unit 3 – quadratic & polynomial modeling - ligon nc math...

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Page 1: Unit 3 – Quadratic & Polynomial Modeling - Ligon NC Math …danielsroar.weebly.com/uploads/5/3/1/4/5314494/u3_cc… ·  · 2015-04-02Unit 3 – Quadratic & Polynomial Modeling

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Common Core Math 3 Unit 3 – Quadratic & Polynomial Modeling

A P E X H I G H S C H O O L

1501 L A U R A D U N C A N R O A D

A P E X , N C 27502

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VOCABULARY

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QUADRATIC REVIEW

Quadratic Function:

f (x) = ax2

+ bx + c where

a,b,&c are real

numbers and

a ! 0

! standard form

y = ax2

+ bx + c

" quadratic term: ax2, linear term: bx , constant term: c

! vertex form

y = a(x - h)2

+ k where

a,h,&k are real numbers and

a ! 0

! the graph is called a parabola

" If the “a” is positive (+), the parabola opens up.

" If the “a” is negative (–), the parabola opens down

! to graph a quadratic

" start with the parent graph (

y = x2

) and apply transformations

" make a T-chart

" use your calculator

! axis of symmetry

" in standard form

x = -b

2a

" in vertex form x=h

! vertex: the high point or low point of the graph

" in standard form

x = -b

2a is the x coord. of the vertex

" in vertex form the vertex is (h,k)

" the x coord. of the vertex is always the x value halfway between the x-

intercepts

" to find the y coord. plug in the value of the x coord. and solve for y

" use the calculator (2nd

Trace > minimum or maximum)

! x-intercepts: where the graph crosses the x-axis

" the real values of x that make y=0

" possible number of x-intercepts: 0, 1, 2

! zeros, solutions, roots: the values of x that make y=0

" may or may not be real

" real zeros, solutions, roots are x-intercepts

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! quadratic equation –

ax2

+ bx + c = 0 , to solve:

" use the calculator (2nd

Trace > zero)

" when there is no linear term, set y = 0 and solve for x (take the ± square

root)

" by factoring, set each factor = 0 and solve for x

" standard form: use the quadratic formula

x =-b ± b

2- 4ac

2a

! discriminant is the value of

b2

- 4ac

"

b2

- 4ac = 0 - one real rational double root; vertex of parabola lies

on the x-axis

"

b2

- 4ac > 0 and a perfect square - two real rational roots;

parabola intersects x-axis twice

" - two real irrational

roots; parabola intersects x-axis twice

"

b2

- 4ac < 0 - no real roots, two complex conjugate/imaginary roots;

parabola does not intersect the x-axis

! Using the calculator:

Enter your quadratic into Y=

(Be sure to use X as your independent variable)

To Find a Vertex (Maximum/Minimum):

1. Enter equation in Y =

2. Use CALC menu (2nd

TRACE)

Choose #3: minimum or #4: maximum

3. Move curser left/right until it is to the left of the vertex (close to point). Press ENTER

4. Move curser left/right until it is to the right of the vertex (close to point). Press ENTER

5. Press ENTER to reveal vertex (max/min)

To Find Zeros/Roots/X-Intercepts:

1. Enter equation in Y =

2. Use CALC menu (2nd

TRACE) Choose #2: zero

3. Move curser left/right until it is to the left of the zero (close to point). Press ENTER

4. Move curser left/right until it is to the right of the zero (close to point). Press ENTER

5. Press ENTER to reveal zero

You will need to repeat for each zero.

b2

- 4ac > 0 and not a perfect square

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Academic

FACTORING FLOW CHART

Check for a GCF.

Polynomial with 4 or more terms

Factor by Grouping

Addition or Subtraction?

Binomial Factors

Binomial (2 terms)

Trinomial (3 terms)

Factor into Binomial Factors

(Use any method or shortcut you’ve learned)

Binomial Factors

Addition Subtraction

Done

Check for Difference of Squares

a2-b2=(a+b)(a-b)

Done

Sum of Squares

PRIME

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Honors

FACTORING FLOW CHART

Check for a GCF.

