1.0 RESULTS AND CALCULATIONExperiment 1 ; Determination of power input, heat output, and coefficient of performance.Cooling water flow rate, FT1%40.5

Cooling water flow rate, FT1LPM2.0

Cooling Water Inlet Temperature, TT5C27.7

Cooling Water Outlet Temperature, TT6C28.9

Compressor Power InputW162

Cooling water flow rate (LPM) = x 5 LPM = X 5 LPM = 2.0

Heat output = x x x x (28.9-27.7) = 167.2 W.

COPH = = = 1.03

Experiment 2 ; Production of heat pump performance curves over a range of source and delivery temperature.Cooling Water Flow Rate, FT1%20.140.560.8

Cooling Water Flow Rate, FT1LPM1.02.03.0

Cooling Water Inlet Temperature, TT529.529.729.9

Cooling Water Outlet Temperature,TT632.131.231.0

Compressor Power InputW163161161

Heat OutputW181.1209.0229.9

COPH-1.111.301.43

Cooling water flow rate (LPM) = X 5 LPM = x 5 LPM = 1.0

Cooling water flow rate (LPM) = X 5 LPM = X 5 LPM = 2.0

Cooling water flow rate (LPM) = X 5 LPM = X 5 LPM = 3.0

For FT1 : 20.1 %Heat output = x x x x (32.1-29.5) = 181.1 W.

COPH = = = 1.11

For FT1 : 40.5%Heat output = x x x x (31.2-29.7) = 209.0 W.

COPH = = = 1.30

For FT1 : 60.8%Heat output = x x x x (31.0-29.9) = 229.9 W.

COPH = = = 1.43

From the calculated value, a graphs is constucted,Cooling Water Outlet Temperature(C)Power Input (W)Heat Output(W)COP

32.1163181.11.11

31.2161209.01.30

31.0161229.91.43

Graph of Performance of Heat Pump vs Cooling Water Outlet Temperature

Experiment 3 : Production of vapour compression cycle on p-h diagram and energy balance study.Refrigerant Flow Rate, FT2%60.7

Refrigerant Flow Rate, FT2LPM0.8

Refrigerant Pressure (Low), P1Bar(abs)2.0

Refrigerant Pressure (High),P2Bar (abs)7.1

Refrigerant Temperature, TT1C28.4

Refrigerant Temperature, TT2C80.3

Refrigerant Temperature, TT3C30.6

Refrigerant Temperature, TT4C24.4

Cooling Water Flowrate, FT1%40.2

Cooling Water Flowrate, FT1LPM2.01

Cooling Water Inlet Temperature, TT5C29.7

Cooling Water Inlet Temperature, TT6C31.2

Compressor Power InputW161

Refrigerant Flow rate(LPM) = = = 0.8

Cooling water flow rate (LPM) = = = 2.011 atm = 101.325 kPa = 1.01325 barRefrigerant pressure (low), P1,= = 200kPa= h1 is 206.09 (kJ/kg) from saturated R-134a-pressure table.Refrigerant pressure (high), P2,= 7.1 = 710 kPa= Find h2 using interpolation from saturated R-134a pressure table.P (kPa)h (kJ/kg)

700176.26

710175.814

750174.03

Find h3 and h4 using interpolation from saturated R-134atemperature tableT (C)h (kJ/kg)

30.095.58

30.6h3 = 95.853

32.096.49

T (C)h (kJ/kg)

24.084.98

24.4h4 = 85.55

2687.83

From the value that calculated, p-h diagram is constructed,h (kJ/kg)Pressure (kPa)

206.09200

175.814710

95.853710

85.55200

206.09200

Graph of P-h diagram of R-134a

Figure 3 : p-h diagram cycle

Experiment 4 ; Estimation of the effect of compressor pressure ratio on volumetric efficiency.Refrigerant Flow Rate, FT2%60.7

Refrigerant Flow Rate, FT2LPM0.8

Refrigerant Pressure (Low), P1Bar(abs)2.0

Refrigerant Pressure, (High), P2Bar(abs)7.1

Refrigerant Temperature, TT1C28.4

Refrigerant flow rate (LPM) = = = 0.8Compressor pressure ratio = = = = 3.55Change the LPM to kg/sMass flow rate= 0.8 LPM x x x x 4.25 = 5.67 x 10-5 Density of refrigerant 134a = 4.25 Actual volume flow rate = = 5.67 x 10-5 x = 1.33 x 10-5 Compressor swept volume= 2800 x x 1.33 x = 6.21 x /sVolumetric efficiency = x 100%= 2.1