chemistry for aggies or “everythin’ i ever needed for chem 111, i learnt in hort 100” a/h 100g...

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Chemistry for Aggies or “Everythin’ I ever needed for CHEM 111, I learnt in HORT 100” A/H 100G J.G. Mexal

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Page 1: Chemistry for Aggies or “Everythin’ I ever needed for CHEM 111, I learnt in HORT 100” A/H 100G J.G. Mexal

Chemistry for Aggiesor

“Everythin’ I ever needed for CHEM 111, I learnt in HORT 100”

A/H 100G

J.G. Mexal

Page 2: Chemistry for Aggies or “Everythin’ I ever needed for CHEM 111, I learnt in HORT 100” A/H 100G J.G. Mexal

Chemistry for Aggies

Stuff ya’ll need to know!

• Woolworth’s 5 and 10 ¢

• Metric units

• Fertilizer calculations

• Irrigation requirements

• pH

Page 3: Chemistry for Aggies or “Everythin’ I ever needed for CHEM 111, I learnt in HORT 100” A/H 100G J.G. Mexal

Metric Scale

• Things to memorize:– M = 1,000,000

– k = 1,000

– c = 0.01 = 1/100

– m = 0.001 = 1/1000 = 0.000001

Page 4: Chemistry for Aggies or “Everythin’ I ever needed for CHEM 111, I learnt in HORT 100” A/H 100G J.G. Mexal

Metric Scale

Yotta Y 1 000 000 000 000 000 000 000 000 1024

Zetta Z 1 000 000 000 000 000 000 000 1021

Exa E 1 000 000 000 000 000 000 1018

Peta P 1 000 000 000 000 000 000 1015

Tera T 1 000 000 000 000 000 1012

Giga G 1 000 000 000 (billion) 109

Mega M 1 000 000 (million) 106

kilo k 1 000 (thousand) 103

hecta h 1 00 (hundred) 102

deca da 10 (ten) 101

1

deci d 0.1 (tenth) 10-1

centi c 0.01 (hundredth) 10-2

milli m 0.001 (thousandth) 10-3

micro µ 0.000 001 (millionth) 10-6

nano n 0.000 000 001 (billionth) 10-9

pico p 0.000 000 000 001 10-12

femto f 0.000 000 000 000 001 10-15

atto a 0.000 000 000 000 000 001 10-18

zepto z 0.000 000 000 000 000 000 001 10-21

yocto y 0.000 000 000 000 000 000 000 001 10-24

Page 5: Chemistry for Aggies or “Everythin’ I ever needed for CHEM 111, I learnt in HORT 100” A/H 100G J.G. Mexal

Chemistry for Aggies Cipherin’ the easy way• Things to memorize:

– M = 1,000,000

– k = 1,000

– c = 0.01 = 1/100

– m = 0.001 = 1/1000 = 0.000001

• Things to help:– 1 m ~ 1 yd

– 1 L ~ 1 qt

– 1 kg ~ 2 lb

Page 6: Chemistry for Aggies or “Everythin’ I ever needed for CHEM 111, I learnt in HORT 100” A/H 100G J.G. Mexal

LengthEnglish Metric

(approx.)

Metric English

(approx.)

1 in 2.5 cm 1 mm 0.04 in

1 ft 30 cm 1 cm 0.4 in

1 yd 0.9 m 1 m 3.3 ft

1 mi 1.6 km 1 km 0.6 mi

Page 7: Chemistry for Aggies or “Everythin’ I ever needed for CHEM 111, I learnt in HORT 100” A/H 100G J.G. Mexal

AreaEnglish Metric

(approx.)

Metric English

(approx.)

1 in2 6.5 cm2 1 cm2 0.16 in2

1 ft2 0.09 m2 1 m2 1.2 yd2

1 yd2 0.8 m2 1 m2 11 ft2

1 mi2 2.6 km2 1 km2 0.4 mi2

1 acre 0.4 ha 1 ha 2.5 ac

Page 8: Chemistry for Aggies or “Everythin’ I ever needed for CHEM 111, I learnt in HORT 100” A/H 100G J.G. Mexal

VolumeEnglish Metric

(approx.)

Metric English

(approx.)

