thermodynamics 1 - properties of pure substances
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Thermodynamics 1 - Properties of Pure SubstancesTRANSCRIPT
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Chapter 3 Thermodynamics 1 1
Thermodynamics I
Introduction 1. Basic Concepts of Thermodynamics 2. Energy, Energy Transfer, and General Energy Analysis 3. Properties of Pure Substances 4. Energy Analysis of Closed Systems 5. Energy and Mass Analysis of Control Volumes 6. The Second Law of Thermodynamics 7. Entropy 8. Steam Power Cycle Applications Examples
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Chapter 3 EG-161: Thermodynamics 1 2
Overview Properties of Pure Substances
3-1 Pure Substance 3-2 Phases of a Pure Substance 3-3 Phase-Change Processes of Pure Substances 3-4 Property Diagrams for Phase-Change Processes 3-5 Property Tables 3-6 The Ideal-Gas Equation of State 3-7 Compressibility Factor
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Chapter 3 EG-161: Thermodynamics 1 3
Pure Substance A pure substance has a
fixed chemical composition throughout various processes.
Examples are: water, nitrogen, helium and carbon dioxide.
Homogeneous mixtures also qualify as pure substances (e.g. air).
A mixture of two or more phases can still be a pure substance.
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Chapter 3 EG-161: Thermodynamics 1 4
Phases of a Pure Substance 3 principal phases: solid, liquid and
gas-phase. Substances may have several phases
with the principal phase (e.g. ice has 7, iron has 3, carbon has 2).
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Chapter 3 EG-161: Thermodynamics 1 5
Phase-Change Processes
Subcooled/compressed liquid
Saturated Liquid Saturated Liquid-Vapour Mixture
Saturated Vapour
Superheated Vapour
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Chapter 3 EG-161: Thermodynamics 1 6
Property Diagrams for Phase-Change Processes: T-v
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Chapter 3 EG-161: Thermodynamics 1 7
Property Diagrams for Phase-Change Processes: P-v
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Chapter 3 EG-161: Thermodynamics 1 8
Rankine Cycle - Phase Change
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Chapter 3 EG-161: Thermodynamics 1 9
Saturation Temperature and Saturation Pressure
The temperature at which water starts boiling depends on the pressure.
If the pressure is fixed, so is the boiling temperature. During the phase change the two phases are in equilibrium. For a pure substance and a given pressure the phase-change
temperature is called saturation temperature Tsat. For a pure substance and a given temperature the phase-change
pressure is called saturation pressure Psat.
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Chapter 3 EG-161: Thermodynamics 1 10
Some Consequences of Tsat and Psat Dependence
The temperature of liquid nitrogen exposed to the atmosphere remains constant at 196C, and thus it maintains the test chamber at 196C.
In 1775, ice was made by evacuating
the air space in a water tank.
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Chapter 3 EG-161: Thermodynamics 1 11
P-v Diagram for Substance that Contracts/Expands on Freezing
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Chapter 3 EG-161: Thermodynamics 1 12
P-T or Phase Diagram
Substance Ttp (K) Ptp (kPa) Water 273.16 0.61
Nitrogen 63.18 12.6
Latent heat of sublimation/ deposition
Latent heat of vaporization/ condensation
Latent heat of fusion
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Chapter 3 EG-161: Thermodynamics 1 13
Enthalpy
Enthalpy is a combination property. In the analysis of cycles we
frequently encounter the expression:
U+PV For simplicity reason this quantity
is termed enthalpy: H=U+PV (kJ) h=u+Pv (kJ/kg)
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Chapter 3 EG-161: Thermodynamics 1 14
Saturated Liquid and Vapour States
vf: specific volume of saturated liquid
vf vg vg: specific volume of saturated vapour
fg g f
fg g f
fg g f
fg g f
v v vu u uh h hs s s
=
=
=
=
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Chapter 3 EG-161: Thermodynamics 1 15
A rigid tank contains 50 kg of saturated liquid water at 90C. Determine the pressure in the tank and the volume of the tank.
Saturated Liquid and Vapour States Example
Answer: P=70.18kPa V=0.0518m3
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Chapter 3 EG-161: Thermodynamics 1 16
A mass of 200g of saturated liquid water is completely vaporized at a constant pressure of 100kPa. Determine a) the volume change and b) the amount of energy added to the water.
Saturated Liquid and Vapour States Example
Answer: DV=0.3386m3 DE=451.6kJ
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Chapter 3 EG-161: Thermodynamics 1 17
To analyse a liquid-vapour mixture in the wet-region we need to know the proportions of the liquid and the vapour phases.
