published article - dydaktyka.fizyka.umk.pldydaktyka.fizyka.umk.pl/publikacje/acta_phys.pdf ·...
TRANSCRIPT
�↵e2/2r4
↵ e
�
� =4⇡
k2
1X
l=0
(2l + 1) sin2 ⌘l(k),
k l⌘l
l
tan ⌘l =m2 � tan2 �l +B%
l tan �l(m2 � 1)
tan �l(1�m2) +B%l (1�m2 tan2 �l)
,
�l = ⇡(v � l � 1/2)/2 m v
B%l (k)
B%l (k) ⇡ Bl(0) +
RlR⇤k2/2+ . . . Rl
R⇤ =p↵e2µ/~2
r�4
µ~
l = 0 B0(0) A sB0 = �R⇤/A
s p d
tan ⌘l(k) ⇡⇡↵k2
8(l � 1/2)(l + 1/2)(l + 3/2), l > 2.
2 2 6 6
6 12
2
2
2 2
A = 9.52a0 13.04a0
B0 a0
Eb = 1/(2A2)6 12 6 6
2
2 6 6 6 12
A = �R⇤/B0 B1 B2 R1
R2
A [a] R0 [a0] B1 R1 [a0] B2 R2 [a0] ↵ [a30]
2 �3.13 �0.12 �1.99 �0.90
�5.52 �4.34
2 �9.23 �22.67
6 12⇤ �0.05 �0.18
6 6⇤ �0.23 �0.29
⇤
��
Ze↵ = 4⇡⇢e�R⇣R2 +
�
4⇡+ 2RRe{f0}
⌘,
Ze↵ = �/(⇡r20cn) r0
c n⇢e
�R
R f0
s⌘0 Re{f0} = sin(2⌘0)/(2k)
⇢e�R
Ze↵
2
R = R⇤
4⇡⇢e�R
sZe↵
r�4 R = R⇤ = 3.35a0 3.40a0
4⇡⇢e�R = 0.51
2 4
4⇡⇢e�R R
Ze↵ �
A [a0] R [a0] 4⇡⇢e�R
⇤ �5.52⇤2 �9.23† �0.52† �0.61† �5.30† �10.4† �45.3
⇤ †
4⇡⇢e�R
4⇡⇢e�R ⇡ 0.5
2
Ze↵(k)2 6 6 6 12
r�4
6 12
6 6