1 in3 16 mL 1 mL 0.06 in3

1 ft3 0.03 m3 1 m3 35 ft3

1 yd3 0.76 m3 1 m3 1.3 yd3

1 fl oz 30 mL 1 mL 0.03 fl oz

1 cup 0.24 L 1 L 4.2 cups

1 pt 0.47 L 1 L 2.1 pt

1 qt 0.95 L 1 L 1.06 qt

1 gal 3.8 L 1 L 0.26 gal

Page 9: Chemistry for Aggies or “Everythin’ I ever needed for CHEM 111, I learnt in HORT 100” A/H 100G J.G. Mexal

MassEnglish Metric

(approx.)

Metric English

(approx.)

1 oz 28 g 1 g 0.035 oz

1 lb 454 g 1 kg 2.2 lb

1 lb 0.454 kg 1 ton 1.1 short ton

1 ton (short) 0.9 metric ton 1 ton 1 long ton

1 ton (long) 1 metric ton

Page 10: Chemistry for Aggies or “Everythin’ I ever needed for CHEM 111, I learnt in HORT 100” A/H 100G J.G. Mexal

Chemistry for Aggies

Doin’ it the hard way

• How many square inches in a square yard?

• How many ounces in a gallon?

• How many square feet in an acre?

• The K-Mart parking lot is one acre in size and receives 1” or rain. How many gallons will run off into the sewer?

Page 11: Chemistry for Aggies or “Everythin’ I ever needed for CHEM 111, I learnt in HORT 100” A/H 100G J.G. Mexal

Chemistry for Aggies

Why use metric units?

• Metrics involves the judicious movement of zeros to determine the answer. There are no complicated conversions to learn.

• RoT: If the answer looks right--it probably is!

• The question you must always ask yourself is: “Does the answer make sense?”

Page 12: Chemistry for Aggies or “Everythin’ I ever needed for CHEM 111, I learnt in HORT 100” A/H 100G J.G. Mexal

Chemistry for Aggies Cipherin’ the easy way• How many cm2 in a m2?

• How many mL in a L?

• The WalMart parking lot is 1 ha in size and receives 1 cm of rain. How many L of water will run off into the sewer?

Page 13: Chemistry for Aggies or “Everythin’ I ever needed for CHEM 111, I learnt in HORT 100” A/H 100G J.G. Mexal

Chemistry for Aggies Rule of Thumb• 1 g = 1 mL = 1 cc or 1 cm3

• This rule really holds only for pure water at 4OC. But remember, this is Chemistry for Aggies, and this estimate is “close enuf”.

• This will allow you convert from weight (g) to volume (mL) to length (cm).

Page 14: Chemistry for Aggies or “Everythin’ I ever needed for CHEM 111, I learnt in HORT 100” A/H 100G J.G. Mexal

Chemistry for Aggies Cipherin’ the easy way• 1 m = 100 cm = 1,000 mm

– 1 km = 1,000 m– 1 ha = 100 m x 100 m

• 1 L = 1,000 mL

• 1 g = 1,000 mg– 1 kg = 1,000 g– 1,000 kg = 1 ton = 1 Mg

Page 15: Chemistry for Aggies or “Everythin’ I ever needed for CHEM 111, I learnt in HORT 100” A/H 100G J.G. Mexal

Chemistry for Aggies Cipherin’ the easy way• How many cm2 in a m2?

• Answer:= 1 m = 100 cm= 1 m x 1 m = 100 cm x 100 cm= 1 m2 = 10,000 cm2

Page 16: Chemistry for Aggies or “Everythin’ I ever needed for CHEM 111, I learnt in HORT 100” A/H 100G J.G. Mexal

Chemistry for Aggies Cipherin’ the easy way• How many mL in a L?

• Answer:= 1 L = 1,000 mL

Page 17: Chemistry for Aggies or “Everythin’ I ever needed for CHEM 111, I learnt in HORT 100” A/H 100G J.G. Mexal

Chemistry for Aggies Cipherin’ the easy way

• The WalMart parking lot is 1 ha in size and receives 1 cm or rain. How many L of water will run off into the sewer?

• Answer:

Page 18: Chemistry for Aggies or “Everythin’ I ever needed for CHEM 111, I learnt in HORT 100” A/H 100G J.G. Mexal

Chemistry for Aggies Cipherin’ the easy way

• The WalMart parking lot is 1 ha in size and receives 1 cm or rain. How many L of water will run off into the sewer?

• Answer:* 1 ha = 100 m x 100 m = (100 m x 100 cm/m) x

(100 m x 100 cm/m) = 100,000,000 cm2

* 1 cm of rain on 100,000,000 cm2 = 100,000,000 cm3

* 100,000,000 mL x 1 L/ 1,000 mL = 100,000 L

Page 19: Chemistry for Aggies or “Everythin’ I ever needed for CHEM 111, I learnt in HORT 100” A/H 100G J.G. Mexal

Chemistry for Aggies Woolworth’s 5 and 10 ¢• To estimate the temperature in OC,

beginning at the freezing point of water (32OF and 0OC), the Celsius scale changes about 5O for every 10O change in the Fahrenheit scale.