The new property is called quality x:
where
Saturated Liquid-Vapour Mixtures Quality x
1
vapour
total
liquid
total
mx
mm
xm
=
=
: mass fraction of vapour
: mass fraction of liquid (or simply moisture)
total liquid vapour f gm m m m m= + = +
(
using 1
or1 )
f g
f g gf f g
f g f fg
g
V V Vm m m m
mv m v m v x xm m m
v x v xv v v xv
= +
= + = =
= + =
=
+
and
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Chapter 3 EG-161: Thermodynamics 1 18
Saturated Liquid-Vapour Mixtures Quality x
f
fg
f fg
f fg
f fg
f fg
v vx
vv v xv
u u xuh h xhs s xs
=
= +
= +
= +
= +
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Chapter 3 EG-161: Thermodynamics 1 19
Saturated Liquid-Vapour Mixtures Example
Answer: P=70.18kPa V=4.73m3
A rigid tank contains 10 kg of saturated liquid water at 90C. If 8 kg of the water is in the liquid phase and the rest is in the vapour phase, determine a) the pressure in the tank, and b) the volume of the tank.
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Chapter 3 EG-161: Thermodynamics 1 20
Saturated Liquid-Vapour Mixtures Example
Answer: T=Tsat@kPa=-15.60C x=0.158 h=62.7kJ/kg mg=0.632kg and Vg=0.0777m3
An 80 L vessel contains 4 kg of refrigerant 134-a at a pressure of 160kPa. Determine a) the temperature of refrigerant, b) the quality, c) the enthalpy of the refrigerant, and d) the volume occupied by the vapour phase.
1
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Chapter 3 EG-161: Thermodynamics 1 21
Compressed Liquid A compressed liquid is to be approximated as saturated liquid at
the given temperature. The properties depend more on the temperature than they do
on the pressure.
Example: Determine the internal energy of compressed liquid water at 80C and 5 MPa: From compressed liquid table:
u=333.72kJ/kg From saturation table:
u334.86kJ/kg Error: 0.34%
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Chapter 3 EG-161: Thermodynamics 1 22
Superheated Vapour Pressure and
Temperature are no longer dependent variables.
Super-heated vapour is a single-phase substance.
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Chapter 3 EG-161: Thermodynamics 1 23
Determine the temperature of water at a state of P=0.5MPa
and h=2890kJ/kg.
Answer:
At 0.5MPa saturated vapour: hg=2748.7kJ/kg. Therefore we have super- heated vapour. Linear interpolation from tables gives: T=216.4C
Superheated Vapour Example
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Chapter 3 EG-161: Thermodynamics 1 24
THE IDEAL-GAS EQUATION OF STATE
Equation of state: Any equation that relates the pressure, temperature, and specific volume of a substance.
The simplest and best-known equation of state for substances in the gas phase is the ideal-gas equation of state. This equation predicts the P-v-T behavior of a gas quite accurately within some properly selected region.
R: gas constant M: molar mass (kg/kmol) Ru: universal gas constant
Ideal gas equation of state P: absolute pressure T: absolute temperature in Kelvin
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Chapter 3 EG-161: Thermodynamics 1 25
THE IDEAL-GAS EQUATION OF STATE
Different substances have different gas constants.
Various expressions of ideal gas equation
Ideal gas equation at two states for a fixed mass
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Chapter 3 EG-161: Thermodynamics 1 26
Compressibility Factor The compressibility factor Z is a correction factor and is a
measure of the deviation from ideal-gas behaviour. Z is defined as:
ideal
actual
vvZ
ZRTPvRTPvZ
=
=
=
or
Thermodynamics IOverview Properties of Pure SubstancesPure SubstancePhases of a Pure SubstancePhase-Change ProcessesProperty Diagrams for Phase-Change Processes: T-vProperty Diagrams for Phase-Change Processes: P-vRankine Cycle - Phase Change Saturation Temperature and Saturation PressureSome Consequences of Tsat and Psat DependenceP-v Diagram for Substance that Contracts/Expands on FreezingP-T or Phase DiagramEnthalpySaturated Liquid and Vapour StatesSaturated Liquid and Vapour StatesExampleSaturated Liquid and Vapour StatesExampleSaturated Liquid-Vapour MixturesQuality xSaturated Liquid-Vapour MixturesQuality xSaturated Liquid-Vapour MixturesExampleSaturated Liquid-Vapour MixturesExampleCompressed LiquidSuperheated VapourSuperheated VapourExampleTHE IDEAL-GAS EQUATION OF STATETHE IDEAL-GAS EQUATION OF STATECompressibility Factor