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  • Nuclear Chemistry

    Copyright The McGraw-Hill Companies, Inc. Permission required for reproduction or display.

  • XAZ

    Mass Number

    Atomic NumberElement Symbol

    Atomic number (Z) = number of protons in nucleus

    Mass number (A) = number of protons + number of neutrons

    = atomic number (Z) + number of neutrons

    A

    Z

    1p1

    1H1or

    proton1n0

    neutron0e-1

    0b-1or

    electron0e+1

    0b+1or

    positron4He2

    4a2or

    a particle

    1

    1

    1

    0

    0

    -1

    0

    +1

    4

    2

    23.1

  • Diagram showing penetrating ability

    www.epa.gov

  • Balancing Nuclear Equations

    1. Conserve mass number (A).

    The sum of protons plus neutrons in the products must equal

    the sum of protons plus neutrons in the reactants.

    1n0U23592 + Cs

    13855 Rb

    9637

    1n0+ + 2

    235 + 1 = 138 + 96 + 2x1

    2. Conserve atomic number (Z) or nuclear charge.

    The sum of nuclear charges in the products must equal the

    sum of nuclear charges in the reactants.

    1n0U23592 + Cs

    13855 Rb

    9637

    1n0+ + 2

    92 + 0 = 55 + 37 + 2x023.1

  • 212Po decays by alpha emission. Write the balanced

    nuclear equation for the decay of 212Po.

    4He2

    4a2oralpha particle -

    212Po 4He + AX84 2 Z

    212 = 4 + A A = 208

    84 = 2 + Z Z = 82

    212Po 4He + 208Pb84 2 82

    23.1

  • 23.1

  • Nuclear Stability and Radioactive Decay

    Beta decay

    14C 14N + 0b + n6 7 -140K 40Ca + 0b + n19 20 -1

    1n 1p + 0b + n0 1 -1

    Decrease # of neutrons by 1

    Increase # of protons by 1

    Positron decay

    11C 11B + 0b + n6 5 +138K 38Ar + 0b + n19 18 +1

    1p 1n + 0b + n1 0 +1

    Increase # of neutrons by 1

    Decrease # of protons by 1

    n and n have A = 0 and Z = 023.2

  • Electron capture decay

    Increase # of neutrons by 1

    Decrease # of protons by 1

    Nuclear Stability and Radioactive Decay

    37Ar + 0e 37Cl + n18 17-1

    55Fe + 0e 55Mn + n26 25-1

    1p + 0e 1n + n1 0-1

    Alpha decay

    Decrease # of neutrons by 2

    Decrease # of protons by 2212Po 4He + 208Pb84 2 82

    Spontaneous fission

    252Cf 2125In + 21n98 49 023.2

  • n/p too large

    beta decay

    X

    n/p too small

    positron decay or electron capture

    Y

    23.2

  • Nuclear Stability

    Certain numbers of neutrons and protons are extra stable

    n or p = 2, 8, 20, 50, 82 and 126

    Like extra stable numbers of electrons in noble gases (e- = 2, 10, 18, 36, 54 and 86)

    Nuclei with even numbers of both protons and neutrons are more stable than those with odd numbers of neutron and protons

    All isotopes of the elements with atomic numbers higher than 83 are radioactive

    All isotopes of Tc and Pm are radioactive

    23.2

  • Nuclear binding energy (BE) is the energy required to break

    up a nucleus into its component protons and neutrons.

    BE + 19F 91p + 101n9 1 0

    BE = 9 x (p mass) + 10 x (n mass) 19F mass

    E = mc2

    BE (amu) = 9 x 1.007825 + 10 x 1.008665 18.9984

    BE = 0.1587 amu 1 amu = 1.49 x 10-10 J

    BE = 2.37 x 10-11J

    binding energy per nucleon = binding energy

    number of nucleons

    = 2.37 x 10-11 J

    19 nucleons= 1.25 x 10-12 J

    23.2

  • Nuclear binding energy per nucleon vs Mass number

    nuclear stability

    23.2

    nuclear binding energy

    nucleon

  • Kinetics of Radioactive Decay

    N daughter

    rate = -DN

    Dtrate = lN

    DN

    Dt= lN-

    N = N0exp(-lt) lnN = lnN0 - lt

    N = the number of atoms at time t

    N0 = the number of atoms at time t = 0

    l is the decay constant

    ln2=

    tl

    23.3

  • Kinetics of Radioactive Decay

    [N] = [N]0exp(-lt) ln[N] = ln[N]0 - lt

    [N]

    ln [

    N]