Page 20: Chemistry for Aggies or “Everythin’ I ever needed for CHEM 111, I learnt in HORT 100” A/H 100G J.G. Mexal

Chemistry for Aggies Woolworth’s 5 and 10 ¢

OF

OC (approximate)

OC (exact) 10 -10 -12 20 - 5 - 7

32 (30) 0 0

40 5 4

50 10 10

60 15 16

70 20 21

80 25 27

90 30 32

100 35 38

Page 21: Chemistry for Aggies or “Everythin’ I ever needed for CHEM 111, I learnt in HORT 100” A/H 100G J.G. Mexal

Chemistry for Aggies More Cipherin’ the easy way• The Rio Grande has 300 ppm dissolved

salts. If a farmer applies 5 cm of irrigation water to one ha, how may tons of salts is the farmer adding?

• Answer:

Page 22: Chemistry for Aggies or “Everythin’ I ever needed for CHEM 111, I learnt in HORT 100” A/H 100G J.G. Mexal

Chemistry for Aggies More Cipherin’ the easy way• The Rio Grande has 300 ppm dissolved salts. If a

farmer applies 5 cm of irrigation water to one ha, how may tons of salts is the farmer adding?

• Answer: Calculate the amount of water

* 1 ha = 100 m x 100 m = (100 m x 100 cm/m) x

(100 m x 100 cm/m) = 100,000,000 cm2

* 5 cm of water on 100,000,000 cm2 = 500,000,000 cm3

* 500,000,000 mL x 1 L/ 1,000 mL = 500,000 L

Page 23: Chemistry for Aggies or “Everythin’ I ever needed for CHEM 111, I learnt in HORT 100” A/H 100G J.G. Mexal

Chemistry for Aggies More Cipherin’ the easy way

• Now calculate the amount of salts in the water:

300 ppm is 300 mg/L (How do I know this?)

300 mg/L x 500,000 L = 150,000,000 mg

150,000,000 mg x 1 g/1,000 mg x 1 kg/1,000 g x 1 t/1,000 kg =

150,000 g

150 kg

0.15 t of salt

Page 24: Chemistry for Aggies or “Everythin’ I ever needed for CHEM 111, I learnt in HORT 100” A/H 100G J.G. Mexal

Chemistry for Aggies

%, ppm, mg/L

• % = parts/100

• ppm = parts/million

• ppb = parts/billion (hazardous materials)• mg/L= 0.001 g/1,000 g (or 1,000 mL)

= 1 g/1,000,000 g

= ppm

Page 25: Chemistry for Aggies or “Everythin’ I ever needed for CHEM 111, I learnt in HORT 100” A/H 100G J.G. Mexal

Chemistry for Aggies

%, ppm, mg/L

• The atmosphere is 21% oxygen and 310 ppm carbon dioxide.

• Express carbon dioxide in %

• Express oxygen in ppm

Page 26: Chemistry for Aggies or “Everythin’ I ever needed for CHEM 111, I learnt in HORT 100” A/H 100G J.G. Mexal

Chemistry for Aggies

%, ppm, mg/L

• The atmosphere is 21% oxygen and 310 ppm carbon dioxide.

• Express carbon dioxide in %= _____310 ____31 ___3.1 _0.31 0.031 or

0.031%

1,000,000 100,000 10,000 1,000 100

• Express oxygen in ppm= 21 210 2,100 21,000 210,000 or 210,000 ppm

100 1,000 10,000 100,000 1,000,000

Page 27: Chemistry for Aggies or “Everythin’ I ever needed for CHEM 111, I learnt in HORT 100” A/H 100G J.G. Mexal

Chemistry for Aggies

%, ppm, mg/L

• How much nutrient is in a fertilizer?• Example: N in ammonium sulfate• Answer:Calculate molecular weight

– ammonium sulfate = (NH4)2SO4

– H = 1, N = 14, O = 16, S = 32

– What % is N of AmSul?

– is / of = 14 + 14 / 28+8+32+64 = 28/132

– N% = 21%

Page 28: Chemistry for Aggies or “Everythin’ I ever needed for CHEM 111, I learnt in HORT 100” A/H 100G J.G. Mexal

Chemistry for Aggies

%, ppm, mg/L• Fertigate with 150 ppm N , using ammonium sulfate

(NH4)2SO4, which is 21% N. The injector dilutes the stock solution 100:1. How much fertilizer should be added to the stock solution?

