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2006 Copyright ОАО «ЦКБ «БИБКОМ» & ООО «Aгентство Kнига-Cервис»

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  • . ..

    ..

    -

    2006

    Copyright & A K-C

  • 517.925

    1673

    91

    -

    . 2006 .

    :

    - .-. , . .. ;

    , .. :

    / .. ; . . -. :

    91 , 2006. 104 .

    ISBN 5-8397-0491-1 (978-5-8397-0491-6)

    -

    . -

    . -

    ,

    .

    .

    -

    ( ) 010100 010200 -

    .

    . 14. .: 32 .

    517.925

    1673

    ISBN 5-8397-0491-1

    c (978-5-8397-0491-6)

    . .. , 2006

    c .., 2006

    Copyright & A K-C

  • 5

    1. 7

    1.1. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 7

    1.1.1. . . . . . . . . . . . . 8

    1.2. . . . . . . . . . . . . . . . . . . . . . . . . . 15

    1.2.1. . . . . . . . . . . . . . . . . 18

    1.2.2. . . . . . . . . . . . . . . . . . . . . . . 20

    1.3. . . . . . . . . . . . . . . . . . . . . . . . . 22

    1.4. . . . . . . . . . . . . . . . . . . . . . . . 31

    1.5.

    . . . . . . . . . . . . . . . . . . . . . . . 38

    2. 45

    2.1. . . . . . . . . . . . . . . . . . . . . . 45

    2.2. 3

    . . . . . . . . . . . . . . . . . . . . . 53

    2.3. f(x) = 4x(1 x) . . . . . . . . . . . . . . 582.4. f(x, r) = rx(1 x) r > 4 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 692.4.1. . . . 73

    2.4.2. 2 f(x, r) r > 2 +

    5 . . . . . . . . . . . . . . . . . . . . . . . . . 76

    79

    1. . . . . . . . . 79

    2.

    . . . . . . . . . . . . . . . . . . . . . . . 84

    3.

    f(x, r) = rx(1 x) r > 4 . . . . . . . . . . . . 883

    Copyright & A K-C

  • 4

    4. - . 93

    5. 3 . . . . . . . . . . . . . . . 95

    6. . . . . . . . . 95

    7. . . . . . . . . . . . . . . . . 99

    102

    Copyright & A K-C

  • ,

    . 3 4 , -

    , -

    . 25

    ,

    .

    2 , 9 , -

    .

    ,

    , . -

    , , -

    .

    . , -

    1. - , -

    .

    . ,

    k . -

    . -

    ,

    .

    -

    f(x, r) = rx(1 x) r 0 r > 4. , ,

    . f(x) = 4x(1x) . -

    , -

    . f(x) = rx(1x) r > 4. - .

    f(x) = rx(1 x) r > 2 +5. , -

    ,

    -

    f(x) = rx(1x) 4 < r < 2+5,

    Copyright & A K-C

  • 6 - ,

    - , , -

    .

    .

    . -

    . -

    . - , (

    ) .

    .. -

    .

    Copyright & A K-C

  • 1.

    1.1.

    -

    xn+1 = f(xn), n = 0, 1, . . . ,

    f(x) , R. x0 R, f(x), O(x0)

    x0, f(x0), f(f(x0)), f(f(f(x0))), . . . (1.1)

    ,

    f(x) = kx(k > 0). x0 R

    x0, kx0, k2x0, . . . , k

    nx0, . . .

    k < 1, x0 6= 1 n . k > 1, . n = 1, O(x0) x0:

    x0, x0, . . .

    , , ,

    , O(x0) n, .. (1.1) x0. , f(x) = sin x, ( )

    0 n.7

    Copyright & A K-C

  • 8

    1.1.1.

    . -

    x, - R () I . f(x) , f(x) 6= f(y), x 6= y. f : I J , f1(y)(y = f(x), x = f1(y)). , f(x) = x3, f1(x) = 3

    x. R R. f(x) = tg x, f1(x) = arctg x. f(x) : (pi/2, pi/2) R, f1(x) : R (pi/2, pi/2). f(x) , - . , f(x) = tg x (pi/2, pi/2) R. f(x) f(x) - , f(x) . ,f(x) = tg x , f(x) = x3 , , f1(x) = 3

    x - x = 0. C f(x) g(x) f(g(x)) = f(x) g(x), n f(x)

    f (n)(x) = f(x) f(x) f(x) n

    .

    f1(x),

    f (n)(x) = f1(x) f1(x) f1(x) n

    .

    (

    ):

    [f(g(x))] = [f g] = f (g(x))g(x).

    , , g(x) = f (n1)(x),

    [f (n)(x)] = f (f (n1)(x))f (f (n2)(x)) . . . f (f(x))f (x).

    .

    . f(x) : [a, b] R - , c [a, b],

    f(b) f(a) = f (c)(b a).

    Copyright & A K-C

  • 9

    1. f(x) [a, b],

    |f(x) f(y)| K|x y|, x, y [a, b].

    , f (x) [a, b] : |f (x)| K. . f : [a, b] R ., f(a) = u, f(b) = v. u < z < v c, a c b , f(c) = z. 2. I = [a, b] f : I I -. a c b , f(c) = c. ( f(x) f(x).)

    . g(x) = f(x) x. g(x) I. f(a) > a, f(b) < b ( a b f(x)). g(a) > 0, g(b) < 0. c, g(c) = 0. , f(c) = c.

    . I = [a, b],f : I I. f(x) I,

    |f(x) f(y)| q|x y|, x, y I, q < 1. - , I , .. .

    ( ). f : I I f(x) I. f(x) I.

    , -

    () f(x).. x0 -

    x0, x1 = f(x0), x2 = f(x1), . . . , xn = f(xn1), . . . (1.2)

    , (1.2) x I. ,

    |x2 x1| = |f(x1) f(x0)| q|x1 x0| = q|f(x0) x0|,

    Copyright & A K-C

  • 10

    |x3 x2| = |f(x2) f(x1)| q|x2 x1| q2|f(x0) x0|,

    |xn+1 xn| = |f(xn) f(xn1)| qn|f(x0) x0|.,

    |xn+p xn| |xn+p xn+p1|+ |xn+p1 xn+p2|+ + |xn+2 xn+1|++|xn+1 xn| (qn+p + + qn)|f(x0) x0| =

    =qn qn+p1

    1 q |f(x0) x0|. q < 1,

    |xn+p xn| < qn

    1 q |f(x0) x0|, , |xn+p xn| 0 n (1.2) x I. , f(x) = x. ,

    |x f(x)| |xn x|+ |xn f(x)| = |xn x|+ |f(xn1) f(x)| |xn x|+ q|xn1 x|. > 0 n

    |xn x| < 2, |xn1 x| <

    2.

    ,

    |x f(x)| < . > 0 ,

    |x f(x)| = 0 x = f(x). . -

    x, y, f(x) = x, f(y) = y.

    |x y| = |f(x) f(y)| q|x y|. q < 1. |x y| = 0. , x = y. (1.2)

    . ,

    |x1 x| = |f(x0) f(x)| q|x0 x|, |x2 x| q2|x0 x|.

    Copyright & A K-C

  • 11

    ,

    |xn x| qn|x0 x|., (1.2) x co c - q., , -

    f (x) |f (x)| q < 1 x I. x f(x).

    ( ). -

    f(x) x

    |f (x)| = q < 1. xn = f(xn1) (n = 0, 1, . . . ) c x, x0 x

    .

    |xn x| (q + )n|x0 x|, (1.3) (q + < 1).

    . . - > 0, |x0 x| <

    |f(x0) f(x) f (x)(x0 x)| |x0 x|. |x0 x| <

    |f(x0) x| |f(x0) f(x) f (x)(x0 x)|++ |f (x)(x0 x)| (q + )|x0 x|.

    (1.4)

    q+ < 1, x1 = f(x0) x, x0 |x1 x| < . (1.4) x1, x2, . . . , xn, - (1.3).

    . (1.3) , (1.2)

    x , f (x) = 0.

    F (x, z), z . , F (x, z) |x x0| , |z z0| . F (x, z), z, ( ), z |z z0|

    |F (x, z) F (y, z)| q|x y|, |x x0| , |y x0| ,

    Copyright & A K-C

  • 12

    q < 1 q z. F (x, z) z |x x0| . -

    |x x0| x = x(z) x = F (x, z).

    f(x, z), |x x0| b, |z z0| a.

    f(x0, z0) = 0,

    .. x0 f(x, z) = 0 (1.5)

    z = z0. z, z0, x0 x(z) (1.4), , (1.4)

    x(z). -

    , .

    . f(x, z) - :

    1) f(x, z) x, z |x x0| b,|z z0| a f(x0, z0) = 0,2) fx(x, z), - (x0, z0),3) fx(x0, z0) 6= 0. , > 0, z

    |z z0| (1.5) |x x0| x(z). x(z) |z z0| ..

    x = x [fx(x0, z0)]1f(x, z) (1.5). , -

    F (x, z) = x [fx(x0, z0)]1f(x, z) , > 0 |x x0| |zz0| . x(z). ,

    Fx(x, z) = 1 [fx(x0, z0)]1fx(x, z)

    Copyright & A K-C

  • 13

    . Fx(x0, z0) = 0, > 0, |x x0| , |z z0|

    |Fx(x, z)| q < 1. F (x0, z0) = x0, , |z z0|

    |F (x0, z) x0| (1 q).

    |F (x, z) x0| |F (x, z) F (x0, z)|+ |F (x0, z) x0| q|x x0|+ (1 q) q + (1 q) = ., F (x, z) |xx0| |zz0| . z

    |F (x, z) F (y, z)| q|x y| (|x x0| , |y x0| ). x(z) . - x(z) z1 |z z0| . ,

    |x(z1) x(z)| = |F (x(z1), z1) F (x(z), z)|

    |F (x(z1), z1) F (x(z1), z)|+ |F (x(z1), z) F (x(z), z)| |F (x(z1), z1) F (x(z1), z)|+ q|x(z1) x(z)|,

    |x(z1) x(z)| 11 q |F (x

    (z1), z1) F (x(z1), z)|.

    F (x, z) . . f(x, z) = x2 + z2 1. -

    f(x, z) = x2 + z2 1 = 0

    x, z. f(x0, z0) = 0 z0 > 0 ( (x0, z0) ), fz(x0, z0) = 2z0 6= 0. , z(x) ,

    f(x, z(x)) = 0

    x, x0. z(x) z =

    1 x2. f(x, y) = x5y4xy5 yx2+1. ,

    f(1, 1) = 0, fy(1, 1) = 2 6= 0.

    Copyright & A K-C

  • 14

    y = p(x) , f(x, p(x)) = 0, - 1. y = p(x) .

    . -

    fz(x, z) (x0, z0), x(z) -,

    dx(z)dz

    = fz(x, z)fx(x, z)

    . (1.6)

    f(x(z), z) 0, - (1.6).

    x(z) . - fz(x, z) fx(x, z), f(x, z)

    f(x+ h, z + k) = f(x, z) + hfx(x, z) + kfz(x, z) + 1h+ 2k, (1.7)

    1 2 0 h k. (x, z), (x+h, z+k), , x = x(z), x + h = x(z + k). f(x, z) = 0,f(x+ h, z + k) = 0 (1.7)

    0 = hfx(x, z) + kfz(x, z) + 1h+ 2k. (1.8)

    x(z) , k 0 h 0 1 0 2 0. (1.8) kfx(x, z) 6= 0, (

    1 +1fx

    )h

    k+fzfx

    +2fx

    = 0.

    k 0,

    limk0

    h

    k+fzfx

    = 0.

    limk0

    h

    k= lim

    k0x(z + k) x(z)

    k=dx(z)dz

    .

    x(z) .

    Copyright & A K-C

  • 1.2. 15

    1.2.

    .

    1.1. x O(x) - l,

    f (l)(x) = x, f (j)(x) 6= x 0 < j < l. 2 x0, x1 = f(x0)

    (f (2)(x0) = x0, f(2)(x1) = x1). 3 x0, x1 = f(x0), x2 = f(x1) = f

    (2)(x0). l l . . f(x) = x3 0, 1 1 . f(x) = x2 1

    152 , 0,1 2.

