edt-ornek-
TRANSCRIPT
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Örnek:
a) Devrenin çalışma noktalar ını bulunuz.
I Q = -3 – V Q I Q = I RQ – 1 + V Q
I Q = | V Q 2+ V Q | + V Q – 1
-3 – V Q =| V Q2+ V Q | + V Q – 1
V Q2+ 3 V Q + 2, V Q
2+ V Q ≥ 0
| V Q2+ V Q | + 2 V Q + 2=
- V Q2
+ V Q + 2, V Q2
+ V Q < 0
V Q2+ 3 V Q + 2=0, VQ1= -1 V, VQ2 = -2 V (V Q
2+V Q ≥ 0)
- V Q2+ V Q +2=0 VQ3= 2 V, VQ4 = -1 V (V Q
2+V Q < 0)
V Q1 = -1 V, I Q1 = -2 A, V Q2 = -2 V, I Q2 = -1 A
0,01 sin t + –
3 V
v R
+
–
i R
1 A
1 Ω
1 Ω
i R=|v R2+v R|
i
v
+
–
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b) Küçük işaret analizi ile devreyi analiz ediniz.
i R-IRQ ≈ (2vR +1) (v R-VRQ)v R-VRQ
i R + 2 ≈ -1 (v R + 1) R R vi ~~−=
0,01 sin t + –
+i~
1 Ω
1 Ω
i~
v~
+
– -1 Ω