daily check
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Daily Check. Homework Review. GPS Geometry Day 25 (9-11-13). UNIT QUESTION: What special properties are found with the parts of a circle? Standard: MMC9-12.G.C.1-5,G.GMD.1-3 Today’s Question: How can I find a segment length for a piece of a chord? Standard: MMC9-12.G.C.2. - PowerPoint PPT PresentationTRANSCRIPT
Daily Check
Homework Review
UNIT QUESTION: What special properties are found with the parts of a circle?Standard: MMC9-12.G.C.1-5,G.GMD.1-3
Today’s Question:How can I find a segment length for a piece of a chord?Standard: MMC9-12.G.C.2
GPS GeometryDay 25 (9-11-13)
How do you know when two chords are congruent?
LP PMALP = BMP = 90
a. corresponding arcs are
congruentA
B
C
D
M
L
P AD BC
b. equidistant from the center
Flow Chart Proof
AB CDGiven
EA EB EC EDAll radii are congruent
AEB CEDCongruent arcs havecongruent measures
AEB CEDSAS
AB CDCPCTC
2x x + 40
2x = x + 40x = 40
In K, K is the midpoint of RE. If TY = -3x + 56 and US = 4x, find the length of TY.
Y
T
S
Kx = 8
TY = 32
U
RE
A
B
C
D
IF AC is the perpendicular bisector of segment DB, then…
It’s the DIAMETER!!!Arcs DC and BC are congruent!!!
IN Q, KL LZ. IF CK = 2X + 3 and CZ = 4x, find x.
K
Q
C
L
Zx = 1.5
In P, if PM AT, PT = 10, and PM = 8, find AT.
T
AM
P
MT = 6AT = 12
Your turn!
UTV XTW.
Find WX.___________ Find ___________mAB11 130º
Your turn! Find the length of each chord.
CE = _______ LN = _______30 96
Segment Lengths in Circles
Find the lengths of segments of chords
Find the lengths of segments of tangents and secants
a
bc
d ab = cd
part part = part part
9
2
6xx = 3
Solve for x.
Find the length of DB.
8
12
2x
3x
x = 4
DB = 20
A
B
C
D
Find the length of each chord.
x = 8
AC = 13
DB = 14
x5
x - 4
10
A
B
C
D
E A B
C
D
EA • EB = EC • EDoutside whole = outside whole
EA
B
C
D
7 13
4
x
7 (7 + 13) 4(4 + x)=
Ex: 3 Solve for x.
140 = 16 + 4x124 = 4x
x = 31
E
A
B
CD 8
5
6
x
6 (6 + 8) 5(5 + x)=
Ex: 4 Solve for x.
84 = 25 + 5x59 = 5x x = 11.8
E
A
B C
EA2 = EB • ECoutside whole = outside whole
E
A
B C
24
12 x
outside whole = outside whole 242 = 12 (12 + x)576 = 144 + 12x x = 36
Ex: 5 Solve for x.
E
A
B
C15
5
x
outside whole = outside whole x2 = 5 (5 + 15)
x2 = 100x = 10
Ex: 6