    23.3

  • Radiocarbon Dating

    14N + 1n 14C + 1H7 160

    14C 14N + 0b + n6 7 -1 t = 5730 years

    Uranium-238 Dating

    238U 206Pb + 8 4a + 6 0b92 -182 2 t = 4.51 x 109 years

    23.3

  • Nuclear Transmutation

    Cyclotron Particle Accelerator

    14N + 4a 17O + 1p7 2 8 1

    27Al + 4a 30P + 1n13 2 15 0

    14N + 1p 11C + 4a7 1 6 2

    23.4

  • Nuclear Transmutation

    23.4

  • Nuclear Fission

    23.5

    235U + 1n 90Sr + 143Xe + 31n + Energy92 54380 0

    Energy = [mass 235U + mass n (mass 90Sr + mass 143Xe + 3 x mass n )] x c2

    Energy = 3.3 x 10-11J per 235U

    = 2.0 x 1013 J per mole 235U

    Combustion of 1 ton of coal = 5 x 107 J

  • Nuclear Fission

    23.5

    235U + 1n 90Sr + 143Xe + 31n + Energy92 54380 0

    Representative fission reaction

  • Nuclear Fission

    23.5

    Nuclear chain reaction is a self-sustaining sequence of

    nuclear fission reactions.

    The minimum mass of fissionable material required to

    generate a self-sustaining nuclear chain reaction is the

    critical mass.

    Non-critical

    Critical

  • Schematic Diagram of a Nuclear Reactor

    23.5

  • Annual Waste Production

    23.5

    35,000 tons SO2

    4.5 x 106 tons CO2

    1,000 MW coal-fired

    power plant

    3.5 x 106

    ft3 ash

    1,000 MW nuclear

    power plant

    70 ft3

    vitrified

    waste

    Nuclear Fission

  • 23.5

    Nuclear Fission

    Hazards of the

    radioactivities in spent

    fuel compared to

    uranium ore

    From Science, Society and Americas Nuclear Waste, DOE/RW-0361 TG

  • Chemistry In Action: Natures Own Fission Reactor

    Natural Uranium

    0.7202 % U-235 99.2798% U-238

    Measured at Oklo

    0.7171 % U-235

  • 23.6

    Nuclear Fusion

    2H + 2H 3H + 1H1 1 1 1

    Fusion Reaction Energy Released

    2H + 3H 4He + 1n1 1 2 0

    6Li + 2H 2 4He3 1 2

    6.3 x 10-13 J

    2.8 x 10-12 J

    3.6 x 10-12 J

    Tokamak magnetic

    plasma

    confinement

  • 23.7

    Radioisotopes in Medicine

    1 out of every 3 hospital patients will undergo a nuclear medicine procedure

    24Na, t = 14.8 hr, b emitter, blood-flow tracer

    131I, t = 14.8 hr, b emitter, thyroid gland activity

    123I, t = 13.3 hr, g-ray emitter, brain imaging

    18F, t = 1.8 hr, b+ emitter, positron emission tomography

    99mTc, t = 6 hr, g-ray emitter, imaging agent

    Brain images

    with 123I-labeled

    compound

  • 23.7

    Radioisotopes in Medicine

    98Mo + 1n 99Mo42 0 42

    235U + 1n 99Mo + other fission products92 0 42

    99mTc 99Tc + g-ray43 43

    99Mo 99mTc + 0b + n42 43 -1

    Research production of 99Mo

    Commercial production of 99Mo

    t = 66 hours

    t = 6 hours

    Bone Scan with 99mTc

  • Geiger-Mller Counter

    23.7

  • 23.8

    Biological Effects of Radiation

    Radiation absorbed dose (rad)

    1 rad = 1 x 10-5 J/g of material

    Roentgen equivalent for man (rem)

    1 rem = 1 rad x Q Quality Factor

    g-ray = 1

    b = 1

    a = 20

  • Chemistry In Action: Food Irradiation

    Dosage Effect

    Up to 100 kilorad

    Inhibits sprouting of potatoes, onions, garlics.