Polynomial with 4 or more terms

Factor by Grouping

Addition or Subtraction?

Binomial Factors

Binomial (2 terms)

Trinomial (3 terms)

Factor into Binomial Factors

(Use any method or shortcut you’ve learned)

Binomial Factors

Addition Subtraction

Done

Check for Difference of Squares or Cubes

a2-b2=(a+b)(a-b) a3-b3=(a-b)(a2+ab+b2

)

Done

Check for Sum of Cubes

a3+b3=(a+b)(a2-ab+b2)

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Quadratics Worksheet 1

Graph: plot the vertex and 4 more points (2 on each side of vertex)

Parent Function y = x2 1. y = (x – 2)

2 + 1 2. y = x

2 +6x+5

3. y = –(x + 1)2 + 3 4. y = 2x

2 –12x +13 5. y = (x)

2 – 2

Put the following in standard form f(x) = ax2 + bx + c. Name the vertex and axis of symmetry!

6. f(x) = (x – 3)2 + 4 7. f(x) = (x + 1)

2 – 3 8. f(x) = 2(x – 4)

2 – 3

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Solve by Graphing:

9.

Solve by Graphing:

Parent Function y = x2 10. y = (x – 3)

2 – 1 11. y = -x

2 – 4x

x- intercepts: __________ _____________ _____________

12. y = –3(x + 4)2 + 3 13. y = 2x

2 – 4x 14. y = (x – 5)

2 – 2

x- intercepts: __________ _____________ _____________

Name the vertex of the graph _______________

Name the axis of symmetry ________________

What are the x-intercepts? _________________

Write the equation ________________________

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Solve by factoring:

15. x – 2x – 15 = 0 16. z – 5z = 0

17. x + 6x = -9 18. 3q – 7q = 20

18. 9y = 49 19.

2c2

- 24c + 54 = 0

20.

25x2

- 4 = 0 21.

25x2

- 30x + 9 = 0

Solve by taking the square root:

22.

5a2

-15 = 0 23.

3 x - 2( )2

= 24

24.

1

5x - 4( )

2

= 6 24.

3x2

+ 42 = 0

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Quadratic Worksheet 2

Identify the quadratic term, the linear term, and the constant term for each function.

1. f(x) = x2 + 14x + 49 2. f(x) = -3(2x + 1)

2

Graph each function. Name the vertex and the axis of symmetry.

3. f(x) = x2 – 10x + 25 4. f(x) = (x + 4)

2 – 6 5. f(x) = -(x – 1)

2 + 4

Vertex: __________ _____________ _____________

axis of sym: __________ _____________ _____________

Solve (i.e. find the x-intercepts) by graphing.

6. f(x) = -(x + 5)2 + 1 7. f(x) = x

2 + 2x 8. f(x) = 2(x + 3)

2 – 8

Vertex: __________ _____________ _____________

x- intercepts: __________ _____________ _____________

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Solve each equation. Remember to set equal to zero. If there is a linear term you can solve

some by factoring. If there is no linear term solve by taking the square root.

9. x2 – 4x – 12 = 0 10. x

2 – 16x + 64 = 0

11. x2 + 25 = 10x 12. 9z = 10z

2

13. 7x2 – 4x = 0 14. x

2 = 2x + 99

15. 5w2 – 35w + 60 = 0 16. 3x

2 + 24x + 45 = 0

17. 15m2 + 19m + 6 = 0 18. 4x

2 + 6 = 11x

19. 36x2 = 25 20. 12x

3 – 8x

2 = 15x

21. 6x3 = 5x

2 + 6 x 22. 9 = 64x

2

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Page 17: Unit 3 – Quadratic & Polynomial Modeling - Ligon NC Math …danielsroar.weebly.com/uploads/5/3/1/4/5314494/u3_cc… ·  · 2015-04-02Unit 3 – Quadratic & Polynomial Modeling

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Page 21: Unit 3 – Quadratic & Polynomial Modeling - Ligon NC Math …danielsroar.weebly.com/uploads/5/3/1/4/5314494/u3_cc… ·  · 2015-04-02Unit 3 – Quadratic & Polynomial Modeling

Quadratic Formula:

Solve using the Quadratic Formula

1.

