oakland math test
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Oakland Math Test. Select Questions and Answers NOT Multiple Choice. What number added to the sum of equal the number 1?. solve for w. - PowerPoint PPT PresentationTRANSCRIPT
Oakland Math TestSelect Questions and Answers
NOT Multiple Choice
What number added to the sum of equal the number 1?
๐ฅ+ 13 +14=1
12๐ฅ+4+3=12
12๐ฅ=5
๐ฅ= 512
(43 )2
16=?
(43 )2
16=4
6
42=44=254
solve for w.
10๐ค=35๐ค=3.5
Jan is making clay coasters for an art fair. Each coaster costs $2.25 to make. If she sells the coasters for $4.00 each, how many will she have to sell to make a profit of exactly $70.00?
๐ฟ๐๐ก ๐ฅ๐๐ h๐ก ๐๐๐ข๐๐๐๐ ๐๐ ๐๐๐๐ ๐ก๐๐๐ h๐ ๐๐๐๐๐ .๐๐๐๐๐๐ก ๐๐ h๐๐๐ ร h๐ก ๐๐๐ข๐๐๐๐ ๐๐ ๐๐๐๐ ๐ก๐๐๐ =๐๐๐๐๐๐ก
(4.00โ2.25 ) ๐ฅ=70.00
1.75 ๐ฅ=70๐ฅ=40
Four pieces of ribbon are cut from a length of ribbon that is 80 ft long. One of the pieces is 15 feet long. Two of the pieces are 7ยฝ feet long. One of the pieces is 3ยพ feet long. How many feet of ribbon are left from the original length?
๐ฟ๐๐ก ๐ฅ ๐๐ก ๐๐ h๐ก ๐ h๐๐๐๐๐ก ๐๐ h๐ก ๐ ๐๐๐๐ก๐๐ฃ๐๐ ๐๐๐๐๐ .15+2(7 12 )+3 34 +๐ฅ=80
15+15+ 154 +๐ฅ=80154 +๐ฅ=50
15+4 ๐ฅ=2004 ๐ฅ=185๐ฅ=46 14 ๐๐ก
A taxi cab charges $0.80 for the first of a mile and $0.10 for each additional of a mile. What is the cost of 3 mile trip?
๐ฟ๐๐ก $ ๐ฅ๐๐ h๐ก ๐๐๐๐ ๐ก
๐ฅ=0.80+0.10 [ (3โ 15 )110
]๐ฅ=๐๐๐ ๐ก ๐๐ 1 ๐ ๐ก 15๐๐๐๐+๐๐๐ ๐ก ๐๐ h๐ก ๐๐๐๐ ๐ก๐๐ h๐ก ๐๐ก๐๐๐
๐ฅ=0.80+0.10 [ 145110
]๐ฅ=0.80+0.10 (28)๐ฅ=0.80+2.80๐ฅ=3.60
Another Method: since taxi cab charges by tenths of a mile. For a 3 mile trip, there are 30 tenths of a mile. The first or 2 tenths of a mile costs 80ยข, the rest, 28 tenths of a mile costs 10ยข.
๐๐๐ ๐ก=80ยข+10ยข(28)
Continue
ยฟ80+280=360=$3.60
John works a variety of different jobs. On Monday he earned $50. Tuesday he earned $40. On Wednesday and Thursday he earned $30 each day, and ion Friday he earned $100. What was johnโs average daily pay for the 5 days?
