physics 114a - mechanics lecture 6 (walker: 3.4-5) the r, v, and a vectors january 12, 2012 john g....
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Physics 114A - MechanicsLecture 6 (Walker: 3.4-5)
The r, v, and a VectorsJanuary 12, 2012
Physics 114A - MechanicsLecture 6 (Walker: 3.4-5)
The r, v, and a VectorsJanuary 12, 2012
John G. CramerProfessor Emeritus, Department of Physics
B451 [email protected]
January 12, 2012 Physics 114A - Lecture 6 2/24
AnnouncementsAnnouncements Because of recent problems with WebAssign, I have moved the
due date for Assignment #1 to 11:59 PM on Tuesday, January 17. Now all 215 registered students have WebAssign Accounts. Good! Assignment #2 is still due at 11:59 PM on Thursday, January 19.
Register your clicker using the “Clicker” link on the Physics 114A Syllabus page. So far 188/215 students have registered their clickers. You may talk to your neighbors during a clicker session. If your clicker ID is not appearing, reset it to Channel 01 and/or if necessary, get closer to the pickup antenna.
We will have Exam 1 on Friday, January 20. It will be about 75% multiple choice and 25% free response. The questions will be based on Walker “2-dot” end-of-chapter questions. There will be assigned seating. If you wish a left-handed seat, a right-handed aisle seat, or a front row seat, send your request to me by E-mail.
January 3, 2012 Physics 114A - Lecture 1 3/21
Physics 114A - Introduction to Mechanics - Winter-2012
Lecture: Professor John G. Cramer
Textbook: Physics, (Edition: UW Vol. 1 or Complete 4th), James S. Walker
Week Date L# Lecture Topic Pages Slides Reading HW Due Lab
1
2-Jan-12 H1 New Year Holiday
No Lab 1st week3-Jan-12 1 Introduction to Physics 12 21 Chapter 1
5-Jan-12 2 Position & Velocity 8 22 2-1 to 2-3 No HW
6-Jan-12 3 Velocity & Acceleration 10 25 2-4 to 2-5
2
9-Jan-12 4 Equations of Motion 9 20 2-6 to 2-7
1-D Kinematics10-Jan-12 5 Vectors 8 24 3-1 to 3-3
12-Jan-12 6 r, v & a Vectors 5 24 3-4 to 3-5 HW1
13-Jan-12 7 Relative Motion 3 18 3-6
3
16-Jan-12 H2 MLK Birthhday Holiday
Free Fall & Projectiles17-Jan-12 8 2D Motion Basics 5 19 4-1 to 4-2
19-Jan-12 9 2D Examples 13 22 4-3 to 4-5 HW2
20-Jan-12 E1 EXAM 1 - Chapters 1-4
Lecture Schedule (Part 1)
Lecture Schedule (Part 1)
We are here.
January 12, 2012 Physics 114A - Lecture 6 4/24
Unit VectorsUnit Vectors Unit vectors are dimensionless vectors of unit length. For example, the vector has magnitude (with units) Ax and points along the +x axis.
ˆxA A x
A
January 12, 2012 Physics 114A - Lecture 6 5/24
Scalar-Vector MultiplicationScalar-Vector MultiplicationMultiplying vectors
by scalars: the scalar multiplier changes the vector length, and the scalar sign can reverse the direction.
This property allows vectors to be factored into a unit vector and a multiplier. The unit vector specifies only the direction, while the multiplier provides the magnitude and units of the vector.
January 12, 2012 Physics 114A - Lecture 6 6/24
Unit VectorsUnit Vectorsˆ (1,0,0) unit vector in +x-direction = "x-hat"
ˆ (0,1,0) unit vector in +y-direction = "y-hat"
ˆ (0,0,1) unit vector in +z-direction = "z-hat"
x
y
z
ˆ ˆ ˆ ( , , )x y k x y z x y zA A A A A x A y A z A A A
ˆ ˆ ˆ4 2 5 (4, 2,5)B x y z Example:
An alternative notation is:
ˆˆ ˆˆ ˆ ˆ, , and . x i y j z k
January 12, 2012 Physics 114A - Lecture 6 7/24
Position, Displacement, Velocity, & Acceleration
Vectors
Position, Displacement, Velocity, & Acceleration
Vectors The position vector r points from the origin to the location in question. The displacement vector Δr points from the original position to the final position.