3x2

+ 8x = 35 2.

3. 4.

5. 6.

Solve by taking the square root:

7. 3x2 = -81 7. 5x

2 + 18 = 3

8. (m – 2)2 = -16 10.

x =-b ± b

2- 4ac

2a

Page 22: Unit 3 – Quadratic & Polynomial Modeling - Ligon NC Math …danielsroar.weebly.com/uploads/5/3/1/4/5314494/u3_cc… ·  · 2015-04-02Unit 3 – Quadratic & Polynomial Modeling

Complex Numbers

We do NOT get a real number when we take the square root of a

negative number. For example

-9 is not a real number because there is

no real number that can be squared to a get -9.

Imaginary numbers are used when there is a negative number under a

square root. “i” is used to signify an imaginary number. The reason for

the name "imaginary" numbers is that when these numbers were first

proposed several hundred years ago, people could not "imagine" such a

number.

i=

-1 so …

-4 =

-1! 4 =

i 4= 2i

i =

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9 = i

13 =

i2 = i

6 = i

10 = i

14 =

i3 = i

7 = i

11 = etc….

i4 = i

8 = i

12 =

To simplify imaginary numbers with an exponent greater than 3:

1) Divide the exponent by 4

2) The remainder becomes the new exponent

3) Simplify

Examples: i13

i12

i94

i27

To simplify the square root of a negative number:

1) pull out the i

2) simplify the radical

Examples:

Page 23: Unit 3 – Quadratic & Polynomial Modeling - Ligon NC Math …danielsroar.weebly.com/uploads/5/3/1/4/5314494/u3_cc… ·  · 2015-04-02Unit 3 – Quadratic & Polynomial Modeling

If two square roots with negative numbers are being multiplied: pull out

the i BEFORE you multiply!

Examples:

-6 ! -10

-8 ! 2

Adding/Subtracting: combine like terms

Examples: (8 – 5i) + (2 + i) (4 + 7i) – (2 – 3i)

Multiplying with imaginary numbers: NEVER leave i2 in your answer!

Examples: (4 + 2i)(3 – 5i) (4 – i)(3 + 2i)

A complex number is any number that can be written in the

standard form a + bi, where a and b are real numbers, and i=

-1 .

! real numbers are complex numbers with b=0 ! pure imaginary numbers are complex numbers with a=0

Every complex number has a complex conjugate. The complex

conjugate of a + bi is a - bi . For example the conjugate of

3 + 5i is 3 – 5i.

What happens when you multiply conjugates?

Examples: (2 + i)(2 – i) (3 + 5i)(3 – 5i)

Page 24: Unit 3 – Quadratic & Polynomial Modeling - Ligon NC Math …danielsroar.weebly.com/uploads/5/3/1/4/5314494/u3_cc… ·  · 2015-04-02Unit 3 – Quadratic & Polynomial Modeling
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Page 26: Unit 3 – Quadratic & Polynomial Modeling - Ligon NC Math …danielsroar.weebly.com/uploads/5/3/1/4/5314494/u3_cc… ·  · 2015-04-02Unit 3 – Quadratic & Polynomial Modeling

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Page 29: Unit 3 – Quadratic & Polynomial Modeling - Ligon NC Math …danielsroar.weebly.com/uploads/5/3/1/4/5314494/u3_cc… ·  · 2015-04-02Unit 3 – Quadratic & Polynomial Modeling

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Page 30: Unit 3 – Quadratic & Polynomial Modeling - Ligon NC Math …danielsroar.weebly.com/uploads/5/3/1/4/5314494/u3_cc… ·  · 2015-04-02Unit 3 – Quadratic & Polynomial Modeling

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Page 31: Unit 3 – Quadratic & Polynomial Modeling - Ligon NC Math …danielsroar.weebly.com/uploads/5/3/1/4/5314494/u3_cc… ·  · 2015-04-02Unit 3 – Quadratic & Polynomial Modeling

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Page 32: Unit 3 – Quadratic & Polynomial Modeling - Ligon NC Math …danielsroar.weebly.com/uploads/5/3/1/4/5314494/u3_cc… ·  · 2015-04-02Unit 3 – Quadratic & Polynomial Modeling

Solving Quadratic Equations

Solve using any method.

