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SBI ASSOCIATE JUNIOR ASST - 3 [PH-I] (SOLUTION)

MATHS(31-35):31. (3) 27% of 450 – ?% of 375 = 76.5

450 × 27

100 – 375 ×

100x

= 76.5

375 × 100x

= 121.5 – 76.5 = 45

x = 45 100

375

= 12

32. (1) 625.97 × 7.5 + 299.87 = ? – 4632.644694.775 + 299.87 + 4632.64 = x x = 9627.285

33. (3) 60% of 7.80 + ? = 35

of 14.75

60

100 × 7.80 + x = 35 × 14.75

4.68 + x = 8.85 x = 4.17

34. (5) 999.99 × 0.99 + 9.99 – 99.99 +0.0099 = ?999.99 × 0.99 + 09.99 – 99.99 +0.0099989.9901 + 09.99 + 0.0099 –99.99 = 900

35. (4) 253 × 43 – 8002 = (?)2

(x)2 = 25 × 25 × 25 × 4 × 4 × 4 –800 × 800

(x)2 = 1000000 – 640000 = 360000

x = 600

36. (1) ? 144 311 24

x × 2(12) = 311 × 24

12x = 311 × 2412x = 7464

x = 746412

x = 622

37. (1)0.4 × 7.5 ÷ 0.6 × 25 = ?

x = 0.4 7.5

0.6

× 25

x = 12538. (2)67.39 – 11.78 + 19.63 = ? + 22.41

87.02 – 11.78 = x + 22.4175.24 = x + 22.41x = 52.83

39. (5)(10248 ÷ 56) – (7568 ÷ ?) = 11

10248

56 – 7568x = 11

183 – 11 = 7568x

172 × x = 7568

x = 7568172 = 44

40. (3) 12 184 23 26 73 ?

x = 12 18426 73

23

x = 96 26 73

x = 49 = 7(41-45):41. (4) Series has been written in reverse

order with a difference of(1)2, (1)3, (2)2, (2)3, (3)2, (3)3i.e. 1, 1, 4, 8, 9, 27

42. (2) Series patternPrime number series3, 5, 7, 11, 13, 17, 19, 23

43. (1) Series pattern4 + (6 × 1) = 1010 + (6 × 5) = 4040 + (30 × 5) = 190190 + (150 × 5) = 940940 + (750 × 5) = 4690should come in place of '?'4690 + (3750 × 5) = 23440

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44. (4) Series pattern7 × 0.5 + 0.5 = 44 × 1 + 1 = 55 × 1.5 + 1.5 = 99 × 2 + 2 = 20should come in place of '?'20 × 2.5 + 2.5 = 52.552.5 × 3 + 3 = 160.5

45. (3) Series pattern5 + 72 = 5454 + 62 = 9090 + 52 = 115115 + 42 =131131 + 32 = 140140 + 22 = 144

46. (2) Average of the first and the thirdnumber = 2 × 69 = 138Average of the second and thefourth number = 69 × 2 = 138Average of the fifth number= 61 × 5 = 305Now, the fifth number= 305 – (138 + 138)= 305 – 276= 29

47. (3) Let the present age of A be x andthat of B be y.

Now, 10 1310 17

xy

or, 17x – 170 = 13y – 130or, 17x – 13y = 40 (I)

Again, 17 1017 11

xy

or, 11x + 187 = 10y + 170or, 11x – 10y = –17 (II)Solving equation (I) and (II),we get x = 23 yrs, y = 27 yrsHence, B's present age = 27 yrs

48. (5) Let the original price of the articlebe ` x. discounted price of the article= x – 20% of x

= x – 20

100x =

45x

Now, according to the question,

45 x = 1840 × 100

115

or, x = 1840 × 100115 ×

54 = 2000

original price = ` 200049. (5) Required number of selections

= 8c1 × 7c5 = 16850. (4) Reqd units of electricity consumed

= 10 × 8(8 × 2 + 3) = 152051. (1) Given M = 8D

M Age of MeenaD Age of her daughter

Also,8D + 8D + 8 =

103

Solving, we get D = 4Meena's present age= 8D = 8 × 4 = 32 yrs

52. (4)53. (2) Relative speed of two trains

= 180 270 m10.8 s = 4500 m

108 s

= 4500 18 km108 5 h

= 150 km/hSpeed of second train= 150 – 60= 90 km/h

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54. (4) CP of wheat = 30 × 45 = ` 135040% of 30 kg = 12 kgSP of 12 kg = 12 × 50 = ` 600For 25% profit, total SP of all thewheat is

1350 × 125100

= 1350 × 54

= `6750

4 = ` 1687.5

Remaining wheat (30 – 12) = 8 kg, Rate

of remaining wheat = 1087.5

6018

`

55. (1) Let the first number be f andsecond number be s.Then, 2f + 3s = 100 ... (i)3f + 2s = 120 ... (ii)Solving (i) & (ii), we getf = 32, s = 12

56. (1) Perimeter of the rectangle= 2(8 + 7) = 30 cmPerimeter of the square= 2 × 30 = 60 cmSide of the square

= 14

× 60 = 15 cm

Circumference of the requiredsemi-circle

= 2r rπ = 227

× 152

+ 2 × 152

= 23.57 + 15 = 38.57 cm57. (1)58. (4) Total amount spent

= 591 45

7803 60

paise

= (197 + 585) paise= 782 paise= ` 7.82

59. (5) Let x boys and x girls join thegroup of 20 boys and 32 girls tomake the ratio 3 : 4.

