pure substances elements

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Pure Substances Elements Composed of one type of atom Metal, Non-metal or Metalloid Simplest type of matter that retains characteristic

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Pure Substances Elements. Composed of one type of atom Metal, Non-metal or Metalloid Simplest type of matter that retains characteristic properties. Pure Substances Compounds. A combination of two or more elements Properties differ from those of component elements - PowerPoint PPT Presentation

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Page 1: Pure Substances Elements

Pure SubstancesElements

Composed of one type of atomMetal, Non-metal or MetalloidSimplest type of matter that retains characteristic properties

Page 2: Pure Substances Elements

Pure SubstancesCompounds

A combination of two or more elements

Properties differ from those of component elements

Separated by chemical means

Page 3: Pure Substances Elements

MixturesHeterogeneous

Has one or more visible boundaries between the components

Composition is not uniformSome boundaries may only be seen with a microscope ie. Blood, milk

Page 4: Pure Substances Elements

MixturesHomogeneous

No visible boundaries because components are mixed as individual atoms, ions or molecules

Composition is uniform on a molecular level

Alloy- steel, a combination of Fe and CWe cannot tell visually whether an object

is a substance or a homogenous mixture

Page 5: Pure Substances Elements

FiltrationSeparates the components of a

mixture on the basis of differences in particle size

Usually a heterogeneous mixtureMost common method is to use filter

paper to separate the components. The remaining liquid, after separation, is the filtrate.

Page 6: Pure Substances Elements

Separation techniquesFiltration – uses a porous barrier to separate

a (non-dissolved) solid from a liquid

Page 7: Pure Substances Elements

DistillationSeparates components through differences in

volatility : used for homogenous mixtures

The mixture is heated until the substance with the lowest boiling point becomes a vapor that can be condensed into a liquid and collected.

If the distillation is controlled ,you can separate substances that differ by a few degrees.

Page 8: Pure Substances Elements

Distillation – separates liquids based on their boiling points

Page 9: Pure Substances Elements

CrystallizationBased on differences in solubilityWhen a solution contains as much

dissolved substance as it can possibly hold it has reached the saturation point

The addition of even a tiny amount causes the dissolved substance to come out and collect as crystals

Page 10: Pure Substances Elements

Crystallization – a method of extracting dissolved solids from a solution

Page 11: Pure Substances Elements

ChromatographyBased on differences in solubilityThe separation is based on the

various components of the mixture spreading out through the paper at different rates

Components with the strongest attraction for the paper move slower (highly soluble)

Page 12: Pure Substances Elements

Chromatography – separates components of a mixture based on how well it can travel across a particular material

Page 13: Pure Substances Elements

Law of Conservation of Mass

Mass is neither created nor destroyed it just changes form:

Mass reactants = Mass products

Page 14: Pure Substances Elements

A 10.0 g sample of magnesium reacts with oxygen to form 16.6 g of magnesium oxide. How many grams of oxygen reacted?

What part of the reaction is a compound?

Page 15: Pure Substances Elements

From a laboratory process designed to separate water into hydrogen and oxygen gas, a student collected 10.0 g of hydrogen and 79.4 g of oxygen. How much water was originally involved in the process?

Page 16: Pure Substances Elements

If 19.9 grams of copper are burned in air to produce 25.0 grams of copper oxide, what is the mass of oxygen from the air that is needed?

Page 17: Pure Substances Elements

Law of Conservation of MassApplies to compounds:

The mass of a compound is equal to the sum of the masses of the elements that make up that compound

Page 18: Pure Substances Elements

20.00 g of sugarCarbon 8.44Hydrogen 1.30Oxygen 10.26 sum 20.00

Find Percent by Mass of each element:

Page 19: Pure Substances Elements

Law of Definite Proportions

percent by mass = mass of element x 100 mass of compound

Page 20: Pure Substances Elements

Carbon: 8.44 g C X 100 = 42.20 % 20.00 g sucrose

Hydrogen: 1.30 g H X 100 = 6.50 % 20.00 g sucrose

Oxygen:

Page 21: Pure Substances Elements

Analyze 500.0 g sucrose

Carbon 211.0Hydrogen 32.5Oxygen 256.5 sum 500.0

Page 22: Pure Substances Elements

A 78.0 g sample of an unknown compound contains 12.4 g of hydrogen. What is the percent by mass of hydrogen in the compound?

Page 23: Pure Substances Elements

What is the percentage by mass of I if 4.07 g reacts with 10.63 g of II to form a compound of mass 14.70 g? Also, calculate the percentage by mass of II in the compound.