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• Objectives
• Heat, Work, and Internal Energy
• Thermodynamic Processes
Chapter 10 Section 1 Relationships
Between Heat and Work
Section 1 Relationships
Between Heat and Work Chapter 10
Objectives
• Recognize that a system can absorb or release
energy as heat in order for work to be done on or by
the system and that work done on or by a system can
result in the transfer of energy as heat.
• Compute the amount of work done during a
thermodynamic process.
• Distinguish between isovolumetric, isothermal, and
adiabatic thermodynamic processes.
Chapter 10
Heat, Work, and Internal Energy
• Heat and work are energy transferred to or from a
system. An object never has “heat” or “work” in it; it
has only internal energy.
• A system is a set of particles or interacting
components considered to be a distinct physical
entity for the purpose of study.
• The environment the combination of conditions and
influences outside a system that affect the behavior
of the system.
Section 1 Relationships
Between Heat and Work
Chapter 10
Heat, Work, and Internal Energy, continued
• In thermodynamic systems, work is defined in terms
of pressure and volume change.
Section 1 Relationships
Between Heat and Work
( )
work = pressure volume change
A FW Fd Fd Ad P V
A A
W P V
• This definition assumes that P is constant.
Chapter 10
Heat, Work, and Internal Energy, continued
• If the gas expands, as
shown in the figure, V is
positive, and the work done
by the gas on the piston is
positive.
• If the gas is compressed,
V is negative, and the
work done by the gas on
the piston is negative. (In
other words, the piston
does work on the gas.)
Section 1 Relationships
Between Heat and Work
Chapter 10
Heat, Work, and Internal Energy, continued
• When the gas volume remains constant, there is no
displacement and no work is done on or by the
system.
• Although the pressure can change during a process,
work is done only if the volume changes.
• A situation in which pressure increases and volume
remains constant is comparable to one in which a
force does not displace a mass even as the force is
increased. Work is not done in either situation.
Section 1 Relationships
Between Heat and Work
Chapter 10
Thermodynamic Processes
• An isovolumetric process is a thermodynamic
process that takes place at constant volume so that
no work is done on or by the system.
• An isothermal process is a thermodynamic process
that takes place at constant temperature.
• An adiabatic process is a thermodynamic process
during which no energy is transferred to or from the
system as heat.
Section 1 Relationships
Between Heat and Work
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Visual Concept
Chapter 10 Section 1 Relationships
Between Heat and Work
Thermodynamic Processes
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• Objectives
• Energy Conservation
• Sample Problem
• Cyclic Processes
Chapter 10 Section 2 The First Law of
Thermodynamics
Section 2 The First Law of
Thermodynamics Chapter 10
Objectives
• Illustrate how the first law of thermodynamics is a
statement of energy conservation.
• Calculate heat, work, and the change in internal
energy by applying the first law of thermodynamics.
• Apply the first law of thermodynamics to describe
cyclic processes.
Chapter 10
Energy Conservation
• If friction is taken into account, mechanical energy
is not conserved.
• Consider the example of a roller coaster:
– A steady decrease in the car’s total mechanical energy
occurs because of work being done against the friction
between the car’s axles and its bearings and between the
car’s wheels and the coaster track.
– If the internal energy for the roller coaster (the system) and
the energy dissipated to the surrounding air (the
environment) are taken into account, then the total energy
will be constant.
Section 2 The First Law of
Thermodynamics
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Visual Concept
Chapter 10 Section 2 The First Law of
Thermodynamics
Energy Conservation
Chapter 10
Energy Conservation, continued
• The principle of energy conservation that takes into
account a system’s internal energy as well as work
and heat is called the first law of thermodynamics.
• The first law of thermodynamics can be expressed
mathematically as follows:
U = Q – W
Change in system’s internal energy = energy
transferred to or from system as heat – energy
transferred to or from system as work
Section 2 The First Law of
Thermodynamics
Chapter 10
Sample Problem
The First Law of Thermodynamics
A total of 135 J of work is done on a gaseous
refrigerant as it undergoes compression. If the
internal energy of the gas increases by 114 J during
the process, what is the total amount of energy
transferred as heat? Has energy been added to or
removed from the refrigerant as heat?
Section 2 The First Law of
Thermodynamics
Chapter 10
Sample Problem, continued
1. Define
Given:
W = –135 J
U = 114 J
Section 2 The First Law of
Thermodynamics
Tip: Work is done
on the gas, so work
(W) has a negative
value. The internal
energy increases
during the process,
so the change in
internal energy
(U) has a positive
value.
Diagram:
Unknown:
Q = ?
Chapter 10
Sample Problem, continued
2. Plan
Choose an equation or situation:
Apply the first law of thermodynamics using the values
for U and W in order to find the value for Q.
U = Q – W
Section 2 The First Law of
Thermodynamics
Rearrange the equation to isolate the unknown:
Q = U + W
Chapter 10
Sample Problem, continued
3. Calculate
Substitute the values into the equation and solve:
Q = 114 J + (–135 J)
Q = –21 J
Section 2 The First Law of
Thermodynamics
Tip: The sign for the value of Q is negative. This
indicates that energy is transferred as heat from
the refrigerant.