    Inactivates trichinae in pork. Kills or prevents insects

    from reproducing in grains, fruits, and vegetables.

    100 1000 kilorads Delays spoilage of meat poultry and fish. Reduces

    salmonella. Extends shelf life of some fruit.

    1000 to 10,000 kiloradsSterilizes meat, poultry and fish. Kills insects and

    microorganisms in spices and seasoning.

  • Half-lifesThe rate at which a particular radioisotope decays is

    described by its half-life.

    The half-life is defined as the time that it takes for

    one half of a sample of a radioactive element to

    decay into another element.

    The half-life of a radioisotope is dependent only on

    what the radioisotope is.

  • Table N provides us

    with a list of various

    nuclides, their decay

    modes, and their half-

    lifes.

    Using Table N, what is

    the decay mode and

    half-life for Radium-

    226?

  • Using Table N

    Table N indicates that Radium-226 undergoes alpha

    decay.

    Based on this we can write a balanced nuclear equation to

    represent this reaction:

    This tells us that for every atom of Radium that

    decays an atom of Radon is produced.

  • Using Half-lifeTable N also tells us that Radium-226 has a half-life of

    1600 years.

    Starting with a 100g

    sample, after 1 half-

    life (or 1600 years),

    50g remain.

    After another 1600

    years, half of the

    50g will remain

    (25g).

  • Carbon-14 Dating

    The age of objects that were once alive can be

    determined by using the C-14 dating test. In this test,

    scientists determine how much C-14 is left in a sample

    and from this determine the age of the object.

    From Table N we can determine that C-14 undergoes

    b decay:

  • Where does the Carbon-14 come

    from?

    C-14 is created in the

    atmosphere by

    cosmic rays.

    It becomes part of living

    things through

    photosynthesis and the

    food chain.

    When the plant or

    animal dies, the C-14

    begins to decay.

  • Using C-14 to Age ObjectsBy comparing the amount of C-14 left in a sample to the amount that

    was present when it was alive, and using the half-life of 5700 years

    (Table N), one can determine the age of a sample.

  • Uranium-238 Series

    The Uranium-238 Decay Series is used to determine the age of

    rocks.

    In this series, the

    ratio of the U-

    238 to the Pb-

    206 is used to

    determine the

    age of the rock.

  • Parent-daughter Relationship

  • Aging moon rocks

    NASA astronauts have retrieved

    842 pounds (382 kg) of moon rocks

    (in many missions), which have

    been closely studied. The

    composition of the moon rocks is

    very similar to that of Earth rocks.

    Using radioisotope dating, it has

    been found that moon rocks are

    about 4.3 billion years old.

  • Sample Half-life Problem 1

    A 10 gram of sample of Iodine-131undergoes b decay, what

    will be the mass of iodine remaining after 24 days?

    From Table N, the life of iodine is determined to be

    approximately 8 days.

    That means that 24 days is equivalent to 3 half-lifes.

    The decay of 10 grams of I-131 would produce:

    1.25 grams of I-131 would remain after 24

    days.

  • Sample Half-life Problem 2A sample of a piece of wood is analyzed by C-14 dating. The

    percent of C-14 is found to be 25% of what the original C-14

    concentration was. What is the age of the sample?

    First, lets analyze how many half-lives have taken place.

    Two half-lives have gone by while the sample decayed from

    the original C-14 concentration to 25% of that concentration.

    Based on Table N, the half-life of C-14 is 5730 years,

    so

  • Your turn!

    On a sheet of paper, answer the following questions

    from your textbook. Indicate how you arrived at your

    answer and turn in your work for a homework/quiz

    grade.

    Page 670

    Questions 34 (a and b), 36, 37, 38, 41, 42.

    Page 671

    Questions 50, 58, 59

  • The End

    This is the end of the first slide show on

    nuclear reactions. You may continue

    learning about nuclear reactions by viewing

    the second show:

    Nuclear Chemistry:

    Fission and Fusion