rotation density and c of m 1 definition of a system energy of a system momentum of a system force a...
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RotationDensity and C of M
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Definition of a System
Energy of a System
Momentum of a System
Force a System
Work a System
Impulse on a System
Center-of-Mass
RotationDensity and C of M
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What is a System?
A system is the particle or group of particles as defined by a problem in physics.
It may be as small as a single atom consisting of neutrons, protons and electrons.
It may be as large as the entire universe.
It may or may not include every object in the problem.This depends on what is being asked?
RotationDensity and C of M
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The Work-Energy Theorem
The work-energy theorem is true for systems as well as for individual particles.
The work by all forces can be found using integration
The change in kinetic energy is just the sum of the change kinetic energy for each particle
systemsystem aon forcesby done KW
particlessystem KK
mass ofcenter systemon donesystem aon forcesby done rFW
RotationDensity and C of M
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The Work-Energy Theorem
Remember that for gravity and elastic forces, we can write
where
And so, we can write (remembering that there are other kinds of energy like energy of deformation, heat, etc.)
gravitygravityby done UW
elasticforce elasticby done UW
hmgU gravity
2elastic 2
1skU
totalothersystemsystemenergyfor with accountednot
system aon forcesby done EEUKW
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Momentum and Collisions
There is nothing new here. You already learned that collisions required knowledge of systems and momenta add.
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The Force on a System
The net force on a system is the sum of the net force on every particle in the system.
The particles to be considered in the system are given as part of the problem.
Example question: What is the net force on the system that includes the two books below?
particlesnetsystemnet FF
We only need to consider the forces ON each of the books.
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The Force on a System
The forces on the top book are:
1. Gravity from the earth2. Normal force from the apple3. Friction from the apple4. Normal force from the bottom book5. Friction from the bottom book
Example question: What is the net force on the system thatincludes the two books below?
The weight of the apple (gravity of the earth on the apple) is acting ON THE APPLE, not ON THE BOOK!!!
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The Force on a System
The forces on the bottom book are:
1. Gravity from the earth2. Normal force from top book3. Friction from the top book4. Normal force from the table5. Friction from the table6. Normal force from the hand
Example question: What is the net force on the system that includes the two books below?
The weight of the top book (gravity of the earth on the top book) is acting ON THE TOP BOOK, not ON THE BOTTOM BOOK!!!
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The Force on a System
1. Gravity from the earth2. Normal force from the apple3. Friction from the apple4. Normal force from the bottom
book5. Friction from the bottom book
Example question: What is the net force on the system that includes the two books below?
The force due to gravity on the system is the force of gravity on the top book plus the force of gravity on the bottom book. In other words, it is Mg.
1. Gravity from the earth2. Normal force from top
book1. Friction from the top book2. Normal force from the table3. Friction from the table4. Normal force from the hand
Top Book
Bottom Book
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The Force on a System
1. Gravity from the earth (on the system)2. Normal force from the apple3. Friction from the apple4. Normal force from the table5. Friction from the table6. Normal force from the hand
Example question: What is the net force on the system that includes the two books below?
Look carefully. You will see that we could have treated both books as a single particle of mass M.
This is a general rule.
Thus, we are left with the following forces acting on the system (both books)…
System
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The Work on a System
The net work on a system is the sum of the net work on every particle in the system.
The particles to be considered in the system are given as part of the problem.
Example question: What is the net work over a distance d on the system that includes the two books below?
net netsystem particlesW W
We only need to consider the forces ON each of the books.
RotationDensity and C of M
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The Force on a System
1. Gravity from the earth2. Normal force from the apple3. Friction from the apple4. Normal force from the bottom
book5. Friction from the bottom book
Example question: What is the net work over a distance d on the system that includes the two books below?
The force due to gravity on the system is the force of gravity on the top book plus the force of gravity on the bottom book. In other words, it is Mg.
1. Gravity from the earth2. Normal force from top
book1. Friction from the top book2. Normal force from the table3. Friction from the table4. Normal force from the hand
Top Book
Bottom Book
RotationDensity and C of M
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The Force on a System
1. Gravity from the earth (on the system)2. Normal force from the apple3. Friction from the apple4. Normal force from the table5. Friction from the table6. Normal force from the hand
Example question: What is the net work over a distance d on the system that includes the two books below?
Look carefully. You will see that we could have treated both books as a single particle of mass M.
This is a general rule.
Thus, we are left with the following forces acting on the system (both books)…
System
RotationDensity and C of M
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The Work on a System
1. Gravity from the earth (on the system)2. Normal force from the apple3. Friction from the apple4. Normal force from the table5. Friction from the table6. Normal force from the hand
Example question: What is the net work over a distance d on the system that includes the two books below?
We can now do the integral on the total force on the system. If this is difficult, we can do the integral separately for each force and add the results.
Thus, we are left with the following forces acting on the system (both books)…
System
RotationDensity and C of M
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The Impulse on a System
The net impulse on a system is the sum of the net work on every particle in the system.
The particles to be considered in the system are given as part of the problem.
Example question: What is the net impulse over a time t on the system that includes the two books below?
net (system) net (particles)J J
We only need to consider the forces ON each of the books.
RotationDensity and C of M
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The Impulse on a System
1. Gravity from the earth (on the system)2. Normal force from the apple3. Friction from the apple4. Normal force from the table5. Friction from the table6. Normal force from the hand
Example question: What is the net impulse over a time t on the system that includes the two books below?
We can now do the integral on the total force on the system. If this is difficult, we can do the integral separately for each force and add the results.
Thus, we are left with the following forces acting on the system (both books)…
System
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Definition of the center-of-mass
The center-of-mass of a system is that point in the system that follows the laws of physics for a single particle. In other words, it is the “position” of the system.
Motion of center-of-mass
The center-of-mass of any group of objects or any large single object follows the same principles as particles in the previous chapters.
Newton’s laws of motion still apply.
The constant acceleration equations still apply.
Work-energy theorem still applies.
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Center-of-mass for individual particles
The center of mass of a system of objects is the point in space that behaves like a single point mass under the influence of external forces. It is the “position” of the system.
Center of mass for a group of point masses is given by the equation…
M
m
m
mN
i
ii
N
ii
N
iii
1
1
1cm
rrr
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Example for calculating center of mass
M
m
m
mN
i
ii
N
ii
N
iii
1
1
1cm
rrr
x
y
1 2
3 4kg 1
kg 2
kg 3
kg 2
4
3
2
1
m
m
m
m
kg 8M 2m
i m 2r
m 0r
j m 2i m 2r
j m 2r
4
3
2
1
j m 25.1i m 00.1kg 8
im 2kg 1m 0kg 2jm 2im 2kg 3jm 2kg 2r cm
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Example: 2 spheres against One
1 2
3
F
F
1F
mg
Fn
fk
F*n
2F*n
mg
Fn
fk
3F
mg
Fn
fk
nk FmgFma *1 mgFma kn *2
mgFma k3
Things to notice
The acceleration a1 is not the same as a2.
The acceleration a1 is always smaller than a3.
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Example: 2 spheres against One
1 2
3
F
F
3F
mg
Fn
fk
gmFma k 22 cm
mgFma k3
Things to notice
For large forces, acm is smaller than a3.
For small forces, acm is almost equal to a3.
2F
2mg
Fn
fk
1
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Velocity and Acceleration of Center-of-Mass
dt
rd
M
vmv
N
iii
cm1cm
dt
vd
M
ama
N
iii
cm1cm