lect 05© 2012 raymond p. jefferis iii1 satellite communications link budget analysis transmitted...
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Lect 05 © 2012 Raymond P. Jefferis III 1
Satellite Communications
Link budget analysis• Transmitted power• Transmitting antenna gain• Path loss• Receiving antenna gain• Receiver sensitivity
Lect 05 © 2012 Raymond P. Jefferis III 2
Tx Down-Link Budget Analysis• Starting with transmitter link loss factors:
– Power is reduced by system loss factors• detuning losses, cabling losses, coupling losses, etc.
– Power is reduced by antenna inefficiency, from beam sidelobes, for instance
• Dynamic losses – Backoff, beamwidth, and pointing losses
• Path loss factors– Free space loss– Atmospheric losses– Precipitation losses
Rx Down-Link Budget Analysis
• Receiver factors:– Receiver antenna gain – efficiency loss– Coupling, cabling, and detuning losses– Receiver sensitivity
• Noise factors– Input noise (natural factors)– Antenna, RF amplifier, and mixer noise
Lect 05 © 2012 Raymond P. Jefferis III 3
Lect 05 © 2012 Raymond P. Jefferis III 4
Transmitted Power• Usually specified in Watts• Can be converted to dBW by,
PtdB =10 logPt1.0⎛⎝⎜
⎞⎠⎟
where,Pt db = Transmitter power [dB-Watts]Pt = Transmitter power [Watts]
Lect 05 © 2012 Raymond P. Jefferis III 5
Transmitted Power• Usually specified in Watts• Can be converted to dBm by,
Pt dBm =10 logPt
1* 10−3
⎛⎝⎜
⎞⎠⎟
where,Pt dbm = Transmitter power [dB-milliWatts]Pt = Transmitter power [Watts]
Lect 05 © 2012 Raymond P. Jefferis III 6
Examples 05-01, 05-02• Transmitter power = 20 Watts• Pt db = 10 log(20) = 13 dBW• Pt dbm = 10 log(20/10-3) = 43 dBm
• Transmitter power = 75 Watts• Pt db = 10 log(75) = 18.75 dBW• Pt dbm = 10 log(75/10-3) = 48.75 dBm
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What does this specification mean?
Intelsat GALAXY-11 at 91W (NORAD 26038)
• 39.1 dBW on C-Band (20W, 24 ch, Bw: 36 MHz)
• 47.8 dBW on Ku-Band (75/140W, 40 ch, Bw: 36 MHz)
• Transmitter power, is simultaneously distributed across all the available channels (CDMA)
• The satellite has four antennas, two for each band, and sequential channels are transmitted on one antenna in a band and received on the other. Shared channel (TDMA)
Two possible interpretations (CDMA vs. TDMA)
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Transmitter Antenna Gain
For a circular antenna (parabolic dish),
Ae =ηAπ(d / 2)2
G=4πλ2 Ae
G=ηA
πdλ
⎛⎝⎜
⎞⎠⎟
2
where,Ae = Effective aperture [m2]η= aperture efficiencyd = aperture diameter [m]G = aperture antenna gainλ= operating wavelength [m]
LECT 04 © 2012 Raymond P. Jefferis III 9
Circular Aperture Antenna
• The electric field of a circular aperture antenna can be calculated from:
E[φ] =2λπD
J 1[(πD / λ)sinφ]sinφ
where, D/λgives the aperture diameter in wavelengths and ϕ is the angle relative to the normal to the plane of the aperture.
Lect 05 © 2012 Raymond P. Jefferis III 10
Example 05-03 - Ku-Band antenna
• 3dB beamwidth = 3˚
• D/λ= 25η= 0.63
• G = 3886
• GdBi = 36
Beamwidth – Circular Aperture
Show demo.