January 12, 2012 Physics 114A - Lecture 6 8/24
The Displacement VectorThe Displacement Vector
ˆ ˆr xx yy
2 1r r r
2 1
2 2 1 1ˆ ˆ ˆ ˆ( ) ( )
ˆ ˆ
r r r
x x y y x x y y
xx y y
January 12, 2012 Physics 114A - Lecture 6 9/24
The Average Velocity VectorThe Average Velocity Vector
Average velocity vector:
(3-3)
So vav is in the same
direction as Δr.
January 12, 2012 Physics 114A - Lecture 6 10/24
The Average & Instantaneous Velocity
Vectors
The Average & Instantaneous Velocity
VectorsInstantaneous velocity vector is tangent to the path:
January 12, 2012 Physics 114A - Lecture 6 11/24
Velocity VectorsVelocity Vectors
2 1
2 2 1 1ˆ ˆ ˆ ˆ( ) ( )
ˆ ˆ
r r r
x x y y x x y y
xx y y
av
rv
t
0limt
rv
t
0 0 0 0
ˆ ˆˆ ˆlim lim lim lim
t t t t
r xx y y x yv x y
t t t t
ˆ ˆx yv v x v y 2 2 ; arctan y
x yx
vv v v
v
January 12, 2012 Physics 114A - Lecture 6 12/24
Example: A DragonflyExample: A Dragonfly
A dragonfly is observed initially at position:
Three seconds later, it is observed at position:
What was the dragonfly’s average velocity during this time?
1 ˆ ˆ(2.00 m) (3.50 m)r x y
2 ˆ ˆ( 3.00 m) (5.50 m)r x y
2 1
ˆ ˆ( 3.00 m) (2.00 m) (5.50 m) (3.50 m)
(3.00 s)
ˆ ˆ( 1.67 m/s) (0.667 m/s)
av
r rrv
t tx y
x y
January 12, 2012 Physics 114A - Lecture 6 13/24
110 m 130 m0.167 m/s
120 sxav
xv
t
Example: Velocity of a Sailboat
Example: Velocity of a Sailboat
ˆ ˆav xav yavv v x v y
218 m 205 m0.108 m/s
120 syav
yv
t
ˆ ˆ( 0.167 m/s) (0.108 m/s)avv x y
2 2( 0.167 m/s) (0.108 m/s) 0.199 m/savv
o0.108 m/sarctan 147
0.167 m/s
A sailboat has coordinates (130 m, 205 m) at t1=0.0 s. Two minutes later its position is (110 m, 218 m). (a) Find ; (b) Find ;
avv
avv
January 12, 2012 Physics 114A - Lecture 6 14/24
Velocity & Acceleration Vectors
Velocity & Acceleration Vectors
The average acceleration vector a is in the direction of the change in velocity v:
January 12, 2012 Physics 114A - Lecture 6 15/24
Acceleration on a CurveAcceleration on a Curve
Typically, for a vehicle moving on a curve at a uniform speed, the acceleration is perpendicular to the velocity and the magnitude of the velocity stays the same, while the velocity’s direction changes.
For example, consider a car that has an initial velocity of 12 m/s east, and 10 seconds later its velocity is 12 m/s south.
2 2ˆ ˆ( 12 m/s) (12 m/s)ˆ ˆ( 1.2 m/s ) ( 1.2 m/s )
(10.0 s)av
v y xa x y
t
January 12, 2012 Physics 114A - Lecture 6 16/24
Example: Car Acceleratingon a Curve
Example: Car Acceleratingon a Curve
A car is traveling northwest at 9.00 m/s. Eight seconds later it has rounded a corner and is now headed north at 15.0 m/s/(a) What is the magnitude and direction of the acceleration during those 8.0 s?
