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Quiz review Lewis Structures, VSEPR shape, polarity, and IMFs Get started!

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Quiz review. Lewis Structures, VSEPR shape, polarity, and IMFs. Get started!. Draw the Lewis Structure for…. SBr 6. HNO 3. Once you have drawn a Lewis Structure, click on the molecule to check your answer and complete the rest of the questions. H 2 S. OF 4. CO 3 2-. KrF 4. SiCl 4. - PowerPoint PPT Presentation

TRANSCRIPT

Page 1: Quiz review

Quiz reviewLewis Structures, VSEPR shape,

polarity, and IMFs

Get started!

Page 2: Quiz review

Draw the Lewis Structure for….

Once you have drawn a Lewis Structure, click on the molecule to check your answer and complete the rest of the questions

H2S

KrF4CO32-

BCl3

HNO3

I3-

SiCl4

OF4

TeO2

SBr6

Page 3: Quiz review

What is its shape?

tetrahedral angular linear

Page 4: Quiz review

Try again!!Go back

Page 5: Quiz review

Angular…Very good!

What is the polarity?Polar Nonpolar

Page 6: Quiz review

Try again!!Go back

Page 7: Quiz review

Polar…Very good!

What is its principal IMF?London

DispersionDipole - Dipole

Hydrogen Bonding

Page 8: Quiz review

Try again!!Go back

Page 9: Quiz review

Dipole-Dipole…Very good!

This molecule is angular because it has 4 e- pairs around the central atom, 2 atoms bonded to it, and 2 lone pairs. It is polar because it is angular

with two lone pairs. Since it is polar, it will have a dipole-dipole IMF

Back to Lewis Structures

Page 10: Quiz review

What is its shape?

Trigonal planar

Pyramidal Tetrahedral

Page 11: Quiz review

Try again!!Go back

Page 12: Quiz review

Trigonal Planar…Very good!

What is the polarity?Polar Nonpolar

Page 13: Quiz review

Try again!!Go back

Page 14: Quiz review

Nonpolar…Very good!

What is its principal IMF?London

DispersionDipole - Dipole

Hydrogen Bonding

Page 15: Quiz review

Try again!!Go back

Page 16: Quiz review

London Dispersion…Very good!

This molecule is trigonal planar because it has 3 e- pairs around the central atom, 3 atoms bonded to it, and 0 lone pairs. It is nonpolar and

therefore will experience london dispersion intermolecular forces.

Back to Lewis Structures

Page 17: Quiz review

What is its shape?

tetrahedral octahedral pyramidal

Page 18: Quiz review

Try again!!Go back

Page 19: Quiz review

Octahedral…Very good!

What is the polarity?Polar Nonpolar

Page 20: Quiz review

Try again!!Go back

Page 21: Quiz review

Nonpolar…Very good!

What is its principal IMF?London

DispersionDipole - Dipole

Hydrogen Bonding

Page 22: Quiz review

Try again!!Go back

Page 23: Quiz review

London Dispersion…Very good!

This molecule is octahedral because it has 6 e- pairs around the central atom, 6 atoms bonded to it, and 0 lone pairs. It is nonpolar so it will

experience london dispersion intermolecular forces.

Back to Lewis Structures

Page 24: Quiz review

What is its shape?

tetrahedral angular square planar

Page 25: Quiz review

Try again!!Go back

Page 26: Quiz review

Tetrahedral…Very good!

What is the polarity?Polar Nonpolar

Page 27: Quiz review

Try again!!Go back

Page 28: Quiz review

Nonpolar…Very good!

What is its principal IMF?London

DispersionDipole - Dipole

Hydrogen Bonding

Page 29: Quiz review

Try again!!Go back

Page 30: Quiz review

London Dispersion…Very good!

This molecule is angular because it has 4 e- pairs around the central atom, 4 atoms bonded to it, and 0 lone pairs. Since it is nonpolar

it will experience london dispersion intermolecular forces.

Back to Lewis Structures

Page 31: Quiz review

What is its shape?

tetrahedral pyramidal see saw

Page 32: Quiz review

Try again!!Go back

Page 33: Quiz review

See Saw…Very good!

What is the polarity?Polar Nonpolar

Page 34: Quiz review

Try again!!Go back

Page 35: Quiz review

Polar…Very good!

What is its principal IMF?London

DispersionDipole - Dipole

Hydrogen Bonding

Page 36: Quiz review

Try again!!Go back

Page 37: Quiz review

Dipole-Dipole…Very good!

