placing figures in the coordinate plane
DESCRIPTION
Placing Figures in the Coordinate Plane. Lesson 6-6. Review:. Angles of a Kite. You can construct a kite by joining two different isosceles triangles with a common base and then by removing that common base. Two isosceles triangles can form one kite. Angles of a Kite. - PowerPoint PPT PresentationTRANSCRIPT
Placing Figures in the Coordinate Plane
Lesson 6-6
Review:
Angles of a KiteYou can construct a kite by joining two
different isosceles triangles with a common base and then by removing that common base.
Two isosceles triangles can form one kite.Two isosceles triangles can form one kite.
Angles of a Kite
Just as in an isosceles triangle, the angles between each pair of congruent sides are vertex anglesvertex angles. The other pair of angles are nonvertex anglesnonvertex angles.
Find the slope….
(a, b)
(3a, b+4)
Find the midpoint….
(a, b)
(3a, b+4)
Naming Coordinates
Rectangle KLMN is centered at the origin and the sides are parallel to the axes. Find the missing coordinates.
L(4, 3)
M(?, ?)
K(?, ?)
N(?, ?)
Answer:
K(-4, 3)
M(4, -3)
N(-4, -3)
Naming Coordinates
Rectangle KLMN is centered at the origin and the sides are parallel to the axes. Find the missing coordinates.
L(a, b)
M(?, ?)
K(?, ?)
N(?, ?)
Answer:
K(-a, b)
M(a, -b)
N(-a, -b)
Naming Coordinates Use the properties of a parallelogram to find the
missing coordinates. (Don’t use any new variables.
Q(?, ?)
P(s, 0)
K(b, c)
N(0, 0)
Answer:
Q(b + s, c)
Finding a Midpoint Find the coordinates of the midpoints
T, U, V, and W.
C(2c, 2d)
E(2e, 0)
A(2a, 2b)
O(0, 0)
W
V
U
T
Use midpoint formula:
2,
22121 yyxx
Answer:
T(a, b)
U(e, 0)
V(c + e, d)
W(a + c, b + d)
Finding a Slope
Find the slope of each side of OACE.
C(2c, 2d)
E(2e, 0)
A(2a, 2b)
O(0, 0)
W
V
U
T
Use slope formula:
12
12
xxyy
Answer:
slope of OA = b / a
slope of AC = d – b / c – a
slope of CE = c – e / d
slope of OE = 0
Midsegment of a trapezoid
The midsegment of a trapezoid is the segment that connects the midpoints of its legs. Theorem 6.17 is similar to the Midsegment Theorem for triangles.
midsegment
B C
DA
Theorem 6.17: Midsegment of a trapezoid
The midsegment of a trapezoid is parallel to each base and its length is one half the sums of the lengths of the bases.
MN║AD, MN║BC MN = ½ (AD + BC)
NM
A D
CB
Example
Find the value of x.
Mmmm cake.
5”
17”2nd layer?
14”
Assignment
Page 328 #’s 1-11 odd 20 , 23, 28-30, 31 Page 333 #’s 1 , 9