ppt lecture- intro to dynamics & kinematic motion

42
LECTURE NOTES BY: ENGR. FRANCIS F. VILLAREAL DLSU-D/CEAT/1 S T  SEM SY 2014-2015 Engineering Mechanics (Dynamics)

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Lecture About Dynamics

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  • 5/21/2018 PPT Lecture- Intro to Dynamics & Kinematic Motion

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    L E C T U R E N O T E S

    B Y :

    E N G R . F R A N C I S F . V I L L A R E A L

    D L S U - D / C E A T / 1 S T S E M S Y 2 0 1 4 - 2 0 1 5

    Engineering Mechanics

    (Dynamics)

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    INTRODUCTION

    Dynamics includes:

    - Kinematics: study of the geometry of motion. Kinematics isused to relate displacement, velocity, acceleration, and timewithout reference to the cause of motion.

    - Kinetics: study of the relationsexistingbetween the forcesacting on a body, the mass of the body, and the motion of thebody. Kinetics is used to predict the motion caused by givenforces or to determine the forces required to produce a given

    motion.

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    12.1 Introduction

    Mechanics

    Rigid-body Deformable-body fluid

    StaticEquilibrium body

    DynamicsAccelerated motion body

    Kinematics(Geometric aspect of motion)

    Kinetics(Analysis of force causing the motion)

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    KINEMATICS OF PARTICLES

    Rectilinearmotion: position, velocity, andacceleration of a particle as it moves along a straightline.

    Curvilinearmotion: position, velocity, andacceleration of a particle as it moves along a curvedline in two or three dimensions.

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    KINEMATICS OF PARTICLES

    Kinematics of

    particles

    Road Map

    Rectilinear motion Curvilinear motion

    x-y coord. n-t coord. r-coord.

    Relative motion

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    RECTILINEAR MOTION

    Particle moving along a straight line is said to be in rectilinear

    motion.

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    Determination of the Motion of a Particle

    Recall, motionof a particle is known if itspositionis known for all time t.

    Typically, conditions of motion are specified by the type of acceleration

    experienced by the particle. Determination of velocity and position requires

    successive integrations.

    Three types of motion may be defined for:

    - acceleration given as a function of time, a=f(t)

    - acceleration given as a function of position, a=f(x)

    - acceleration given as a function of velocity, a=f(v)

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    Graphical Solution of Rectilinear Motion

    Given thex-tcurve, the v-tcurve is equal to

    thex-tcurve slope.

    Given the v-tcurve, the a-tcurve is equal to

    the v-tcurve slope.

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    Kinematic Equations

    Consider particle which occupies positionPat time tand Pat t+Dt,

    Average velocity

    t

    xv

    t

    x

    t D

    D

    D

    D

    D 0

    limInstantaneous velocity

    Instantaneous velocity may be positive or negative.Magnitude of velocity is referred to asparticle speed.

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    Kinematic Equations

    Consider a particle with velocity vat time tand vatt+Dt,

    Instantaneous acceleration

    t

    va

    t D

    D

    D 0

    lim

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    RECTILINEAR MOTION FORMULAS

    Average velocity: V = dS/dt

    Average acceleration: a = d2S/dt2= dV/dt

    Constant acceleration:

    V V0= atS = V0t + (at

    2)

    V2V02= 2aS

    This applies to a freely falling object:dvvdsa

    22/2.32/81.9a sf tsm

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    Application Problem 1

    Consider a particle moving a straight line andassume that its position is defined by the equationwhere x is in meters and t in seconds.

    Show the graphical representation of the 3 motioncurves where x is a function of t, v as a function of tand a as a function of t.

    326 ttx

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    The brake mechanism used to reduce recoil in certain types of guns asshown in the given figure consists essentially of a piston attached to thebarrel and moving in a fixed cylinder filled with oil. As the barrel recoilswith an initial v0, the piston moves and oil is forced through orifices inthe piston, causing the piston and the barrel to decelerate at a rate

    proportional to their velocity; that is a = -kv. Express a.) v in terms of tb.) x in terms of t c.) v in terms of x and d.) draw the correspondingmotion curves.

    Application Problem 2

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    Cars A and B approached each other on a straightroad from a point where the 2 cars are 450 metersapart. Car A has an initial velocity of 70 kph and is

    being decelerated at a rate of 0.40m/s2. Cars B hasan initial velocity of 20 kph and is accelerating at arate of 0.30m/s2. When will the cars meet and howfar will Car A have traveled? Show accompanying

    figure.

