otomatik kontrol sistemleri - sakarya Üniversitesi Çözümlü sorular 2015

8/9/2019 Otomatik Kontrol Sistemleri - Sakarya Üniversitesi Çözümlü Sorular 2015

1/13

56.65.76


2/13

g)

( )_ s( )J s

( ) W s

7

7

7

( ) ( )( )

( ) < ( )<

se `

_ s J s se ̀ s m J s se ` W s J s s m

s m

U-7)

6.3


3/13

ooo)

7 7

< <

6.63 6.63*<( ) dom( 7` ` `

y y `

U-5) řk`odnk @(X/X) jkrodom ̀ uvvktdkinoroeo adml` ôzkrk kinô`tlis nkđkroioi`

D( o )

o(t )

adlrl` nkđoőtođo

vkrodmoőtor. Guil jørk0

l) Uostkmo tliļmdlyli nohkrlisoykd nki`dkmdkro ylzļiļz. 6o( t ) o ,

6u( t ) u êldļőml ia`tlsļ oêoi sostkmo doikkrdkőtoroioz.

g) Doikkrdkőtorodmoő sostkm oêoi N( z ) lyrļ` zlmli slyļsld

`aitradeô adml` ôzkrk ̀ lpldļ êkvrom ̀ aitrad gda` noyljrlmļiļ êozoioz.

l) `

D

o(t )

vk uno( t )

u ( t ) D Wo( t )

nt

kőotdođo ̀ uddliļdlrl` 7no( t ) W <

o ( t ) u( t )o( t )

nt ` `

kdnk knodor.

7

<

W < h o ( t ) u( t )o( t )

` `

6 6

* <6 6

o ,u

h 7W < L o u

o ` `

6 6

* 6<

o ,u

o h G

u `

* * Ξo( t ) L Ξo(t ) G Ξu(t ) Ξt

Doikkrdkőtorodmoő Nurum nki`dkmo

66 6

o Ξo(t ) 7W <o u Ξo( t ) Ξu( t )

Ξt ` ` `

adlrl` ylzļdļr.

Nurum nki`dkmoioi Dlpdlek nøiôőômô ldļiļr osk,

66 6

o7W < s o u ΞO ( s ) Ξ[ ( s )

` ` `

6

66

o / ` ΞO( s )

7Wo


4/13

g)

Or(z) O(s)

^ N(z)+

-

^

s^ < k

s

66

6

o / `

7Wo < s u

` `

\o

C

Xj@o

pampl

qa qa qa< 7 I

l)

t -namkoi


5/13

U->)

l)

t-namkoi s-namkoi

. ( ) ( )g g K s @ s

;. . ( ) H ` x t ;. . ( ) H ` S s

8. ( ) . ( ). y^ t Hr ` x t r 8. ( ) . . ( ) y^ s ` r S s

:. ( )m ynw

^ t B ^

nt

:.( ) ( )

( ) ( ) ( ) ( )m y

m y

^ s ^ s^ s Bs s ^ s s

Bs

3. ( ) n

w t nt

3.

( )( ) ( ) ( )

s s s s s

s

?. ( ) ( )k m^ t ^ t ?. ( ) ( )k m^ s ^ s


6/13

U-;)

^= 6.< si oêoi r(t) u(t) oêoi E(z) ‟o kdnk knoioz. E( ) nkđkroio ckslp knoioz.

W(s)RAC

E(s)<s(s


7/13

<


8/13

7

7

7

6.66>3 6.66>:7

3 6.?6>36.66>3 6.66>:7

3 6.66>:7

3 6.?6>3 6.66

>3 6

>3 6.66>:

6><

.? 3

7

E z z

W z z

z

z z z

z z

z z

7

6.66>3 6.66>:73 6.66>:7

3 6.66>:7


9/13

UlyļsldĶődkmeo

rkh u

joroő

h W

h D

h o

h k (t)

lo =sgt

B

w @v

LNE

NLE Jôê @uv.@

uCļz Ødêkr

E(t)

g) Øiek Ldli @aitraddô NE-ml`oikyk lot nki`dkmdkr ylzļdļr.

-) ( ) ( )k m^ t ^ t (sôrk`do rkbomnk) iat2 ratarui slgot l`ļm `lyilđļ odk gksdkinođo `lgud

knodnođoinki zļt km` søz `aiusu admlz.

t- namkioink kdnk knodki nki`dkmdkroioi Dlpdlek nøiôőômdkro lőlđļnl vkrodmoőtor.

-) ( ) ( )k m^ s ^ s (sôrk`do rkbomnk)


10/13

sD+Wh h

<@ o sb

<K(s)

h O(s)

h

m^(s)

ŷ(s)

s @

@v

k̂(s)^

^

N(z)rkh

u u*

u< ŝ k

s

U-:)

J5(s)

<

7s 6.;

E(s)

6.<

J7(s)


11/13

E(s);>6

W(s)J(s)

(s)

J8(s)

E(s)W(s) K(s) J(s)

(s)

J8(s)

;E s K s J s

8K s W s K s J s

8

<K s W s

< J s

7- W(s)=6 oêoi

J5(s)

<

7s 6.;

E(s)

6.<

J7(s)

L s E s J s E s J

7 nG s L s J s ^ s

5E s G s J s

K s W s E s


12/13

< >L s K s J s K s J

< > 7 nG s K s J s K s J J s ^ s

< > 7 n 5E s K s J s K s J s J s ^ s J s

< 7 5 > 7 5 n 5K s K s J s J s J s K s J s J s J s ^ s J s

< 7 5 > 7 5 n 5K s < J s J s J s J s J s J s ^ s J s

5

n

< 7 5 > 7 5

J sK s ^ s

< J s J s J s J s J s J s

5

n < 7 5 > 7 5

K s J s

^ s < J s J s J s J s J s J s

Joroődkr oêoi K(s) êļ`ļő ohlnkso lőlđļnl vkrodmoőtor.

5

r ^n n

8 < 7 5 > 7 5

J s<K s K s K s W s ^ s

< J s < J s J s J s J s J s J s

g)

K s hai`soyaiuil lot saisuznl`o nkđkro sai nkđkr tkarkmo `uddliļdlrl` êøzôdôr.

^n ^n tnt s 6

k domk t domsK s

5

n^n tns 6

< 7 5 >s 6

7 5

J s^ s

< J s J s Jk do

smsK s doms

J s J s J s


13/13

n̂ t 7u(t) oêoi dlpdlek nøiôőômô n7

^ ss

nor.

^ns 6

<7 7s 6.;k doms

otomatik kontrol sistemleri - sakarya Üniversitesi Çözümlü sorular 2015

Documents