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Section 7.3. Products and Factors of Polynomials. Factoring the Sum and Difference of Two Cubes. Factor Theorem. (x-r) is a factor of the polynomial expression that defines the function P if and only if r is a solution of P(x) = 0, that is, if and only if P(r) = 0. In other words: - PowerPoint PPT Presentation

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Section 7.3

Products and Factors of Polynomials

Factoring the Sum and Difference of Two Cubes

Factor Theorem

• (x-r) is a factor of the polynomial expression that defines the function P if and only if r is a solution of P(x) = 0, that is, if and only if P(r) = 0.

• In other words:– Set x-r = 0– Solve for x. x = r– Plug this r in for every x in the original polynomial– Simplify– If you get 0 then (x – r) IS a factor of the polynomial

Let’s look at how to do this using the example:

4 25 4 6 ( 3)x x x x In order to use synthetic division these

two things must happen:There must be a coefficient for every possible power of the

variable.

The divisor must have a leading coefficient of 1.

#1 #2

Step #1: Write the terms of the polynomial so the degrees are in descending order.

4 3 25 0 4 6x x x x

3

Since the numerator does not contain all the powers of x,

you must include a for the .0 x

Step #2: Write the constant a of the divisor x- a to the left and write down the

coefficients.

Since the divisor , then 3 3 x a

4 3 25 0 4 6

3 5 0 4 1 6

x x x x

Step #3: Bring down the first coefficient, 5.

3 5 0 4 1 6

5

Step #5: After multiplying in the diagonals, add the column.

3 5 0 4 1 6

15

5 15

Add the column

Step #6: Multiply the sum, 15, by ; 15 3=15,

and place this number under the next coefficient,

then add the column again.

r

3 5 0 4 1 6

15 45

5 15 41

Multiply the diagonals, add the columns.

Add

41

15*3 = 45

Step #7: Repeat the same procedure as step #6.

3 5 0 4 1 6

15 45 123 372

5 15 41 12 784 3

Add Columns

Add Columns

Add Columns

Add Columns

The quotient is:

5x3 15x2 41x 124 378

x 3

Remember to place the remainder over the divisor.

Step #8: Write the quotient.

The numbers along the bottom are coefficients of the power of x in descending order, starting with the power that is one less than that of the dividend.

Divide a polynomial by a monomial.

2

564 3 xx

2

5

2

6

2

4 3

xx

2

532 3 xx

Divide a polynomial by a monomial.

x

xxx

2

462 23

x

x

x

x

x

x

2

4

2

6

2

2 23

232 xx

Divide the following numbers.

13

5733

5733134

5253

4

5213

1 Check

13

441

5733

130

Divide the following numbers (Long Division)

11

8034

8034117

7733

3

3304

0

04 Remainder

11

4730

822 2 xxx

Dividing a polynomial by a polynomial (Long Division)

2

822

x

xxCheck

JUST WATCH THIS ONE!

Dividing a polynomial by a polynomial (Long Division)

2

822

x

xx

822 2 xxxx

xx 22 x4 8

4

84 x0

Check

)2)(4( xx

8422 xxx

822 xx

x

x2

)2(xx

x

x4 )2(4 x

JUST WATCH THIS ONE!

Dividing a polynomial by a polynomial (Long Division)

7

42133

36

x

xx Check

42137 363 xxx

JUST WATCH THIS ONE!

36x

Dividing a polynomial by a polynomial (Long Division)

7

42133

36

x

xx

3x

36 7xx 42

6

426 3 x0

Check

)6)(7( 33 xx

4276 336 xxx

4213 36 xx

)7( 33 xx

)7(6 3x

42137 363 xxx

3

6

x

x

3

36

x

x

JUST WATCH THIS ONE!

Dividing a polynomial by a polynomial (Long Division)

1

124

x

xx

1001 234 xxxxx

NOW YOU WRITE THIS ONE

Dividing a polynomial by a polynomial (Long Division)

1

124

x

xx

1001 234 xxxxx

3x

34 xx 3x 2x

2x

23 xx 22x x0

x2 x2

xx 22 2 x2 1

2

12 x22 x3

1

3

x

Dividing a polynomial by a polynomial (Long Division)

yy

yyy

523

19730152

23

7301915253 232 yyyyy

NOW YOU WRITE THIS ONE

Dividing a polynomial by a polynomial (Long Division)

yy

yyy

523

19730152

23

7301915253 232 yyyyyy5

yyy 102515 23 26y y20

2

4106 2 yy11y10

7

253

11102

yy

y

Homework Problems

1.

2.

3.

4.