• Answer: How much nitrogen do you need?

150 mg N/L-I x 100 -I / 1L-S = 15,000 mg N/L-S

= 15 g N/ L-S

How much ammonium sulfate do you need?

• RoT = % = is/of 21% = 15 g/ ? .21 x ? = 15 g

? = 15 / .21 ? = 71 g AmSul

Page 29: Chemistry for Aggies or “Everythin’ I ever needed for CHEM 111, I learnt in HORT 100” A/H 100G J.G. Mexal

Chemistry for Aggies

%, ppm, mg/L

• Conclusion: You will need to add 71 g of ammonium sulfate per liter of stock solution to deliver 150 ppm N from your 1:100 injection fertigater.

Page 30: Chemistry for Aggies or “Everythin’ I ever needed for CHEM 111, I learnt in HORT 100” A/H 100G J.G. Mexal

More problems

• A cabbage crop is 1.5% N. If 1 ha yields 2,000 boxes of 24 heads each weighing 0.1 kg (DW), how much ammonium nitrate should be added to meet the minimum nitrogen requirement?– Hints: H = 1, N = 14, O = 16

Page 31: Chemistry for Aggies or “Everythin’ I ever needed for CHEM 111, I learnt in HORT 100” A/H 100G J.G. Mexal

More problems

• A homeowner irrigates the yard with city water (150L/min). If his yard is 800 m2 (40 m x 20 m), how long will it take to apply 1 cm?

Page 32: Chemistry for Aggies or “Everythin’ I ever needed for CHEM 111, I learnt in HORT 100” A/H 100G J.G. Mexal

More problems

• Your roommate decides to kill you for eating all the Oreos. The only thing toxic in the house is some A-rest from your HORT 100 lab. If the plant growth regulator A-rest is toxic to humans at a rate of 5000 mg A-rest to 1 kg human body weight, what % A-rest will be found in your body at the time of death?

• Alternatively, could he force feed you Oreos (sucrose LD50 = 5,440 mg/kg)?

Page 33: Chemistry for Aggies or “Everythin’ I ever needed for CHEM 111, I learnt in HORT 100” A/H 100G J.G. Mexal

More problems

• How much ammonium nitrate should be applied to fertilize a crop at the 35 kg N/ha rate. Ammonium nitrate = NH4NO3, N = 14, H = 1, O = 16, S = 32, K = 39.

• How much hydrogen are you applying?

Page 34: Chemistry for Aggies or “Everythin’ I ever needed for CHEM 111, I learnt in HORT 100” A/H 100G J.G. Mexal

More problems

• A farmer applies 40 t dry cow manure to 1 ha. If the manure contains 1% N and 7% salts (Ca, Mg, K, Na, etc):

Hint: 1 t = 1,000 kg, 1 ha = 100 m2 x 100 m2

• How much N is added to the field?• How much total salt is added?

Page 35: Chemistry for Aggies or “Everythin’ I ever needed for CHEM 111, I learnt in HORT 100” A/H 100G J.G. Mexal

pH

• pH is the measure of the hydrogen ion concentration in solution

• pH is calculated as = -- log [H+]

= -- log (10-7 g H+ /LH20)

= -- (--7)

= -- 7 (neutral)Neutral means there are equal amounts of H+ and OH-

Page 36: Chemistry for Aggies or “Everythin’ I ever needed for CHEM 111, I learnt in HORT 100” A/H 100G J.G. Mexal

pH

• pH 6 = 0.000001 g H+ / L = 10-6 g H+ /L• pH 7 = 0.0000001 g H+ / L = 10-7 g H+ /L• pH 8 =0.00000001 g H+ / L = 10-8 g H+ /L

• Change from pH 8 to pH 6?– pH 6 = 0.00000100 g H+ / L = 10-6 g H+ /L– pH 8 =-- 0.00000001 g H+ / L = -10-8 g H+ /L– Add 0.00000099 g H+ / L = 9.9 x 10-7 g H+ /L

Page 37: Chemistry for Aggies or “Everythin’ I ever needed for CHEM 111, I learnt in HORT 100” A/H 100G J.G. Mexal

pH

• Therefore, to change 1L of pH 8 solution to pH 6, you need to add 0.00000099 g H+ or add 1 L of pH 6.004 solution.