solved problems in vibration

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    Turning moment diagram of a

    multi cylinder engine

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    A three cylinder engine has its crank set equally at

    1200 and runs at 700 rev/min. the turning moment

    diagram for each cylinder is a triangle and

    maximum torque is 80 Nm at 60 0from top deadcentre of the corresponding crank. The torque on

    the return stroke is zero. Determine,

    1. Power developed

    2. coefficient of fluctuation of speed if the mass of the fly

    wheel is 10 kg and the radius of gyration is 100 mm.

    3. Coefficient of fluctuation of energy

    4. the maximum angular acceleration of the flywheel

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    The turning moment diagram

    0 60 120 180 240 300 360 420

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    Solution

    The work done per cycle = are of three triangles

    Nm120

    802

    1

    3

    Mean torque= Nm602

    120

    2

    cycleperdoneWork

    m

    T

    Power = kW4.4100060

    607002

    100060

    2

    x

    x

    x

    NTP

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    The combined turning moment

    diagram

    0 60 120 180 240 300 360

    A

    B

    C

    D

    E

    F

    G

    H

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    (ii) Coefficient of fluctuation of speed.

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    (iii) Coefficient of fluctuation of

    energy

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    (iV) Angular acceleration

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    problems in vibration

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    From the free body diagram, The

    equation of motion is given by.

    The solution take the form

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    s is a constant. Upon substitution into the differential equation,

    which is satisfied for all values of t when

    The roots are,

    --------(18)

    --------(19)

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    Hence the general solution is

    .

    --------(20)

    --------(21)

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    overdamped (c/2m)2>k/m,

    The general solution is given by,

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    underdamped

    (c/2m)2

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    critical damping,

    The general solution is given by,

    tneBtA )(

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    Problems in free vibration

    Problem 1

    Determine the natural frequency of a vibrating system

    shown in the figure

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    Let the mass m be displaced by a distance x

    Applying Newtons law of motion,

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    A cylinder partially immersed in water is dipressed

    slightly and released. Find its natural frequency

    assuming that it stays upright all the time.

    L t

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    Let

    X - displacement of the cylinder

    Aarea of the cylinder

    mmass of the cylinder

    rdensity of water

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    Find the natural frequency of the system shown in

    the following figure

    Let us first find an equivalent position B for replacement of spring positioned at C

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    Equivalent stiffness of two springs is given by,

    Natural frequency,

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    Determine the natural frequency of

    the mass pulley spring system

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    solution

    m - mass of the block

    M - mass of the pulley

    r -radius of the pulley

    x - displacement of the block

    total kinetic energy is:

    kinetic energy of mass + kinetic energy of pulley

    The polar moment of inerta of the pulley (= Mr2/2)

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    The polar moment of inerta of the pulley (= Mr/2)

    we can assume that linear displacement x = r

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    A uniform stiffrod of length l is restrained to move vertically by means of

    both linear and torsional springs as shown in Figure. The stiffness of

    linear spring is k N/mm and that of torsional spring is k Nm/rad. Calculate

    the frequency of oscillation of the rod.

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    Let the rod is displaced by angle .

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    Calculate the natural frequency of a spring connected

    pendulum system shown in Figure. The mass of

    pendulum is mand spring stiffness is k. Neglect the

    mass of the rod.

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    A springmass--damper system consists of a spring of

    stiffness 343 N/m. mass is 3.43 kg. The mass is

    displaced by 20 mm beyond the equilibrium position and

    Find the equation of motion for the system if the dampingcoefficient of the damper is

    (1) 137.2 Ns/m and

    (ii) 13.72 Ns/m.

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    (1)

    (2)

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    This is an under-damped system and therefore,

    the equation of motion is

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    Differentiating the above equation,

    Substituting initial conditions

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    Solving above equations we get,

    The equation of motion for under damped system is

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    A single pendulum is pivoted at a point 0 as

    shown in Figure. If mass of the rod is

    negligible for small oscillations, find thedamped natural frequency of pendulum.

    Solution

    Solution

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    Solution

    Consider the position of the pendulum when it

    rotates by small angle . The forces acting on the

    pendulum rod are shown in the Figure 2. Taking

    moments about point 0, we get

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    Tutorial 9 Q3

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    Taking mass A as the reference plane, the data may be tabulated as follows.

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    First of all, the angular setting of masses C and D is obtained by drawing

    the couple polygon from the data given in table. Assume the position of

    mass B in the horizontal direction

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    Now draw OC parallel to vector oc and OD parallel to bc. Measure

    the angular position of C position of C

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    Measure the angles and

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    In order to find the required mass A and its angular setting, draw the

    force polygon to some suitable scale. ( column 4) since the closing side

    of the force polygon ( vector do) is proportional to 0.1 mA. Therefore

    by measurement

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    Now draw OA parallel to vector do

    By measurement,

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