Chapter 10
Sample Problem, continued
4. Evaluate
Although the internal energy of the refrigerant
increases under compression, more energy is
added as work than can be accounted for by the
increase in the internal energy. This energy is
removed from the gas as heat, as indicated by the
minus sign preceding the value for Q.
Section 2 The First Law of
Thermodynamics
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Visual Concept
Chapter 10 Section 2 The First Law of
Thermodynamics
First Law of Thermodynamics for Special
Processes
Chapter 10
Cyclic Processes
• A cyclic process is a thermodynamic process in
which a system returns to the same conditions under
which it started.
• Examples include heat engines and refrigerators.
• In a cyclic process, the final and initial values of
internal energy are the same, and the change in
internal energy is zero.
Unet = 0 and Qnet = Wnet
Section 2 The First Law of
Thermodynamics
Chapter 10
Cyclic Processes, continued
• A heat engine uses heat to do
mechanical work.
• A heat engine is able to do work
(b) by transferring energy from
a high-temperature substance
(the boiler) at Th (a) to a
substance at a lower
temperature (the air around the
engine) at Tc (c).
Section 2 The First Law of
Thermodynamics
• The internal-combustion engine found in most
vehicles is an example of a heat engine.
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Visual Concept
Chapter 10 Section 2 The First Law of
Thermodynamics
Combustion Engines
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Visual Concept
Chapter 10 Section 2 The First Law of
Thermodynamics
Refrigeration
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• Objectives
• Efficiency of Heat Engines
• Sample Problem
• Entropy
Chapter 10 Section 3 The Second Law of
Thermodynamics
Section 3 The Second Law of
Thermodynamics Chapter 10
Objectives
• Recognize why the second law of thermodynamics
requires two bodies at different temperatures for work
to be done.
• Calculate the efficiency of a heat engine.
• Relate the disorder of a system to its ability to do work
or transfer energy as heat.
Chapter 10
Efficiency of Heat Engines
• The second law of thermodynamics can be stated
as follows:
No cyclic process that converts heat entirely
into work is possible.
• As seen in the last section, Wnet = Qnet = Qh – Qc.
– According to the second law of thermodynamics,
W can never be equal to Qh in a cyclic process.
– In other words, some energy must always be
transferred as heat to the system’s surroundings
(Qc > 0).
Section 3 The Second Law of
Thermodynamics
Chapter 10
Efficiency of Heat Engines, continued
• A measure of how well an engine operates is given
by the engine’s efficiency (eff ).
• In general, efficiency is a measure of the useful
energy taken out of a process relative to the total
energy that is put into the process.
Section 3 The Second Law of
Thermodynamics
• Note that efficiency is a unitless quantity.
• Because of the second law of thermodynamics, the
efficiency of a real engine is always less than 1.
eff Wnet
QhQh –Qc
Qh 1
Qc
Qh
Chapter 10
Sample Problem
Heat-Engine Efficiency
Find the efficiency of a gasoline engine that, during
one cycle, receives 204 J of energy from combustion
and loses 153 J as heat to the exhaust.
Section 3 The Second Law of
Thermodynamics
1. Define
Given: Diagram:
Qh = 204 J
Qc = 153 J
Unknown
eff = ?
Chapter 10
Sample Problem, continued
2. Plan
Choose an equation or situation: The efficiency of
a heat engine is the ratio of the work done by the
engine to the energy transferred to it as heat.
Section 3 The Second Law of
Thermodynamics
eff Wnet
Qh 1
Qc
Qh
Chapter 10
Sample Problem, continued
3. Calculate
Substitute the values into the equation and
solve:
Section 3 The Second Law of
Thermodynamics
eff 1Qc
Qh 1
153 J
204 J
eff 0.250
4. Evaluate
Only 25 percent of the energy added as heat is used
by the engine to do work. As expected, the efficiency
is less than 1.0.
Chapter 10
Entropy
• In thermodynamics, a system left to itself tends to go
from a state with a very ordered set of energies to
one in which there is less order.
• The measure of a system’s disorder or randomness
is called the entropy of the system. The greater the
entropy of a system is, the greater the system’s
disorder.
• The greater probability of a disordered arrangement
indicates that an ordered system is likely to
become disordered. Put another way, the entropy
of a system tends to increase.
Section 3 The Second Law of
Thermodynamics
Chapter 10
Entropy, continued
• If all gas particles moved toward the piston, all of the
internal energy could be used to do work. This
extremely well ordered system is highly improbable.
Section 3 The Second Law of
Thermodynamics
• Greater disorder means there is less energy to do
work.
Chapter 10
Entropy, continued
• Because of the connection between a system’s
entropy, its ability to do work, and the direction of
energy transfer, the second law of
thermodynamics can also be expressed in terms of
entropy change:
The entropy of the universe increases in all
natural processes.
• Entropy can decrease for parts of systems, provided
this decrease is offset by a greater increase in
entropy elsewhere in the universe.
Section 3 The Second Law of
Thermodynamics
Chapter 10
Energy Changes Produced by a Refrigerator
Freezing Water
Section 3 The Second Law of
Thermodynamics
Because of the refrigerator’s less-than-perfect efficiency, the entropy of
the outside air molecules increases more than the entropy of the
freezing water decreases.
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Visual Concept
Chapter 10 Section 3 The Second Law of
Thermodynamics
Entropy of the Universe