mole/stoichiometry the awesome team of alyssa h, lauren f, and dylan r

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Mole/Stoichiometry The awesome team of Alyssa H, Lauren F, and Dylan R

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Page 1: Mole/Stoichiometry The awesome team of Alyssa H, Lauren F, and Dylan R

Mole/StoichiometryThe awesome team of Alyssa H, Lauren F,

and Dylan R

Alyssa Haupt
did mrs molchany want particle to particle?
Page 2: Mole/Stoichiometry The awesome team of Alyssa H, Lauren F, and Dylan R

Stoichiometry:

• A balanced equation can be in terms of particles, mass, and moles

• Study relationships or ratios between two or more substances going under a physical or chemical change

Page 3: Mole/Stoichiometry The awesome team of Alyssa H, Lauren F, and Dylan R

Mole:

• The SI based unit used to measure the amount of a substance whose number of particles is the same as the number of atoms of Carbon in exactly 12 grams of Carbon 12

• When you convert from moles to moles use the molar ratio

Page 4: Mole/Stoichiometry The awesome team of Alyssa H, Lauren F, and Dylan R

Mole to Mole Ratio

• The coefficient in front of the balanced equation is the # of moles

• A mole ratio is required. A mole ratio is the ratio between moles of one substance to moles of another

• ex.) __H2 +__ O2 ---> __ H2O

How many moles of H2O are produced when

5.00 moles of oxygen are used?

Page 5: Mole/Stoichiometry The awesome team of Alyssa H, Lauren F, and Dylan R

1.) Balance the equation

2H2 + O2 ---> 2H2O

2.) Set up the equation with mole ratio

5 mole O2 2 H2O

1 O2

3.) Cancel out the O2 because they are across from each other.(Cross Multiply)

4.) This leaves you with 10 moles H2O

Mole Ratio

Page 6: Mole/Stoichiometry The awesome team of Alyssa H, Lauren F, and Dylan R

Mole to Mass Walkthrough

What is the mass of 2.4 moles of Lithium hydroxide (LiOH)

1. find the formula mass for LiOH- 23.95g

2. set up the equation so moles will cancel

2.4 mole LiOH X 23.95g LiOH = 57 grams LiOH

1 mole LiOH

3. multiply across

Page 7: Mole/Stoichiometry The awesome team of Alyssa H, Lauren F, and Dylan R

Mole to mass practice

1.) 3.79 moles of NaCl, what is the mass

3.79moles NaCl X 58.44g. NaCl=221g. NaCl

1 mole NaCl

2.) 1.63 moles of Hg2Cl, what is the mass

1.63moles Hg2Cl X 436.64g.Hg2Cl = 712g. Hg2Cl

1 mole Hg2Cl

Page 8: Mole/Stoichiometry The awesome team of Alyssa H, Lauren F, and Dylan R

Mole to Particles Walkthrough

There is 2.4 moles of LiOH, how particles are there

1. use avogadro's number- 6.02 X 10^23

2. set up equation2.4 mole LiOH X 6.02 X 1023 LiOH = 1.4 X 10^24

LiOH

1 mole LiOH

3. multiply across

Page 9: Mole/Stoichiometry The awesome team of Alyssa H, Lauren F, and Dylan R

Mole to particle practice

1.) 3.79 moles of NaCl, how many particles

3.79moles NaCl X 6.02 X 1023 NaCl=2.28X1024NaCl

1 mole NaCl

2.) 1.63 moles of Hg2Cl, how many particles

1.63moles Hg2Cl X 6.02 X 1023Hg2Cl =2.28X1024Hg2Cl

1 mole Hg2Cl

Page 10: Mole/Stoichiometry The awesome team of Alyssa H, Lauren F, and Dylan R

Moles to volume Walkthrough

What is the volume of 2.4 moles of Lithium hydroxide (LiOH)

1. use 22.4 liters

2. set up the equation so moles will cancel

2.4 mole LiOH X 22.4 L LiOH = 53.76 L LiOH

1 mole LiOH

3. multiply across

Page 11: Mole/Stoichiometry The awesome team of Alyssa H, Lauren F, and Dylan R

Mole to volume practice

1.) 3.79 moles of NaCl, how many liter

3.79moles NaCl X 22.4 L NaCl =84.9 L NaCl

1 mole NaCl

2.) 1.63 moles of Hg2Cl, how many liters

1.63moles Hg2Cl X 22.4 L Hg2Cl = 36.5 L Hg2Cl

1 mole Hg2Cl

Page 12: Mole/Stoichiometry The awesome team of Alyssa H, Lauren F, and Dylan R

Mass to Moles Walkthrough

15g NH4NO3 X 1 mol NH4NO

80.04g NH4NO3

0.19molesNH4NO3

If you have 15g NH4NO3 how many moles of NH4NO3 do you have?

