physics 218

21
Physics 218 Alexei Safonov Lecture 3: Kinematics

Upload: august-schmidt

Post on 02-Jan-2016

35 views

Category:

Documents


2 download

DESCRIPTION

Lecture 3: Kinematics. Physics 218. Alexei Safonov. Today. Finish material from last time Start Kinematics. z. ^. k. y. x. ^. ^. j. i. First Question:. A . B = |A||B|Cos Q. Harder Example. Vector Cross Product. This is the last way of multiplying vectors we will see - PowerPoint PPT Presentation

TRANSCRIPT

Page 1: Physics 218

Physics 218

Alexei Safonov

Lecture 3: Kinematics

Page 2: Physics 218

Moving CarA harder example:

X = ct2

What’s the velocity at t=1 sec?Want to calculate the “Slope” here.Instantaneous VelocityWhat would my speedometer read?

Page 3: Physics 218

Displacement

Time taken

Displacement and Velocity in One Dimension

Page 4: Physics 218

Definition:

Speed = |v(t)|

The v(t) vs. t plot is just the slope of the x(t) vs. t plot

Displacement and Velocity in One Dimension

Page 5: Physics 218

Check: Constant Position

– X = C = 22 feet – V = slope = dx/dt = 0

Page 6: Physics 218

Check: Constant Velocity• Car is moving

– X=0 feet at t0=0 sec

– X=22 feet at t1=1 sec

– X=44 feet at t2=2 sec

• What is the equation of motion?

• X = bt with b=22 ft/sec• V = dX/dt

V= b = 22 ft/sec

Page 7: Physics 218

Derivatives: Common Mistakes

• The trick is to remember what you are taking the derivative “with respect to”

• More Examples (with a=constant):• What if X= 2a3tn?

– Why not dx/dt = 3(2a2tn)?– Why not dx/dt = 3n(2a2tn-1)?

• What if X= 2a3?– What is dx/dt?– There are no t’s!!! dx/dt = 0!!!– If X=22 feet, what is the velocity? =0!!!

Page 8: Physics 218

Check: Non-Constant Velocity• X = ct2 with c=11 ft/sec2

• V = dX/dt = 2ct• The velocity is:

• “non-Constant” • a “function of time” • “Changes with time”

– V=0 ft/s at t0=0 sec

– V=22 ft/s at t1=1 sec

– V=44 ft/s at t2=2 sec

Page 9: Physics 218

A) YESB) NO

Are the plots shown at the left correctly related

Displacement and Velocity in One Dimension

Page 10: Physics 218

Acceleration• If the velocity is changing, we are

“accelerating”• Acceleration is the “Rate of change of

velocity”– Just like velocity is the rate of change in

distance (or position)• You hit the accelerator in your car to speed

up– (It’s true you also hit it to stay at constant velocity, but that’s

because friction is slowing you down…we’ll get to that later…)

Page 11: Physics 218

Acceleration

• Acceleration is the “Rate of change of velocity”

• Said differently: “How fast is the Velocity changing?” “What is the change in velocity as a function of time?”

dtdV

ttVV

ΔtΔVAccel

12

12

Page 12: Physics 218

ExampleYou have an equation of motion of:

X(t) = X0 + V0t + ½at2

where X0, V0 , and a are constants. What is the velocity and the

acceleration? V(t) = dx/dt = 0 + V0 + at

• Remember that the derivative of a constant is Zero!!

Accel = dV/dt =d2x/dt2 = 0 + 0 + a

Page 13: Physics 218

Important Equations of MotionIf the acceleration is constant

Position, velocity and Acceleration are vectors. More on this in Chap 3

221

00

0

tatv x x

tav v

Page 14: Physics 218

Constant Acceleration

constanta(t) = a

Page 15: Physics 218

Acceleration

Page 16: Physics 218

Problem with Derivatives

• A car is stopped at a traffic light. It then travels along a straight road so that its distance from the light is given by – x(t) = bt2 - ct3, b= 2.40 m/s2, c = 0.12 m/s3

• Calculate: – instantaneous velocity of the car at t= 0,5,10 s – How long after starting from rest is the car

again at rest?

Page 17: Physics 218

Position, Velocity and Acceleration

• All three are related– Velocity is the derivative of position with

respect to time– Acceleration is the derivative of velocity

with respect to time– Acceleration is the second derivative of

position with respect to time• Calculus is REALLY important• Derivatives are something we’ll come

back to over and over again

Page 18: Physics 218

Inverse Derivative?

• If someone gives us an equation of motion for position x(t), we have shown that by taking derivatives we can find velocity and acceleration

• Can we go in the opposite order: if someone gives us acceleration, how do we get velocity and position?

• Is there a reverse of derivative?– Integrals

Page 19: Physics 218

Definite and Indefinite Integrals

cacbct|cdt

ca, b,

cdt

b)d(ct

b

b ct dt c

itiveanti-deriv

Value

btat

b

a

constants) are and (assuming

:ends and begins nintegratio of regionmy know where I If

equation theof

sideright the toadded is andconstant arbitrary an is where

)(

an is integral an many ways In

integral? an of thecalculate youHow to

Page 20: Physics 218

• Imagine you were instead given the velocity vs. time graph:– v(t)=v0+at

• You can find the total distance traveled from the area under the curve:– v0t + ½at2

• Can also find this by analytical integration…

Getting Displacement from Velocity

t

ovdt0x-x

For const acceleration the

Equation of motion: x(t)=x0+v0t + ½at2

Page 21: Physics 218

Next Time

• Temporary web-site:– http://people.physics.tamu.edu/safonov/218/lectures/

– Will contain lectures and notes• Homework for Chapter 2 due Sunday• Pre-lectures for Chapter 3 due Monday at

8am