    1.2. x , f (i)(x) i f(x)., f(x) = x2 x = 1 , x = 1 , f(1) = 1. f(x) == x2 1 1 , f(1) = 0, ( ) 2. 1.3. x0 f(x) -, U , fU U limn f

    (n)(x) = x0 x U . 1.4. x0 f(x) -, U , U \{x0} , .. x U \{x0} n = n(x), f (n)(x) / U . 1.1. x0 f(x)

    |f (x0)| < 1, x0 . |f (x0)| > 1, x0 .. |f (x0)| < 1, > 0, |f (x)| q < 1 x [x0 , x0 + ].

    |f(x) x0| = |f(x) f(x0)| q|x x0|.

    , f(x) [x0 , x0 + ] f(x) x0, x. ,

    |f (n)(x) x0| qn|x x0|.

    Copyright & A K-C

  • 16

    f (n)(x) x0 n. x0 . |f (x0)| > 1, > 0, |f (x)| q > 1 x [x0, x0+].

    |f(x) x0| = |f(x) f(x0)| q|x x0| > |x x0|. f(x) [x0 , x0 + ], , ,

    |f (n)(x) x0| qn|x x0|. , n, f (n)(x) / [x0 , x0 + ]. . f(x) = x3 f (x) = 3x2. , x0 = 0 f(x) , 1, 1 . , f(x) = x21 x0,1 =

    152 .

    , , -

    |f (x)| = 1. , f(x) = xa(x)3 x = a > 0 , f () = 1. 1.5. x0 l f(x) , x0 f

    (l)(x) . ,

    x0 f(l)(x) .

    1.1 .

    1.2. x0 l f(x) , ddxf (l)(x0)

    < 1, , ddxf (l)(x0)

    > 1. = ddxf

    (l)(x0) - (). ,

    d

    dxf (l)(x0) = f

    (f (l1)(x0))f (f (l2)(x0)) f (x0).

    x0, x1 = f(x0), . . . ,xl = f

    (l1)(x0). - , 1.2,

    Copyright & A K-C

  • 17

    .

    , .

    ,

    .

    . f(x) = x2 1 0,1 , d

    dxf (2)(0) = f (0)f (1) = 0.

    f(x), ,

    .

    1.

    ) f(x) = 2x x2,) f(x) = 2x 2x2,) f(x) = 2, 44x x3,) f(x) = arctan x,

    ) f(x) =ax2 + bx(1 x)

    ax2 + 2bx(1 x) + c(1 x)2 , 0 x 1, b > a, b > c.e) f(x) = 1 +

    3 + x, x+ 3 0.2.

    f(x) =2x

    1 + x3.

    2?

    3. , R - 2. ,

    2.

    4. 2 -

    ) f(x) = 3, 2x 3, 2x2,) f(x) = 2, 2x3 + 1, 2x.)

    f(x) =

    {2x, 0 x 1/2,2 2x, 1/2 x 1.

    Copyright & A K-C

  • 18

    ) F (x) = x+tf(x), t > 0,

    f(x) =

    { x, x 0,x, x > 0.) f(x) = (c 1/2)x2 + (1/2 2c)x+ c, 0 < c 1.5. 2 3 - f(x) = 1 2|x|.6. -

    f(x) =

    { 13x+

    23 +

    13p , 0 x 1 1p ,

    p px, 1 1p x 1, p > 1. 2 3.

    1.2.1.

    xn+1 = f(xn), n = 0, 1, . . . , (1.9)

    f(x) : A A . h(x) , - B A. (1.9) :

    xn = h(yn).

    h(yn+1) = f(h(yn)),

    yn+1 = h1(f(h(yn))) = g(yn), n = 0, 1, . . . (1.10)

    , g = h1 f h B B.

    x0, f(x0), f(2)(x0), . . .

    (1.9) (1.10):

    y0 = h1(x0), y1 = h1(f(h(x0))), . . . .

    x0 f(x), y0 = h1(x0) g(x). x0 l f(x)(f (l)(x0) = x0),

    (h1f(h(y0))(l) = h1f (l)(h(y0)) = y0,

    Copyright & A K-C

  • 19

    .. y0 l g(y). , y0 g(y), x0 = h

    1(y0) f(x).

    1.6. (1.9) (1.10) -

    , f(x) g(y) = h1(f(h(y)) .

    , f : A A g : B B -, h : A B , h g = f h. -

    . x0 f(x) , y0 g(y) . h(y) ,

    h g(l) = f (l) h

    ,

    f(x) g(y) . x0 , f (x0) = 0 ( f(x)), y0 g(y).

    . f(x) = x21 x = h(y) = y+c (c > 0). y = h1(x) == x c g(y) = h1[(y + c)2 1] = y2 + 2cy + c2 c 1 - f(x). x = h(y) = y3, g(y) = (y6 1)1/3 f(x) = x2 1.

    1. f g, f(x) g(x) -. ,

    , ..

    ) f f ,) f g , g f ,) f1 f2, f2 f3, f1 f3.2. f(x) = x2, g(x) = x2+ax+ b(x R).

    (a, b), f g.3. a R b R, f(x) = 1 ax2 g(x) = bx(1 x)(x R) ? .

    Copyright & A K-C

  • 20

    1.2.2.

    , ,

    .

    ( )

    , . -

    (-

    ).

    1.7. f(x) g(x) , R = (,+). C0- f(x) g(x)

    d0(f, g) = supxR

    |f(x) g(x)|.

    Cr-

    dr(f, g) = supxR

    {|f(x) g(x)|, |f (x) g(x)|, . . . , | dr

    dxrf(x) d

    r

    dxrg(x)|}.

    f(x) g(x) - J = [a, b]. , Cr- , . , C0- f1(x) = 2x g2(x) = (2 + )x , f2(x) = 2x g2(x) = 2x + C

    r- r. J = [0, 5] C0- f1(x) g1(x) 5||. 1.8. f : J J . , f(x) - Cr- (Cr- ) J , > 0, g(x), J , dr(f, g) < , f(x).

    .

    . -

    . f(x) = 12x. C1- R. - . > 0, , d1(f, g) < , f(x) g(x) . , < 1/2. d1(f, g) < 1/2, 0 < g

    (x) < 1 x R. , g(x) . , g(x) p R x R p . , |g(x)| < 1 ,, g(x) .

    Copyright & A K-C

  • 21

    h(x). -

    . 5 < |x| 10. f(x) ( 0) - . g(x) . , g(10) < x 10 10 x < g(10) g(x),.. , , g(x) - . h(x) - [5, 10] [10,5] h : [5, 10] [g(10), 10], h :[10,5] [10, g(10)]. , h(x) , h(10) = 10. h(x) - . x 6= 0. n, f (n)(x) - f(x). , hg(x) . h(x) = g(n)hf (n)(x). , g(n) h(x) = h f (n)(x). f(x), g h(x) = hf(x). , h(0) = p. , h(x) ., , , -

    , .

    . f0(x) = xx2. x = 0 - x0 (0, 1), f (0) = 1. f(x) = xx2+., f(x) C

    r - f0(x). f(x) , > 0, -, < 0. , f(x) f0(x). f0(x) . .

    1.9. p k f(x) - ,

    0 6= ddxf (n)(p)

    6= 1. f(x) Cr-, - f(x) (, , f(x) ). -

    f(x) C1-, f(x) . - f(x) Cr- (r 2), f(x) ( x0 f(x) , f (x0) 6= 0). .

    Copyright & A K-C

  • 22

    f(x) C1- . ,

    > 0 , g(x) C1 - f(x) , f(x) g(x) . , , .

    . p - f(x). U p V 0 - h : U R, f(x) U l(x) = f (p)x V .

    , ,

    .

    1.3.

    , -

    . , -

    ()

    , .

    f(x, c), c, - . c = c0 , f(x, c) - f(x, c0) c c0. c -, . ,

    .

    , ..

    .

    , -

    f(x, c). f(x, c) c = c0 k, .. f (k)(p, c0) = p. (p) , |(p)| < 1 , |(p)| > 1 . (p) 6= 1, c0 p(c)(p(c0) = p) - k f(x, c), c. - -

    (x, c) = f (k)(x, c)x = 0, (p, c0) = 0, d(x,c)dx(p,c0)

    = (p)1 6= 0. , k .

    Copyright & A K-C

  • 23

    , -

    k c, p k, (p) = 1. - |(p)| = 1. , , -

    1. , f (k)(x, c) x c.

    1.1. f(x, c) -

    1) f (k)(x0, c0) = x0,

    2)

    f (k)

    x(x0, c0) = (x0) = 1,

    3)

    2f (k)

    x2(x0, c0) =

    (x0) > 0,

    4)

    f (k)

    c(x0, c0) > 0.

    (c1, c0) (c0, c2) > 0 , c (c1, c0), f (k)(x, c) (x0 , x0 + ), , . c (c0, c2), f (k)(x, c) (x0 , x0 + ).. g(x, c) = f (k)(x, c) x.

    g(x0, c0) = 0,gx(x0, c0) = 0,

    gc(x0, c0) > 0, c = h(x) , c0 = h(x0)

    g(x, h(x)) 0 (1.11) (x0, c0). (1.11), -

    gx(x, h(x)) + gc(x, h(x))dh

    dx= 0. (1.12)

    dh

    dx(x0) = 0,

    gx(x0, c0) = 0. (1.12),

    gxx(x, h(x)) + 2gxc(x, h(x))dh

    dx+ gcc(x, h(x))

    (dh

    dx

    )2+ gc(x, h(x))

    d2h

    dx2= 0.

    x = x0

    gxx(x0, c0) + gc(x0, c0)d2h

    dx2(x0) = 0.

    Copyright & A K-C

  • 24

    d2h

    dx2(x0) = gxx(x0, c0)

    gc(x0, c0)< 0.

    , x0 - c = h(x), f (k)(x, c) :f (k)(x, h(x)) = x. , c > c0, , c < c0 ( k). , -, , ,

    xf

    (k)(x, h(x)) x (x0, c0), fxx(x0, c0) 6= 0. (. 1.1)

    ( ), (-

    ) .

    . 1.1.

    . 3) 4),

    (c1, c0) (c0, c2). , x0, (x0) = 1, c k k. c < c0 k, c = c0 c > c0 . c < c0 k, c = c0 k -, 1, c > c0 k, , .

    1.2 ( ). -

    f(x, c) 1) f (k)(x0, c0) = x0,

    2)

    f (k)

    x(x0, c0) = (x0) = 1. x(c) k c c0 x(c0) = x0.

    Copyright & A K-C

  • 25

    (c) =f (k)

    x(x(c), c)

    3)

    d

    dc(c0) > 0

    , ,

    4)

    3f (2k)

    x3(x0, c0) < 0,

    (c1, c0) (c0, c2) > 0 , i) c (c1, c0), f (k)(x, c) , f (2k)(x, c) (x0, x0+);ii) c (c0, c2), f (2k)(x, c) (x0 , x0+ ), f (k)(x, c).

    .

    f (k)(x, c) g(x, c) = f (k)(x, c) x, 3) 1.2 , - f (k)(x, c) (c1, c0) (c0, c2). 2k, -

    h(x, c) = f (2k)(x, c) x. h(x0, c0) = f

    (2k)(x0, c0) x0 = 0. , 2)

    hx(x0, c0) =

    x(f (k)(f (k)(x, c), c))

    x=x0,c=c0

    1 =

    = f (k)x (f(k)(x0, c0), c0)f

    (k)x (x0, c0) 1 = [f (k)x (x0, c0)]2 1 = 0,

    hxx(x0, c0) =2

    x2(f (k)(f (k)(x, c), c))

    x=x0,c=c0

    =

    = f (k)xx (f(k)(x0, c0), c0)(f

    (k)(x0, c0))2 + f (k)x (f

    (k)(x0, c0), c0)f(k)xx (x0, c0) =

    = f (k)xx (x0, c0)[f(k)x (x0, c0)]

    2 + f (k)x (x0, c0)f(k)xx (x0, c0) = 0

    4)

    hxxx(x0, c0) =3

    x3f (2k)(x0, c0) < 0.

    Copyright & A K-C

  • 26

    x(c) h(x, c) = 0, h(x, c)

    h(x, c) = (x x(c))g(x, c).

    hx(x, c) = g(x, c) + (x x(c))gx(x, c)

    g(x0, c0) = 0.

