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HIDRODINAMIKA I Diketahui floating body bergerak pada perairan bergelombang reguler dengan data-data sebagai berikut : !pp 92 m "!"l #m $%&'( g ) ! 13.2 m #b $%*+& ρ , ! 6 m #p $% $* . 16 knot ! +%(/00000$1 m2s 3 &1%$$ m ! 8.23 m2s disp &/%$$ m 4 ! 4494.61188 ton #os 5 0%$$ 0knot!$6 #7 ! 0.744 m dibelakang midship .in5 $%$$ 0m2s! 06& #) ! 0.744 m dibelakang midship 8" $%'0+ 5 ! 0 9 heading angle ! follo"ing sea " ! 94.00 m .tat% No% )n ,n .n 9m 9m 0 ( / 1 A; 1% 1 1%* 0 * 0( *+%*1( 0$ 0/%( ' %&++ 0* & *(%$($ <; $ $%$$$ 0 7erakan Hea=ing ! $%+0 rad2se8 (g ! 0&% ( $%$ ' $%** ! $%( rad2se8 inertial fo8e .tat% No% #> 0 ( / 1 * ' + & 0$ 00 A; 1% 1 1%* 0 $%$0 $%''/ ('%+1$ $%0 1 $%&10 (0%*/$ +% ( * 0(%$$ *+%*1( $%$10 (%$$$ '(%$$$ $%+0/ 0%1$$ 011%$$$ *'%&// 0$ 0/%($ ' %&++ $%$1* (%($$ '&%($$ $%&'( 0%1+1 0'1%(1$ '$%$&& 0* &%$$ *(%$($ $%$/0 0%*$$ *1%$$$ $%& / 0%*0$ +0%$$$ /(%*+' <; $%$$ $%$$$ $%$$$ $%$$$ $%$$$ $%$$$ $%$$$ $%$$$ $%$$$ $ $ $%0 $%&10(&+ $%+ 0%1 $%* 0%1 $%+0 0%1 = s 9u ! o 9m ( ? " ! 9(@g2" 02( ? e ² ! ? e ! ? " - 9? " ( 2g u 8os 5 ) n , n . n ? e ( )n 2(g ) n 2 , n ) n , n B n ) n ( C@2+ ζ_a