๐ด๐ฃ๐๐๐๐๐=50+40+30+30+100
5
ยฟ2505 =$50
Evaluate:
3 (โ2 )2โ2 (โ2 ) (3 )+32
ยฟ3 (4 )+12+9
ยฟ12+12+9
ยฟ33
Simplify:
(๐ฅ+ ๐ฆ )2โ (9๐ฅ๐ฆโ6 ๐ฅ2 )ยฟ ๐ฅ2+2๐ฅ๐ฆ+ ๐ฆ2โ9 ๐ฅ๐ฆ+6 ๐ฅ2
ยฟ7 ๐ฅ2โ7๐ฅ๐ฆ+ ๐ฆ2
Multiply:
(2 ๐ฅโ5 ) (6 ๐ฅ+4 )
ยฟ12 ๐ฅ2+8๐ฅโ30 ๐ฅโ20
ยฟ12 ๐ฅ2โ22 ๐ฅโ20
Divide:
12๐ฅ5โ6 ๐ฅ3+4 ๐ฅ2
4 ๐ฅ2
ยฟ12๐ฅ5
4 ๐ฅ2โ 6 ๐ฅ
3
4 ๐ฅ2+4 ๐ฅ2
4 ๐ฅ2
ยฟ3 ๐ฅ3โ 32 ๐ฅ+1
Factor:
6 ๐ฅ3+27 ๐ฅ2โ105 ๐ฅยฟ3 ๐ฅ (2๐ฅ2+9 ๐ฅโ35)
ยฟ3 ๐ฅ (2 ๐ฅโ5 ) (๐ฅ+7 )
Simplify:
๐ฅ2โ5 ๐ฅ+4๐ฅโ1
ยฟ(๐ฅโ4 ) (๐ฅโ1 )
๐ฅโ1
ยฟ ๐ฅโ4
Simplify:
ยฟ3+4=7
Evaluate: , find A
๐ด=๐ (1+๐ )
๐ด=450 (1+0.12 )
๐ด=450(1.12)
๐ด=504
Simplify:
โ18 ๐ฅโ4โ๐ฅ3ยฟ3 โ2 ๐ฅโ4 ๐ฅ โ๐ฅ
Rationalize:
2+โ32โโ3
โ(2+โ3 )(2+โ3 )
ยฟ 4+4โ3+34โ3
ยฟ7+4 โ3
Solve:
3 ๐ฅ+7=2(๐ฅโ1)
3 ๐ฅ+7=2๐ฅโ2
๐ฅ+7=โ2๐ฅ=โ9
Find the sum of the roots:
๐ฅ2โ6 ๐ฅ=7๐ฅ2โ6 ๐ฅโ7=0
(๐ฅ+1 ) (๐ฅโ7 )=0
๐ฅ+1=0 ๐๐ ๐ฅโ7=0
๐ฅ=โ1๐๐ ๐ฅ=7
๐ ๐ข๐๐๐ ๐๐๐๐ก๐ =โ1+7=6
Solve for x:
1๐ฅ +
2๐ฅ=10
1+2=10 ๐ฅ
10 ๐ฅ=3
๐ฅ= 310
Solve the Inequality:
โ2 ๐ฅ+3<5โ2 ๐ฅ<2๐ฅ>โ1
System of Equations:
(1 )2๐ฅ+3 ๐ฆ=โ11(2 )6 ๐ฅ+๐ฆ=7
๐น๐๐๐ (2): ๐ฆ=7โ6 ๐ฅ๐๐ข๐ ๐ก๐ (1 ) :2 ๐ฅ+3 (7โ6 ๐ฅ )=โ11
2 ๐ฅ+21โ18 ๐ฅ=โ11โ16 ๐ฅ=โ32๐ฅ=2
๐ฆ=7โ6 (2 )=7โ14=โ7
Solution:
Simplify the Expression:
2๐โ 2
(2๐)โ 3
ยฟ2 (2๐)3
๐2
ยฟ2 (8๐3 )๐2
ยฟ16๐3
๐2
ยฟ16 ๐
Scientific Notation:
(2.1ร105 )2
ยฟ (2.1ร105 ) (2.1ร105 )
ยฟ 4.41ร1010
Radicals:
3โ๐ โ 4โ๐ยฟ๐1 /3 โ๐1 /4
ยฟ๐13 +14
ยฟ๐412+ 312
ยฟ๐712
ยฟ 12โ๐7
Altogether Mark, John, and Alan earned $104. John earned twice as much as Mark and Alan earned $4 more than John. How much did Alan earn?
๐ฟ๐๐ก $ ๐ฅ๐๐ h๐ก ๐๐๐๐๐ข๐๐ก ๐๐๐๐๐๐๐๐๐๐h๐ฝ๐ ๐=2 ๐ฅ
๐ด๐๐๐= h๐ฝ๐ ๐+4=2๐ฅ+4
๐๐๐๐+ h๐ฝ๐ ๐+ ๐ด๐๐๐=104๐ฅ+2๐ฅ+2๐ฅ+4=104
5 ๐ฅ+4=1045 ๐ฅ=100๐ฅ=20
๐๐๐๐=$20
h๐ฝ๐ ๐=2 (20 )=$ 40
๐ด๐๐๐=2 (20 )+4=$ 44
A train travels 4 hrs at 60 miles per hour and 2 hours at 75 miles per hour. What is the trainโs average rate for 6 hours?
