pipe concrete column

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PROJECT : PAGE : CLIENT : DESIGN BY : JOB NO. : DATE : REVIEW BY : Pipe Concrete Column Design Based on ACI 318-11 INPUT DATA & DESIGN SUMMARY CONCRETE STRENGTH fc' = 5 ksi REBAR YIELD STRESS fy = 60 ksi COLUMN OUTSIDE DIAMETER D = 20 in CONCRETE WEB THICKNESS T = 7 in FACTORED AXIAL LOAD Pu = 480 k FACTORED MAGNIFIED MOMENT Mu = 190 ft-k FACTORED SHEAR LOAD Vu = 20 k COLUMN VERT. REINFORCEMENT 8 # 7 LATERAL REINF. OPTION (0=Spirals, 1=Ties) 1 Ties LATERAL REINFORCEMENT # 4 @ 12 in o.c. THE COLUMN DESIGN IS ADEQUATE. ANALYSIS AT AXIAL LOAD ONLY 819 0 AT MAXIMUM LOAD 819 70 AT 0 % TENSION 643 148 AT 25 % TENSION 533 180 AT 50 % TENSION 444 197 318 206 AT BALANCED CONDITION 313 208 146 229 AT FLEXURE ONLY 0 164 CHECK FLEXURAL & AXIAL CAPACITY 819.14 kips., (at max axial load, ACI 318-11, Sec. 10.3.6.1) where 0.65 (ACI 318-11, Sec.9.3.2.2) > [Satisfactory] 286 4.80 8 in (at balanced strain condition, ACI 10.3.2) = 0.656 (ACI 318-11, Fig. R9.3.2) where 10 in 0.002069 0.003 d = 17.56 in, (ACI 7.7.1) 0.8 ( ACI 318-11, Sec. 10.2.7.3 ) 164 190 480 kips > [Satisfactory] = 0.08 (ACI 318-11, Section 10.9) = 0.017 = 0.01 (ACI 318-11, Section 10.9) [Satisfactory] CHECK SHEAR CAPACITY 49 kips, (ACI 318-11 Sec. 11.1.1) > [Satisfactory] where 0.75 (ACI 318-11 Sec. 9.3.2.3) 214 0.40 60 ksi 30.3 kips, (ACI 318-11 Sec. 11.2.1) 35.1 kips, (ACI 318-11 Sec. 11.4.7.2) = 14 (ACI 318-11, Section 7.10.5.2) = 12 in = 1 [Satisfactory] f Pn (k) f Pn (kips) f Mn (ft-kips) AT e t = 0.002 f Mn (ft-k) AT e t = 0.005 f Pmax =0.85 f [ 0.85 fc' (Ag - Ast) + fy Ast] = f = Pu Ag = in 2 . Ast = in 2 . a = Cbb1 = f = 0.75 + ( et - 0.002 ) (50), for Spiral 0.65 + ( et - 0.002 ) (250 / 3), for Tie Cb = d ec / (ec + es et = ec = b1 = f Mn = 0.9 Mn = ft-kips @ Pn = 0, (ACI 318-11, Sec. 9.3.2) ,& et,min = 0.004, (ACI 318-11, Sec. 10.3.5) f Mn = ft-kips @ Pu = Mu rmax rprovd rmin f Vn = f (Vs + Vc) = Vu f = A0 = in 2 . Av = in 2 . fy = Vc = 2 (fc') 0.5 A0 = Vs = MIN (d fy Av / s , 4Vc) = smax sprovd smin 0 50 100 150 200 250 0 100 200 300 400 500 600 700 800 900 e e ' ' 2 ' ' 2 0.85 , 57 , 29000 0.85 2 , 0 0.85 , , , C C C C C S f ksi f E E c s o E c c c for f c o f o o for f c o for Es s s y f for f s y y e e e e e e e e e e e e e e = = = = =

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Page 1: Pipe Concrete Column

PROJECT : PAGE :

CLIENT : DESIGN BY :

JOB NO. : DATE : REVIEW BY :

Pipe Concrete Column Design Based on ACI 318-11

INPUT DATA & DESIGN SUMMARYCONCRETE STRENGTH fc' = 5 ksiREBAR YIELD STRESS fy = 60 ksiCOLUMN OUTSIDE DIAMETER D = 20 inCONCRETE WEB THICKNESS T = 7 inFACTORED AXIAL LOAD Pu = 480 kFACTORED MAGNIFIED MOMENT Mu = 190 ft-kFACTORED SHEAR LOAD Vu = 20 kCOLUMN VERT. REINFORCEMENT 8 # 7LATERAL REINF. OPTION (0=Spirals, 1=Ties) 1 TiesLATERAL REINFORCEMENT # 4 @ 12 in o.c.

THE COLUMN DESIGN IS ADEQUATE.

ANALYSIS

AT AXIAL LOAD ONLY 819 0

AT MAXIMUM LOAD 819 70

AT 0 % TENSION 643 148

AT 25 % TENSION 533 180

AT 50 % TENSION 444 197

318 206

AT BALANCED CONDITION 313 208

146 229

AT FLEXURE ONLY 0 164

CHECK FLEXURAL & AXIAL CAPACITY

819.14 kips., (at max axial load, ACI 318-11, Sec. 10.3.6.1)

where 0.65 (ACI 318-11, Sec.9.3.2.2) > [Satisfactory]

286 4.80

8 in (at balanced strain condition, ACI 10.3.2)

= 0.656 (ACI 318-11, Fig. R9.3.2)

where 10 in 0.002069 0.003

d = 17.56 in, (ACI 7.7.1) 0.8 ( ACI 318-11, Sec. 10.2.7.3 )

164

190 480 kips > [Satisfactory]

= 0.08 (ACI 318-11, Section 10.9) = 0.017

= 0.01 (ACI 318-11, Section 10.9) [Satisfactory]

CHECK SHEAR CAPACITY

49 kips, (ACI 318-11 Sec. 11.1.1)

> [Satisfactory]where 0.75 (ACI 318-11 Sec. 9.3.2.3)

214 0.40 60 ksi

30.3 kips, (ACI 318-11 Sec. 11.2.1)

35.1 kips, (ACI 318-11 Sec. 11.4.7.2)

= 14 (ACI 318-11, Section 7.10.5.2) = 12 in

= 1 [Satisfactory]

f Pn (k)

f Pn (kips) f Mn (ft-kips)

AT e t = 0.002

f Mn (ft-k)

AT e t = 0.005

f Pmax =0.85 f [ 0.85 fc' (Ag - Ast) + fy Ast] =

f = Pu

Ag = in2. Ast = in2.

a = Cbb1 =

f =0.75 + ( et - 0.002 ) (50), for Spiral

0.65 + ( et - 0.002 ) (250 / 3), for Ties

Cb = d ec / (ec + es) = et = ec =

b1 =

f Mn = 0.9 Mn = ft-kips @ Pn = 0, (ACI 318-11, Sec. 9.3.2) ,& et,min = 0.004, (ACI 318-11, Sec. 10.3.5)

f Mn = ft-kips @ Pu = Mu

rmax rprovd

rmin

f Vn = f (Vs + Vc) =

Vu

f =

A0 = in2. Av = in2. fy =

Vc = 2 (fc')0.5A0 =

Vs = MIN (d fy Av / s , 4Vc) =

smax sprovd

smin

0 50 100 150 200 2500

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forf c o

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