    ,

    hxx(x, c) = 2gx(x, c) + (x x(c))gxx(x, c),hxxx(x, c) = 3gxx(x, c) + (x x(c))gxxx(x, c) hxx(x, c),hxxx(x, c) (x0, c0) ,

    gx(x0, c0) = 0, gxx(x0, c0) < 0.

    gc(x0, c0).

    hxc(x, c) = gc(x, c) dxdcgx(x, c) + (x x(c))gxc(x, c).

    hxc(x0, c0) = gc(x0, c0).

    hxc(x, c).

    hx(x, c) = f(k)x (f

    (k)(x, c), c)f (k)x (x, c) 1,

    hxc(x, c) = f(k)xx (f

    (k)(x, c), c)f (k)c (x, c)f(k)x (x, c) + f

    (k)xc (f

    (k)(x, c), c)f (k)x (x, c)+

    +f (k)x (f(k)(x, c), c)f (k)xc (x, c).

    hxc(x0, c0) = f(k)xx (x0, c0)f

    (k)c (x0, c0)f

    (k)x (x0, c0) + f

    (k)xc (x0, c0)f

    (k)x (x0, c0)+

    +f (k)x (x0, c0)f(k)xc (x0, c0) = f (k)xx (x0, c0)f (k)c (x0, c0) 2f (k)xc (x0, c0).

    Copyright & A K-C

  • 27

    f (k)(x(c), c) x(c),

    f (k)c (x(c), c) + f(k)x (x(c), c)

    dx

    dc=dx

    dc. (1.13)

    (1.13)

    f (k)c (x0, c0) = 2x(c0).

    , 3)

    d

    dc(f (k)x (x(c), c))

    c=c0

    = f (k)xx (x0, c0)x(c0) + f (k)xc (x0, c0) > 0.

    gc(x0, c0) = hxc(x0, c0) = f (k)xx (x0, c0)f (k)c (x0, c0) 2f (k)xc (x0, c0) == 2f (k)xx (x0, c0)x(c0) 2f (k)xc (x0, c0) < 0.,

    g(x0, c0) = 0, gx(x0, c0) = 0, gxx(x0, c0) < 0, gc(x0, c0) < 0. (1.14)

    x x0 - c(x), c(x0) = c0

    g(x, c(x)) 0. ,

    gx(x, c(x)) + gc(x, c(x))dc

    dx= 0. (1.15)

    (1.14) (1.15) ,

    c(x0) = 0.

    (1.15),

    gxx(x, c(x)) + 2gcx(x, c(x))dc

    dx+ gc(x, c(x))

    d2c

    dx2+ gcc(x, c(x))

    (dc

    dx

    )2= 0.

    c(x0) = gxx(x0, c0)gc(x0, c0)

    < 0.

    Copyright & A K-C

  • 28

    , c(x) x = x0 . -, c < c0 2k, c > c0 - . , 2k . 2f (2k)(x0,c0)

    x2 = 0 4), df (2k)(x,c(x))

    dx

    x = x0. df (2k)(x,c(x))

    dx

    x=x0

    = 1 c < c0 ,

    2k . . 1.2 c(x) 2k, x(c) k.

    . 1.2.

    . 3) 1.2 -

    , k -, 4) 1.2

    , 2k . 3), 4) ,

    2k. f(x)

    Sf(x) =f (x)f (x)

    32

    (f (x)f (x)

    )2.

    , -

    . ,

    3f (2k)(x, c)

    x3=3f (k)(f (k)(x, c), c)

    x3= f (k)xxx(f

    (k)(x, c), c)[f (k)(x, c)]3+

    +3f (k)xx (f(k)(x, c), c)f (k)xx (x, c)f

    (k)x (x, c) + f

    (k)xxx(x, c)f

    (k)x (f

    (k)(x, c), c).

    f (k)(x0, c0) = x0, f(k)x (x0, c0) = 1

    3f (2k)

    x3(x0, c0) = 2f (k)xxx(x0, c0) 3[f (k)xx (x0, c0)]2,

    Copyright & A K-C

  • 29

    , ,

    3f (2k)

    x3(x0, c0) = 2Sf

    (k)(x0, c0),

    .. 4) -

    1.2.

    , , -

    , :

    k k 2k. (. 1.3) . -

    . -

    , ,

    1.1 1.2. -

    , x = 0 .

    . 1.3.

    1.3. f(x, c) -,

    1) f(0, c) = 0,

    2)

    f

    x(0, c) = (c), (0) = 1

    d

    dc(0) > 0,

    3)

    2f

    x2(0, 0) > 0.

    f(x, c) x(c) c 0, x(0) = 0 x(c) 6= 0, c 6= 0. x = 0 , c < 0, , c > 0, c < 0 c > 0.

    Copyright & A K-C

  • 30

    f(x, c) = f(x, c), .. f(x, c) x, f(0, c) = 0, ,

    2fx2 (0, 0) = 0. .

    1.4. f(x, c) -,

    1) f(x, c) = f(x, c),2)

    f

    x(0, c) = (c), (0) = 1 ddc (0) > 0,

    3)

    3f

    x3(0, 0) < 0.

    (c1, 0) (0, c2) > 0 , i) c (c1, 0), x = 0 f(x, c) (, );ii) c (0, c2), f(x, c) (, ). x = 0 , .

    . 1.1 - 1.4. -

    f(x, c) = c x2. f(x, c) = c x2 = x , x1,2 =

    11+4c2 c > 1/4. c = 1/4 -. c = 1/4 x = 1/2. 1. 4) 1.1 , 3) . -

    c < 1/4 c > 1/4. x1,2 1,2 = 2x = 1

    1 + 4c. -

    , x1 =1+1+4c

    2 ,

    1 < 11 + 4c < 1. , 1/4 < c < 3/4. c = 3/4 - 1. 1.2. 1) 2) . (c) = 11 + 4c,

    d

    dc

    c=3/4

    = (

    21 + 4c

    )c=3/4

    = 1 < 0.

    , f(x, c) = cx2 . 4) . , c > 3/4 -

    Copyright & A K-C

  • 1.4. 31

    2.

    f (2)(x, c) = c c2 + 2cx2 x4 x = 0,, cx2x. f(x, r) = rx(1 x), - , 1.3. -

    , f(0, r) = 0 r = 1

    1.3 (fx(0, r) = r, (1) = 1, (1) = 1

    2fx2 (0, 1) = 2 < 0).

    r > 1 x(r) = r1r . f(x, c) = cxx3 1.4. , -

    c 1. c < 1 x = 0 . c > 1 x = 0, x1,2 =

    c 1. x = 0 , x1,2 -.

    1. , -

    :

    1) f(x, r) = rx(1 x), r = 3,2) f(x, c) = cex, c = e1, c = e,3) f(x, r) = xer(1x), r = 2,4) f(x, c) = cx x3, c = 1.2. F (x) = x+tf(x),

    f(x) =

    {(x)1/3, x 0,(x)1/2, x > 0, t > 0, 2 - t 0 t.

    1.4.

    , -

    . -

    , . -

    . .

    1.1. f(x) k > 1, ( 1).

    Copyright & A K-C

  • 32

    . a k f(x)(f (k)(a) = a). f(a) > a.

    a, f(a), f (2)(a), . . . , f (k1)(a), f (k)(a) = a. (1.16)

    b = f (i)(a), (i < k) (1.16), f(b) < b. (1.16) a. , (x) = f(x) x, , c (a < c < b), f(c) = c. f(a) < a. ,

    .

    1.2. f(x) , - J . I J ( -) . I f(I). p I, f(p) = p, .. p f(x).

    . I = [0, 1]. i, i = 0, 1 I , f(i) = i. (x) = f(x)x (0) = f(0)0 = 00 < 0,(1) = f(1) 1 = 1 1 > 0. p I, (p) = 0, .. f(p) = p. 1.3. f : I R I. I1 f(I) Q1 I, f(Q1) = I1.. I1 = [f(p), f(q)], p, q I. p < q,

    r I, f(r) = f(p). s r I, f(s) = f(q). f([r, s]) = I1, .. Q1 = [r, s]. p > q. . f : R R x1, x2, . . . , xk - k . a xi(i = 1, . . . , k). a, , - k 1 . I1, I2, . . . , Ik1 -. , f(x) 5

    a < f (3)(a) < f(a) < f (2)(a) < f (4)(a),

    I1 = [a, f(3)(a)], I2 = [f

    (3)(a), f(a)], I3 = [f(a), f(2)(a)], I4 = [f

    (2)(a), f (4)(a)]. f(I1). I1 - a f (3)(a), f(x) f(a) f (4)(a)

    Copyright & A K-C

  • 33

    . f(I1) - , f(a) f (4)(a). ,f(I1) I3 I4. f(I2) I4, f(I3) I2 I3 f(I4) I1. ,

    (directed graph).

    I1, I2, . . . , Ik1. si ti Ii. Ij f(si) f(sj) (f(Ii) Ij), , - Ij Ij, Ii Ij. , . 1.4.

    . 1.4. 5

    , k, k . -

    IkIl . . . ImIk, f(Ik) Il, . . . , f(Im) Ik. , -

    , . ,

    I1I3I2I4I1I3I2I4I1 . 1.4 8, I1I3I3I3I3I3I2I4I1 8.

    k (k > 2) 2: I1I2I1.

    I1f f(I1)

    I2

    .

    1.3 , Q1, -

    I1f f(I1)

    Q1

    f I2.

    Copyright & A K-C

  • 34

    1.3 , f(I2) I1,

    I1f f(I1)

    Q1f I2

    Q2

    f (2) I1 f f(I1) .

    , f (2)(Q2) = I1 Q2 1.1 , f(x) Q2 x Q2 2: f (2)(x) = x. x f(x), f(x) = x I2. x I1I2 ( I1 I2) x k > 2, . .

    1.3. k , - f(x), l, f(x) l.

    . I0I1 . . . Il = I0 -

    . 1.5. 1.3

    , f(Ii) Ii+1(i = 0, 1, . . . , l 1). , f(x) l. 1.2 , (. 1.5).

    I0 Q1 Q2 Ql1 Ql,

    Copyright & A K-C

  • 35

    Qlf (l) Il = I0. , Ql I0 = f (l)(Ql). 1.2 , f (l)(x) x Ql. , x k < l f(x). 1.1. f(x) 3, .

    .

    3:a < f(a) < f (2)(a), a < f (2)(a) < f(a).

    I1 = [a, f(a)], I2 = [f(a), f(2)(a)]. , f(I1) = I2,

    f(I2) I1 I2. I1 = [a, f (2)(a)], I2 = [f (2)(a), f(a)], f(I1) I1I2, f(I2) = I1. 3 (. 1.6). -

    . , 7 I1I2I2I2I2I2I2I1. 5 (. 1.4), , , 3.

    . 1.6. 3

    4. 4:

    a < f(a) < f (2)(a) < f (3)(a), (1.17)

    a < f(a) < f (3)(a) < f (2)(a), (1.18)

    a < f (2)(a) < f (3)(a) < f(a), (1.19)

    a < f (2)(a) < f(a) < f (3)(a), (1.20)

    a < f (3)(a) < f (2)(a) < f(a), (1.21)

    a < f (3)(a) < f(a) < f (2)(a). (1.22)

    Copyright & A K-C

  • 36

    (1.17)

    I1 = [a, f(a)], I2 = [f(a), f(2)(a)], I3 = [f

    (2)(a), f (3)(a)]

    , ,

    f(I1) I2, f(I2) I3, f(I3) I1 I2 I3. I3 - I2I3I3I2 3. 1.1 4 (1.17) -. ,

    (1.18), (1.21), (1.22) 4, (1.18), (1.19) 4 2. , .

    1.4. f : R R k > 1, , k 1. ,

    .

    1.4. k- - k, -.

    k, 1.4, , .

    , ,

    , .

    1.5. f(x) k > 1, 2.

    . k = 2. - , k 3. 1.4 k- f(x) k, - . , , -

    1. .

    , -

    , .

    Copyright & A K-C

  • 37

    . .. ,

    ()

    . ,

    .

    1.5. -

    :

    3C 5C 7C C 2 3C 2 5C 2 7C C 2n 3C 2n 5C 2n 7C . . .C2n C C 23 C 22 C 2C 1. f : R R , n, f(x) m m N , nCm. 1.1 1.1, ,

    1.5.

    f(x), I. [n] - , f(x) n. 1.5 .

    1.6.

    [1] [2] [4] [5 2] [3 2] . . . [5] [3].

    1. 5- .

    2. 8,

    .

    Copyright & A K-C

  • 38

    1.5.

    .