1.) You multiply grams of what you are given( 15g NH4NO3) by the mole ratio of the compound.(The mole ratio is 1 mole of the compound over the formula mass of the compound)2.) Simply multiply and BAM you found your answer. 3.) Now you know how to go from grams to moles

Page 13: Mole/Stoichiometry The awesome team of Alyssa H, Lauren F, and Dylan R

Mass to Moles Practice

25g NH4NO3 X 1 mol NH4NO

80.04g NH4NO3

0.31molesNH4NO3

If you have 25g NH4NO3 how many moles of NH4NO3 do you have?

Page 14: Mole/Stoichiometry The awesome team of Alyssa H, Lauren F, and Dylan R

Mass to Moles Practice

583g NH4NO3 X 1 mol NH4NO

80.04g NH4NO3

7.28molesNH4NO3

If you have 583g NH4NO3 how many moles of NH4NO3 do you have?

Page 15: Mole/Stoichiometry The awesome team of Alyssa H, Lauren F, and Dylan R

Particle:

• To go from moles to particles or particles to moles use Avagadros number

o 6.02 10^23 particles/mole

Page 16: Mole/Stoichiometry The awesome team of Alyssa H, Lauren F, and Dylan R

Mass to Particles Walkthrough

15g NH4NO3 X 1 mol NH4NO

80.04g NH4NO3

1.13 X 1023

formula unitsNH4NO3

If you have 15g NH4NO3 how many particles of NH4NO3

do you have?

1.) You multiply grams of what you are given( 15g NH4NO3) by the mole ratio of the compound.(The mole ratio is 1 mole of the compound over the formula mass of the compound)2.) Next multiply the third block which is 6.02 X 1023 formula units over 1 mole of the compound.3.) You can plug this into your wiz bang and BAM you have found formula units from moles

6.02 X 1023 formula units 1 mol NH4NOX

Page 17: Mole/Stoichiometry The awesome team of Alyssa H, Lauren F, and Dylan R

Mass to Particles Practice

73g NH4NO3 X 1 mol NH4NO

80.04g NH4NO3

5.49 X 1023

formula unitsNH4NO3

If you have 73g NH4NO3 how many particles of NH4NO3

do you have?

6.02 X 1023 formula units 1 mol NH4NO

X

Page 18: Mole/Stoichiometry The awesome team of Alyssa H, Lauren F, and Dylan R

Mass to Particles Practice

68g NH4NO3 X 1 mol NH4NO

80.04g NH4NO3

5.11 X 1023

formula unitsNH4NO3

If you have 68g NH4NO3 how many particles of NH4NO3

do you have?

6.02 X 1023 formula units 1 mol NH4NO

X

Page 19: Mole/Stoichiometry The awesome team of Alyssa H, Lauren F, and Dylan R

Mass to Mass Walkthrough

30g NH4NO3 X 1 mol NH4NO

80.04g NH4NO3

If you have 30g NH4NO3 how many grams of H2O do you have?NH4NO3 N2O + H2O

1.) Balance the equation. NH4NO3 N2O + 2H2O2.) Multiply the grams of what you're given (30g) by 1 mole of the compound you're given over the formula mass of that compound3.) Next multiply by the mole ratio using the balanced formula4.) Finally multiply by the formula mass of what you're finding of 1 mole of what you're finding5.) Shazaam you've just converted from mass to mass

2 mol H2O1 mol NH4NO3

X18.02g H2O1 mol H2O

X13.5g H2O

Formula Mass of NH4NO3

Mole RatioFormula Massof H2O

Page 20: Mole/Stoichiometry The awesome team of Alyssa H, Lauren F, and Dylan R

Mass to Mass Practice:

60g NH4NO3 X 1 mol NH4NO

80.04g NH4NO3

If you have 60g NH4NO3 how many grams of H2O do you have?NH4NO3 N2O + H2O

2 mol H2O1 mol NH4NO3

X18.02g H2O1 mol H2O X

27.02g H2O

Page 21: Mole/Stoichiometry The awesome team of Alyssa H, Lauren F, and Dylan R

Mass to Mass Practice:

78g NH4NO3 X 1 mol NH4NO

80.04g NH4NO3

If you have 78g NH4NO3 how many grams of H2O do you have?NH4NO3 N2O + H2O

2 mol H2O1 mol NH4NO3

X18.02g H2O1 mol H2O X

35.12g H2O

Page 22: Mole/Stoichiometry The awesome team of Alyssa H, Lauren F, and Dylan R

Particle to Mole Walkthrough

If you have 4X1024 particles of NH3 how many moles of NH3 are there?

