Stoichiometry !!

Problem

What mass of CdS is produced if 8.47g of cadmium reacts with 2.51g of sulfur ?

Cd + S CdSNext!!

What’s The First Step To Solving This Problem ?

.

Convert The Grams Into Moles.

Figure Out The Grams For Cd

Back !!

Make Sure The Problem Is Balanced.

Sorry. Try Again !!

.

Back To Question!!

The Next Step Is Changing 8.47g of Cd Into Moles. How

Would You Do That ?.

8.47gCd * gCd

molCd

41.112

1

molCd

gCd

1

47.8molCdS

molCd

1

1112.41gCd *

Back To Problem !!

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Back To Question !!

The Next Step Is: Where Did The 1’s Come

From ?

molCd

molCdS

1

1

The ChargesThe coefficientsThe Mass

Back To The Problem !!

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Back To Question !!

The Mass of CdS (144.47)would go over ??

.

1molCdS 1molCd112.41gCd

Back To Problem !!

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Back To The Question !!

Do The Calculations !!

• 8.47gCd * * * is equal to ??

gCd

molCd

41.112

1

molCd

molCdS

1

1molCdS

gCdS

1

47.144

10.89gCd 10.89molCd 10.89gCdS

Back To Problem !!

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Back To Question !!

Now, Change 2.51gS into grams of CdS.

.

2.51gS * * * = 11.31gCd

2.51gS * * * = 11.31gS

gSmolS065.321

molS

gCdS

1

475.144

molSmolCdS11

2.51gS * * * = 11.31gCdS

gSmolS065.321

molSmolCdS11

molS

gCdS

1

475.144

gSmolS065.321

molSmolCdS11

molS

gCdS

1

475.144

Sorry. Try Again !!

Back To Question!!

8.47gCd is 10.89gCdS. 2.51gS is 11.31gCdS. Which

one is the limiting reactant ?

• .

Cd S

Your Finished !!

•Good Job !!

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Back To Question !!