A jogger runs 145m in a direction 20.0 degrees east of north (vector A), and then runs 105m in a direction 35.0 degrees south of east (vector B). Using components, determine the magnitude

and direction of the resultant vector C for these two displacements.

A jogger runs 145m in a direction 20.0 degrees east of north (vector A), and then runs 105m in a direction 35.0 degrees south of east (vector B). Using components, determine the magnitude and

direction of the resultant vector C for these two displacements.

A jogger runs 145m in a direction 20.0 degrees east of north (vector A), and then runs 105m in a direction 35.0 degrees south of east (vector B). Using components, determine the magnitude and

direction of the resultant vector C for these two displacements.

Sin 20 = Ax / 145Ax = 49.6 m

Cos 35 = Bx/105Bx = 86.0 m

Ax + Bx = 135.6 m

cos 20 = Ay / 145Ay = 136.2 m

sin 35 = Bx/105By = 60.2 m

Ay - By = 75.8 m

135.62 + 75.82 = C2

C = 155m

tan angle = 75.8/135.6angle = 29 degrees