goljian general path
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High Yield Concepts in General Pathology
High Yield Concepts in General Pathology
General Principles of Lab Medicine
Sensitivity of a tcst: "posith;iry ill disease"-
A. TP = pa.t.ienl with the disease
n. FN = palien( with disease who has a negative tesl result
C. fOflllUt:1 for sensitivity- TP I TP + FN
usc of a test " ... ith J 00 % sensith-ii)'-
best used 10 screen for disease
excludes disease when negative
includes people \.vith disease when positive '
catch words: excludes and includes
interpretation of a test with J 00% sensirivity when it returns nor11lal in a paticllt-
always has a ne!..!ative orediclive value of '100% (PY- = TN / TN + FN)
it mUSt be a TN lest re-sult (excludes disease) since there are no J-Ns: a TN is a true
negative or a nomlai [cst result in a person wilhout disease
e.g .. )ci'um ANA has 100% sensitivity for SLE: a negative serum ANA excludes SLE, interpretation of a test with 100% sensitivity wheu it returns positive i 11 a patient-
may be a TP or FP:
(I) FP = false positive or a positive test result in a nomlaJ person
(2) note that FPs are not in the fom1ula for sensitivit)l
people with the disease are a!wavs included
c.g., a positive senlm AKA result includes all ~le with SLE: it does nOT confirm SLE sinct! other diseases also have a positive ANA (e.g., rheumatoid a.rthritis. progressive
2.
4.
B. c.
systemic sclerosis)
Disease ;'\rIo D~ease
Positive test (TP) 100 (FP) 10
Negative test (FN) 0 (Ti\) 90
Calculate sensiriviry or the test: TP J TP + FN = 100 I 100 - 0 == 1000,,"i1 Calculate PY-: TN 1 TN + fN = 90 190 + 0 = 100%
"'"
Specificity or a rest:
"negativity in health"-
TN == normal test result in a person wilhom disease
FP = patient vv'ilholl! diseuse who has a positive test result
C. formula for specificity- TN / TN + FP
use of a test witb 100% specificity- confinns disease: there are no FP test results, therefore. a positive test must be a TP
interpretation of a test with 100% specificity when it returns positive in a patient-
confinns disease in that patient
positive predictive value is always ~:oO% (PV' ~ TP / TP + FP)
must be a TP (confirms disease) since there are no FPs
e.g., anti-Sm for SLE has 100% specificity (110 FPs): glLpatients with a posiLive anti-Sm have SLE
interpretation of a test with 100% specificity when it returns negative/normal In a patient-
may be a TN or FN: note that the FN rate is not in the formula for speci.ficity
it does not exclude SLE
e.g., anti-Sm is negative in a patient: ( I) does not exclude SLE
(2) use other tests to confirm SLE if your suspicions are high
Disease
No Disease
Positive test (TP) 90
(FP) 0
Negative test (FN) 10
(TN) 100
Calculate specificity of tl,e test: TN / TN + FP ~ 100 / 100 + 0 ~ 100% Calculate P: TP / TP + FP ~ 90 /90 + 0 ~ 100%
CalcuJate the reference interval of the t.est when given the mean of the test and 1 SD (standard deviation):
remember to double the SD- 2 SD covers 95% of the normal population
example- .
meanofthetest~IOOmzldLand I SD~5mgldL(2SD~IOmgldL)
reference interval ~ 90-110 mgldL (l 00 - 10 ~ 90 and 100 + I 0 ~ 110)
for each test, 5% of normal people wilt have test results outside the reference intenal-
chance of a FP increases when more than one test is ordered on a patient
example. 2 tests on a patient increases the chance of a FP test result on one of those tests ro-lO%
SD is a marker of the precision (reproducibility) of the test- it is not a marker of how accurate the test result is
Accuracy: good Accuracy: poor
Precision: good Precision: good
Effect of tcst sensitivity/specificity of a test on prevalence:
test with highest sensitivity (not specificity) increases prevalence of disease (number of people in a population tbat have disease)-
it picks lip more people with the disease since it is a good scree_ning test
tests with high specificity confinn disease and help differentiate a TP from a FP but they are poor screening tests
,Effect of increasing the upper limit of normal of a test reference interval (e.g., raising a reference lnten'a! of 0-4 ng/mL to 0-10 ng/mL) on sensitivity, specificity, PY+, and PV":
increases specificity and positive predictive value-
h.igher values are more likely to represent\.TPs than FPs
specificity always increases, which automatically increases PY+ decreases sensitivity and negative predictive value (PV)-
increasing specificity of a test always decreases its sensitivity and PV
FN rate increases, since more people. with disease are encountered as the reference interval increases
a nomlai test result is more likely to be a FN rarher than a TN
Effect of decreasing the upper limit of normal of a test reference interval (e.g., lowering the fasting glucose level (or diagnosing diabetes mellitus (DM] from >140 mg/dL to >126 mgldL) on sensitivity, specificity, PV, and PV:
increases sensitivity and negative predictive value (PV)-
dropping the upper limit to a lower value means that more people with a negative test
result are likely to be TNs (not have DM) rather than FNs
sensitivity and PV always i_T'lcrease when the upper limit ofa test is lowered decreases specificity and positive predictive vaJue (PV)-
fewer people are likely to have OM, a test result >126 mgldL is more likely to be a FP than a TP test result
summary schematic
2.
Pre\'alence:
Prevalence (number of people with disease in tbe popu.lation studied) == (number of new cases over a period of time) x Duration oftbe disease-
P~IxD
as duration (.D) decreases, prevalence (P) decreases
Incidence
-
as D increases, P increases
incidence (1) is a constant in this relationship-
prevalence c.lcuJation- TP + FN (all people with disease)1 TP + FN + TN + FP (all people with and without disease)
3, example- if treatment for leukemia lengthens the survival period but does not lead to its 'cure, prevalence (P) of leukemia Increases owin~ to the increase in dumtion (D): no effect on incidence (number of new cases of leukemiaY
Example of a calculation for sensitivity, specificity, PV+1 PV-, prevaJence:
Disease
No Disease
Positive test (TP) 60
(FP) 40
Negative test (FN) 20
(TN) 80
Sensitivity of the test: TP / TP + FN ~ 60 / 80 ~ 75% Specificity of the test: TN / TN + FP ~ 80 I 120 ~ 66%
PV-: TN I TN + FN ~ 80 1100 ~ 80% (80% chance it is a TN and a 20% chance it is a FN) p\,,: TP I TP + FP = 60 / 100 ~ 60% (60% chance it is a TP and 40% chance it is a FP) Prevalence: TP + FN I TP + FN + TN + FP ~ 80 1200 = 40%