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Fontana Unified School District Every Student Successful | Engaging Schools | Empowered Communities
Offline Distance Learning
Secondary
Honors IM3 May 2020
School Name: _____________ Student ID#: ______________
Math Teacher Name: _____________ Period: ____
May 2020
May 2020
Modeling with Functions
Function Family
Function Name Algebraic Shape of Graph
Linear π¦ = ππ₯ + π
Exponential π¦ = πππ₯
Quadratic π¦ = ππ₯2 + ππ₯ + π
Polynomial π¦ = πππ₯π + ππβ1π₯πβ1 + ππβ2π₯πβ2 + β― π0
May 2020
Rational π¦ =
1
π₯
Absolute Value π¦ = |π₯|
Logarithmic π¦ = ππππ(π₯)
Trigonometric π¦ = π sin(ππ₯)
or
π¦ = π cos (ππ₯)
Radical π¦ = βπ₯π
May 2020
Function Transformation Rules
Examples: The parent function is π¦ = π₯
a. π¦ = π₯ + 2
the function shifted up by 2
b. π¦ = π₯ β 2
the function shifted down by 2
c. π¦ = 2π₯
the function compressed horizontally by 2
d. π = βπ
the function reflected over the y β axis
May 2020
May 2020
Try It:
Graph the following quadratic equations on the grid. The equation π¦ = π₯2 has been graphed for you. For each new
equation explain what the number 3 does to the graph π¦ = π₯2. Pay attention to the y-intercept, the x-intercept(s), and
the rate of change. Identify what changes in the graph and what stays the same.
a. π¦1 = π₯2 + 3
b. π¦2 = π₯2 β 3
c. π¦3 = (π₯ β 3)2
d. π¦4 = (π₯ + 3)2 + 3
e. π¦1 = 3π₯2
Practice Problems: Sketch the graph of the parent function and the graph of the transformed function on the same set of axes.
1.
2.
3. 4.
May 2020
May 2020
Composing and Decomposing
Composing Functions: Applying one function to the results of another. A composite function is created
when one function is substituted into another function.
It can be written as (π β π)(π₯) which means π(π(π₯)). This can be read as β π of π of π₯β
Examples:
1. Given: π(π₯) = 2π₯2 + 1 πππ π(π₯) = π₯ β 4. πΉπππ π(π(π₯)).
π(π(π₯)) = π(π₯ β 4) [π π’ππ π‘ππ‘π’π‘π π₯ β 4 πππ‘π π(π₯)]
= 2(π₯ β 4)2 + 1 [ πΉππ ππ£πππ¦ π₯ ππ π(π₯), π π’ππ π‘ππ‘π’π‘π π₯ β 4]
= 2(π₯2 β 8π₯ + 16) + 1 [ ππππππππ¦ ππ’πππ‘πππ ππ¦ ππ₯πππππππ (π₯ β 4)2]
= 2π₯2 β 16π₯ + 32 + 1 [ π·ππ π‘ππππ’π‘π 2]
π(π(π₯)) = 2π₯2 β 16π₯ + 33 [ππππππππ¦]
2. Given: π(π₯) = 4π₯ + 9 πππ π(π₯) =π₯β9
4. πΉπππ π(π(π₯)).
π(π(π₯)) = π(4π₯ + 9) [π π’ππ π‘ππ‘π’π‘π 4π₯ + 9 πππ‘π π(π₯)]
=(4π₯+9)β9
4 [ πΉππ ππ£πππ¦ π₯ ππ π(π₯), π π’ππ π‘ππ‘π’π‘π 4π₯ + 9]
= 4π₯
4 [ ππππππππ¦ ]
π(π(π₯)) = π₯ [ ππππππππ¦ ]
3. Given: π(π₯) = 4π₯ + 9 πππ π(π₯) =π₯β9
4. πΉπππ π(π(π₯)).
π(π(π₯)) = π(4π₯ + 9) [π π’ππ π‘ππ‘π’π‘π 4π₯ + 9 πππ‘π π(π₯)]
= 4(4π₯ + 9) + 9 [ πΉππ ππ£πππ¦ π₯ ππ π(π₯), π π’ππ π‘ππ‘π’π‘π 4π₯ + 9]
= 16π₯ + 36 + 9 [ ππππππππ¦ ]
π(π(π₯)) = 16π₯ + 45 [ ππππππππ¦ ]
4. Given: π(π₯) = 4π₯ + 9 πππ π(π₯) =π₯β9
4. πΉπππ π(π(3)).