1. 2x2 = 16

2. 4x2 + 8 = 0

3. 3x2 + 8x + 4 = 0

4. 9x2 + 15 = 0

5. 3x2 + 8 = 10

6. 2y2 + 2y – 24 = 0

7. b2 - 12b = 2b – 45

8. x2 = 8x + 20

9. 25x2 = -4

10. 5x2 + 6x – 12 = -4

11. 4x2 = 9

12. 2x2 + 12 = 0

13. 3x2 - 7x = 6

14. 2x2 = 12x – 16

15. x2 + 6x = 40

16. 15x2 = -10

17. x2 – 3x + 20 = 38

18. 15x2 + 8 = 5

19. 3n2 – 6n – 45 = 0

20. 5x2 – 12 = 18

21. 9x2 – 3x = 0

22. 3x2 – 8x = 0

23. 8x2 – 12 = -15

24. y2 - 7y = 30

25. x2 -7x + 10 = 0

26. 4x2 = 6x

27. 3x2 +4x – 12 = 3

28. 6x2 +17x + 5 = 0

29. 4y2 = -11y – 6

30. 6x2 = 3 - 7x

Page 33: Unit 3 – Quadratic & Polynomial Modeling - Ligon NC Math …danielsroar.weebly.com/uploads/5/3/1/4/5314494/u3_cc… ·  · 2015-04-02Unit 3 – Quadratic & Polynomial Modeling

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Page 34: Unit 3 – Quadratic & Polynomial Modeling - Ligon NC Math …danielsroar.weebly.com/uploads/5/3/1/4/5314494/u3_cc… ·  · 2015-04-02Unit 3 – Quadratic & Polynomial Modeling

Sum & Product of Roots Worksheet (Honors)

Solve each equation, then find the sum and product of the roots to check your solutions.

1. x2 – 7x + 4 = 0 2. x2 + 3x + 6 = 0

3. 2n2 + 5n + 6 = 0 4. 7x2 – 5x = 0

5. 4r2 – 9 = 0 6. –5x2 – x + 4 = 0

7. 3x2 + 8x = 3 8.

Write the quadratic equation, in standard form, that has the given roots

9. 7, -3 10.

11. 12.

13. 14. 7 – 2i , 7 + 2i

15. 8i, -8i 16.

17. 18.

Find k such that the number given is a root of the equation.

19. 7; 2x2 + kx – 21 = 0 20. –2; x2 – 13x + k = 0

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Quadratic Modelling Word Problems

1. A ball is thrown upward into the air with an initial velocity of 80 ft/sec. The

formula h(t) = 80t – 16t2 give its height h(t) after t seconds.

a) What is the height of the ball after 2 seconds?

b) What is the maximum height of the ball?

c) How long does it take the ball to reach its maximum height?

d) How long is the ball in the air?

When an equation is NOT given:

1. Define your variable(s)

2. Write an equation(s) to solve the problem.

3. State the solution.

4. Explain in words how you found the solution.

1. The length of a rectangular pool is 4 yd longer than its width. The area of the

pool is 60 yd. What are the dimensions of the pool? (6 x 10 yds)

2. A rectangle has a perimeter of 52 inches. Find the dimensions of the rectangle

with maximum area. (13 x 13 in)

3. Find two consecutive negative integers whose product is 240. (-15 & -16)

4. Find two numbers who sum is 20 and whose product is a maximum (10 & 10).

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Page 41: Unit 3 – Quadratic & Polynomial Modeling - Ligon NC Math …danielsroar.weebly.com/uploads/5/3/1/4/5314494/u3_cc… ·  · 2015-04-02Unit 3 – Quadratic & Polynomial Modeling

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Quadratic Equations Review #1

Solve each equation by factoring.

1. x2 ! 4x ! 32 = 0 2. 4x

2 + 20x = 0 3. d

2 ! 29d = -100 4. 18x

2 + 29x + 3 = 0

Solve each equation by completing the square.

