power flow analysis
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Power flow Analysis
Loud FLOW SOLUTION
Prepared toDr. Emaad Sedeek
Prepared byAhmed Raafat Ahmed
Power flow Analysis 2011
1. Gauss iterative Routine Method using [Y] Matrix
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Power flow Analysis 2011
i. Construct [Y] matrix
Y= y11 y 12 y 13y 21 y 22 y 23y 31 y 32 y 33
ii. Initial Assumption
iii. Calculation transmitted Power
iv. 1st iteration:
v. 2nd iteration :
vi. Calculation of complex power
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Power flow Analysis 2011
2. Gauss iterative Routine Method using [Z] Matrix
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Power flow Analysis 2011
i. Construct [Y] matrix
Y= y11 y 12 y 13y 21 y 22 y 23y 31 y 32 y 33
ii. Matrix ref. to bus one
iii. Matrix ref. to bus one
iv. Initial Assumption
v. Calculation transmitted Power
vi. 1st iteration:
vii. Calculation of complex power
3. Newton & Raphthon method
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Power flow Analysis 2011
i. Construct [Y] matrix
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Power flow Analysis 2011
Y= y11 y 12 y 13y 21 y 22 y 23y 31 y 32 y 33
ii. Initial Assumption
iii. Matrix formation of N.R Method
Where:
iv. Calculation of complex power
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Power flow Analysis 2011
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Power flow Analysis 2011
Solution :
(a)
1. Line impedances are converted to admittances
2. Initial condition
3. Calculation of transmitted power
4. 1st iteration
5. 2nd iteration
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Power flow Analysis 2011
6. Calculation of complex power
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(b)
To find the line flows1. Line Current
2. Line power flow
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Power flow Analysis 2011
3. Line power loss
4. Power flow diagram
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(C) The power flow program lfgauss is used to obtain the solution, with the following statements:clearbasemva = 100; accuracy = 0.000001; accel = 1.1; maxiter = 100;% Problem 6.7(c)% Bus Bus Voltage Angle -Load--- -Generator-- Injected% No code Mag. Degree MW MVAR MW MVAR Qmin Qmax Mvarbusdata=[1 1 1.0 0.0 0.0 0.0 0.0 0.0 0 0 02 0 1.0 0.0 400 320 0.0 0.0 0 0 03 0 1.0 0.0 300 270 0.0 0.0 0 0 0];% Line code% Bus busR X 1/2 B = 1 for lines% nl nr pu pu pu >1 or <1 tr. tap at bus nllinedata=[1 2 0.0 1/30 0.0 11 3 0.0 0.0125 0.0 12 3 0.0 0.050 0.0 1];disp('Problem 6.7(c)')Lfybus % form the bus admittance matrixlfgauss % Load flow solution by Gauss-Seidel methodbusout % Prints the power flow solution on the screenlineflow % Computes and displays the line flow and losses
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Power flow Analysis 2011
Result
Power Flow Solution by Gauss-Seidel MethodMaximum Power Mismatch = 7.39775e-007
No. of Iterations = 10
Bus Voltage Angle ------Load------ ---Generation--- Injected No. Mag. Degree MW Mvar MW Mvar Mvar 1 1.000 0.000 0.000 0.000 700.000 700.000 0.000 2 0.906 -6.340 400.000 320.000 0.000 0.000 0.000 3 0.951 -3.013 300.000 270.000 0.000 0.000 0.000 Total 700.000 590.000 700.000 700.000 0.000
Line Flow and Losses
--Line-- Power at bus & line flow --Line loss-- Transformer from to MW Mvar MVA MW Mvar tap 1 700.000 700.000 989.950 2 300.000 300.000 424.264 0.000 60.000 3 400.000 400.000 565.685 0.000 40.000 2 -400.000 -320.000 512.250 1 -300.000 -240.000 384.187 0.000 60.000 3 -100.000 -80.000 128.062 0.000 10.000 3 -300.000 -270.000 403.609 1 -400.000 -360.000 538.145 0.000 40.000 2 100.000 90.000 134.536 0.000 10.000 Total loss 0.000 110.000
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