ugwt design
DESCRIPTION
Manual design of underground water tankTRANSCRIPT
6 7 ft7 ft
4inches
6 7 8.2ft ft ft
10inches
10 ft1 ft
7 X 6 ft2
Thickness of Top slab = 4 inches
Thickness of Bottom Slab = 10 inches
Thickness of Wall = 6 inches
Clear Height of Wall = 7 ft(Excluding Top & Bottom Slab)
Overhang Length = 1 ft
γc (Density of Concrete) 0.15 ksf
γsoil (Density of Soil) 0.11 ksf
γwater (Density of Water) 0.0624 ksf
1. DESIGN OF WALLSa.) INNER FACE OF WALL
7ft
A
Rectangular UGWT
DESIGN
Dimensions or Parameters :
Total Area ( Length X Width ) =
Pwater = 0.4368 ksf
Mu(A) = 1.7 x Pwater x l2 x 1.3 = 3.15 k-ft/ft15
As = 0.1834 in2> Ast (min) = 0.108 in2
(Therefore Ast Governs )Use bar no 3
VERTICAL R/FCalculated Reinforcement: Use 3 7.22 in c/c
Provided Reinforcement : Use 3 6 in c/c
HORIZONTAL R/F As(min) = 0.18 in2(FOR ONE FACE)
Use bar no 3Calculated Reinforcement: Use 3 7.36 in c/c
Provided Reinforcement : Use 3 7 in c/c
b.) OUTER FACE OF WALL
7.0ft
Pwater = 0.5096 ksfPsoil = 0.7700 ksf
Mu(A) = 1.7 x Pwater x l2 x 1.3 + 1.7 x Psoil x l2 x 1.3 = 5.56 k-ft/ft15 15
Ast = 0.3366 in2> Ast (min) = 0.108 in2
(Therefore Ast Governs )Use bar no 4
VERTICAL R/FCalculated Reinforcement: Use 4 7.00 in c/c
Provided Reinforcement : Use 4 6 in c/c
HORIZONTAL R/F As (min) = 0.18 in2(FOR ONE FACE)
Use bar no 3Calculated Reinforcement: Use 3 7.36 in c/c
Provided Reinforcement : Use 3 6 in c/c
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