5. x2 + 4 = 8x 6. x

2 !

5x = 8 7. 2x

2 ! 12x = 8 8. 4x

2 !12x = 16

Solve each equation by using the quadratic formula.

9. x2 + 2x = 7 10. 2x

2 ! 12x + 5 = 0 11. 2x ! 5x

2 + 3 = 0 12. 6x

2 ! 3x + 2 = 0

Solve each equation by using any method.

13. 3x2 + 6x +3 = 0 14. x

2 + 6x = 4 15. 2x

2 + x !1 = 3 16. 3x

2 + 2 = -7x

17. r2 = 3r + 70

18. (x ! 3)

2 = 6 19. 6x

2 – 8x + 9 = 4 20. 4x

2 + 8x = -3

Write the equation of the parabola with the given info:

21. Focus (-1, 6) Directrix y=0 22. Focus (3,-2) Directrix y=-4

Given a = -3 + 2i and b= 4-5i

23. Find a+ b 24. Find a – b 25. Find the product of a and b

26. Find 2a – 3b 27. Find a2 – b

2

Use your calculator to answer the following questions:

28. A ball is thrown upward vertically with an initial speed of 96 feet per second. The

equation h = 96t – 16t2 gives the height of the ball in t in seconds. What is the

maximum height reached by the ball? When will the ball be 128 feet above its

starting point?

29. Terry has 200 yards of fencing to enclose a rectangular garden on three sides. The

fourth side will be the side of the house. What dimensions of the garden will

maximize the area?

(HONORS) Write the quadratic equation with the given solutions

30. 3, -8 31. -5, 32.

33. 34. 35.

(HONORS) Solve by factoring.

36. x4 ! 6x

2 + 5 = 0 37. a

3 ! 81a = 0 38. 39.

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Page 48: Unit 3 – Quadratic & Polynomial Modeling - Ligon NC Math …danielsroar.weebly.com/uploads/5/3/1/4/5314494/u3_cc… ·  · 2015-04-02Unit 3 – Quadratic & Polynomial Modeling

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Page 50: Unit 3 – Quadratic & Polynomial Modeling - Ligon NC Math …danielsroar.weebly.com/uploads/5/3/1/4/5314494/u3_cc… ·  · 2015-04-02Unit 3 – Quadratic & Polynomial Modeling

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GRAPHS of POLYNOMIAL FUNCTIONS:

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END BEHAVIOR: Is the behavior of the graph as x approaches +! or -!

If the degree is EVEN, both ends have the SAME behavior

! If the leading coefficient is positive, both ends are up

! If the leading coefficient is negative, both ends are down

If the degree is odd, the ends have OPPOSITE behavior

! If the leading coefficient is positive, the right end is up, left down

! If the leading coefficient is negative, the right end is down, left up

Leading

Coefficient Degree Example x " - ! x " !

+ even f(x) = x2 f(x) " ! f(x) " !

- even f(x) = -x2 f(x) " -! f(x) " -!

+ odd f(x) = x3

f(x) " -! f(x) " !

- odd f(x) = -x3

f(x) " ! f(x) " -!

Page 52: Unit 3 – Quadratic & Polynomial Modeling - Ligon NC Math …danielsroar.weebly.com/uploads/5/3/1/4/5314494/u3_cc… ·  · 2015-04-02Unit 3 – Quadratic & Polynomial Modeling

The Fundamental Theorem of Algebra says that every polynomial with degree greater

then zero has at least one complex root. An extension of this theorem says that:

A polynomial of degree n has exactly n complex roots

In other words …. the degree of a polynomial = # of zeros/roots/solutions

Ex. x3 + 4x2 + 4x = 0 has 3 zeros Ex. x4 – 10x2 + 9 = 0 has 4 solutions

! solutions, zeros, and roots are the values of x which give y = 0

! complex roots means real and/or imaginary

o complex numbers have the form a + bi

! ‘n’ counts multiple roots the number of times they occur

o multiplicity is the number of times a zero occurs

! imaginary roots always come in conjugate pairs (a + bi, a – bi)

