families of circles
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8/7/2019 families of circles
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Families of Circle
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Equation of circle: (x-3)2 + (y -1)2 = k2
Center at the origin ( 3,1) the radius
varies
k = 3
k =
5
k = 8
k = 9
Concentric circles: the same center
point.
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Ex. 1. Write an equation which represents a family of
circles with center on the line y = x and which passes
through the origin. Find the member of this family which
passes through the point ( 6 ,0).
Ans. (x
- h )2
+ ( y - k )2
= r2
( x - 3 ) 2 + ( y - 3 )2 = 18
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Circle Passing Through the Intersection
of Two Circles
Circle 1: x2 + y2 + D1
x + E1
y + F1
= 0
Circle 2: x2 + y2 + D2x + E2y + F2 = 0
(x2 + y2 + D1
x + E1
y + F1
) + k (x2 + y2 + D2
x + E2
y + F2
) = 0
Equation of a family of circles passing
through the intersection of two circles:
where k -1
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Ex 1. Write the equation of the family of circles C3
all members of which pass
through the intersection of the circles C1 and C2 represented by the equations
C1: x2 + y2 + 2x - 4y - 4 = 0
C2: x2 + y2 - 6x + 2y - 6 = 0
Find the member of the family C3 that passes through the point ( 9, -1).
Answer:
Family: (x2 + y2 + 2x - 4y - 4 ) + k (x2 + y2 - -6x + 2y - 6 ) = 0
C3: k = -5; x2 + y2 - 8x + 7y/2 - 13/2 = 0
center ±radius form: ( x ± 4)2 + ( y + 7/4)2 = 409/16.
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C1
C2
C3
C1: center: ( -1, 2) r = 3
C2: center: ( 3, - 1) r = 4
C3: center: ( 4, -7/4) r =4
409
C1: C1: x2 + y2 + 2x - 4y - 4 = 0
C2: x2 + y2 - 6x + 2y - 6 = 0
k = - 4
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The equation: (x2+ y2+ D1x + E1y + F1) + k (x2 + y2 + D2x + E2y + F2) = 0
represents a circle if k - 1
If k = - 1, equation of Circle 2 is subtracted from that of circle 1
and the equation becomes:
( D1 - D2) x + ( E1 - E2 ) y + F1 - F2 = 0
Note: the above equation is linear so the graph of the equation is
a straight line which is the radical axis.
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Ex., Find the equation of the radical axis of the circles
in the previous problem.
C1
C2
C1: x2 + y2 + 2x - 4y - 4 = 0
C2: x2 + y2 - 6x + 2y - 6 = 0
Ans. 4x - 3y + 1 = 0
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Assignment:
1. Write the equation of the f amily of circles passing through the intersection
points of
x2 + y2 + 16x + 10y + 24 = 0 and x2 + y2 + 4x - 8y - 6 = 0
Find the member of the f amily that passes through the origin. Construct
the three circles. Ans. 5x2 + 5y2 + 32x - 22y = 0.
2. Write the equation of the f amily of circles passing through the intersection of
two circles:x2 + y2 + 2x + 4y - 4 = 0 and x2 + y2 + 6x + 2y + 6 = 0
Find the member for which k = 2. Ans. 3x2 + 3y2 + 14x +-8y + 8 = 0.
or 3x2 + 3y2 + 10x + 10y - 2 = 0.
3. Draw the graph of the equations:
x2 + y2 + 4x + 6y - 3 = 0 and x2 + y2 + 12x + 14y + 6 0 = 0. Then
find the equation of the radical axis and draw the axis. Ans. 8x + 8y = -63.