๐ด๐ฃ๐๐๐๐๐=๐ท๐๐ ๐ก๐๐๐๐๐๐ 1 ๐ ๐ก๐๐๐๐ก+๐ท๐๐ ๐ก๐๐๐๐๐๐ 2๐๐๐๐๐๐ก
๐๐๐ก๐๐๐ก๐๐๐
๐ด๐ฃ๐๐๐๐๐=4 (60 )+2 (75 )
6
ยฟ3906 =65 h๐๐
Graph:
2 ๐ฅ+๐ฆ=5๐ฆ=โ2๐ฅ+5
๐=โ21 ๐๐
2โ1 ๐๐๐๐=5
Start with point A, where b = 5 or (0, 5).For point B, start from point A, go down 2 and go to the right 1, For point C, start from point A,go up 2 and go to the left 1.
๐ด
๐ต
๐ถ
Slope: Are these two lines parallel?
๐ฟ13 ๐ฆ=โ2๐ฅ+6
๐ฆ=โ 23 ๐ฅ+2 ;๐1=โ23
๐ฟ2๐2=7โ105โ3 =
โ32
๐ฟ1๐๐๐๐ฟ2๐๐๐๐๐๐ ๐๐๐๐๐๐๐๐ ,๐ ๐๐๐๐๐ ๐๐๐ ๐๐๐ ๐๐๐ข๐๐ .
Write the equation of the line through (2, -1) and has slope m = 3. Write the equation in general form (standard form).
(2 ,โ1 )๐ฅ1 , ๐ฆ1
๐ฆโ ๐ฆ1=๐ (๐ฅโ๐ฅ1 )
๐ฆโ (โ1 )=3(๐ฅโ2)
๐=3
๐ฆ+1=3 ๐ฅโ6โ3 ๐ฅ+๐ฆ=โ7
Standard form
What is the distance between A(2, -5) and B(6, 3)? (Round to the nearest tenth).
๐ด (2 ,โ5 )๐ต (6 ,3)๐ฅ1 ๐ฆ1๐ฅ2 ๐ฆ2
๐ท=โ๐๐๐ ๐2+๐๐ข๐2
๐ท=โ ( ๐ฆ2โ ๐ฆ1 )2+ (๐ฅ2โ๐ฅ1)2
๐ท=โ (3+5 )2+(6โ2 )2
๐ท=โ (8 )2+ (4 )2
๐ท=โ64+16๐ท=โ80๐ท=4โ5
Graph:
๐ฆ=โ๐ฅ2+4๐ฆ=โ(๐ฅ2โ4)๐ฆ=โ (๐ฅ+2 ) (๐ฅโ2 )๐๐๐๐ก๐ : ๐ด (โ2 ,0 ) ,๐ต (2 ,0 )
๐๐ฅ๐๐ ๐๐ ๐ ๐ฆ๐๐๐๐ก๐๐ฆ :๐ฅ=โ ๐2๐
๐ฅ=โ 02 (โ1 )
=0
๐=โ1 ;๐=0 ;๐=4
๐ฆ=โ02+4=4๐๐๐ฅ=๐ถ(0 ,4 )
๐ด๐ต
๐ถ
.
ยฟ๐2+2๐+1+2๐+2+3
ยฟ๐2+4๐+6
What is the domain of ?
2 ๐ฅ+6=02 ๐ฅ=โ6๐ฅ=โ3
The domain of f(x) is ALL real numbers except -3
๐ท๐๐๐๐๐=(โโ ,โ3 )โช (โ3 ,โ )
h๐ ๐๐๐๐ ๐ (๐ฅ )๐ข๐๐๐๐๐๐๐๐?
What is the domain of
๐ฅโ7 โฅ0๐ฅโฅ7h๐ ๐๐๐๐๐๐๐๐๐ ๐ (๐ฅ ) ๐ด๐๐๐๐๐๐ ๐๐ข๐๐๐๐๐ โฅ7
๐๐๐๐๐๐=ยฟ
Composition of functions: Find
( ๐ โ๐) (3 )= ๐ (3) โ๐(3)ยฟ [3 (3 )โ2 ] โ[32+1]
ยฟ7 โ10( ๐ โ๐ ) (3 )=70
Composition of functions: Find .
๐ (๐ (3 ) )= ๐ (32+1)ยฟ ๐ (10)ยฟ3 (10 )โ2
๐ (๐ (3 ))=28
๐ (๐ (3 ) )=( ๐ โ๐)(3)