Lect 05 © 2012 Raymond P. Jefferis III Lect 00 - 11
E-Field of a Circular Aperture Antenna
Lect 05 © 2012 Raymond P. Jefferis III Lect 00 - 12
eps = 0.001;Diam = 20;
Manipulate[e2 = (2.0/p*Diam)*(BesselJ[1, p*Diam*Sin[theta]])/Sin[theta]; Plot[Abs[e2], {theta, -p/6, p/6}, PlotRange -> {{-0.5, 0.5}, {0, 600}}, PlotStyle -> {Directive[Thick, Black]}], {Diam, 1, 25} ]
Lect 05 © 2012 Raymond P. Jefferis III 13
Antenna Gain vs Beamwidth Calculation
eff = 0.63;beamw = 1;f = 12*10^9;c = 2.99792458*10^8;lam = c/f;Plot[app = 75.0/beamw; diam = app*lam; G = eff*p^2*app^2; lG = 10*Log[10, G]; lG, {beamw, 1, 5}, AxesLabel -> {Beamwidth [deg], Gain}]
Antenna Gain vs Beamwidth Result
Lect 05 © 2012 Raymond P. Jefferis III Lect 00 - 14
Link Budget – General Information
• The accounting of gains and losses over a link• Other effects that can be considered
– Fading– Reflections (multipath interference)– Ground absorption
• Excessive power losses can reduce a transmitted signal to levels below the receiver sensitivity in the presence of noise
Lect 05 © 2012 Raymond P. Jefferis III Lect 00 - 15
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Link Budget Calculation (Downlink)
• Calculate power density of isotropic antenna• Calculate effective radiated power (EIRP)
using transmitter antenna gain and efficiency• Calculate path loss• Calculate receiving antenna aperture and gain• Calculate received power at the earth station
Link Budget Calculation (continued)
• Compare receiver input specifications with the calculated power levels at the receiver
• Add noise factors• Calculate receiver input Signal/Noise ratio• If this is inadequate, change accessible link factors
Lect 05 © 2012 Raymond P. Jefferis III Lect 00 - 17
The Isotropic (Ideal) Antenna
• The gains of antennas can be stated relative to an isotropic ideal antenna as G [dBi], where G > 0.
• This antenna is a (theoretical) point source of EM energy
• It radiates uniformly in all directions• A sphere centered on this antenna would exhibit
constant energy per unit area over its surface• The gain of an isotropic antenna is 0 dBi
Lect 05 © 2012 Raymond P. Jefferis III Lect 00 - 18
EIRP
• Equivalent Isotropic Radiated Power
• – the equivalent power input that would be needed for an isotropic antenna to radiate the same power over the angles of interest
LECT 04 © 2012 Raymond P. Jefferis III Lect 00 - 19
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Equivalent Isotropic Radiated Power - EIRP
EIRP =GtPtWhere: (in the far-field only),EIRP = Equiv. isotropic rad. power [W]Pt = Transmitted power [W]Gt = Gain of lossless transmitting antenna (Gt = 1 for lossless isotropic antenna)or, in dB units,EIRPdBW = Pt dBW + Gt dBi
Lect 05 © 2012 Raymond P. Jefferis III 21
Isotropic Radiated Flux Density
ψ =1
4π r2
⎛⎝⎜
⎞⎠⎟EIRP
where (in the far-field only),ψ = Transmitted power flux density (W/m2)EIRP = Equiv. isotropic rad. power [W]r = Distance from transmitter
Note: This is the EIRP per unit area of a sphere at radius r from an isotropic antenna.
