 4

    n h (n) h1 (n) (k) 1 (k) k

    N = 2

    n h (n) h1 (n) (k) 1 (k) k

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    N = 6

    k (k) 1 (k) m (k) m1 (k)

    N = 4

    k (k) 1 (k) m (k) m1 (k)

    (0) =

    21 (0) = m1 (0) = 0

    h (n) h1 (n) m (0) = 1N/2 1 m1 (k)

    N/2 1 m1 (0) = 0 N/2m (2) = m(1)

    2

    N = 4, 6, 8, 10, 12, 16, 20, 40

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    h (n)N

    N = 2 N = 4 N = 6N = 14 h (n)

    h (n)

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    N = 4, 6, 8, ...,40

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    (t)

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    N = 4, 6, 8, ...,40

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    |H() |2

    N > 2 KR (y)

    H() = /2 =

    H() = 0

    M(0) = 0d M()

    d

    =0

    = 0

    h (n)

    H()

    h (n)

    o

    o

    o : IR < < o

    | | | | x, y IR > 1

    > 1 or > 0

    o : R C r = P +

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    r o L2

    Hs+1/2 Cr Hs

    oo

    limN

    NN

    =

    1 log (3)

    2 log (2)

    = (0.2075 )

    o

    oo

    o

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    o +

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    = +

    =

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    N = 26 SH = 4.005SH = 5.06

    M = 2 M

    H() (t) (t) h (n)

    nh (n) = 2 (t) dt = 1 K 2

    m (2) = m2 (1) .

    f(t) Vj

    Pj{f(t)} =k

    < f (t) , j,k (t) > j,k (t)

    f(t) Vj f(t)Vj

    th (t)

    m1 () =

    t (t) dt.

    f(t)

    m1 () = 0 = 0, 1,

    , L L2

    1 = f(t) Pj{f(t)}2 C2j(L+1),C j L f(t)

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    f(t)f(t)

    Sj{f(t)} =k

    2j/2 f

    k/2j

    j,k (t)

    m () =

    t (t) dt

    m () = 0 = 1, 2, , L L2

    2 = Sj{f(t)} Pj{f(t)}2 C2 2j(L+1),

    C2 j L f(t)

    f(t) j

    f(t)

    Vjf(t) L2 Vj

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    m () = m1 () = 0 = 1, 2, , L m1 (0) = 0 L2

    3 = f(t) Sj{f(t)}2 C3 2j(L+1),C3 j L f(t)

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    f(t)

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    tk (t) dt = m (k) = 0, k = 1, 2, , L 1

    tk (t) dt = m1 (k) = 0, k = 1, 2, , L 1.

    L 1L 1 m1 (0)

    Lh (n) N

    N/2 1

    h =3 + 7

    16

    2, 1 7

    16

    2, 7 7

    8

    2, 7 + 7

    8

    2, 5 + 7

    16

    2, 1 7

    16

    2

    ,

    h =

    3 7

    16

    2,

    1 +

    7

    16

    2,

    7 +

    7

    8

    2,

    7 78

    2,

    5 716

    2

    ,1 +

    7

    16

    2

    ,

    h =

    3 + 15

    16

    2,

    1 1516

    2

    ,3 15

    8

    2,

    3 +

    15

    8

    2,

    13 +

    15

    16

    2,

    9 1516

    2

    ,

    h =

    3 15

    16

    2,

    1 + 1516

    2

    ,3 + 15

    8

    2,

    3 158

    2,

    13 1516

    2

    ,9 + 15

    16

    2

    ,

    (k) 1 (k) k = 0, 1, 2, 3

    1 (0) = 0

    m (2) = m(1)2

    N = 6 = 1, 2, 3,

    H() h (n)

    = /3

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    o

    K 1h (n) H() =

    nh (n) e

    in 2K 1 = 0 kth k 1 < k < 2K 1

    k

    =0

    k

    (1)

    () (k ) = 0.

    (k) (0) =

    2 k

    (k) =1

    2

    2

    k1=1

    k

    (1) () (k )

    k = 2, 4, , 2K 2

    (2) = 12

    2 (1)

    (4) = 122

    8 (1) (3) 34 (1)

    k=0

    k

    (1)km () m (k ) = 0

    0 < k < 2K K 1 m (k)k

    m (k) =12

    k1=1

    k

    (1)m () m (k )

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    k = 2, 4, , 2K 2

    m (2) = m2 (1)

    m (4) = 4 m (3) m (1) 3 m4 (1)m (6) = 6 m (5) m (1) + 10 m2 (3) + 60 m (3) m3 (1) + 45 m6 (1)

    m (8) = 8 m (7) m (1) + 56 m (5) m (3) 168 m (5) m3 (1)+2520 m (3) m5 (1) 840 m (3) m2 (1) 1575 m8 (1)

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    N = 6 L = 2

    n h (n) h1 (n) (k) 1 (k) k

    N = 8 L = 3

    n h (n) h1 (n) (k) 1 (k) k

    N = 12 L = 4

    n h (n) h1 (n) (k) 1 (k) k

    k = K 1 m (1) = m (3) = 0m (2) = m (4) = m (6) = m (8) = 0

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    m (8)

    N = 6 L = 2k (k) 1 (k) m (k) m1 (k)

    N = 8 L = 3

    k (k) 1

    (k) m (k) m1

    (k)

    m (4) = (4) = 0

    N = 6 + 2 (t) (t)

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    N = 6 + 2

    N = 6N

    N = 6 2

    N = 6 2

    N = 4 L = 1

    n h (n) h1 (n) (k) 1 (k) k

    N = 10 L = 3

    n h (n) h1 (n) (k) 1 (k) k

    N = 10, 16, 22, 28

    N = 6 + 2 N = 6

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    N L m = 0 m1 = 0 m = 0 m1 = 0 o

    N Lm1 (0) = 0

    m1 (0) = 0N = 6 + 2

    o N L

    NN h (n) (t)

    N/2 N/2 1N/2 1

    (N/2 1) /2

    2N/3N/2

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    N = 6 + 2N = 6

    N = 6 2

    o

    N m = 0 m1 = 0

    N = 6 + 2 (N 2) /3 (N 2) /3 (2/3) (N 2)N = 6 N/3 (N 3) /3 (2/3) (N 3/2)N = 6

    2 (N + 2) /3 (N

    4) /3 (2/3) (N

    1)

    = 1, 2, 1 (0) = 0

    N = 6 2

    o

    N/2

    1

    o

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