placing figures in the coordinate plane

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Placing Figures in the Coordinate Plane Lesson 6-6

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Placing Figures in the Coordinate Plane. Lesson 6-6. Review:. Angles of a Kite. You can construct a kite by joining two different isosceles triangles with a common base and then by removing that common base. Two isosceles triangles can form one kite. Angles of a Kite. - PowerPoint PPT Presentation

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Page 1: Placing Figures in the Coordinate Plane

Placing Figures in the Coordinate Plane

Lesson 6-6

Page 2: Placing Figures in the Coordinate Plane

Review:

Page 3: Placing Figures in the Coordinate Plane

Angles of a KiteYou can construct a kite by joining two

different isosceles triangles with a common base and then by removing that common base.

Two isosceles triangles can form one kite.Two isosceles triangles can form one kite.

Page 4: Placing Figures in the Coordinate Plane

Angles of a Kite

Just as in an isosceles triangle, the angles between each pair of congruent sides are vertex anglesvertex angles. The other pair of angles are nonvertex anglesnonvertex angles.

Page 5: Placing Figures in the Coordinate Plane

Find the slope….

(a, b)

(3a, b+4)

Page 6: Placing Figures in the Coordinate Plane

Find the midpoint….

(a, b)

(3a, b+4)

Page 7: Placing Figures in the Coordinate Plane

Naming Coordinates

Rectangle KLMN is centered at the origin and the sides are parallel to the axes. Find the missing coordinates.

L(4, 3)

M(?, ?)

K(?, ?)

N(?, ?)

Answer:

K(-4, 3)

M(4, -3)

N(-4, -3)

Page 8: Placing Figures in the Coordinate Plane

Naming Coordinates

Rectangle KLMN is centered at the origin and the sides are parallel to the axes. Find the missing coordinates.

L(a, b)

M(?, ?)

K(?, ?)

N(?, ?)

Answer:

K(-a, b)

M(a, -b)

N(-a, -b)

Page 9: Placing Figures in the Coordinate Plane

Naming Coordinates Use the properties of a parallelogram to find the

missing coordinates. (Don’t use any new variables.

Q(?, ?)

P(s, 0)

K(b, c)

N(0, 0)

Answer:

Q(b + s, c)

Page 10: Placing Figures in the Coordinate Plane

Finding a Midpoint Find the coordinates of the midpoints

T, U, V, and W.

C(2c, 2d)

E(2e, 0)

A(2a, 2b)

O(0, 0)

W

V

U

T

Use midpoint formula:

2,

22121 yyxx

Answer:

T(a, b)

U(e, 0)

V(c + e, d)

W(a + c, b + d)

Page 11: Placing Figures in the Coordinate Plane

Finding a Slope

Find the slope of each side of OACE.

C(2c, 2d)

E(2e, 0)

A(2a, 2b)

O(0, 0)

W

V

U

T

Use slope formula:

12

12

xxyy

Answer:

slope of OA = b / a

slope of AC = d – b / c – a

slope of CE = c – e / d

slope of OE = 0

Page 12: Placing Figures in the Coordinate Plane

Midsegment of a trapezoid

The midsegment of a trapezoid is the segment that connects the midpoints of its legs. Theorem 6.17 is similar to the Midsegment Theorem for triangles.

midsegment

B C

DA

Page 13: Placing Figures in the Coordinate Plane

Theorem 6.17: Midsegment of a trapezoid

The midsegment of a trapezoid is parallel to each base and its length is one half the sums of the lengths of the bases.

MN║AD, MN║BC MN = ½ (AD + BC)

NM

A D

CB

Page 14: Placing Figures in the Coordinate Plane

Example

Find the value of x.

Page 15: Placing Figures in the Coordinate Plane

Mmmm cake.

5”

17”2nd layer?

14”

Page 16: Placing Figures in the Coordinate Plane

Assignment

Page 328 #’s 1-11 odd 20 , 23, 28-30, 31 Page 333 #’s 1 , 9