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Actual Transmitting Antenna Gain
Gte =ηtGt
EIRPeff =ηtGtPtwhere (in the far-field only),EIRPeff = Effective EIRP [W]Pt = Transmitted power [W]Gt = Gain of a lossless (ideal) transmitting antennaηt = Transmitting antenna efficiency Gte = Effective gain of transmitting antenna
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Example 05-04: Ku-Band Satellite• Pt: 75 [W] => 18.75 [dBW]
• Antenna diam: 1.8 [m]• Frequency: 12 [GHz]• Wavelength: 0.025 [m]• Antenna Eff.: 0.62 [-2.1 dBW]• Antenna Gain: 45.02 [dBi]
• EIRPeff 63.77 [dBW]
EIRP Calculation for Ku-band Example
c = 2.99792458*10^8; (* m/sec *)
freq = 12.0*10^9; (* Hz *)
pt = 75.0;(* Watts *)
ptdbW = 10*Log[10, pt]; (* dBW *)
eff = 0.62; (* efficiency *)
lam = c/freq; (* m *)
diam = 1.8; (* m *)
dl = diam/lam;
gain = eff*(p*diam/lam)^2;
loggain = 10*Log[10, gain];(* dB *)
eirp = gain*pt;(* W *)
dBW = 10*Log[10, eirp];(* dBW *)
Print["EIRP = ", dBW, " [dBW]"]
Lect 05 © 2012 Raymond P. Jefferis III Lect 00 - 24
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Free Space Path Loss Calculation
• Due to the spreading of transmitted energy• Other losses will be accounted separately
Lp =λ
4πr⎛⎝⎜
⎞⎠⎟
2
where,λ= wavelength [m]r = transmission-reception distance [m]
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Received Power (Gain & Losses)Pr =EIRP ⋅Lp ⋅Gr
Gr =ηr
πdrλ
⎛⎝⎜
⎞⎠⎟
2
where,EIRP = Effective Isotropic Radiated Powerηr = Antenna efficiencyGr = Antenna gain (G = 1 for isotropic)dr = Antenna diameter [m]Lp = Path lossλ= wavelength [m]
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Net Received Power CalculationPr =EIRP ⋅Lp ⋅Gr _ eff
EIRP =Gt_ effPt
Gt_ eff =ηt
πdtλ
⎛⎝⎜
⎞⎠⎟
2
Lp =λ
4πr⎛⎝⎜
⎞⎠⎟
2
Gr _ eff =ηr
πdrλ
⎛⎝⎜
⎞⎠⎟
2
EIRP = Eff. Isotropic Radiated Powerηt/r = Antenna efficiencyGt/r = Antenna gain Dt/r = Antenna diameter [m]Lp = Path lossλ = wavelength [m]R = transmitter-receiver distance [m]
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Another Received Power Interpretation
Pr =ψ r ⋅Aeff
Where,Pr = Received power [W]ψr = Received flux density [W/m2]Aeff = Effective receiving antenna aperture [m2]
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Path Loss Summary Diagram
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Power Ratio over Path Calculation
where,ηt = Efficiency of receiving antenna [-]ηr = Efficiency of receiving antenna [-]Gt = Antenna gain (G=1 for isotropic antenna)Gr = Antenna gain (G=1 for isotropic antenna)λ = wavelength [m]d = distance between antennas [m]
Lect 05 © 2012 Raymond P. Jefferis III 31
Path Loss [dB]
Pr dB =PtdB +10 log(ηtGt) +10 logλ
4πr⎛⎝⎜
⎞⎠⎟
2
+10 log(ηrGr )
Lect 05 © 2012 Raymond P. Jefferis III 32
Example 05-05: Ku-Band Satellite• Receiving antenna diameter: 0.9 [m]• Frequency: 12 [GHz]• Wavelength: 0.025 [m]• Path length: 42000 [km]• Antenna Eff.: 0.62• Receiving Antenna Gain: 39 [dBi]• EIRPeff 63.8 [dBW]• Path gain (-loss): -206.5 [dBW]• Received power: -103.7 [dBW]
Class Activity
• Compute the path loss of the previous example in dBW.
• Compute the received power of the previous example in dBW.