    , -

    1. -,

    . , -

    ,

    ,

    .

    . -

    f(x) x

    Sf(x) =f (x)f (x)

    32

    (f (x)f (x)

    )2.

    f(x) = ax2 + bx + c, f (x) 0, Sf(x) < 0 x (Sf(x) = x = b2a). -,

    . , S(ex) = 1/2, S(sinx) = 1 32(tan x)2. ,

    .

    1.7. f(x) . f (x) - , Sf(x) < 0.

    . ,

    f (x) 1.

    f (x) =Nk=1

    (x ak),

    ak .

    f (x) =Nj=1

    f (x)x aj =

    Nj=1

    Nk=1(x ak)x aj ,

    f (x) =Nj=1

    Nk=1,k 6=j

    Ni=1(x ai)

    (x aj)(x ak) .

    Copyright & A K-C

  • 39

    ,

    Sf(x) =j 6=k

    1

    (x aj)(x ak) 3

    2

    (Nj=1

    1

    (x aj)

    )2=

    = 12

    (Nj=1

    1

    (x aj)

    )2

    Nj=1

    (1

    (x aj))2

    < 0.

    1. :

    ) f(x) = x3 + 1,) f(x) = x3 + 10x,) f(x) = ln x.

    2. ,

    .

    3. , f(x)

    , f(x) =ax+ b

    cx+ d, a, b, c, d .

    4. h(x) =ax+ b

    cx+ d, a, b, c, d g = h f, Sg(x) = Sf(x).

    .

    1.8. Sg(x) < 0 Sf(x) < 0, S(f g) < 0..

    (f g)(x) = f (g(x))g(x),(f g)(x) = f (g(x))g2(x) + f (g(x))g(x),

    (f g)(x) = f (g(x))g3(x) + 3f (g(x))g(x)g(x) + f (g(x))g(x). ,

    S(f g)(x) = Sf(g(x))g2(x) + Sg(x). , S(f g)(x) < 0. 1.8 .

    Copyright & A K-C

  • 40

    1.2. Sf(x) < 0, Sf (n)(x) < 0 n > 1.

    , ,

    .

    .

    .

    1.9. x0 f(x) , f (x0) = 0.

    1.9. Sf(x) < 0 (Sf(x) = ). f(x) n . f(x) n + 2 .

    1.9 .

    1.6. Sf(x) < 0, f (x) - , -

    .

    ., x0 f(x),.. f (x0) = 0. Sf(x0) < 0,

    f (x0)f (x0)

    < 0.

    , f (x0) f (x0) . . , -

    f (x) - x. , f (x) f(x).

    1.7. f(x) , f (m)(x)(m > 1) .

    . c f1(c) . , f(x1) = c f(x2) = c, p, x1 < p < x2 f (p) = 0. f (2)(x)

    [f (2)(x)] = f (f(x))f (x) = 0.

    , f (2)(x) - xc f(x) f

    1(xc) . - f1(xc) ,

    Copyright & A K-C

  • 41

    f (2)(x) . -. g(x) = f (m1)(x) , , ,

    , , f (m)(x) .

    1.8. Sf(x) < 0 f(x) - , f(x) m m.

    . g(x) = f (m)(x). 1.2 Sg(x) < 0., g(x) , .. g(x) = x . - g(x) = 1 . g(x) = 1 x, Sg(x) = 0, - Sg(x) < 0. x1 < x2 < x3 , g(x) = 1. g(x) (x1, x2) (x2, x3) g

    (x) > 1, x2 - ,

    1.6. , (x1, x3) x0 , g(x0) < 1. g(x) , , g(x) = 0. , g(x) - , .

    1.9.

    p m f(x). W (p) , p, - p f (m)(x), .. W (p) () {x|f (mj)(x) p j }, p. -, W (p) f (m)(W (p)) W (p). W (p) = (r, s). , p . f(W (p)) W (p) (r, s) , f(x) (r, s), r s . , , :

    1. f(r) = r f(s) = s.2. f(r) = s f(s) = r.3. f(r) = f(s). . , r < p < s.

    f(r) = r, f(p) = p , u(r < u < p), f (u) = 1. , v(p < v < s), f (v) = 1. f (p) < 1 f (x)

    Copyright & A K-C

  • 42

    , f(x) (r, s). , f(x) f (2)(x). f(x) (r, s), (r, s). r s , . .

    p , - W (p) g(x) = f (m)(x).

    f(x).

    1. ,

    -

    . , ,

    , , . f(x) = arctan x > 1. Sf(x) = 2/(1 + x2)2 < 0. f(x) , -

    , f(x) = arctan x .

    . 1.7. f(x) = arctan x, > 1

    2. 1.9 ,

    1. - .

    , f(x) Sf(x) < 0. f(x) c f (c)= 1 f (c)=1. c - W (c). , f (c) = 1 ( f (2)(x)). 1.8 f(x) . , , f(x)

    Copyright & A K-C

  • 43

    , c. , c - , .. x < c c f(x) < x, y > c c f(y) > y. f (x) 1. 1.6 , f(x) > x a < x < c, f(x) < x c < x < b. - , c , , ., W (c) , , 1.9, W (c) .

    m > 1. g(x) == f (m)(x). , cW (c)c. f(x) = ex1. f(x) - x = 1. . , f(x) = ex1 .

    3. , f(x) x R. f : I I, I = [a, b] . 1.6 .

    1.9 ( ). I = [a, b] f(x) I. Sf(x) < 0 (a, b), |f (x)| > min{|f (a)|, |f (b)|} x (a, b).. |f (x)| I, x0 I. x0 (a, b), f (x0) 6= 0, Sf(x) < 0 (a, b). f (x0) > 0, f (x) (a, b), 1.6. f (x0) < 0, f (x) (a, b), 1.6. , x0 = a x0 = b.

    -

    1.9 .

    1.10. f : I I - Sf(x) < 0, W (p) ( p)

    f(x), I.

    .

    Copyright & A K-C

  • 44

    1.10. f(x), I= [0, 1] I, , :1. f(0) = f(1) = 0.2. f(x) I c, - I. f(x) .

    , -

    [0, c] [c, 1]. f(x, r) = rx(1 x) 0 < r 4 -. -

    g(x, p) =

    {px, 0 x 12 ,

    p px, 12 x 1, p, 0 < p 2. -

    h(x, l, p) =

    {lx, 0 x 1p ,

    lp1 lp1x, 1p x 1,

    l/p 1, p > 1. 1.10 -

    .

    1.3. f : I I , , Sf(x) < 0 I \ {c}. x = 0 I -. f(x) .

    Copyright & A K-C

  • 2.

    2.1.

    xn+1 = rxn(1 xn), (2.1)

    r,

    xn+1 = fxn x2n. (2.2)

    (2.2) (2.1),

    xn =f

    zn.

    (2.2) ,

    zn+1 = fzn(1 zn).

    , f(x, r) = rx(1 x) [0, 1] :

    0 rx(1 x) 1 (2.3)( 0 x 1). , (2.3) r > 0, , r2 4r 0.

    rx2n rxn + 1 0, x [0, 1].45

    Copyright & A K-C

  • 46

    , 0 < r 4 f(x, r) [0, 1] . , -

    [0, 1] Hx = fx x2,

    0 1. x < 0, f (n)(x, r) n ., x > 1, f (n)(x, r) n.. x < 0, f(x, r) = rx(1 x) < x. ,

    f (n)(x, r) . p. f (n+1)(x, r)f(p, r) < p, f (n)(x, r) p. , f (n)(x, r) . x > 1, f(x, r) < 0, f (n)(x, r) , .

    2.2. f(x, r) - .

    . , Sf(x, r) < 0 |x| , |f (n)(x, r)| n . , - .

    1.9.

    Copyright & A K-C

  • 47

    f(x, r) x0=0. , fx(0, r)= r, 0 < r < 1. , fx(0, 1) = 1. r > 1 x0 x1 = 1 1/r. (r) = fx(1 1/r, r) = r+ 2, x1

    1 < r + 2 < 1,..

    1 < r < 3. (2.4)

    (2.4) x1. 1 < r < 2 O(x0), x0 (0, 1) x1 , (r) > 0. 2 < r < 3 O(x0), x1, x1, x1. r = 3 fx(1 1/3, 3) = 1. r > 3 x1 2, 1.2. . ,

    f (2)(x, r) = r3x4 + 2r3x3 r2(1 + r)x2 + r2x. f (2)(x, r) = x:

    r3x4 + 2r3x3 r2(1 + r)x2 + r2x = x. (2.5) (2.5) : x0 x1. (2.5) -

    x

    (x r 1

    r

    )(r3x2 r2(1 + r)x+ r(1 + r)) = 0,

    r3x

    (x r 1

    r

    )(x 1 + r +

    (r + 1)(r 3)2r

    )

    (x 1 + r

    (r + 1)(r 3)2r

    )= 0.

    , 2:

    x =1 + r +

    (r + 1)(r 3)2r

    ,

    = 1. , x+, x 2 f(x, r). ,

    = fx(x+, r) fx(x, r) = r2 + 2r + 4 = f2(r).

    Copyright & A K-C

  • 48

    ,

    1 < f2(r) < 1.

    , 2 :

    3 < r < 1 +6.

    r x+, x . - x0 (0, 1) \ {f (n)(x1)(n = 0, 1, . . . )}, O(x0) (x+, x), f (2n)(x0), (n = 0, 1, . . . ) , f (2n+1)(x0), (n = 0, 1, . . . ) -. , (0, 1), , (.. x1 -), . r = 1+

    6 1. r, x = 1/2 f(x, r). r . -, r = 1+

    5 x = 1/2. f2(r) : f2(3) = 1 r = 3 ( - 2), f2(1+

    5) = 0 2 , f2(1+

    6) = 1 2 4 1.2.

    , H(x) = fx x2 2

    x(n,2) =f + 1 + (n, 2)

    (f + 1)(f 3)

    2, (2.6)

    (n, 2) = cos(n 1)pi, n = 1, 2. 4 f(x, r), H(x). , x(n,2) -

    H(2)(x):

    H(2)(x(n,2)) = x(n,2).

    2 H(2)(x) 4 - H(x). x = x(n,2) + y, x 4 H(x).

    H(2)(x) = H(2)(x(n,2) + y) = H(2)(x(n,2)) +H

    (2)x (x(n,2))y+

    +1

    2H(2)xx (x(n,2))y

    2 +O(y3).

    Copyright & A K-C

  • 49

    H(2)x (x) = Hx(H(x))Hx(x), H(2)xx (x) = Hxx(H(x))(Hx(x))

    2 +Hx(H(x))Hxx(x),

    H(2)x (x(n,2)) = Hx(x(1,2)) Hx(x(2,2))

    H(2)xx (x(n,2)) = (Hx(H(x(n,2))))x Hx(x(n,2)) = Hxx(H(x(n,2)))[Hx(x(n,2))]2 +Hx(H(x(n,2))) Hxx((x(n,2))). x(n,2) (2.6),

    H(2)(x(n,2) + y) = x(n,2) + fy y2 +O(y3),

    f = f 2 + 2f + 4, = [(f + 1)(f 3) + 3(n, 2)

    (f + 1)(f 3)]. f , , (n, 2) (+1 1).

    H(2)(y) = fy y2 (2.7) , H(x).

    2 H(2)(y):

    y =f + 1 +

    (f + 1)(f 3)2

    , = 1. (2.8)

    4 H(x) ( O(y3))

    x, = x + y,

    .. x1,1, x1,1, x1,1, x1,1. f = = r, .. - f(x, r), 4 f(x, r):

    a(4)n =r + 1 + (n, 2)

    (r + 1)(r 3)

    2r+

    +f2(r) + 1 + (n, 4)

    (f2 + 1)(f2 3)

    2(n, 2), n = 1, 2, 3, 4,

    Copyright & A K-C

  • 50

    f2 = r2 + 2r + 4, (n, 2) = r[(r + 1)(r 3) + 3(n, 2)

    (r + 1)(r 3)

    ],

    (n, 2) = cos(n 1)pi, n = 1, 2, 3, 4

    (n, 4) =

    {+1, n = 1, 2,1, n = 3, 4. , 8. - y = y+ y (2.7) , y = H(4)(y). , H(4)(y+ y) y. -, (2.8). ,

    p = 2k:

    a(p)n =k

    =1

    (fm + 1) + [(fm + 1)(fm 3)]1/2(n, 2m)2(n,m)

    (2.9)

    [m = 21, p = 2k

    ],

    fm (n,m) r,

    f2m = f 2m + 2fm + 4 (f1 = r), (2.10)

    (n, 2m) = (n,m){(fm + 1)(fm 3) + 3[(fm + 1)(fm 3)]1/2(n, 2m)

    }(2.11)

    ((n, 1) = r),

    (n, 2m) +1,1 , . (2.9) - (2.11) -

    p . rp < r < r2p p. p/2 p p = 2k (2.9):

    a(p)n = a(p/2)n +

    (fp/2 + 1) + [(fp/2 + 1)(fp/2 3)]1/2(n, p)2(n, p/2)

    .

