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SECOND DERIVATIVE TEST
Section 3.4
Calculus AP/Dual, Revised ยฉ2017
7/30/2018 1:18 AM ยง3.4A: Second Derivative Test 1
FILL IN THE BLANK REVIEW
A. First Derivative Test and Concavity
1. ๐โฒpositive then f is: _____________________________
2. ๐โฒ negative then f is: _____________________________
3. ๐โฒโฒ positive then ๐ is Concave _______
4. ๐โฒโฒ negative then ๐ is Concave _______
5. ๐โฒ ๐ = ๐ or ๐โฒ ๐ = ๐ซ๐ต๐ฌ to which ๐ is ๐ of a critical point, then the point is called __________________
6. ๐โฒโฒ(๐) = ๐ or ๐โฒโฒ(๐) = ๐ซ๐ต๐ฌ and ๐โฒโฒ(๐) changes signs, then the point is called _______________________
7/30/2018 1:18 AM ยง3.4A: Second Derivative Test 2
INCREASINGDECREASING
UP
DOWN
CRITICAL POINT
POINT OF INFLECTION
Graph ๐ ๐ = ๐๐ โ ๐, ๐โฒ(๐), and ๐โฒโฒ(๐)
REVIEW EXAMPLE
7/30/2018 1:18 AM ยง3.4A: Second Derivative Test 3
Compare ๐ ๐ = ๐๐ โ ๐ and ๐โฒโฒ(๐)
REVIEW EXAMPLE
7/30/2018 1:18 AM ยง3.4A: Second Derivative Test 4
Opens
UP
Opens
DOWN
Solve for ๐โฒ ๐ = ๐ of ๐ ๐ = ๐๐ โ ๐ and then take ๐โฒโฒ(๐)
REVIEW EXAMPLE
7/30/2018 1:18 AM ยง3.4A: Second Derivative Test 5
( ) 3f x x x= โ
( ) 2' 3 1f x x= โ
23 1 0x โ =
23 1x =
2 1
3x =
1
3
. .
x
C N
=
Solve for ๐โฒ ๐ = ๐ of ๐ ๐ = ๐๐ โ ๐ and then take ๐โฒโฒ(๐)
REVIEW EXAMPLE
7/30/2018 1:18 AM ยง3.4A: Second Derivative Test 6
1
3
. .
x
C N
=
( ) 2' 3 1f x x= โ
( )'' 6f x x=
1 6"
3 3f
= +
1 6"
3 3f โ = โ
Relative
MAX
Relative
MIN
Fโ VS Fโโ
๐ โ Test ๐ โโ Test for Concavity
7/30/2018 1:18 AM ยง3.4A: Second Derivative Test 7
CRITICAL POINTS
ABSOLUTE/GLOBAL EXTREMA
RELATIVE/LOCAL MAX OR MIN
CONCAVITY
POINT OF INFLECTION
PROCESS F โโ = 0 OR DNE
A. Let ๐ be a function such that ๐โฒ ๐ = ๐ and ๐โฒโฒ exists on an open interval containing ๐:
1. If ๐โฒโฒ ๐ > ๐, then ๐(๐) has a relative minimum at ๐, ๐ ๐ and ๐ is concave
up
2. If ๐ โฒโฒ(๐) < ๐, then ๐(๐) has a relative maximum at ๐, ๐ ๐ and ๐ is concave
down
3. If ๐โฒ ๐ = ๐ and ๐โฒโฒ ๐ = ๐, then ๐(๐) is inconclusive. Use the first derivative test.
SECOND DERIVATIVE TEST
7/30/2018 1:18 AM ยง3.4A: Second Derivative Test 8
STEPS
A. Identify all critical points using the first derivative.
B. Determine the second derivative
C. Plug in the critical points into the second derivative
1. If the critical point is positive, there is a relative minimum
2. If the critical point is negative, there is a relative maximum
3. If the critical point is zero, test is inconclusive and test must revert back to the first derivative test
7/30/2018 1:18 AM ยง3.4A: Second Derivative Test 9
Using the Second Derivative Test to find the relative extrema of
๐ ๐ = ๐ +๐
๐.
EXAMPLE 1
7/30/2018 1:18 AM ยง3.4A: Second Derivative Test 10
( ) 12f x x xโ= +
( ) 2' 1 2f x xโ= โ
2
2:1 0
take common denominator
CPx
โ =
: 0, 2CP x =
( ) 2
2' 1
TAKE CRITICAL POINT
f xx
= โ
2 22 0, 0x xโ = =
0, 2x =
2
2 2
20
x
x xโ =
Using the Second Derivative Test to find the relative extrema of
๐ ๐ = ๐ +๐
๐and justify.
EXAMPLE 1
7/30/2018 1:18 AM ยง3.4A: Second Derivative Test 11
( )2
2' 1f x
x= โ
( ) 3
3
4'' 4f x x
x
โ= =
( )( )
( )
'' 2
'' 0
'' 2
f
f
f
โ =
=
=
2โ 2
.Inc
โ
+
( )( )
( )( )
( )( )
3
3
3
4 4'' 2 ( )
2 22
4'' 0
0
4 4'' 2 ( )
2 22
f NEG
f Und
f POS
โ = = = โโโ
= =
= = = +Rel.