N (y)
E(x)
ˆ ˆ ˆ ˆ(9.0 m/s)cos135 (9.0 m/s)sin135 ( 6.36 m/s) (6.36 m/s)iv x y x y
ˆ(15.0 m/s)fv y
ˆ ˆ(6.36 m/s) (8.64 m/s)f iv v v x y
2 2ˆ ˆ(0.795 m/s ) (1.08 m/s )av
va x y
t
2 2 2 2 2(0.795 m/s ) (1.08 m/s ) 1.34 m/sava
1 2 2tan (1.08 m/s ) / (0.795 m/s ) 53.6a
January 12, 2012 Physics 114A - Lecture 6 17/24
Acceleration VectorsAcceleration Vectors
;av
va
t
0limt
va
t
0ˆ ˆ ˆ ˆˆ ˆlimx y z
t
x y zv v x v y v z x y z
t t t
0ˆ ˆ ˆ ˆˆ ˆlim yx z
x y zt
vv va x y z a x a y a z
t t t
0 0 0lim ; lim ; limyx z
x y zt t t
vv va a a
t t t
January 12, 2012 Physics 114A - Lecture 6 18/24
Position, Displacement, Velocity, & Acceleration
Vectors
Position, Displacement, Velocity, & Acceleration
Vectors The velocity vector v always points in the direction of motion.
The acceleration vector a can point anywhere.
January 12, 2012 Physics 114A - Lecture 6 19/24
Clicker Question 1Clicker Question 1
A particle moves to the right in the x-y plane along the blue path. Identify each vector in the figure as a position (P) , velocity (V), or acceleration (A) vector.
(1) 1=V, 2=A, 3=P, 4=V; (2) 1=A, 2=P, 3=V, 4=P;
(3) 1=P, 2=V, 3=V, 4=A; (4) 1=P, 2=A, 3=A, 4=V;
January 12, 2012 Physics 114A - Lecture 6 20/24
Example: A Thrown Baseball
Example: A Thrown Baseball
The position of a thrown baseball is given by:
(a) Find the velocity as a function of time.(b) Find the acceleration as a function of time.
2 2ˆ ˆ[1.5 m (12 m/s) ] [(16 m/s) (4.9 m/s ) ]r t x t t y
1.5 m (12 m/s) ;x t 2 2(16 m/s) (4.9 m/s )y t t
0lim 12 m/s;xt
xv
t
2
0lim (16 m/s) 2(4.9 m/s )y t
yv t
t
0lim 0;x
x t
va
t
2
0lim 9.8 m/sy
y t
va
t
2ˆ ˆ(12 m/s) [(16 m/s) (9.8 m/s ) ] ;v x t y 2 ˆ( 9.8 m/s )a y
January 12, 2012 Physics 114A - Lecture 6 21/24
Example: Rounding a Curve
Example: Rounding a Curve
A car is traveling east at 60 km/h. It rounds a curve, and 5.0 s later it is traveling north at 60 km/h.(a) Find the average acceleration of the car.
;av
va
t
f iv v v
ˆ ˆ(60 km/h) (60 km/h)
5.0 sf i
av
v v j ia
t
1 h 1000 m60 km/h 16.7 m/s
3600 s 1 km
2 2ˆ ˆ(16.7 m/s) (16.7 m/s)ˆ ˆ( 3.4 m/s ) (3.4 m/s )
5.0 sav
y xa x y
January 12, 2012 Physics 114A - Lecture 6 22/24
Direction of theAcceleration Vector
Direction of theAcceleration Vector
Bungee Jumper’sDecent and Ascent
Bungee Jumper
January 12, 2012 Physics 114A - Lecture 6 23/24
You are asked to substitute for an illperformer in a circus that is sponsoredby your school. The job, should youchoose to accept it, is to be shotout of a cannon. Never afraidto accept a challenge, youaccept. The barrel ofthe cannon is inclinedat an angle of 600
above the horizontal. Your physics teacher offers you extra credit if you successfully use a motion diagram to estimate your acceleration during the ascending portion of your flight. 1. Make a motion diagram with velocities. 2. Draw a vector addition diagram usingthe relation: 3. Draw the acceleration from:
Example: Human Cannonball
Example: Human Cannonball
i fv v v
/a v t
Before the next lecture, read WalkerChapter 3.6
Homework Assignment #1 should be submitted using the WebAssign system by11:59 PM on Thursday, January 12 (Tonight!). Homework Assignment #2 should be submitted using the WebAssign system by 11:59 PM on Thursday, January 19.
End of Lecture 6End of Lecture 6