    Application Problem 3

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    FREELY FALLING BODIES

    In the absence of air resistance, it is found that all bodies at the

    same location above the earth fall vertically with the same

    acceleration.

    Furthermore, if the distance of the fall is small compared to theradius of the earth, the accelerationremains essentially

    constant throughout the fall.

    This idealized motion, in which air resistance is neglected and

    the acceleration is nearly constant, is known as free-fall.

    Since the acceleration is constant in free-fall, the equations of

    kinematicscan be used.

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    GalileoGalilei (1564-1642)

    Father of Kinematics

    Concluded that all objects fallat same rate of acceleration.

    Demonstrated the scientificmethod in developing thekinematics of free fallmotion.

    Tested his hypothesisthrough experimentation.

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    Sir Isaac Newton (1642-1727)

    Father of dynamics(why)

    Published Three laws

    of motion and

    universal law ofgravitation in 1687.

    InertiaF=ma

    Action/reaction

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    Acceleration Due to Gravity

    Galileo calculated that all freely falling objectsaccelerate at a rate of

    9.8 m/s2

    This value, as an acceleration, is known as g

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    Free Fall An Object Dropped

    Initial velocity is zero

    Use the kinematic equations Generally use y instead of x since y

    is verticalAcceleration is ay= g= 9.80 m/s

    2

    vo= 0

    a =g

    Section 2.7

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    Free Fall Object Thrown Upward

    Initial velocity is upward,

    so positive

    The instantaneous velocity

    at the maximum height is

    zero.

    ay= -g = -9.80 m/s2

    everywhere in the motion

    v = 0

    vo 0a = -g

    Section 2.7

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    Application Problem 1

    A ball is tossed with a velocity of 10m/s directed vertically upward from a window of abuilding located 20 meters above the ground. Determine the following:

    Velocity v of the ball at any time t with graphical motion diagram

    Elevation y of the ball at any time t with graphical motion diagram

    Highest elevation in meters reached by the ball and value of time in seconds

    Time in seconds when the ball hits the ground

    V0= 10m/s

    20 m

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    A stone is thrown vertically upward over the top of a well with a velocity of21m/s and the splash is heard in 5.05 sec. If the velocity of sound is constant at350m/s, determine the depth of the well to which the stone falls.

    v0= 21m/s

    depth

    Application Problem 2

    water

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    CURVILINEAR MOTION

    Particle moving along a curve other than a straightline is in curvilinear motion

    Position vectorof a particle at time tis defined by a

    vector between origin Oof afixed reference frameand the position occupied by particle.

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    Plane Curvilinear Motion

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    Speed and Velocity

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    Acceleration

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    Visualization of Motion

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    The Coordinate System

    RECTANGULAR, x-y

    NORMAL TANGENTIAL, n-t

    POLAR, r-

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    Rectangular Coordinate System

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    Projectile Motion (x-y coordinate )

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    Application Problem 2

    A rocket has expended all its fuel when it reaches point A, where it hasvelocity u at angle with respect to the horizontal. It then beginsunpowered flight and attains a maximum added height h at position Bafter traveling a horizontal s from A. Determine the expression for hand s, the time t of flight from A to B and the equation of the path. For

    the interval concerned, assume a flat earth with a constant accelerationg and neglect any atmospheric resistance.

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    Normal-Tangential Coordinate System

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    Acceleration (n-t coordinate )

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    Acceleration (n-t coordinate )

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    Direction of Acceleration (n-t coordinate)

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    Circular Motion (n-t coordinate)

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    When a skier reaches point A along the parabolic path, he has a speed of 6m/swhich is increasing at 2m/s2. Determine the direction of his velocity anddirection and magnitude of his acceleration at this instant. Neglect the size ofthe skier.

    Application Problem 1

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    Polar Coordinate System

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    Velocity and Acceleration (r-)

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    Geometric Interpretation (r-)

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    Circular Motion (r-)

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    The searchlight shown in the given figure casts a spot of light along the face of awall that is located 100m from the searchlight. Determine the magnitudes ofthe velocity and acceleration at which the spot travels across the wall at theinstant = 450. The searchlight at a constant rate of 4 rad/sec.

    Application Problem 1