    0 < r < rp r = rp, fp/2(rp) = 1. m = p/2 fm, fp(rp) = 1. rp < r < r2p r = rp, p . y ,

    . , fp(rp) = 0. , :

    Copyright & A K-C

  • 51

    fp/2(rp) = 1, p/2 ,fp(rp) = 1, p ,fp(r

    p) = 0, p ,

    fp(r2p) = 1, p ,f2p(r2p) = 1, 2p .

    ,

    fp(rp) = f2p(r2p) = 1,

    .

    :

    r sp s2p , fp(sp) p - f2p(s2p) 2p

    fp(sp) = f2p(s2p) = (), p = 2, 4, . . .

    rp r2p. - f2(r2) = 1 , f1 = r2, (2.10) r2 = 3.,

    f4(r4) = f 22 (r4) + 2f2(r4) + 4 = f2(r2) = r22 + 2r2 + 4 = 1.

    f 22 (r4) 2f2(r4) + 2r2 r22 = 0

    f2(r4) = r24 + 2r4 + 4 = 2 r2.

    r4 = 1 +3 + r2.

    1 = f4(r8) = f 22 (r8) + 2f2(r8) + 4 = f2(r4) = r24 + 2r4 + 4,f 22 (r8) 2f2(r8) + 2r4 r24 = 0.

    f2(r8) = 1 +1 2r4 + r24 = 2 r4, r28 + 2r8 + 4 = 2 r4.

    , ,

    r8 = 1 +3 + r4.

    Copyright & A K-C

  • 52

    ,

    f2(r2p) = r22p + 2r2p + 4 = 2 rp.

    r2p = 1 +3 + rp. (2.12)

    , r2 = 3, r4 = 1 +6 3.4495. r4. :

    r8 = 1 +4 +

    6 3.5396, r16 = 1 +

    4 +

    4 +

    6 3.5573,

    r32 = 1 +

    4 +

    4 +

    4 +

    6 3.5607.

    (

    , y) :

    r8 = 3.5441, r16 = 3.5644, r32 = 3.5688.

    , 2 3 < r < 3.4495, 4 3.4495 < r < 3.5396, 8 3.5396 < r < 3.5573, 16 3.5573 < r < 3.5607. . , -

    (2.12), . ,

    . p (2.12), r = 1 +

    3 + r,

    r =3 +

    17

    2 3.5615. r = 3.569. r > r .

    limp

    r2p rpr4p r2p = limp

    r2p rp1 +

    3 + r2p r2p

    = limp

    r2p rp3 + r2p

    3 + rp

    =

    = limp

    (r2p rp)(3 + r2p +

    3 + rp)

    r2p rp = limp(3 + r2p +

    3 + rp) =

    = 23 + r = 2(r 1) = 2

    (3 +

    17

    2 1)= 1 +

    17 5.1231.

    Copyright & A K-C

  • 3 53

    , ,

    = 4.6692. -. f(x)= 1+

    3+x, r2p= f(rp),

    r, f (r) =1

    23 + r

    =1

    .

    1 1

    |r2np r| Cn, n,

    C . , -

    , ,

    , , -

    . .

    p r = rp(rp < rp < r2p), p. a = 1/2. ap p, - a. , rp

    r2p = 1 +3 + rp (r

    1 = 2),

    r2 = 1 +5 = 3.23606 . . . .

    = limp

    [ap aa2p a

    ]= {(r + 1)(r 3) 3

    (r + 1)(r 3)}

    r

    =

    = 2.2399 . . . (2.50290 . . . ),

    .

    2.2. 3

    xn+1 = rxn(1 xn) r < r . -. r < r,

    Copyright & A K-C

  • 54

    2m ( m r). - (0, 1), , 2i, i = 0, 1, . . . ,m 1. r > r . r = 3.57 , . -, x0 (0, 1) , - x0. , [0, 1] ( A [0, 1], (, ) [0, 1] , A). , - [0, 1] , (. 2). -

    x0 = 1/2 f(x, r).

    . 2.2. f(x, r) r = 3.832

    r = 3.832. r 3 ,, ,

    1/2. ,

    f (3)(x, r) = r3x(1 x)[r4x3(1 x)3 + 2r3x2(1 x)2 r(1 + r)x(1 x) + 1].

    x = 1/2

    f (3)(1/2, r) =r3

    256(4 r)(r3 4r2 + 16) = 1

    2,

    r = r = 3.832. , r 3 c. , - (0, 1). 3 x = 0.15, y = 0.5, z = 0.95.

    Copyright & A K-C

  • 3 55

    [0, x] = , [x, y] = , [y, z] = , [z, 1] = . f(x, r)(. 2.2)

    f(, r) = + ,f(, r) = ,f(, r) = + ,f(, r) = .

    , , , . . 2.3.

    . 2.3.

    , -

    f(x, r), . f(x, r) {, , , }

    1 1 0 0 0 0 1 0 0 1 1 0 1 0 0 0

    T =

    1 1 0 00 0 1 00 1 1 01 0 0 0

    ,

    tij =

    {1, i j,0, .

    -

    k. , + , .. , , , + . , x1 = 1 1/r f(x, r) > x x < x1. +, x = 0.

    Copyright & A K-C

  • 56

    , x , f(x, r) > x f (n)(x, r) 3, n . x , x - + , , . , f(x, r) - . ,

    0 1 1 1

    A =

    (0 11 1

    ).

    A , f(x, r). ,

    A2 =

    (1 11 2

    ),

    f (2)(, r) , f (2)(, r) , . , f (2)(, r), , - f (2)(x, r) , 2. x1 2. f

    (2)(x, r) , , . , f (2)(x, r) + 3 A2 (, ).

    , A2 2, . A3

    A3 =

    (1 22 3

    ).

    3, :

    ,

    Copyright & A K-C

  • 3 57

    3, :

    , , . A3 4. x1 - 3. f (k)(x, r) k - , k, . A4 7. x1, - 2

    4. Nk f (k)(x, r),

    Nk = tr (Ak) (2.13)

    (tr (A) A). - k, Nk -, k, k. , tr (A6) = 18. , 2 ( ) 3 ( ). , 6. , k- f(x, r) , - ,

    .

    . -

    f (k)(x, r) . , , , . , (2.13). Ak, A:

    det |A E| = (1 ) 1 = 0, 1,2 = 15

    2.

    Nk = tr (Ak) =

    (1 +

    5

    2

    )k+

    (15

    2

    )k.

    , f(x, r), 0,

    Nk + 1 = 1 +

    (1 +

    5

    2

    )k+

    (15

    2

    )k= 1 + Fk+1 + Fk1,

    Fk

    F0 = 0, F1 = 1, Fk = Fk1 + Fk2, k = 2, 3, . . .

    Copyright & A K-C

  • 58

    Nk + 1 = 1 + Fk+1 + Fk1

    Fk =15

    (1 +52

    )k(15

    2

    )k (

    1 +5

    2

    )k= Fk

    1 +5

    2+ Fk1,

    (15

    2

    )k= Fk

    152

    + Fk1.

    k = 5, N5 + 1 = 12, .., , -

    5. k = 8 N8 = F9 + F7 = 47. , 2,

    4 8.

    , , + , , . , , ,

    :

    . . . .

    2.3. f (x) = 4x(1 x)

    xn+1 = 4xn(1 xn), (2.14).. r = 4. (2.14).

    xn+1 = rxn(1 xn) (2.15) r = 2.

    xn =1

    2(1 yn).

    Copyright & A K-C

  • f(x) = 4x(1 x) 59

    (2.15)

    yn+1 = y2n

    (yn+1 =

    r

    2y2n + 1

    r

    2

    ).

    yn = y2n0 .

    xn =1

    2[1 (1 2x0)2n]. r = 4

    yn = cos pizn

    yn+1 =r

    2y2n + 1

    r

    2(r = 4 : yn+1 = 2y

    2n 1).

    cos pizn+1 = 2 cos2 pizn 1 = cos 2pizn = 2 cos2 2pizn1 1 =

    = cos 22pizn1.

    ,

    cos pizn = cos 2npiz0.

    zn : 0 zn 1. cos pizn+1 = cos 2pizn

    cos u = cos v

    u = v + 2kpi (2.16)

    zn+1 =

    {2zn, 0 zn 12 ,

    2(1 zn), 12 zn 1(2.17)

    z0 =1

    piarccos y0,

    0 arccos y pi arccos y, (2.14):

    xn =1

    2(1 cos pizn) = 1

    2(1 cos 2npiz0) = 1

    2[1 cos{2n arccos(1 2x0)}],

    Copyright & A K-C

  • 60

    :

    xn = sin2(2n arcsin

    x0).

    (2.17)

    zn =1

    piarccos cos(2npiz0).

    , (2.14) (2.17), -

    .

    f(x) = 4x(1 x),

    g(x) =

    {2x, 0 x 12 ,

    2(1 x), 12 < x 1,

    h1(g(h(x))) = f(x),

    h(x) =2

    piarcsin

    x.

    , 0 x 12

    0 h1(x) 12

    h1(g(h(x))) = sin2(2 arcsinx) = (2

    x(1 x))2 = f(x).

    12 x 1,

    1

    2 h1(x) 1

    h1(g(h(x))) = sin2[2(pi2 arcsinx

    )]= sin2(2 arcsin

    x) = f(x).

    (2.17) (2.14).

    (2.14)

    f(x) = 4x(1 x), . , -

    g(x) (|g(x)| = 2 x 6= 1/2). , p

    cos(2ppizp) = cos pizp.

    Copyright & A K-C

  • f(x) = 4x(1 x) 61

    , q < p

    cos(2qpizp) 6= cos pizp.

    , (2.16)

    zp =2k

    2p 1 , (2.18)

    k = 0, 1, 2, . . . , 2p1 12 12,

    zp 6= 2k

    2q 1 ,

    k = 0, 1, 2, . . . , 2q1 12 12 q < p. p. - (p = 1)

    z1 = 0 2

    3.

    (2.14) x0 = 0 x1 = 3/4. 2:

    z2 =2

    5

    4

    5.

    2 (2.14):

    x2 =(55)

    8

    (5 +5)

    8.

    3

    z3 =2k

    8 1 , k = 1, 2, 3, 41

    2 12,

    3:

    z3 =2

    7,4

    7,6

    7 z3 =

    2

    9,4

    9,8

    9.

    Copyright & A K-C

  • 62

    p = 4

    z4 =2

    15,4

    15,8

    15,14

    15; z4 =

    2

    17,4

    17,8

    17,16

    17; z4 =

    6

    17,12

    17,10

    17,14

    17.

    , 5 .. ,, p, - (2.18) ,

    .

    p (2.18) () z(p)+(z(p)). z(p)+

    z(p)+ =2k

    2p + 1=

    2k

    22p 1 ,

    k = k(2p 1)., z(p)+ z(2p), .. z(p). , (2.17), -

    .

    cos(2jpiz0) = cos(pizp), (2.19)

    z0, j - p, , (2.19) z0, (2.18) , zp - p. , - , .

    , z0 , - l/m, l < m l,m . , -

    z0 =2k

    2p 1 ,

    k = 0, 1, 2, . . . , 2p1 1.

    1: l /m . .

    r m .

    r(m) = 1 (mod m), (r(m) 1 m),

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  • f(x) = 4x(1 x) 63

    (m) , 1, 2, . . . ,m1, m (m , (m) == m 1 (1) = 1). 1 z0 z0 = 2l

    /m. m , r = 2. ,

    2(m)1m . , z0

    z0 =2k

    2(m) 1 ,.. 1

    (m) (, , q < (m), (m)) (2.17).

    2: l /m . z1, ,

    2z0 = 2l/m l/m 1/2, 2(1 z0) = 2l/m 1, l = m l 1/2 l/m 1. , 2 .

