phys 322 chapter 9 interference lecture 24
TRANSCRIPT
Interference
Optical interference: superposition of two or more lightwavesyielding resultant irradiance that deviates from the simple sum of the components
Chapter 9
Phys 322Lecture 24
Example
Two point sources
11011 cos, trkEtrE
22022 cos, trkEtrE
Assume linear polarization:
Irradiance:T
EI 2
v
TTTTT
EEEEEEEI 2122
21
221
2
v2vvvv
~I1 ~I2
interference term, I12
1221 IIII
cos020112 EEI
v
2121 rkrk phase difference:
Two point sources
cos020112 EEI
v
2121 rkrk
1221 IIII
1. Orthogonal polarization: 012 I 21 III
2. Parallel polarization: cos020112 EEI v2
2012
121
EEIT
vv
cos2 2112 III
cos2 2121 IIIII
Two point sources
cos2 2121 IIIII
Total destructive interference: = ±, ±3, …
2121min 2 IIIII
Constructive interference: cos > 0Total constructive interference: = 0, ±2, ±4, …
2121max 2 IIIII
Destructive interference: cos < 0
Special case, : 0201 EE
2
cos4)cos1(2 200
III
0
4I0
Interference and conservation of energy
4I0Is the law of conservation of energy violated?
0The interference term must average out to zero over space!The space average of I is I1+I2.
2cos4)cos1(2 2
00 III
interference fringes
Interference minima and maxima
Note: equation works only when distances r1 and r2 are large compared to the distance between the sources, and also the interference region is small.
2cos4)cos1(2 2
00 III
0201 EE
2121
20 2
1cos4 rrkII
If emitters are in-phase: 21 rrk
maximum: mkmrr /221 , m = 0, ±1, ±2, …
minimum: '21/'21 mkmrr , m’ = ±1, ±3, …
Interference and conservation of energy
2cos4)cos1(2 2
00 III
maximum: mkmrr /221 , m = 0, ±1, ±2, …
minimum: '21/'21 mkmrr , m’ = ±1, ±3, …
hyperboloid of revolution
Young’s double-slit experiment: center
Screen a distance sfrom slits
Single source of monochromatic light
a
2 slits-separated by a
1) Constructive
2) Destructive
3) Depends on s
The rays start in phase, and travel the same distance, so they will arrive in phase.
s
Light waves from a single source travel through 2 slits before meeting on a screen. The interference will be:
Young’s double-slit experiment: screen
Path difference changesacross the screen:Sequence of minima and maxima
At points where the difference in path length is0, , 2, …, the screen is bright. (constructive)
At points where the difference in path
length is
the screen is dark. (destructive)
...2
5,2
3,2
screen
Young’s double-slit experiment: quantitative
Destructive interference
Constructive interference
where m = 0, ±1, ± 2, ... Need < a
Path length difference = a sin
a a
ma sin
21sin ma
ExampleTwo slits 1 mm apart are 2 m away from the screen. What would be the distance between the zero’th and first maximum for light with =500 nm?
a
y
s
ma sin
m=0
m=1
sy tansinGeometry:(for small )
msay
asmy
mm 1m 101
21050013
9
y
Examples
When Young’s double slit experiment is placed under water. The separation y between minima and maxima
1) increases 2) same 3) decreases
Under water decreases so y decreases
ma sin
When distance between the slits in Young’s double slit experiment is decreased,
The separation y between minima and maxima
1) increases 2) same 3) decreases
asmy
Double slit: intensity distributionFar from the sources, s>>a
sa
2cos4 2
0II
2
cos4 2120
rrkII r2 r1 y
syaaarr tansin21
skayII2
cos4 20
sayII 2
0 cos4
a
r1- r2
9.2 Conditions for interference1) For producing stable pattern, the two sources must have
nearly the same frequency.2) For clear pattern, the two sources must have similar
amplitude.3) For producing interference pattern, coherent sources are
required.
Temporal coherence:Time interval in which the light resembles a sinusoidal wave. (~10 ns for nature light)Coherent length: lc= ctc.Spatial coherence:The correlation of the phase of a light wave between different locations.
Double slit interference: conditions
1. Spatial coherence: wave front should be coherent over distance a
2. Spatial coherence: r1-r2<lc
3. Waves should not be orthogonally polarized
a
Reminder: The coherence time is the reciprocal of the bandwidth.
The coherence time is given by:
where is the light bandwidth (the width of the spectrum).
Sunlight is temporally very incoherent because its bandwidth isvery large (the entire visible spectrum).
Lasers can have coherence times as long as about a second,which is amazing; that's >1014 cycles!
1/c v
The Temporal Coherence Time and the Spatial Coherence LengthThe temporal coherence time is the time the wave-fronts remain equally spaced. That is, the field remains sinusoidal with one wavelength:
The spatial coherence length is the distance over which the beam wave-fronts remain flat:
Since there are two transverse dimensions, we can define a coherence area.
Temporal Coherence
Time, c
Spatial Coherence
Length
Spatial and Temporal Coherence
Beams can be coherent or
only partially coherent
(indeed, even incoherent)
in both space and time.
Spatial andTemporal
Coherence:
TemporalCoherence;
Spatial Incoherence
Spatial Coherence;
TemporalIncoherence
Spatial andTemporal
Incoherence
Fresnel-Arago laws (on the interference of polarized light ):
1) Two orthogonal, coherent P-states cannot interfere. 2) Two parallel, coherent P-states will interfere in the same way as will
natural light.3) The two constituent orthogonal P-states of natural light cannot
interfere even if rotated into alignment (because these P-states are incoherent).
4) Two orthogonal P-states obtained from one P-state will interfere if rotated back into alignment (because they were coherent from the start).
Summary: Irradiance of a sum of two waves
2
*2
1
1Rec E E
I I I
Different colors
Different polarizations
Same colors
Same polarizations
1 2I I I
1 2I I I 1 2I I I
Interference only occurs when the waves have the same color and polarization.