! each x-intercept represents a real root of the polynomial equation

! a polynomial function with odd degree must have at least 1 real root

o the graph must cross the x-axis at least once (think about the end behavior)

! a polynomial function with even degree will have either no real roots or an even

number of real roots

o the graph may or may not cross the x-axis, but if it does it will cross an even

number of times (think about the end behavior)

! every polynomial of degree n > 0 can be written as the product of a constant k

and n linear factors. P(x) = k(x – r1)(x – r2) (x – r3) ….(x – rn)

! to find zeros write the polynomial in factored form and set each factor = 0

! for polynomial P(x), if a is a zero then P(a) = 0

When finding the zeros of polynomials REMEMBER:

! #zeros = degree of polynomial = # of factors

! if a is a zero then (x-a) is a factor

! when you divide a polynomial by one of it’s factors the remainder is 0

! you can use division to break a polynomial down into its factors (just like you do

with numbers)

! for quadratics you have multiple tools for finding the zeros (factor, complete

the square, quadratic formula, graphing)

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Graphing Polynomial Functions Worksheet

To graph a polynomial function:

a. Find the zeros of the function. Remember real zeros = x-

intercepts so graph these points on the x-axis.

b. Find the y-intercept (value of y when x=0)

c. Determine the end behavior of the function based on the

degree and the leading coefficient.

d. Using the end behavior and the intercepts to make a smooth

curve.

Graph each function. USE GRAPH PAPER!

1.

y = -2 x2

- 9( ) x + 4( ) 2. y = (x2 -4)(x+3)

3. y = -1(x2-9)(x2-4) 4.

y =1

4x + 2( ) x -1( )

2

5.

y =1

5x - 3( )

2

x +1( )2

6.

y = x +1( )3

x - 4( )

7. y = x(x-1)(x+5) 8. y = x2 (x + 4) (x-3)

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Page 57: Unit 3 – Quadratic & Polynomial Modeling - Ligon NC Math …danielsroar.weebly.com/uploads/5/3/1/4/5314494/u3_cc… ·  · 2015-04-02Unit 3 – Quadratic & Polynomial Modeling

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Page 58: Unit 3 – Quadratic & Polynomial Modeling - Ligon NC Math …danielsroar.weebly.com/uploads/5/3/1/4/5314494/u3_cc… ·  · 2015-04-02Unit 3 – Quadratic & Polynomial Modeling

!"#$%&$'()*'+','-#).%&#)$%&)(-&//'('&#$)-/)0)'#)$%&)1'+',-2)3)4) ) 567879!:)

Divide:

Step 1: To set up the problem, first, set the denominator

equal to zero to find the number to put in the division

box. Next, make sure the numerator is written in

descending order and if any terms are missing you must

use a zero to fill in the missing term, finally list only the

coefficient in the division problem.

Step 2: Once the problem is set up correctly, bring the

leading coefficient (first number) straight down.

Step 3: Multiply the number in the division box with

the number you brought down and put the result in the

next column.

Step 4: Add the two numbers together and write the

result in the bottom of the row.

Step 5: Repeat steps 3 and 4 until you reach the end of

the problem.

Step 6 : Write the final answer. The final answer is

made up of the numbers in the bottom row with the last

number being the remainder and the remainder must be

written as a fraction. The variables or x’s start off one

power less than the original denominator and go down

one with each term.

Multiply everything by 1/2 to

eliminate the fraction in the

denominator

2x^2 - 3x - 2 + 3/(2x - 1)

is the answer

!