    3: l /m . m = 2sm, s , m . l

    arccos cos(2spiz0) =l

    mpi (0 l

    m 1).

    , s 3 - 1, 2. ,

    3 .

    ,

    (2.17). -

    ,

    (2.17) [0, 1] ( [0, 1], ,.. , [0, 1]). , [0, 1], l/m, l , m . ,

    (2.14). .

    2.3. (2.14) -

    [0, 1].

    , [0,1] -

    .

    Copyright & A K-C

  • 64

    (2.17). z [0, 1] :

    z =a12+a222

    + + ak2k

    + = .a1a2 . . . ak . . . ,

    ak 0, 1. z < 1/2, g(z) 2z, ..

    g(z) = g(.a1a2 . . . ) = .a2a3 . . . .

    z > 1/2, g(z) 1 2z -

    g(z) = g(.a1a1 . . . ) = .a2a3 . . . ,

    ak = 1 ak k. g(z) :

    g(.a1a2 . . . ) =

    {.a2a3 . . . a1 = 0,.a2a

    3 . . . a1 = 1,

    .. g(z) a1a2a3 . . . - , ( a1 = 0) 1 ai ( a1 = 1). , :

    g(.0111 . . . ) = .111 . . . , g(.111 . . . ) = .000 . . . .

    :

    z0 = .000 . . . , z1 =2

    3= .101010 . . . .

    z = 1/3 = .010101 . . . z1 = 2/3. . , g(n)(z) z z1 = 2/3, - , z = .a1a2 . . . 010101 . . . . g(n)(z) z

    , z 000 . . . , .. z .

    z = .100100 . . . g(z) = .110110 . . . , g(2)(z) = .010010 . . . , g(3)(z) = .100100 . . . . z, , . ,

    Copyright & A K-C

  • f(x) = 4x(1 x) 65

    g(n)(z) z - , z - p.

    p 2, - z = 0, 2/3. z = .011011 . . . , O(z) z .

    g(z) = .110110 . . . , g(2)(z) = .01001001 . . . , g(3)(z) = .1001001 . . . ,g(4)(z) = .110110 = g(z). , g(n)(z) n .

    z = .11001100 . . . , g(z) = .01100110 . . . , g(2)(z) = .11001100 = z. , g(n)(z) n . , g(z) ()

    ( ). -

    1 ak, ak1 6= ak. p , ak+p = ak k. ak, ak+p, ak 1 . ak 1 , ak+p. :

    O(.101101 . . . ) = {.100100 . . . , .110110 . . . , .010010 . . . }.,

    . -

    p , g(n)(z) p. , a1 ak+p, , , , -

    1. ak = ak+p, ak ak+p, , . - , ak ak+p g(n)(z) (.. - ) p. ,

    g(n)(z) n p. . g(n)(z) , - z .

    .

    Copyright & A K-C

  • 66

    2.4. z p, g(n)(z) n p. , g(n)(z) , z .

    O(z), -, . -

    . O(z), z = .1010010001 . . . . , O(z) 1, 1/2, . . . , 1/2n, . . . , 0. , O(z) - [0, 1].

    2.5. z [0, 1] z z, O(z) [0, 1].

    . s0 , - z , s0 z, . S :

    s1 = .0, s2 = .1, s3 = .00, s4 = .01, s5 = .10, s6 = .11, . . . ,

    n 1 , s2n2. z . - z s0. z sn S , s

    n

    . ,

    n , L z. - z sn, L . z sn, , , ( 1) sn. , , z. z z0, . , z0 [0, 1] - , sN S M , 1/2M < /2 |sN z0| < /2. , s O(z) sN . ,

    |s z0| |s sN |+ |sN z0| < 2+

    2= .

    Copyright & A K-C

  • f(x) = 4x(1 x) 67

    , z0 O(z) O(z) [0, 1].

    2.5 , -

    z, , z O(z). , - [0, 1] , 0 2/3. .

    2.6. [0, 1]:1) z , g(n)(z) 0 2/3;2) z , g(n)(z) p;3) z , O(z) [0, 1].

    , 2.6 f(x) ( 0 3/4). (2.17) , .

    , .

    2.1. f : J J , - > 0 , x, y J n, |f (n)(x) f (n)(y) > . , [0, 1] J [0, 1] n > 0, g(n)(J) = [0, 1]. , 1/2 / J , l(g(J)) = 2l(J), l() ; 1/2 J , > 0, [0, ] g(2)(J), 1 g(J). g(m+2)([0, ]) = [0, 2m] 2m < 1 g(m+2)([0, ]) = [0, 1] 2m > 1. ,

    (2.17). ,

    (2.14).

    2.7. [0, 1] J [0, 1] - m , f (m)(J) = [0, 1].

    (2.14) (2.17), , [0, 1] - .

    2.2. f : J J , > 0 ,

    Copyright & A K-C

  • 68

    x J N x y N n 0, |f (n)(x) f (n)(y)| > . ,

    x, x, - , f . , , - x, x . , , x. - .

    , , -

    .

    .

    -

    , x . (2.17) ,

    - 1/2.

    2.3. f : J J , U, V J k > 0, f (k)(U) V .

    , , -

    .

    .

    ,

    .

    2.4. V . f :V V V , :1) f ,2) f ,3) f V .

    (2.14) (2.17),

    .

    2.8. (2.14) (2.17) [0, 1].

    . -

    .

    O(x0),

    Copyright & A K-C

  • f(x, r) = rx(1 x) r > 4 69

    , n = 100, ,

    . (2.17)

    m log 1log 2 [0, 1]. = 1020, , [0, 1] m > 20 log2 10( 70), - . (2.14) (2.17) (x0), n : -

    J [0, 1]? , J = (, ), (2.17) , (2.14)

    1

    pi

    dxx(1 x) =

    2

    pi(arcsin

    arcsin) = h() h(),

    h(x) , f(x) g(x).

    2.4. f (x, r) = rx(1 x) r > 4

    f(x, r) = rx(1 x) r > 4. - . 2.4.

    . 2.4. f(x, r) r > 4

    f(x,r) r/4, x = 1/2 - f(x, r) I = [0, 1]., , x = 1/2

    I . , r = 4.002, [0.49,0.51] I. A0 I, . ,

    Copyright & A K-C

  • 70

    A0 x = 1/2. x A0, f(x, r) > 1 f (2)(x, r) < 0. f (n)(x, r) n. I, A0, I f(x, r). A1 = {x I : f(x, r) A0}. x A1, f (2)(x, r) > 1,

    f (3)(x, r) < 0 , , , f (n)(x, r) n. - An = {x An : f (n)(x, r) A0}. ,An = {x I : f (i)(x, r) I i n, f (n+1)(x, r) / I}. ,An , I (n+1)- . x An, O(x) . , , An. - I, . r. ,

    r = I \( n=0

    An

    )=

    n=1

    f (n)(x, r).

    , .

    r. A0 1/2, I1 = I \ A0 : B0 = [0, q0] B1 = [q1, 1], q0 < q1 f(q0, r) = f(q1, r) = 1. , f

    (2)(q0, r) = f(2)(q1, r) = 0. - , f(x, r) B1 B2 I. f(x, r) B1 B2. f(B0, r) = f(B1, r) = I, ( B0, B1), f(x, r) A0. , A1. f (2)(x, r) x = 1.

    . 2.5. f (2)(x, r) r > 4

    Copyright & A K-C

  • f(x, r) = rx(1 x) r > 4 71

    I2 = I \ (A0 A1). - [0, q00], [q01, q0], [q1, q10], [q11, 1], f(x, r) B1, B2. -, f (2)(x, r) I. , I2 = I \ (A0 A1) , f (2)(x, r) A0. - I . , A2. , f

    (2)(x, r) . , f (2)(x, r) . An, . -, An 2n . , In+1 == I \ (A0 An) 2n+1 ,

    1 + 2 + + 2n = 2n+1 1.-, f (n+1)(x, r) - I. f (n+1)(x, r) . f (n+1)(x, r) 2n I., In = f

    (1)(In1, r) = f (n)(I, r) In In1 r

    r =n=0

    In (I0 = I). (2.20)

    , -

    , .. .

    2.1. r .

    . r (2.20) ( - ). , . -

    , n In ( An) r. , , 0. I - f(x, r). x r In,jx n In, x. A |A| -. |In,jx| 0, n , In,jx x n , , x

    r \ x. |In,jx| 0 n, n=0

    In,jx

    x n=0

    In,jx r. , x r \ x. , r .

    Copyright & A K-C

  • 72

    B1 B2 q0 =rr24r

    2r , q1 =r+r24r2r -

    . f (q0, r) =r2 4r. r > 2+5

    f (q0, r) > 1. r > 2+5 f (q1, r) < 1. f (x, r) (f (x, r) < 0), |f (x, r)| > 1 x I1., |f (x, r)| > 1 x r, r > 2 +

    5.

    2.5. f : R R . ( ) f (.. f() = ). f , n0 1 , |(f (n0))(x)| > 1 x .

    , r - f(x, r) r > 2 +

    5 n0 = 1. ,

    , .. -

    , . -

    . ,

    r . r r > 2 +

    5 .

    2.2. r r > 2 +5 .

    ., r . [a, b]r. n 1 f (n)(x, r). , [a, b],

    f (n)(b, r) f (n)(a, r) = f (n)(cn, r)(b a),

    cn [a, b]. f(q0, r) =

    r2 4r = . , |f (x, r)| > x I1. r > 2 +

    5, > 1. cn [a, b] r, f (i)(cn, r) r I1 0 i n 1. |f (n)(cn, r)| n

    |f (n)(b, r) f (n)(a, r)| = |f (n)(cn, r)||b a| n|b a|.

    , n |f (n)(b, r) f (n)(a, r)| > 1, > 1. r ,, {f (n)(a, r), |f (n)(b, r)} r [0, 1] n. . r . , .

    Copyright & A K-C

  • f(x, r) = rx(1 x) r > 4 73

    2.4.1.

    f(x, r) - r. - f(x) = 4x(1 x) , f(x) - - (2.17). -

    ,

    f(x, r) r. ,

    0 1.

    2.6. 2 = {s = (s0s1s2 . . . )|sj = 0 1}.

    2 0 1. - 2 . - s = (s0s1s2 . . . ) t = (t0t1t2 . . . )

    d[s, t] =t=0

    |si ti|2i

    .

    |si ti| 1, d[s, t] i=0

    12i = 2, ..

    d[s, t] . , s = (111 . . . ), t = (1010 . . . ),

    d[s, t] =i=1

    1

    22i1=

    2

    3.

    2. d[s, t] 2.

    . , d[s, t] 0, d[s, t] = d[t, s] d[s, t] , si = ti i. |ri ti| |risi|++|si ti| , d[r, t] d[r, s] + d[s, t].

    , 2 , , , .

    , s, t 2 si = ti i = 0, 1, . . . , n,

    d[s, t] =ni=0

    |si ti|2i

    +

    i=n+1

    |si ti|2i

    i=n+1

    1

    2i=

    1

    2n.

    Copyright & A K-C

  • 74

    , d[s, t] < 1/2n, si = ti i n, sj 6= tj j n

    d[s, t] 12j 1

    2n.

    , -

    . 2, . -

    .

    2. s, t 2 si = ti i = 0, 1, . . . , n. d[s, t] 1/2n. , d[s, t] 1/2n, si = ti i n.

    2.

    2.7. 2

    (s0s1s2 . . . ) = (s1s2s3 . . . ).

    . ,

    , s0 0 1. , .

    3. : 2 2 .

    . > 0 s = (s0, s1s2 . . . ) 2. n , 1/2n < . = 1/2n+1. t = (t0t1t2 . . . ) 2 , d[s, t] < , 2 - si = ti i n+ 1. , d[(s), (t)] 1/2n < .

    . (1.17) . -

    .

    .

    . (0, 0, 0 . . . ) (1, 1, 1, . . . ). 2 -, ,

    (010101 . . . ). n

    Copyright & A K-C

  • f(x, r) = rx(1 x) r > 4 75

    (s0s1 . . . sn1s0s1 . . . sn1 . . . ). 2n - n. 2n - 0 1 n. -, 0 1 0 1., 2. - s = (s0s1s2 . . . ) t, d[s, t] 1/2n., 2 , .. , 2. -. s :

    s0 = 0, s1 = 1, s2 = 00, s3 = 01, s4 = 10, s5 = 11, . . . ,

    0 1 3 , 4 .. , , s, ,

    . , -

    ,

    t 2. -

    t. , .