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Tugas Hidrodinamika 1

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Tabel 4.1HIDRODINAMIKA IDiketahui floating body bergerak pada perairan bergelombang reguler dengan data-data sebagai berikut :Stat. No.1/2 BnTnSnL =Lpp92mLw=LwlCm0.972g9.81m/s(m)(m)(m2)B =13.2mCb0.5891.025kg/m31234T =6m6Cp0.605S23AP2.3262.28vs (u) =16knot =8.231111104m/sLWL94.00m56629.2709=8.23m/sL disp93.00m106.6638.4942 =4494.61188tonCos 1.001knot= 0,5144 m/s8.2304154.5626.01LCG =0.744m di belakang midshipSin 0.001m/s= 1,94388 knotFP060LCB =0.744m di belakang midshipcw0.718 =0o( heading angle = following sea)Lw =94.00mStat. No.BnTnSn(m)(m)(m2)1234AP4.6464.561512658.5421013.2676.988159652.020FP060.0001) Gerakan Heavingw =(2g/Lw)1/2=0.81rad/sec2g =19.62e =0.067e =w - (w2/g) x u cos 0.55=0.26rad/secinertial foceStat. No.BnTnSne2 x Bn /2gBn / TnBn x TnnC*Bn2/8 x Bn2anSimpsonProduct1234567891011121314AP4.6464.5610.0160.77327.8400.1640.94121.5308.6628.15318.153512.00658.5420.0412.00072.0000.8131.400144.00057.93381.1064324.4251013.20676.9880.0452.20079.2000.9721.484174.24070.099104.0112208.022159.00652.0200.0311.50054.0000.9631.51081.00032.58749.2074196.827FP0.0060.0000.0000.0000.0000.0000.0000.0000.0000.00010.000000.160.94129885060.81.40.51.40.811.4000SUM737.427ton/m0.91.40.971.483772727311.70.961.510.71.4Jadi, besarnya added mass, M adalah sebagai berikut :0.8001.4added massship massvirtual mass0.90.120.121.4M =1/3 x station spacing x SUMM =a =M + M10.12=5653.608ton=4494.612ton =10148.22tondamping force123456789stat. number{(We^2)/2g}*BnBn/TnbnAAbn=gA/ wesimpsproductJadi Dumping Coeff :000.160.0481005305AP0.0160.7730.1640.048100.0021.32911.329b = bn dx0.50.036230.810.07101562550.0412.0000.8130.071020.0052.897411.587=1/3 * S * S0.70.081250.970.0796414742100.0452.2000.9720.079640.0063.64327.286=266.39ton-s/m0.80.080.960.0795636667150.0311.5000.9630.079560.0063.636414.5440.90.079890.000FP0.0000.0000.0000.000000.0000.00010.00010.079S =34.747ton-s/m2restoring force12345restoring force coeff :stat. numberBnCn = .Bnsimpsonproductc=1/3 x s x SUMAP4.6404.7561.0004.756=904.0226666667ton/m512.00012.3004.00049.2001013.20013.5302.00027.060159.0009.2254.00036.900FP0.0000.0001.0000.000sum117.916ton/m2exiting force12345678910k=(2 x 3,14) /Lwstat. numb.Bny = Bn/2cos mLCG (x)K'=kx Cos mcos K'y . Cos K'simpsonproduk=0.067AP4.6402.3201.00045.2563.023-0.993-2.3041-2.304173.3209512.0006.0001.00022.2561.4870.0830.49841.99285.23571013.2006.6001.0000.7440.0500.9996.592213.1842.8494159.0004.5001.000-23.744-1.586-0.016-0.0734-0.294-90.9345FP0.0000.0001.000-46.744-3.123-1.0000.00010.000-179.0196S12.578a =6mintergal=1/3 x s x SUMfo=(2/LB) x integralFo= x _ x L B x fo=96.434=0.1588170455=1186.134633ton2KA0.0765135741za/a0.8578322111-A0.2431646122z =(c/a)^0.5=e / zk=(b/2a)/zZa=Fo/c x 1/ ((1-^2)^2+4k^2 x ^2)^0.52KA/1-A0.3146575214=0.2984659065=0.8699628658=0.0439751955=5.146993266mtan-117.46655derajat1.31206293460.05912902860.00585432717.46655-17.466550.0591290286cos(wet-)0.9542) gerakan pitchingz4.9102315758mmomen inertial forceStat. No.an2an x 2SimpsonProduct1234567MP =1/3 x station spacing x SUMAP8.15345.2562048.10616698.573116698.573=2211662.78056534ton-m581.10622.256495.33040174.2964160697.18610104.0110.7440.55457.5742115.148MP =1549.207-23.744563.77827741.7124110966.848=4494.6125292377649.68452FP0.000-46.7442185.0020.00010.000a=(MP + MP) x (0.25xLw)^2ton/m=1223872920.0ton-ma=4589312.46508534SUM288477.754ton-mdamping forceStat. No.bn2bn x 2SimpsonProduct1234567Jadi Dumping Coeff :AP1.32945.2562048.1062721.81512721.815b = bn dx52.89722.256495.3301434.85745739.428=1/3 * S * S103.6430.7440.5542.01724.033=127765.671274213ton-s-m153.636-23.744563.7782049.95348199.812FP0.000-46.7442185.0020.00010.000ton-s/mSUM16665.088ton-srestoring force1234567restoring force coeff :stat. numberBnCn = .Bn2Cn x 2simpsonproductc=1/3 x s x SUMAP4.644.7562048.1069740.79019740.790=421125.191949483ton-m512.0012.300495.3306092.553424370.2131013.2013.5300.5547.489214.979159.009.225563.7785200.848420803.391FP0.000.0002185.0020.00010.000ton/mSUM54929.373tonexiting force123456789intergal=1/3 x s x SUMst =Mo/c=(c/a)^0.5stat. numb.y=Bny.K'=k Cos msin K'y. . sin K'simpsonproduk=14909.014=0.4354545=0.3029226846AP4.6445.256209.9883.0230.11624.4221.0024.422512.0022.256267.0721.4870.997266.1484.001064.592fo=4/(BL^2)*integtralk=(b/2a)/=e /1013.200.7449.8210.0500.0500.4882.000.976=0.533776=0.0459520362=0.8571634564159.00-23.744-213.696-1.586-1.000213.6664.00854.664FP0.00-46.7440.000-3.123-0.0170.0001.000.000Mo=1/2 x x L^2 B x fo=1/ ((1-^2)^2+4k^2 x ^2)^0.5SUM1944.654=183380.874414918=3.6137510596173.32085106380.07036860210.006205786285.2357446809a =st x v0.01391991422.8493617021=1.57362429radK0.0459520362-90.9344680851=90.2001440374derajat2KA0.0787768124-179.0195744681 =1+22=tan-1 (2k/(1-^2))1-A20.265270809=106.5414=16.5414derajat2KA/1-A20.2969675129(wet-)-16.5490.2077615817sin(wet-)-0.28-0.4406147999-25.2581732429derajat-25.2560403305