This molecule is see saw shape because it has 5 e- pairs around the central atom, 4 atoms bonded to it, and 1 lone pairs. It is polar because it has one lone pair which will distort the

shape. Since it is polar, it will have a dipole-dipole IMF

Back to Lewis Structures

Page 38: Quiz review

What is its shape?

tetrahedral trigonal planar pyramidal

Page 39: Quiz review

Try again!!Go back

Page 40: Quiz review

Trigonal planar…Very good!

What is the polarity?Polar Nonpolar

Page 41: Quiz review

Try again!!Go back

Page 42: Quiz review

Nonpolar…Very good!

What is its principal IMF?London

DispersionDipole - Dipole

Hydrogen Bonding

Page 43: Quiz review

Try again!!Go back

Page 44: Quiz review

London Dispersion…Very good!

This molecule is trigonal planar because it has 4 e- pairs around the central atom, 3 atoms bonded to it, and 0 lone pairs. It is polar because it is

angular with two lone pairs. Since it is polar, it will have a dipole-dipole IMF

Back to Lewis Structures

**It is also ok to determine shape by saying 3 electron regions, 3 atoms bonded to it, and 0 lone pairs. You

get the same answer

Page 45: Quiz review

What is its shape?

Square planar Pyramidal Octahedral

Page 46: Quiz review

Try again!!Go back

Page 47: Quiz review

Square Planar…Very good!

What is the polarity?Polar Nonpolar

Page 48: Quiz review

Try again!!Go back

Page 49: Quiz review

Nonpolar…Very good!

What is its principal IMF?London

DispersionDipole - Dipole

Hydrogen Bonding

Page 50: Quiz review

Try again!!Go back

Page 51: Quiz review

London Dispersion…Very good!

This molecule is square planar because it has 6 e- pairs around the central atom, 4 atoms bonded to it, and 2 lone pairs. Although it has lone pairs, it is nonpolar because it is one of the exceptions. The fluorines cancel each other out, as do the lone pair in this specific

shape. Since it is nonpolar it experiences london dispersion intermolecular forces.

Back to Lewis Structures

Page 52: Quiz review

What is its shape?

see saw angular linear

Page 53: Quiz review

Try again!!Go back

Page 54: Quiz review

Linear…Very good!

What is the polarity?Polar Nonpolar

Page 55: Quiz review

Try again!!Go back

Page 56: Quiz review

Nonpolar…Very good!

What is its principal IMF?London

DispersionDipole - Dipole

Hydrogen Bonding

Page 57: Quiz review

Try again!!Go back

Page 58: Quiz review

London Dispersion…Very good!

This molecule is linear because it has 5 e- pairs around the central atom, 2 atoms bonded to it, and 3 lone pairs. Although it has lone pairs, this is one of the exceptions and is

nonpolar since the lone pairs are on the same plane and cancel each other out. Since is it nonpolar, it will experience london dispersion intermolecular forces.

Back to Lewis Structures

Page 59: Quiz review

What is its shape?

angular trigonal planar linear

Page 60: Quiz review

Try again!!Go back

Page 61: Quiz review

Angular…Very good!

What is the polarity?Polar Nonpolar

Page 62: Quiz review

Try again!!Go back

Page 63: Quiz review

Polar…Very good!

What is its principal IMF?London

DispersionDipole - Dipole

Hydrogen Bonding

Page 64: Quiz review

Try again!!Go back

Page 65: Quiz review

Dipole-Dipole…Very good!

This molecule is angular because it has 4 e- pairs around the central atom, 2 atoms bonded to it, and 1 lone pair. It is polar because it is angular

with a lone pair. Since it is polar, it will have a dipole-dipole IMF

Back to Lewis Structures

Page 66: Quiz review

Remember for any acid with an oxygen (starts with H and has an O), the hydrogen is bonded to one of the oxygen atoms

What is its shape?

tetrahedral angular trigonal planar

Page 67: Quiz review

Try again!!Go back

Page 68: Quiz review

Trigonal planar…Very good!

What is the polarity?Polar Nonpolar

Page 69: Quiz review

Try again!!Go back

Page 70: Quiz review

Polar…Very good!

What is its principal IMF?London

DispersionDipole - Dipole

Hydrogen Bonding

Page 71: Quiz review

Try again!!Go back

Page 72: Quiz review

Hydrogen bonding…Very good!

This molecule is trigonal planar because it has 4 e- pairs around the central atom, 3 atoms bonded to it, and 0 lone pairs. It is polar because all of the

electrons around the central atom are not pulled equally because of the -OH group. Since it is polar and there is an oxygen atom covalently bonded

to a hydrogen atom, this molecule will experience hydrogen bonding

Back to Lewis Structures

**It is also ok to determine shape by saying 3 electron regions, 3 atoms bonded to it, and 0 lone pairs. You

get the same answer