So, 20 3

80 4 96 332 4

xx x

x

x = 16Total number of people in the groupwill be 20 + 32 + 16 + 16 = 84

60. (4) Raju runs on Monday and Friday= 1250 × 2 = 2500 mOn Tuesday, Wednesday,Thursday and Saturday, Rajuruns 1500 × 4 = 6000 mIn 1 week Raju runs 6000 + 2500 =8500 cmIn 3 week Raju runs 3 × 8500 =25500 m = 25.5 km

(61-65):61. (3) Total number of people

contributing from all the cities= 4000 + 5500 + 5000 + 3500 +4500 + 2500= 25000People from Q and U= 5500 + 2500 + 8000

% = 8000

25000 × 100 = 32%

62. (4) Required percentage

= 4500 3500

3500 × 100 = 28.57%

63. (5) Required ratio = PR

= 40005000

= 45

64. (1) 18% of the total population

= 18100

× 25000 = 4500

So, three cities, P, S, and U, formless than 18%.

65. (2) S : T = 11 : 9 = 5500 : 4500Which means there should be5500 – 3500 = 2000 more peoplefrom City S.

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REASONING66. (2) FIST

67. (3)

68. (3) 2nd digit from right = 7th digitfrom leftNow, 7th digit after arrangement= 3rd digit in the given number= 1

69. (1)

Similarly,

70. (2) Move five letters backward.(71-75):

From the given information wehave the following:

71. (5) G is on the right of E.72. (1) A and B are on the extreme ends.73. (3) G's position can be taken by C.74. (4) D is between C and F.75. (4) All the conditions are required to

get the final order.(76-79):76. (4) All rivers can never be oceans

implication Some rivers areoceans.This conclusion is the converseof the given premise "All oceansare rivers".

77. (5) Conclusion II is the aboveconclusion (ii). Conclusion I is theabove conclusion (i).

(77-81):No day is night + All nights arenoon = E + A = O* = Some noonare not days (i). Again, All nightsare noon + No noon is an evening= A + E = E = No night is anevening (ii).

78. (4) None follows.79. (5) Conclusion I is converse of the

above conclusion (ii).(80-81):

Some papers are boards + No boardis a card = I + E = O = Some papersare not cards.

80. (3) Conclusions I and II formcomplementary pair. Therefore,either I or II follows.

81. (5) None follows.(82-87):

Using the given four statements,the codes areher bu been jologic fo displayed sihas la name yamerit na there zolist ke in go

82. (5)83. (1)84. (2)85. (1)86. (4) Code for 'is' is not known but out

of the given five options only 'yazo wo bu' may be the coding.

87. (3) go(87-92):88. (2) A > B = C < D < E

I. D > A is not true.II. E < C is true.

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89. (5) Split them asL > U ... (i);U > K ... (ii);Z < U ... (iii) andU < R ... (iv)Combining (i) and (iii), we getL > U > Z or L > ZHence I follows.Combining (ii) and (iv), we getK < U < R or K < RHence II follows.

90. (1) Y < J = P > R > II. J > I is true.II. Y < R is not true.

91. (4) V > K > M = N > SK > TI. T < N is not true.II. V = S is false.

92. (1) Split them asF < X ... (i)X < A ... (ii)R < X ... (iii) andX < E ... (iv)Combining (i) and (iv), we getF < X < E or F < EHence I follows.From (i) and (iii), R and F can'tbe compared. Hence II does notfollow.

(93-96):From the given information wehave the following order:

Note: K = Kanjeevaram Silk SareeG = Gadwal Silk SareeT = Tangail Cotton SareeP = Paithani Silk SareeS = Sambalpuri Cotton Saree

93. (3) Tangail Cotton Saree94. (2)95. (2) Bhonsle96. (4)(57-60):97. (3) If climate change is a natural

phenomenon, all this maligning ofindustrial development amounts tounnecessary fuss.

98. (4) The realisation of wrong priortiesis leading to the shift of focus.

99. (1) Since industrial development is"not the only reason" behind theproblem, we need to address thisas well as other reasons.

100. (2) Industrial development is beingcurtailed so that the saiddestruction can be avoided.

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1. (4)2. (1)3. (2)4. (3)5. (2)6. (3)7. (5)8. (4)9. (2)10. (5)11. (3)12. (1)13. (2)14. (5)15. (4)16. (5)17. (3)18. (1)19. (4)20. (5)

21. (3)22. (3)23. (2)24. (3)25. (3)26. (3)27. (2)28. (5)29. (3)30. (3)31. (3)32. (1)33. (3)34. (5)35. (4)36. (1)37. (1)38. (2)39. (5)40. (3)

SBI ASSOCIATE JUNIOR ASST - 3 [PH-I] [ANSWER KEY]

41. (4)42. (2)43. (1)44. (4)45. (3)46. (2)47. (3)48. (3)49. (5)50. (4)51. (1)52. (4)53. (2)54. (4)55. (1)56. (1)57. (1)58. (4)59. (5)60. (4)

61. (3)62. (4)63. (5)64. (1)65. (2)66. (2)67. (3)68. (3)69. (1)70. (2)71. (5)72. (1)73. (3)74. (4)75. (4)76. (4)77. (5)78. (4)79. (5)80. (3)

81. (5)82. (5)83. (1)84. (2)85. (1)86. (4)87. (3)88. (2)89. (5)90. (1)91. (4)92. (1)93. (3)94. (2)95. (2)96. (4)97. (3)98. (4)99. (1)100. (2)