Page 59: Unit 3 – Quadratic & Polynomial Modeling - Ligon NC Math …danielsroar.weebly.com/uploads/5/3/1/4/5314494/u3_cc… ·  · 2015-04-02Unit 3 – Quadratic & Polynomial Modeling

Dividing Polynomials - EXAMPLES

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Page 60: Unit 3 – Quadratic & Polynomial Modeling - Ligon NC Math …danielsroar.weebly.com/uploads/5/3/1/4/5314494/u3_cc… ·  · 2015-04-02Unit 3 – Quadratic & Polynomial Modeling

Polynomial Division Worksheet

Divide using Synthetic Division

1. (3y3 + 2y

2 – 32y + 2) / (y – 3)

2. (2b3 + b

2 – 2b + 3) / (b + 1)

3. (2c3 – 3c

2 + 3c – 4) / (c – 2)

4. (3x3 – 2x

2 + 2x – 1) / (x – 1)

5. (t4 – 2t

3 + t

2 – 3t + 2) / (t – 2)

6. (3r4 – 6r

3 – 2r

2 + r – 6) / (r + 1)

7. (z4 – 3z

3 – z

2 – 11z – 4) / (z – 4)

8. (2b3 – 11b

2 + 12b + 9) / (b – 3)

9. (6s3 – 19s

2 + s + 6) / (s – 3)

10. (x3 + 2x

2 – 5x – 6) / (x – 2)

11. (x3 + 3x

2 – 7x + 1) / (x – 1)

12. (n4 – 8n

3 + 54n + 105) / (n – 5)

13. (2x4 – 5x

3 + 2x – 3) / (x – 1)

14. (z5 – 6z

3 + 4x

2 – 3) / (z – 2)

15. (y4 + 3y

3 + y – 1) / (y + 3)

Divide using long division:

16. (4s4 – 5s

2 + 2s + 3) / (2s – 1)

17. (2x3 – 3x

2 – 8x + 4) / (2x + 1)

18. (4x4 – 5x

2 – 8x – 10) / (2x – 3)

19. (6j3 – 28j

2 + 19j + 3) / (3j – 2)

20. (y5 – 3y

2 – 20) / (y – 2)

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Remainder Theorem: The value of the polynomial p(x) at x=a is the same

as the remainder you get when you divide that polynomial p(x) by x – a.

! To evaluate a polynomial p(x) at x = a, use synthetic division to divide

the polynomial by x = a. The remainder is p(a).

Use the Remainder Theorem and synthetic division to find f(4) where

f(x) =

The Remainder Theorem tells us that if we use synthetic division and divide

f(x) by (x-4), the remainder will be equal to f(4).

The remainder is 127. So f(4) = 127.

Factor Theorem: p(a) = 0 if and only if x – a is a factor of p(x).

! If you divide a polynomial by x = a and get a zero remainder, then, not

only is x = a a zero of the polynomial, but x – a is also a factor of the

polynomial.

Determine whether x + 4 is a factor of each polynomial.

Note: synthetic division can be used instead of long division !

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Practice 6-3 Dividing Polynomials

Determine whether each binomial is a factor of x3 ± 3x2 – 10x – 24.

1. x + 4 2. x - 3 3. x + 6 4. x + 2

Divide using synthetic division.

5. (x3 - 8x2 + 17x - 10) ! (x - 5) 6. (x3 + 5x2 - x - 9) ! (x + 2)

7. (-2x3 + 15x2 - 22x - 15) ! (x - 3) 8. (x3 + 7x2 + 15x + 9) ! (x + 1)

9. (x3 + 2x2 + 5x + 12) ! (x + 3) 10. (x3 - 5x2 - 7x + 25) ! (x - 5)

11. (x4 - x3 + x2 - x + 1) ! (x - 1) 12.

13. (x4 - 5x3 + 5x2 + 7x - 12) ! (x - 4) 14. (2x4 + 23x3 + 60x2 - 125x - 500) ! (x + 4)

Use synthetic division and the Remainder Theorem to find P(a).

15. P(x) = 3x3 - 4x2 - 5x + 1; a = 2 16. P(x) = x3 + 7x2 + 12x - 3; a = -5

17. P(x) = x3 + 6x2 + 10x + 3; a = -3 18. P(x) = 2x4 - 9x3 + 7x2 - 5x + 11; a = 4

Divide using long division. Check your answers.

19. (x2 - 13x - 48) ! (x + 3) 20. (2x2 + x - 7) ! (x - 5)

21. (x3 + 5x2 - 3x - 1) ! (x - 1) 22. (3x3 - x2 - 7x + 6) ! (x + 2)

Use synthetic division and the given factor to completely factor eachpolynomial function.