    2.9. 2n n. 2. 2 .

    1. s = (001001001 . . . ), t = (010101 . . . ), r = (101010 . . . ). d[s, t], d[t, r], d[s, r].2. 2, 3 4 .3. 2 2, - : sj = 0, sj+1 = 1, ..

    2 ,

    . ,

    a) 2 2 2;b) 2;c) 2 .

    4. s 2. W s(s) s : W s(s) t, d[i(s), i(t)] 0, i. , W s(s).

    Copyright & A K-C

  • 76

    2.4.2. 2 f (x, r)

    r > 2 +5

    f(x, r), ., r B0 = [0, q0],

    q0 < 1/2 B1 = [q1, 1], q1 > 1/2. x r, , x.

    2.8. x S(x) = s0s1s2 . . . , sj = 0, f

    (j)(x, r) B0; sj = 1, f (j)(x, r) B1., x r 0 1. S(x) r 2.

    2.10. S(x) .

    . , S(x) -. a, b r a 6= b. , S(a) = S(b). n f (n)(a, r) f (n)(b, r) 1/2. - , f(x, r) f (n)(a, r) f (n)(b, r). - B1 B2 n. , r .

    , S(x) r 2. s = s0s1s2 . . . . x r, S(x) = s. . J I, J , f1(J, r) = {x I : f(x, r) J} , B0, B1. Bs0s1...sn

    Bs0s1...sn = {x I : x Bs0, f(x, r) Bs1, . . . , f (n)(x, r) Bsn} =

    = Bs0 f1(Bs1, r) f (n)(Bsn, r)., Bs0s1...sn - n. ,

    Bs0s1...sn = Bs0 f1(Bs1...sn). , Bs1...sn . -, f1(Bs1...sn) ,

    Copyright & A K-C

  • f(x, r) = rx(1 x) r > 4 77

    B0, B1. Bs0 f1(Bs1...sn) -. ,

    Bs0s1...sn = Bs0...sn1 f (n)(Bsn, r) Bs0...sn1. ,

    n0Bs0s1...sn

    . x n0

    Bs0s1...sn, x Bs0, f(x, r) Bs1 .. ,S(x) = (s0s1 . . . ). , S(x) r 2.,

    n0

    Bs0s1...sn . -

    S(x). , , diamBs0s1...sn 0 n. , S(x) . x r , S(x) = s0s1s2 . . . . > 0 n , 1/2n < . Bt0t1...tn, , t0t1 . . . tn. , r. 2

    n+1

    . < 1/2n+1 , |x y| < y r y Bs0s1...sn. C, S(x) S(y) n+1. 2

    d[S(x), S(y)] 2 +

    5 r . ,

    . n 2n , 2, 2 . -, .

    2.12. f(x, r) r > 2 +5 - .

    . , f B, > 0, x B U(x) x - y U(x) n 0 , |f (n)(x) f (n)(y)| > . , A0, .. - [0,1], I . x, y r. x 6= y, S(x) 6= S(y). x y , , , n-. - f (n)(x, r) f (n)(y, r) A0. ,|f (n)(x, r) f (n)(y, r)| > . , , f(x, r) r > 2 +

    5 r :1) r;2) r ;3) f(x, r) - .

    1.4 .

    2.13. f(x, r) = rx(1 x) r > 2 +5 r.

    Copyright & A K-C

  • 1.

    f(x) (0, X) - 0 < f(x) < x . xn+1 =f(xn) (n = 0, 1, 2, . . . , x0 (0, X)) , (0, X). - (0, X). , = 0, f(x), , f(x). , xn . - n ? .

    1 [5]. f(x) = x + O((x)), 0 < < 1, (x) > 0, x1(x)

    0

    x2(x)dx

  • 80

    (., , [9]), -

    ,

    k=0

    (xk)

    xk.

    , (x), , x1(x) 0 x 0.

    limk

    xkxk1

    = limk

    xk1 +O((xk1))xk1

    = .

    , x1(x) -,

    xk1xk

    x2(x)dx x1k (xk) lnxk1xk

    cx1k (xk),

    c . ,

    k=0

    (xk)

    xk 1

    c

    x00

    x2(x)dx 0 (0, 1]. xn = f(xn1) xn Crn (n). , = 1. xn = f(xn1) (x) = x f(x).

    xn xn1 = (xn1)., xn n (x), - [1,+),

    (n) (n 1) = ((n 1)). (n) (n1) (n1), (x) (x)((x)). ,

    (1)(n)

    dt

    (t) n,

    Copyright & A K-C

  • 81

    .. xn = (n) 1(n),

    (y) =

    (1)y

    dt

    (t).

    (xn) (xn1) , , , . , (xk) (xk1) == 1 + o(1) k = 1, . . . , n, (xn) = n + o(n). , xn == 1(n+o(n)). (y) (y), . xn = xn1 x2n1.

    (y) =

    x1y

    dt

    t2 1y= (y).

    (xn) (xn1)

    (xn) (xn1) = 1xn 1xn1

    =xn1 xnxnxn1

    1

    n . , (xn) = 1xn n. , xn 1n n. , .

    2 [5]. xn+1 = f(xn), n = 0, 1, . . . , f(x) = x(x)+ (x)(0 < x X). (x) > 0, (x) 0. :

    limx0

    (x) = 0, limx0

    (x) = 0, limx0

    (x)

    (x)= 0.

    (t) (0 t .

    Copyright & A K-C

  • 82

    xn (n) (n).

    . (x) ,

    xk1xk

    d

    () xk1 xk

    (xk1= 1 (xk1)

    (xk1).

    ,

    t(xk) k k1i=0

    (xi)

    (xi)+

    Xx0

    d

    ().

    limi

    (xi)

    (xi)= 0,

    limk

    t(xk)

    k 1.

    Pk =(xk1)(xk)

    , Qk =(xk1)(xk)

    .

    Pk = 1 +(k)(xk1 xk)

    (xk,

    xk < k < xk1. ,

    Pk = 1 + (k)

    (1 (xk1)

    (xk1)

    )Pk.

    limk

    Pk = 1,

    Pk (k) 0 k . ,

    limk

    Qk = limk

    Pk(xk1)(xk1)

    = 0.

    Copyright & A K-C

  • 83

    xk1xk

    d

    () xk1 xk

    (xk)= Pk Qk,

    t(xk) k +k1i=0

    (Pi 1Qi) +X

    x0

    d

    ()

    , ,

    limk

    t(xk)

    k 1. ,

    limk

    t(xk)

    k= 1.

    ,

    Xxk

    d

    () k k .

    .

    (t) =t(t)(t)

    (t > 0)

    , .. (t) > c > (t) < 0, (t) = ((t)) < 0. (0) = X,

    (t) = X exp

    ( t0

    ()

    d

    ).

    (t+ h)

    (t)= exp

    ( t+ht

    ()

    d

    ) h > 0 (

    t

    t+ h

    )c 2 +5. , r, I = [0, 1] f(x, r), I. f(x, r). r > 2 +

    5 - |f (x, r)| > 1 I1 = [0, q0] [q1, 1], f(q0) = f(q1) = 1, r. , r f(x, r). r (4, 2+

    5) - . I1 |f (x, r)| 1. , r - f(x, r). -

    .

    1. f : R R . f(x). - :

    (I) C > 0 > 1, |(f (n))(x)| Cn x n 1.(II) N 1, |(f (n))(x)| > 1 x n N .(III) n0 1, |(f (n0))(x)| > 1 x .(IV) x nx 1, x, |(f (nx))(x)| > 1.

    . , (IV)(III). - x nx, | ddxf (nx)(x)| > 1 ddxf (nx)(x) . - Ux x x > 1, y Ux | ddxf (nx)(y)| > x. {Ux|x } . , - {Ui}ki=1. {i}ki=1 1

    Copyright & A K-C

  • 89

    {ni}ki=1 , | ddxf (ni)(y)| > i y Ui. = max{n1, . . . , nk}, 0 = min{1, . . . , k}, m = min

    x{|f (x)|}.

    , |f (x)| . , m>0. k , - k0m

    > 1, n0 = k + . , n0 x | ddxf (n0)(x)| > 1. - x n0, x . 1 , x U1. = n1 - 2 , f

    ()(x) U2. + n2 > k, . , 3.

    {1, . . . , j}. =ji=1

    ni. j+1 , f()(x) Uj+1. + nj+1 > k. j . ,

    k 1. , j k 0 > 1. , x , | ddxf (n0)(x)| > 1. (III).(III)(II). n0 = 1 (III), . , n0 > 1.

    = min{ ddx

    f (n0)(x)}, m = min

    x{|f (x)|},

    > 1, m > 0. n0 > 1, m 1. k , - mn01k > 1. N = n0k + (n0 1). n > N , n = n0(k + ) + i, > 0 0 i n0 1. x

    Copyright & A K-C

  • 90

    ddx

    f (n)(x) = d

    dxf (n0(k+)(f (i)(x))

    ddx

    f (i)(x) k+mi

    kmn01 > > 1.(II)(I). N = 1 (II), . N > 1.

    m1 = minx

    { ddx

    f (N)(x)}, m = min

    x{|f (x)|}.

    , m1 > 1. , m 1, N > 1.

    = m1/N1 , C = (m/)

    N1.

    , > 1 C > 0. n > 0 n = kN + i, k 0 0 i N 1. x d

    dxf (n)(x)

    = ddx

    f (kN)(f (i)(x)) d

    dxf (i)(x)

    mk1mi = kNmi == kNi(m/)i kN+i(m/)(N1) = Cn.(I)(IV). n ,

    Cn > 1. ddx

    f (n)(x) Cn > 1. nx = n x .

    , -

    , (IV).

    ,

    (I).

    r - f(x, r) r > 4. , ,.. . -

    , r f(x, r). r > 0 f(x, r) p1 = 11/r f (p1, r) = 2r. |f (p1, r)| > 1, r > 3. p0 = 1/r. p0 p1 1/2.

    Copyright & A K-C

  • 91

    . 1.

    , f(p0, r) = p1 ( r > 1). ,

    f([p0, q0], r) = f([q1, p1], r) = [p1, 1].

    , x, J = (p0, q0) (q1, p1), J f(x, r), .. f(x, r) / J . .

    2. r > 4 c x J , n 2, f (n)(x, r) [p0, p1).. x J . f(x, r) (p1, 1) f (2)(x, r) (0, p1)., n 1 f (2+n)(x, r) [p0, p1). - f (2)(x, r) [p0, p1), . f (2)(x, r) (0, p0). , n 1 f (2+n)(x, r) [p0, p1). . f(z, r) > z z (0, p0), f (n+2)(z, r) p0. - f (n+2)(z, r) n z0 p0. , z0 f(x, r). 0 < z0 < p1. , p1 f(x, r).

    3. r > 4, q0 p0 < p0. , (p0, q0) (q1, p1) , (0, p0) (p1, 1).

    . , r > 4 - 2p0 > q0. , p0 = 1/r

    q0 =1

    21

    4 1r.

    Copyright & A K-C

  • 92

    , 0 < 1 4/r < 1. 1 4/r > 1 4/r. 1/2

    1

    4 1r>

    1

    2 2r,

    21

    r>

    1

    21

    4 1r.

    , -

    r.

    . r > 4, r f(x.r).

    . xr. , x>1/2. x 1. r 1. x p1, n = 1, f (x, r) f (x, p1) =

    = r + 2 < 1. x = q1, f (n)(q1, r) = 0 n 2

    | ddx

    f (n)(q1, r)| = |f (q1, r)| |f (1, r)| |f (0, r)|n2 =

    = rn1r2 4r = rn

    1 (4/r), , 1 n. x, q1 p1. 2 - , n, f (n)(x, r) [p0, p1). In,j In, x (, In -, , [0, 1] f (n)(x, r)). In,j [q1, p1), . , In,j [q1, p1). f (n)(x, r) In,j [0, 1] (. 2.4), In,j -:

    In,j = Ln,j Kn,j Rn,j, f (n)(Ln,j, r) = [0, p0], f

    (n)(Kn,j, r) = (p0, p1), f(n)(Rn,j, r) = [p1, 1].