Min.
Rel.
Max.
0Inc.
.
Concave Down
Inc
Concave Up
Using the Second Derivative Test to find the relative extrema of
๐ ๐ = ๐ +๐
๐and justify.
EXAMPLE 1
7/30/2018 1:18 AM ยง3.4A: Second Derivative Test 12
02โ 2Rel.
Min.
Rel.
Max.
( )
( )
has a Relative Minimum at 2 when '' 0
has a Relative Maximum at 2 when '' 0
When = 0, the test is inconclusive and must use the
first derivative test to determine relative extrema.
f x x f
f x x f
x
=
= โ
Inc.
Using the Second Derivative Test to find the relative extrema of
๐ ๐ = ๐ +๐
๐and justify.
EXAMPLE 1
7/30/2018 1:18 AM ยง3.4A: Second Derivative Test 13
โ โ โ โ
โ
โ
โ
โ
x
y
( )
( )
has a Relative Minimum at 2 when '' 0
has a Relative Maximum at 2 when '' 0
When = 0, the test is inclusive and must use the
first derivative test to determine relative extrema.
f x x f
f x x f
x
=
= โ
Using the Second Derivative Test to find the relative extrema of
๐ ๐ = โ๐๐๐ + ๐๐๐ and justify.
EXAMPLE 2
7/30/2018 1:18 AM ยง3.4A: Second Derivative Test 14
( ) 5 33 5f x x x= โ +
( ) 4 2' 15 15f x x x= โ +
( )2 2: 15 1 0CP x xโ โ =
: 0, 1CP x x= =
Using the Second Derivative Test to find the relative extrema of
๐ ๐ = โ๐๐๐ + ๐๐๐ and justify.
EXAMPLE 2
7/30/2018 1:18 AM ยง3.4A: Second Derivative Test 15
( ) 4 2' 15 15f x x x= โ +
( ) 3'' 60 30f x x x= โ +
( )
( )
( )
'' 0
'' 1
'' 1
f
f
f
=
=
โ =
0
30
30
โ
Using the Second Derivative Test to find the relative extrema of
๐ ๐ = โ๐๐๐ + ๐๐๐ and justify.
EXAMPLE 2
7/30/2018 1:18 AM ยง3.4A: Second Derivative Test 16
01โ 1Rel.
Min.
Rel.
Max.
( )If '' 0 =0, then we revert back
to the First Derivative Test to
decide the Relative Maxima.
f
( ) ( ) ( )5 3
1 3 1 5 1f โ = โ โ + โ
( )1 2f โ = ( )1 2f = โ
( ) ( ) ( )5 3
1 3 1 5 1f = โ +
( ) ( )
( ) ( )
( )
has a Relative Minimum at 1, 2 when '' 0
has a Relative Maximum at 1,2 when '' 0
At " 0 0 it is inconclusive and must use the
first derivative test to determine relative extrema.
f x f
f x f
f
โ โ
=
( )
( )
( )
'' 0
'' 1
'' 1
f
f
f
=
=
โ =
0
30
30
โ
Using the Second Derivative Test to find the relative extrema of
๐ ๐ = โ๐๐๐ + ๐๐๐ and justify.
EXAMPLE 2
7/30/2018 1:18 AM ยง3.4A: Second Derivative Test 17
( ) ( )
( ) ( )
( )
has a Relative Minimum at 1, 2 when '' 0
has a Relative Maximum at 1,2 when '' 0
At " 0 0 it is inconclusive and must use the
first derivative test to determine relative extrema.
f x f
f x f
f
โ โ
=
โ โ โ โ
โ
โ
โ
โ
x
y
Using the Second Derivative Test to find the relative extrema of
๐ ๐ =๐
๐๐๐ โ ๐๐ โ ๐๐ and justify.
YOUR TURN
7/30/2018 1:18 AM ยง3.4A: Second Derivative Test 18
( ) ( )
( )
has a Relative Minimum at 3, 9 when '' 0
5 has a Relative Maximum at 1, when '' 0
3
f x f
f x f
โ
โ
โโ โ โ โ โ โ โ โ โ โ
โ
โ
โ
โ
โ
โ
โ
โ
โ
โ
x
y
Suppose that the function ๐ has a continuous second derivative for all ๐and that ๐ โ๐ = ๐, ๐โฒ โ๐ = โ๐, ๐โฒโฒ โ๐ = ๐. Let ๐ be a function
whose derivative is given by ๐โฒ ๐ = ๐๐ โ ๐๐๐ เตซ
เตฏ
๐๐ ๐ +
๐ ๐โฒ ๐ for all ๐. Write an equation of the tangent line to the graph of
๐ at the point of where ๐ = โ๐. Justify response.
