shear strain

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Mechanics of Materials CIVL 3322 / MECH 3322 Shear Strain

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Mechanics of MaterialsCIVL 3322 / MECH 3322

Shear Strain

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Shear Strain

¢  Axial strain is the ratio of the deformation of 

a body along the loading axis to the original

un-deformed length of the body¢  The units of axial strain are length per 

length and are usually given without

dimensions

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Shear Strain

¢  Shear strain is defined as angular change

at some point in a shape

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Shear Strain

¢  If we look at a material undergoing a shear 

stress, we have to go back to statics to start

¢  We need to remember about couples

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F02_004

Shear Strain

We can start by looking at anelement of material undergoing

a shear stress (the red arrows)

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F02_004

Shear Strain For the block to be in

equilibrium, the top forcedirected to the right must beoffset by a force directed to the

left.Since we are talking about

shear, it must act parallel to a

face.

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F02_004

Shear Strain So the bottom face has a force

directed parallel to it that it equaland opposite to the force that isacting parallel to the top face.

This assumes that the area of the top and bottom face are

equal.

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F02_004

Shear Strain These two forces equal in

magnitude but opposite indirection generate a couple onthe element.

Since the element is inequilibrium, something must

offset the moment produced by

this couple.

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F02_004

Shear Strain The two forces acting on the left

and right faces produce a couplethat is equal in magnitude to thecouple produced by the forces

acting on the top and bottomfaces.

It is also opposite in direction.

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F02_004

Shear Strain This will always be the case

when an element in under shear.

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F02_004

Shear Strain The shear acting on the four 

faces of the element cause adeformation of the element.If the lower left corner is

considered stationary, we canlook at how much the upper left

corner of the element moves.

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F02_004

Shear Strain The upper left corner has moved

a distance δ in the positive x-direction. If we look at the anglemade by the deformation and

the positive y-axis.

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F02_004

Shear Strain This is not the angle θ’.

The sine of this angle is

δ  x

 L

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F02_004

Shear Strain If δx is very small with respect to

L, which is generally the case,then the value of the angle inradians is approximately equal

to the sign of the angle.

δ  x

 L

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F02_004

Shear Strain γ is the symbol for the shear, so

we have

γ  y =δ  x

 L

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F02_004

Shear Strain It is labeled with an xy subscript

because we are looking at theshear strain in the xy planeI have labeled it with a y

subscript because it is the anglemade with the y-axis.

γ  y =δ  x L

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F02_004

Shear Strain The shear is actually the

difference between the originalangle between the side alongthe y-axis and the side along the

x-axis and the angle after loading θ’

γ  y =δ  x L

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F02_004

Shear Strain The angle θ’ is determined by

using

θ ' =π 

2

− γ  y =π 

2

δ  x

 L

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F02_004

Shear Strain If there is also a deformation

above or below the x-axis, itmust also be included to solvefor θ’

θ ' =π 

2

−γ  xy

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P02_009

Problem 2.9

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P02_012

Problem P2.12

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Homework

¢  P 2.11

¢  P 2.13

¢  P 2.14

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