pd3 paralelo s3 (2t)

13
PD3||S3 (2T) -primarioak izarrean-

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Page 1: PD3 paralelo S3 (2T)

PD3||S3 (2T) -primarioak izarrean-

Page 2: PD3 paralelo S3 (2T)
Page 3: PD3 paralelo S3 (2T)

Tentsio konposatuen arteko transformazio erlazioa:

n1n2

=Vp

Vs

=12000

3706

3=17

Vo = 2 ⋅ U23

⇒Vo = 2 ⋅ 706

3

= 576.4v

Vo' = 2 ⋅U2 ⇒Vo

' = 2 ⋅ 706 = 998.4v

Page 4: PD3 paralelo S3 (2T)

PD3 S3

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U =Vl1 −Vl2 ⇒ 0 ÷ 30º⇒U = V32( )1 − V12( )2

U = 2 ⋅Vo' ⋅ cos75 ⋅ sin α +165( )

α = 0º⇒Umax = 2 ⋅Vo' ⋅ cos2 75 =133.7v

α =15º⇒U = 0α = 30º⇒Umin = −2 ⋅Vo

' ⋅ cos2 75 = −133.7v

Page 10: PD3 paralelo S3 (2T)

U =ω ⋅ LB ⋅d JB( )dα

0 ÷ 30º⇒ JB =U

ω ⋅ LB0

α

∫ ⋅ dα =−2 ⋅Vo

' ⋅ cos75 ⋅ sin α −15( )ω ⋅ LB0

α

∫ ⋅ dα

JB =2 ⋅Vo

' ⋅ cos75ω ⋅ LB

⋅ cos α −15( ) − cos15[ ]

α = 0º etaα = 30º⇒ JB = 0

α =15º⇒ JB ,max =2 ⋅Vo

' ⋅ cos752 ⋅ π ⋅ fSAREA( ) ⋅ LB

⋅ 1− cos15[ ] = 320A

IC , kritikoa = 2 ⋅ JB ,max = 640A fJB = 6 ⋅ fSARE

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Ja =4 + 2 33

⋅n2n1⋅IC2

=4 + 2 33

⋅117

⋅100002

= 464A

VLC 0 PD3 =3 ⋅ 3 ⋅VO

π=3 ⋅ 3 ⋅ 576.4

π= 953.4v

VLC =VLC 0 −ΔVX ⇒ΔVX =VLC 0 −VLC = 953.4 − 600 = 353.4v

PLC =VLC ⋅ IC = 600 ⋅10000 = 6000000w

SSARE = 3 ⋅U ⋅ Ja = 3 ⋅12000 ⋅ 464 = 9644059w

FSARE =PLCSSARE

=60000009644059

= 0.622