_a

Tabel 4.2L = Lpp92Cb =0.59ww0.81B =13.2Cm =0.97we0.26T =6Cp =0.61S23V =8.2 =1.025disp =4494.61g =9.81LCG =0.744cos m =1LCB =0.744123456789stat. number{(We^2)/2g}*BnBn/TnbnAAbn=gA/ wesimpsproductAP0.020.770.160.000.000.0010.0050.042.000.810.000.000.0040.00100.052.200.970.000.000.0020.00150.031.500.960.000.000.0040.00FP0.000.00000010S =0.00Jadi Dumping Coeff :b = bn dx=1/3 * S * S=0.00

Tabel 4.3L = Lpp92Cb =0.59ww0.81B =13.2Cm =0.97we0.26T =6Cp =0.61S23V =8.24.2344128 =1.025disp =4494.61g =9.81LCG =0.744cos m =-1LCB =0.744stat. numbBnCn = r*g*BnsimpsonproductAP4.6446.66146.66512.00120.664482.651013.20132.732265.46159.0090.504361.99FP0.00010S =1156.76Jadi restoring force coeff :C =1/3 * S * S=8868.46Lb/m

Tabel 4.465LCB0.2belakang midship1 m =3,28 feetLCG0.2belakang midshipp =1.025k(2 x 3,14) / LPP0.070.321234567891011stat. numb.Bny = Bn/2cos mLCG (x)K'=kx Cos m(K')cos (K')y cos (K')faktor simpsonprodukAP4.642.32139.682.60148.800.010.0210.02512.006.00119.681.2973.800.724.32417.281013.206.601-0.32-0.02-1.200.996.53213.07159.004.501-20.32-1.33-76.200.703.15412.60FP0.0001-40.32-2.64-151.20-0.010.0010S42.97x untukAP =(Lpp/2) - LCGStat 5 =(Lpp/4) - LCGStation 10 =LCGStat 15 =(Lpp/4) + LCGFP =(Lpp/2) + LCGFo =2 x x g x 1/3 * S * S6043.047011.811820.09300.80

damping pitchingstat. numb.bnLCGLCGbn*LCGsimpprodukAP0.9339.681574.50241463.3611463.3654.9719.68387.30241924.9647699.84105.24-0.320.10240.5421.07153.95-20.32412.90241632.4646529.85FP0-40.321625.702401015694.13

restoring pitchingstat. numb.BnCn = r*g*BnLCGLCGCn*LCGsimpsonprodukAP440.1839.681574.502463263.51163263.51510.2102.4619.68387.302439682.624158730.471011110.50-0.320.102411.31222.6315990.41-20.32412.902437328.444149313.77FP00-40.321625.7024010371330.37