    Ln,j In,j [q1, p1) Rn,j In,j [q1, p1), 3 , |f (n)(Ln,j, r)| > |Ln,j| |f (n)(Rn,j, r)| > |Rn,j| (, |A| A). , f (n)(x, r) - In,j. f

    (n)(x, r), -, y Ln,j z Rn,j, - | ddxf (n)(y, r)| > 1 | ddxf (n)(z, r)| > 1. f (n)(x, r) [p0, p1),

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  • - 93

    x Kn,j. , y x < z. f (n)(x, r) [y, z], ( 1.9) -, | ddxf (n)(x, r)| > 1. , In,j [q1, p1). In,j :

    In,j = Ln,j Kn,j Rn,j,

    f (n)(Ln,j, r) = [0, p0], f(n)(Kn,j, r) = (p0, p1), f

    (n)(Rn,j, r) = [p1, 1]. -, x Kn,j, f

    (n)(x, r) [p0, p1). x (q1, p1), Ln,j Rn,j [q1, p1). [q1, p1) , In,j . , Ln,j [q1, p1), Rn,j -. . In,j [q1, 1] In,j [q1, p1) 6= , p1 In,j. , |f (n)(Ln,j, r)| > |Ln,j|. y Ln,j, | ddxf (n)(y, r)| > 1. , | ddxf (n)(p1, r)| > 1, p1 - . , x [y, p1] f (n)(x, r) [y, p1]. , | ddxf (n)(x, r)| > 1.

    .

    . r > 4, r .

    , r > 2+5.

    4. -

    [0, 1] [0, 1],

    f(x) =

    3x, 0 x 1/3,1, 1/3 x < 1/2,1/2, x = 1/2,0, 1/2 < x 2/3,3x 2, 2/3 x 1.

    . 2.

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  • 94

    . 2. f(x)

    x , f(x) . x = .0abc . . . , f(x) = .abc . . . . x = .1abc . . . ,

    f(x) =

    1, , 1, 0,1/2, c 1,0, , 1, 2.

    x = .2abc . . . , f(x) = .abc . . . . , x 1, f(x) f(x) (x = 0, 1/2, 1). , - 1 ( 000 . . . , 222 . . . ), . ,

    , 0 2. .

    1/3, 2/3, 1/9, 2/9, . . . , , , -

    , 0 2. - x0 f

    (n)(x0) , , - , -

    . , x0 = .200220220 . . . , x1 = .00220220 . . . , x2 = .022022 . . . ,x3 = .22022022 . . . , x4 = .2022022 . . . , x5 = x2, x6 = x3 .. ,

    , .

    a, b, c, . . . x0 , - x0, x1 = f(x0), x2 = f

    (2)(x0), . . . (0, 1/3) a , (2/3, 1) b , (0, 1/3) - c .. , a, b, c, = 1, 1, 2, 2, 3, 3, . . . , x0 = .020022000222 . . . ( ).

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  • 3 95

    , ,

    , , -

    , -

    . ,

    .

    .

    5. 3

    J f : J J . , 3 f(x) , - S J ( ), :

    1) p, q S (p 6= q)

    limn sup |f

    (n)(p) f (n)(q)| > 0,

    limn inf |f

    (n)(p) f (n)(q)| = 0,2) p S q

    limn sup |f

    (n)(p) f (n)(q)| > 0. f(x) ( - ) - J , S J c . , , 3, . , 2)

    ( ) 1).

    6.

    , 0, 1, 2. - , ..

    3/2? -, .

    1-, 2-, (3/2)-.

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  • 96

    . - 0 ,

    . -

    - ( .

    .. ).

    ,

    . -

    . -

    . , -

    , . . -

    .

    X . N() , , -X. , X d = dimX, 0 d 1, 0 N() C/d, C - , d- X, ..

    C = lim0

    dN().

    d

    d = dimX = lim0

    lnN()

    ln 1, (1)

    lim0

    lnN()

    ln 1= lim

    0lnCd

    ln 1= lim

    0d ln 1 + lnC

    ln 1= d.

    (1) , d-. d X . X , N() = 1. - 0. X L, N() = L/. d = 1. C. = 1/3 N(), C, N(1/3) = 2. = 1/9, , N(1/9) = 4 = 1/3m N(1/3m) = 2m. - C

    d = limm

    ln 2m

    ln 3m=

    ln 2

    ln 3= 0.630929 . . . .

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  • 97

    .. C . 2

    . r1 = r2 = r, ,

    d =ln 2

    ln r1.

    , -

    d (0, 1). , r1 6= r2

    rd1 + rd2 = 1,

    (0, 1). , . , N(/2k) = 2k.

    d = limk

    ln 2k

    ln 2k

    = 1.

    . X - [0, 1]. |l| l. - X - li, .

    L(X, ) = infi

    |li|, (2)

    - X. (2) , -

    , L(X, ) , , . ( )

    L(X) = lim0

    L(X, )

    .

    , X X , L(X) L(X ). Xn. - {lni},

    i

    |lni| < L(Xn, ) + 2n L(Xn) +

    2n.

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  • 98

    - nXn, in

    |lni| . {li} - X,

    i

    |li| L(X, ) + 1 L(X) + 1 = K , , 0, L(X) = 0. L(X) , . , 0, L(X) = < 0 L(X) = 0 > 0. L(X) 0 , . 0 - X. dimX. ,

    dimX = sup{ : L(X) =} = inf{ : L(X) = 0}.

    :

    1) L(X) > 0 dimX ; 2) dimX L(X) =;

    3) L(X)

  • 99

    -

    , ,

    .

    . X(p) , 1 p, .. x = 0, 12 . . . X(p),

    limn

    1

    n

    nk=1

    k = p.

    , X(1/2) 1. , p 6= 1/2, X(p) 0. (. [2]),

    dimX(p) = 1ln 2

    [p ln p+ (1 p) ln(1 p)].

    r, xn() n- -

    r. , x =n=1

    xn()/rn.

    Ni(, n) , i x1(), . . . , xn(). X(p0, p1, . . . , pr1) x,

    limn

    Ni(, n)

    n= pi, i = 0, 1, . . . , r 1.

    ,

    dimX(p0, . . . , pr1) = 1ln r

    r1i=0

    pi ln pi.

    , -

    ln 2/ ln 3, .. .

    7.

    -

    .

    xn+1 = f(xn).

    f(x) , - |df/dx|. x0 x0 +

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  • 100

    O(x0) O(x0 + ) ,

    f(x0 + ) f(x0) = f (x0) + o(). , (n+ 1)- ,

    f (n)(x0 + ) f (n)(x0) = ddx

    f (n)(x)

    x=x0

    + o() = n1i=0

    f (f (i))(x0) + o().

    .

    = limn

    1

    nln ddx

    f (n)(x0) = lim

    n ln

    (n1i=0

    |f (f (i))(x0)|)1/n

    =

    = limn

    1

    n

    n1k=0

    ln |f (xk)|,

    xk = f(k)(x0), . , .

    xn+1 = axn.

    xn = an , = ln |a|. ln |a|>0, . ln |a| < 0, . - (p > 0)

    g(x) =

    {px, x < 1/2,p px, x 1/2. g(x) = p ,

    = ln p.

    , > 0 p > 1 . p < 1, < 0. . , (0, 1) x = 0. p = 2 ,

    f(x) = 4x(1x). ,

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  • 101

    f(x) g(x) h g(n) = f (n) h, h(x) , - . ,

    .

    f(x) = 4x(1x) = ln 2.

    xn = sin2(2n arcsin

    x0),

    xn+1 = 4xn(1 xn). , (. [24]), -

    ,

    f(x, r) = rx(1 x), 0 < r 4, , .

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  • 1. , .. /

    .. . .: , 1977. 368 .

    2. , . / . .

    .: , 1969. 239 .

    3. , .. / .. . .: , 1978.

    142 .

    4. , .. / .. //

    . : , 1974.

    . 109 138.

    5. , .. /

    .. . : , 1983. 296 .

    6. , .. -

    / .. , .. , .. : 92.33 /

    , 1992. 55 .

    7. / .. [ .].

    .: , 1992. 431 .

    8. , .. , / .. -

    , .. . : , 1992. 208 .

    9. , .. .

    3 . .2. / .. . .: , 1969. 800 .

    10. , .. / .. -

    , .. , .. . : , 1986.

    280 .

    11. / . [ .]. :

    , 1989. 216 .

    12. , . . / . . .: ,

    1988. 240 .

    13. Arterborn, D.R. A Cantor set of nonconvergence / D.R. Arterborn, W.D.

    Stone // Amer. Math. Mon. 1989. V. 96, 7. P. 604 608.

    14. Coppel, W.A. An interesting Cantor set / W.A. Coppel // Amer. Math. Mon.

    1983. V. 90, 7. P. 456 460.

    15. Devaney, R.L. An introduction to chaotic dynamical systems / R.L. Devaney.

    Menlo Park, California, Reading, 1986. 321 p.

    102

    Copyright & A K-C

  • 103

    16. Guckenheimer, J. On the bifurcation of maps on the interval / J. Guckenheimer

    // Invent. Math. 1977. V. 39, 2. P. 165 178.

    17. Guckenheimer, J. The dynamics of density dependent population models / J.

    Guckenheimer, G.R. Oster, A. Ipaktchi // J. Math. Biology. 1977. V. 4, 2.

    P. 101 147.

    18. Ho, C.W. A graph theoretic proof of Sharkovsky's theorem on the periodic

    points of continuous functions / C.W. Ho, C. Morris // Pacic J. Math. 1981.

    V. 96, 2. P. 361 370.

    19. Kraft, R.L. Chaos, Cantor sets, and hyperbolicity for the logistic maps /

    R.L. Kraft // Amer. Math. Mon. 1999. V. 106, 5. P. 400 408.

    20. Li, T.Y. Period three implies chaos / T.Y. Li, J.A. Yorke // Amer. Math.

    Mon. 1975. V. 82, 10. P. 985 992.

    21. Maeda, Y. Discretization of non-lipschitz continuous o.d.e. and chaos / Y. Maeda,

    M. Yamaguti // Proc. Japan Acad., Ser. A. 1996. V. 72, 2. P. 43 45.

    22. May, R.M. Biological populations obeying dierence equations: stable points,

    stable cicles and chaos / R.M. May // J. Theor. Biology. 1975. V. 51, 3.

    P. 511 526.

    23. May, R.M. Bifurcation and dynamic complexity in simple ecological models

    / R.M. May, G.F. Oster // Amer. Natur. 1976. V. 110, 974. P. 573 599.

    24. de Melo, W. One-dimensional dynamics. Ergebnisse der Mathematik und

    ihrer Grenzgebiete (3) / W. de Melo, S. van Strien. Berlin: Springer-Verlag, 1993.

    605 p.

    25. Phillipson, P.G. Analytics of period doubling / P.G. Phillipson // Commun.

    Math. Phys. 1987. V. 111, 1. P. 137 149.

    26. Rogers, T.D. Chaos in the cubic mapping / T.D. Rogers, D.C. Whitley //

    Math. Modelling. 1983. V. 4. P. 9 25.

    27. Saito, N. Exact solutions of simple nonlinear dierence equation systems that

    show chaotic behavior / N. Saito, A. Szabo, T. Tsuchiya // Z. Naturforsch. 1983.

    V. 38a, 9. P. 1035 1039.

    28. Singer, D. Stable orbits and bifurcation of maps of the interval / D. Singer//

    SIAM J. Appl. Math. 1978. V. 35, 2. P. 260 267.

    29. Smale, S. The qualitative analysis of a dierence equation of population

    growth / S. Smale, R.F. Williams// J. Math. Biology. 1976. V. 3, 1. P. 1 4.

    30. Stran, F.D.Jr. Periodic points of continuous functions / F.D.Jr. Stran //

    Math. Mag. 1978. V. 51, 2. P. 99 105.

    31. Whitley, D.C. Discrete dynamical systems in dimensions one and two /

    D.C. Whitley // Bull. London Math. Soc. 1983. V. 15, 3. P. 177 217.

    32. Whittaker, J.V. An analytical description of some simple cases of chaotic

    behavior / J. V. Whittaker // Amer. Math. Mon. 1991. V. 98, 6. P. 489 504.

    Copyright & A K-C

  • , ..

    , ..

    2.10.06. 6084/16. Data Copy.. . . 6,1. .-. . 5,9. 100 .

    - -

    .

    .. , . , 94, . 37.

    . (0852) 73-35-03

    Copyright & A K-C