EXAMPLE 3
7/30/2018 1:18 AM ยง3.4A: Second Derivative Test 19
( )
( )
1 2,
' 1 3
f
f
โ =
โ = โ
( )1,2โ
( )2 3 1y xโ = โ +
The figure below shows the graph of the derivative of ๐, ๐โฒ on the closed interval โ๐. ๐, ๐. ๐ . The graph of ๐โฒ has a horizontal tangent line at ๐ = ๐ and is linear on the interval โ๐. ๐, ๐. ๐๐ .
(a) Find the ๐-coordinates of the relative maxima of ๐. Justify your answer.
(b) Find the ๐-coordinates of the points of inflection of ๐. Justify your answer.
(c) On what intervals is ๐ decreasing? Justify your answer.
(d) Is the function ๐ twice-differentiable? Justify your answer.
EXAMPLE 4
7/30/2018 1:18 AM ยง3.4A: Second Derivative Test 20
The figure below shows the graph of the derivative of ๐, ๐โฒ on the closed interval โ๐. ๐, ๐. ๐ . The graph of ๐โฒ has a horizontal tangent line at ๐ = ๐ and is linear on the interval โ๐. ๐, ๐. ๐๐ .
(a) Find the ๐-coordinates of the relative maxima of ๐. Justify your answer.
EXAMPLE 4A
7/30/2018 1:18 AM ยง3.4A: Second Derivative Test 21
( ) has a relative maximum at 1, 3
where ' changes sign from positive to negative
f x x x
f
= โ =
The figure below shows the graph of the derivative of ๐, ๐โฒ on the closed interval โ๐. ๐, ๐. ๐ . The graph of ๐โฒ has a horizontal tangent line at ๐ = ๐ and is linear on the interval โ๐. ๐, ๐. ๐๐ .
(b) Find the ๐-coordinates of the points of inflection of ๐. Justify your answer.
EXAMPLE 4B
7/30/2018 1:18 AM ยง3.4A: Second Derivative Test 22
( )
( )
has a POI at 0.75, 3.5 where ' changes from decreasing to increasing.
has a POI at 2,7 where ' changes from increasing to decreasing.
f f
f f
โ
The figure below shows the graph of the derivative of ๐, ๐โฒ on the closed interval โ๐. ๐, ๐. ๐ . The graph of ๐โฒ has a horizontal tangent line at ๐ = ๐ and is linear on the interval โ๐. ๐, ๐. ๐๐ .
(c) On what intervals is ๐ decreasing? Justify your answer.
EXAMPLE 4C
7/30/2018 1:18 AM ยง3.4A: Second Derivative Test 23
( ) ( ) is decreasing where ' 0 at I 1,1 3,3.5 .f f I โ
The figure below shows the graph of the derivative of ๐, ๐โฒ on the closed interval โ๐. ๐, ๐. ๐ . The graph of ๐โฒ has a horizontal tangent line at ๐ = ๐ and is linear on the interval โ๐. ๐, ๐. ๐๐ .
(d) Is the function ๐ twice-differentiable (Continuous and differentiable)? Justify your answer.
EXAMPLE 4D
7/30/2018 1:18 AM ยง3.4A: Second Derivative Test 24
is continuous and not differentiable because 0.75 has a sharp turn and therefore, not differentiable. f x =
TO RECAP
A. The First Derivative tells us:
1. Extrema
2. Relative Maximum
3. Relative Minimum
B. The Second Derivative tells us:
1. Concavity
2. Points of Inflection
C. The Second Derivative TEST tells us:
1. Extrema
7/30/2018 1:18 AM ยง3.4A: Second Derivative Test 25
Let ๐ be twice differentiable. ๐โฒ ๐ > ๐ and ๐โฒโฒ ๐ > ๐ for all reals. What is a possible value for ๐ ๐ if ๐ ๐ = ๐, ๐ ๐ = ๐ and ๐ ๐ = ๐ ?
(A) ๐๐
(B) ๐
(C) ๐
(D) ๐๐
AP MULTIPLE CHOICE PRACTICE QUESTION 1 (NON-CALCULATOR)
7/30/2018 1:18 AM ยง3.4A: Second Derivative Test 26
Let ๐ be twice differentiable. ๐โฒ ๐ > ๐ and ๐โฒโฒ ๐ > ๐ for all reals. What is a possible value for ๐ ๐ if ๐ ๐ = ๐, ๐ ๐ = ๐ and ๐ ๐ = ๐ ?
AP MULTIPLE CHOICE PRACTICE QUESTION 1 (NON-CALCULATOR)
7/30/2018 1:18 AM ยง3.4A: Second Derivative Test 27
Vocabulary Connections and Process Answer and Justifications
1st Derivative
Test
2nd Derivative
Test
( )' 0 : increasingh x
( )'' 0 : concave uph x
( ) ( ) ( )0,0 , 1,2 , 2,7
25 8
7 8 15
close to 14
+ =
D( ) ( )As ' 0 and '' 0, the function is
increasing and concave up. The only possible
answer is 14.
h x h x
ASSIGNMENT
Page 192
31-40 all & Justify all responses
7/30/2018 1:18 AM ยง3.4A: Second Derivative Test 28