1.)Check to make sure the equation is balanced

2.)Multiply 4X1024 by Avogadro's Number

3.) Make sure to place Avogadro's Number on the numerator or denominator in order to cancel out units and leave moles

2NH3+H2SO4 (NH4)2SO4

4X1024 particlesNH31moleNH3

6.02X1023particl

esNH3

6.6molsNH3

Page 23: Mole/Stoichiometry The awesome team of Alyssa H, Lauren F, and Dylan R

Particle to Mole Practice

1.)There is 8.76X1022 particles of H2SO4 convert to moles.

2NH3+H2SO4 (NH4)2SO4

8.76X1022 particles H2SO4

1moleH2SO4

6.02X1023particlesH2SO4

.146molsH2SO4

2.49X1017particles (NH4)2SO4

1mole(NH4)2SO4

6.02X1023particles(NH4)2SO4

4.13X10-7mols(NH4)2SO4

2.)How many moles is 2.49X1017 particles of (NH4)2SO4?

Page 24: Mole/Stoichiometry The awesome team of Alyssa H, Lauren F, and Dylan R

Particle to Mass Walkthrough

If you have 6.82X1020 particles of O2 how many grams of O2 are there?

1.)Check to make sure the equation is balanced

2.)Multiply 6.82X1020 by Avogadro's Number and 1mole and make particle units cancel

3.)Multiply again by formula mass of O2 over 1mole to cancel out mole units leaving gramsO2

O2+2H2 2H2O

6.82X1020

particlesO2

1moleO2

6.02X1023parti

clesO2

.0363gO232gO2

1moleO2

Page 25: Mole/Stoichiometry The awesome team of Alyssa H, Lauren F, and Dylan R

Particle to Mass Practice

1.)1.67X1018particlesH2 is how many grams?O2+2H2 2H2O

1.67X1018

particlesH2

1moleH2

6.02X1023parti

clesH2

5.59X10-6gH22.016gH2

1moleH2

2.)8.43X1022particlesH2O is how many grams?

8.43X1022

particlesH2O1moleH2O

6.02X1023particl

esH2O

2.52gH2O18.016gH2O

1moleH2O

Page 26: Mole/Stoichiometry The awesome team of Alyssa H, Lauren F, and Dylan R

Particle to Particle Walkthrough

If you have 6X1015 particles of Fe how many particles of FeCl3 are there?

1.)Check to make sure the equation is balanced

2.)Multiply by Avogadro's Number

3.)Multiply by the mole to mole ratio

4.)Go back to particles by multiplying by Avogadro again

5.)cancel out units and leave particlesFeCl3

2Fe+3Cl2 2FeCl3

6X1015 part.Fe 1molFe6.02X1023particlesFe

6X1015particlesFeCl3

2molFeCl3

2molFe

6.02X1023particlesFeCl31molFeCl3

Page 27: Mole/Stoichiometry The awesome team of Alyssa H, Lauren F, and Dylan R

Particle to Particle Practice

1.)8X1020particles Cl2 is___ particles of Fe?2Fe+3Cl2 2FeCl3

8X1020 part.Cl21molCl26.02X1023particlesCl2

5.3X1020particlesFe

2molFe

3molC2

6.02X1023particlesFe1molFe

2.)1.7X1019particlesFe is ___ particles of Cl2?

1.7X1019 part.Fe 1molFe6.02X1023particlesFe

2.55X1019particlesCl2

3molCl2

2molFe

6.02X1023particlesCl21molCl2

Page 28: Mole/Stoichiometry The awesome team of Alyssa H, Lauren F, and Dylan R

Volume to Mole Walkthrough

If you have 8L of Carbon how many moles are there?

1.)Check to make sure the equation is balanced

2.)Multiply 8L by 22.4L/moles

3.) Make sure to place the correct unit on the numerator or denominator in order to cancel out units and leave moles

2As2O3+3C 3CO3+4As

8LC 1moleC22.4LC

.4molsC

Page 29: Mole/Stoichiometry The awesome team of Alyssa H, Lauren F, and Dylan R

Volume to Mole Practice

1.) If you have 2.5L of As2O3 how many moles is it?

2As2O3+3C 3CO3+4As

2.5LAs2O31moleAs2O3

22.4LAs2O3

.11molesAs2O3

2.) There is 11L of CO2 what is that in moles?

11LCO21moleCO2

22.4LCO2

.49molesCO2