π(π(π₯)) = 16π₯ + 45 [π€π ππππ€ π‘βππ ππππ ππ₯ππππ 3]
π(π(3)) = 16(3) + 45 [π π’ππ π‘ππ‘π’π‘π 3 πππ‘π π₯]
= 48 + 45 [ ππππππππ¦ ]
π(π(3)) = 93 [ ππππππππ¦ ]
May 2020
May 2020
Practice Problems:
1. Let π(π₯) = 2π₯2 β 4 πππ π(π₯) = 5π₯. πΉπππ πππβ πππ π πππππππ¦.
a) (π β π)(1) b) (π β π)(1) c) (π β π)(β2) d) (π β π)(β1)
2. Let π(π₯) =8
π₯β3πππ π(π₯) =
15
π₯+1. πΉπππ πππβ πππ π πππππππ¦.
a) (π(π(π₯)) b) (π β π)(π₯) c) (π(π(π₯)) d) (π(π(π₯))
3. Use your answers for a) and B) in problem 2 to calculate the two problems below.
a) (π(π(β1)) b) (π β π)(3)
May 2020
May 2020
Translating My Composition
Decomposing Functions: is a process by which you can break down one complex function into multiple
smaller functions. By doing this, you can solve for functions in shorter, easier-to-understand pieces. There
may be more than one way to decompose a composite function.
Examples:
Let π(π₯) = π₯ + 5, π(π₯) = π₯2, β(π₯) = 3π₯ πππ π(π₯) = 2π₯. Express each function as a composite of π, π
β, and/or j. 1. π΄(π₯) = π₯4 [Think: What multiple functions composed this?]
The two functions are
g(π₯) = π₯2 and g(π₯) = π₯2
Check:
π(π(π₯)) = π(π₯2)
= (π₯2)2
= π₯4
2. πΆ(π₯) = 3π₯ + 15 [Think: What multiple functions composed this?]
The two functions are
β(π₯) = 3π₯ and π(π₯) = π₯ + 5
Check:
β(π(π₯)) = β(π₯ + 5 )
= 3(π₯ + 5)
= 3π₯ + 15
3. πΆ(π₯) = 3(π₯ + 5)2 [Think: What multiple functions composed this?]
The three functions are
β(π₯) = 3π₯ and π(π₯) = π₯ + 5 and π(π₯) = π₯2,
Check:
β(π(π(π₯)))) = β(π(π₯ + 5 ) [ work inside first- substitute π₯ + 5 into π(π₯)]
= β((π₯ + 5)2) [ For every π₯ in π(π₯), substitute π₯ + 5]
= 3(π₯ + 5)2 [For every π₯ in β(π₯), substitute π(π(π₯)) which is (π₯ + 5)2]
May 2020
May 2020
Practice Problems:
Let π(π₯) = π₯2, π(π₯) = 5π₯, πππ β(π₯) = βπ₯ + 2. Express each function as a composite of π, π and/or β. 1. F(π₯) = π₯4
2. πΆ(π₯) = 5π₯2
3. π(π₯) = π₯ + 2
4. π (π₯) = 5βπ₯ + 10
5. π(π₯) = 25π₯
7. π·(π₯) = ββπ₯ + 2 + 2
8. π΅(π₯) = π₯ + 4βπ₯ + 4
May 2020
May 2020
Different Combinations
SET Problems: Identifying the 2 functions that make up a composite function.
Find functions π and π so that π β π = π»
1. π»(π₯) = βπ₯2 + 5π₯ β 4
2. π»(π₯) = (3 β1
π₯)2
3. π»(π₯) = (3π₯ β 7)4 4. π»(π₯) = |5π₯2 β 78|
5. π»(π₯) = 2
3βπ₯5 6. π»(π) = (tan π)2
7. π»(π₯) = 9(4π₯ β 8) + 1 8. π»(π₯) = β
1
6π₯
May 2020
GO Problems: Finding function values given the graph. Use the graph to find all of the missing values.
1. π(β ) = 8 2. π(β ) = 5
3. π(β ) = -1 4. π(β ) = 0
5. π(β1) = 6. π(0) =
7. π(π₯) = π(π₯) 8. π(π₯) β π(π₯) = 0
9. π(π₯) β π(π₯) = 0 10. π(2) + π(2) =
May 2020