basic chemistry copyright © 2011 pearson education, inc. 1 chapter 12 solutions 12.4 percent...
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Basic Chemistry Copyright © 2011 Pearson Education, Inc.1
Chapter 12 Solutions
12.4 Percent Concentration
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The concentration of a solution • is the amount of solute dissolved in a specific
amount of solution
amount of soluteamount of solution
• as percent concentration describes the amount of solute that is dissolved in 100 parts of solution
amount of solute100 parts solution
Percent Concentration
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The mass percent (m/m)
• concentration is the percent by mass of solute in a solution
Mass percent (m/m) = mass of solute x 100% mass of solute + mass of solvent
• is the g of solute in exactly100 g of solution Mass percent = g of solute x 100%
100. g of solution
Mass Percent
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Mass percent (%m/m) is calculated from the grams of solute (g KCl) and the grams of solution (g KCl solution).
g of KCl = 8.00 g
g of solvent (water) = 42.00 g
g of KCl solution = 50.00 g
8.00 g KCl (solute) x 100 = 16.0% (m/m)
50.00 g KCl solution
Calculating Mass Percent
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Mass of Solution
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Calculating Solution Concentration
6
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A solution is prepared by mixing 15.0 g of Na2CO3 and 235 g of H2O. Calculate the mass percent (m/m) of the solution.
A. 15.0% (m/m) Na2CO3
B. 6.38% (m/m) Na2CO3
C. 6.00% (m/m) Na2CO3
Learning Check
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STEP 1 Determine quantities of solute and solution.
Mass of solute = 15.0 g of Na2CO3
Mass of water = 235 g of water
Mass of solution = 250. g of Na2CO3 solution
STEP 2 Write the % concentration expression.
Mass percent (m/m) = grams of Na2CO3 x 100% grams of Na2CO3 solution
Solution
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STEP 3 Substitute solute and solution quantities into the expression
Mass percent (m/m) = 15.0 g Na2CO3 x 100%
250. g Na2CO3 solution
= 6.00% (m/m) Na2CO3 solution
(C)
Solution (continued)
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The volume percent (v/v) is
• percent volume (mL) of solute (liquid) to volume (mL) of solution
Volume percent(v/v) = mL of solute x 100% mL of solution
• solute (mL) in 100 mL of solution
Volume percent (v/v) = mL of solute x 100% 100 mL of solution
Volume Percent
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A volume percent (v/v) solution is prepared by
• using a specific volume (mL) of solute (liquid)
• adding water to the volume line
Volume Percent
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Percent Conversion Factors
• Two conversion factors can be written for each type of percent value.
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Write two conversion factors for each solution.
A. 8.50% (m/m) NaOH
B. 5.75% (v/v) ethanol
Learning Check
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A. 8.50% (m/m) NaOH solution
100 g of NaOH solution = 8.50 g of NaOH
8.50 g NaOH and 100 g NaOH solution
100 g NaOH solution 8.50 g NaOH
B. 5.75% (v/v) ethanol solution
100 mL of ethanol solution = 5.75 mL of ethanol
5.75 mL ethanol and 100 mL solution
100 mL solution 5.75 mL ethanol
Solution
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Using Concentration to Calculate Mass or Volume
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How many grams of NaCl are needed to prepare
225 g of a 10.0% (m/m) NaCl solution?
STEP 1 State the given and needed quantities. Given 225 g of NaCl solution; 10.0% (m/m) NaCl solution
Need grams of NaCl
STEP 2 Write a plan to calculate mass or volume.
grams of NaCl solution grams of NaCl
Example of Using Percent Factors
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STEP 3 Write equalities and conversion factors. 100 g of NaCl solution = 10.0 g of NaCl
10.0 g NaCl and 100 g NaCl solution 100 g NaCl solution 10.0 g NaCl
STEP 4 Set up problem to calculate mass or volume.
225 g NaCl solution x 10.0 g NaCl = 22.5 g of NaCl 100 g NaCl solution
Example of Using Percent Factors (continued)
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How many grams of NaOH are needed to prepare 75.0 g of a 14.0% (m/m) NaOH solution?
A. 10.5 g of NaOHB. 75.0 g of NaOH
C. 536 g of NaOH
Learning Check
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STEP 1 State the given and needed quantities.
Given 75.0 g of NaOH of a 14.0% (m/m) solution
Need grams of NaOH
STEP 2 Write a plan to calculate mass or volume.
grams of NaOH solution grams of NaOH
Solution
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STEP 3 Write equalities and conversion factors. 100 g of NaOH solution = 14.0 g of NaOH 14.0 g NaOH and 100 g solution 100 g solution 14.0 g NaOH
STEP 4 Set up problem to calculate mass or volume.
75.0 g solution x 14.0 g NaOH = 10.5 g of NaOH (A)
100 g solution 14.0 % (m/m) factor
Solution (continued)
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How many milliliters of a 5.75% (v/v) ethanol solution can be prepared from 2.25 mL of ethanol?
A. 2.56 mL
B. 12.9 mL
C. 39.1 mL
Learning Check
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STEP 1 State the given and needed quantities.
Given 2.25 ml of ethanol
5.75% (v/v) ethanol solution
Need milliliters of ethanol solution
STEP 2 Write a plan to calculate mass or volume.
mL of ethanol mL of ethanol solution
Solution
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STEP 3 Write equalities and conversion factors. 100 mL of ethanol solution = 5.75 mL of ethanol 5.75 mL ethanol and 100 mL solution 100 mL solution 14.0 mL ethanol
STEP 4 Set up problem to calculate mass or volume.
5.75% (v/v) inverted
2.25 mL ethanol x 100 mL ethanol solution 5.75 mL ethanol
= 39.1 mL of solution (C)
Solution (continued)