Lect 05 © 2012 Raymond P. Jefferis III Lect 00 - 33
Activity Results
• f = 12 GHz [12000 MHz]
• λ= 0.025 [m] => (-32 dBW)
• Pt = 18.75 dBW
• ηtGt = 45.02 dBW
• ηrGr = 39.0 dBW
• r = 42,000 km => (-206.5 dBW)
• Pr = 18.75 + 45.02 - 206.5 + 39 = -103.7 [dBW]
Lect 05 © 2012 Raymond P. Jefferis III Lect 00 - 34
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Activity Calculationc = 2.99792458*10^8; f = 12.0*10^9; lam = c/f;r = 42.0*10^6;pwrTx = 75.0; dAntTx = 1.8; effAntTx = 0.62;gAntTxEff = effAntTx*(p*dAntTx/lam)^2;gAntTxEffdB = 10 Log[10, gAntTxEff];EIRPdB = 10 Log[10, pwrTx] + gAntTxEffdB;Lp = (lam/(4*p*r))^2;LpdB = 10 Log[10, Lp];dAntRx = 0.9; effAntRx = 0.62;gAntRxEff = effAntRx*(p*dAntRx/lam)^2;GAntRxEffdB = 10 Log[10, gAntRxEff];PrdB = EIRPdB + LpdB + GAntRxEffdB;Print["Path Loss ", LpdB, " [dB]"];Print["Rcv pwr = ", PrdB, " [dBW]"];
Lect 05 © 2012 Raymond P. Jefferis III 36
Example: Ku-Band Link• Tx power: 10 [Watts]• Rx and Tx antenna diameters:3.0 [m]• Frequency: 12 [GHz]• Path length: 35,900 [km]• Antenna Efficiencies 0.55• Antenna Gains: 48.93[dBi]• EIRPeff 58.93 [dBW]• Path gain (-loss): -205.1 [dBW]• Received power: -97.24
[dBW]
Example Ku-Band Calculationf = 12.0*10^9; Bw = 36.0*10^6; c = 2.99792458*10^8;lam = c/f;r = 35.9*10^6;(* Tx EIRP CALC. *) pwrTx = 10.0;pwrTxdB = 10 Log[10, pwrTx];dAntTx = 3.0; effAntTx = 0.55;gAntTxEff = effAntTx*(p dAntTx/lam)^2;gAntTxEffdB = 10 Log[10, gAntTxEff];EIRPdB = 10 Log[10, pwrTx] + gAntTxEffdB;(* Path Loss *) Lp = (3.0*10^8/(4*p*f*r))^2;(* Path Loss [DB] *) LpdB = 10 Log[10, Lp];(* Rx Antenna CALC. *) dAntRx = 3.0; effAntRx = 0.55;gAntRxEff = effAntRx*(p dAntRx/lam)^2;GAntRxEffdB = 10 Log[10, gAntRxEff];(* Received Power [DB] *) PrdB = EIRPdB + LpdB + GAntRxEffdB;(* Received Power [W] *) PrWatts = 10^(PrdB/10);
Lect 05 © 2012 Raymond P. Jefferis III 37
Lect 05 © 2012 Raymond P. Jefferis III 38
Conversion to Frequency Baseλ =c / f
Pr = Pt3*108
4π fR
⎛
⎝⎜⎞
⎠⎟
2
GtGr
Lp =c
4π fR
⎛⎝⎜
⎞⎠⎟
2
Pr( )dB
= Pt( )dB
+ (Gt )dB + (Lp )dB + (Gr )dB
where,(Pt)dB = Transmitted power [dBW](Pr)dB = Received power [dBW](Lp)dB = Path loss power [dBW](Gt/r)dB = Transmitting or receiving antenna gainf = frequency [Hz]R = distance [m]
Lect 05 © 2012 Raymond P. Jefferis III 39
Example Calculation: Ku-Band• f = 12 GHz [12000 MHz]• Pt = 18.7 dBW• Gt = 45 dBi• Gr = 39 dBi• R = 42, 000 km• Pr = 18.7 + 45 - 206.49 + 39 = - 103.8 dBW
Note:Considering free space loss only
Workshop 05
• Please do all work indicated on the Workshop 05 handout.
• You may use a spreadsheet or a mathematics package (Mathematica®is recommended) for your calculations
• Document ALL work and calculations
• Submit as a written Workshop report.
Lect 05 © 2012 Raymond P. Jefferis III 40
Lect 05 © 2012 Raymond P. Jefferis III 41
Workshop 05 Calculationsc = 2.99792458*10^8; f = 12.0*10^9;lam = c/f; r = 42.0*10^6;pwrTx = 75.0; pwrTxdB = 10 Log[10, pwrTx];dAntTx = 1.8; effAntTx = 0.62;gAntTxEff = effAntTx*(p dAntTx/lam)^2;gAntTxEffdB = 10 Log[10, gAntTxEff];EIRPdB = 10 Log[10, pwrTx] + gAntTxEffdB;Lp =(3.0*10^8/(4*p*f*r))^2; LpdB =10 Log[10, Lp];dAntRx = 0.9; effAntRx = 0.62;gAntRxEff = effAntRx*(p dAntRx/lam)^2;GAntRxEffdB = 10 Log[10, gAntRxEff];PrdB = EIRPdB + LpdB + GAntRxEffdB;
End
Lect 05 © 2012 Raymond P. Jefferis III 42