23. y = x3 + 3x2 - 13x - 15; (x + 5) 24. y = x3 - 3x2 - 10x + 24; (x - 2)

Divide.

25. (6x3 + 2x2 - 11x + 12) ! (3x + 4) 26. (x4 + 2x3 + x - 3) ! (x - 1)

27. (2x4 + 3x3 - 4x2 + x + 1) ! (2x - 1) 28. (x5 - 1) ! (x - 1)

29. (x4 - 3x2 - 10) ! (x - 2) 30.

31. A box is to be mailed. The volume in cubic inches of the box can be expressed as the product of its three dimensions:V(x) = x3 - 16x2 + 79x - 120. The length is x - 8. Find linearexpressions for the other dimensions. Assume that the width is greater than the height.

(3x3 2 2x2 1 2x 1 1) 4 ax 1 13b

ax4 1 53x

3 2 23x

2 1 6x 2 2b 4 ax 2 13b

Name Class Date

Lesson 6-3 Practice Algebra 2 Chapter 64

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Page 67: Unit 3 – Quadratic & Polynomial Modeling - Ligon NC Math …danielsroar.weebly.com/uploads/5/3/1/4/5314494/u3_cc… ·  · 2015-04-02Unit 3 – Quadratic & Polynomial Modeling

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Page 70: Unit 3 – Quadratic & Polynomial Modeling - Ligon NC Math …danielsroar.weebly.com/uploads/5/3/1/4/5314494/u3_cc… ·  · 2015-04-02Unit 3 – Quadratic & Polynomial Modeling

HONORS

EXAMPLES: Find the possible rational roots, then find all the zeros.

1.

3x3

- x2

-15x + 5 = 0 2.

x4

- 5x3

+ 9x2

- 7x + 2 = 0

PRACTICE:

1. Solve

2. Solve

3. Find all the zeros of

f x( ) = x4

- x3

+ 2x2

- 4x - 8

4. Find all the roots of

5. Find all the zeros of

6. Find all the solutions of

0 = 15x4

+ 68x3

- 7x2

+ 24x - 4

Page 71: Unit 3 – Quadratic & Polynomial Modeling - Ligon NC Math …danielsroar.weebly.com/uploads/5/3/1/4/5314494/u3_cc… ·  · 2015-04-02Unit 3 – Quadratic & Polynomial Modeling

Rational Root Theorem Worksheet

Find all the roots.

1.

p x( ) = x4

+ 5x3

+ 5x2

- 5x - 6 2.

p x( ) = x3

- 5x2

- 4x + 20

3.

p x( ) = x4

- 5x3

+ 9x2

- 7x + 2 4.

p x( ) = x3

- 2x2

- 8x

5.

p x( ) = x3

+ 7x2

+ 7x -15 6.

p x( ) = 2x3

- 5x2

- 28x +15

7.

p x( ) = x3

- 7x - 6 8.

p x( ) = x4

+ 2x3

- 9x2

- 2x + 8

Page 72: Unit 3 – Quadratic & Polynomial Modeling - Ligon NC Math …danielsroar.weebly.com/uploads/5/3/1/4/5314494/u3_cc… ·  · 2015-04-02Unit 3 – Quadratic & Polynomial Modeling
Page 73: Unit 3 – Quadratic & Polynomial Modeling - Ligon NC Math …danielsroar.weebly.com/uploads/5/3/1/4/5314494/u3_cc… ·  · 2015-04-02Unit 3 – Quadratic & Polynomial Modeling

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Page 74: Unit 3 – Quadratic & Polynomial Modeling - Ligon NC Math …danielsroar.weebly.com/uploads/5/3/1/4/5314494/u3_cc… ·  · 2015-04-02Unit 3 – Quadratic & Polynomial Modeling

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Page 75: Unit 3 – Quadratic & Polynomial Modeling - Ligon NC Math …danielsroar.weebly.com/uploads/5/3/1/4/5314494/u3_cc… ·  · 2015-04-02Unit 3 – Quadratic & Polynomial Modeling