newton’s first law of motion 11/18/13 – 11/22/13

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Newton’s First Law of Motion 11/18/13 – 11/22/13 11/18 Weight vs Mass Textbook p 392-393 11/19 Newton’s 1 st Law of Motion Workbook p 65-68 11/20 Newton’s 1 st Law of Motion Workbook p. 69-72 11/21 Newton’s 1 st Law of Motion WB p. 73-76 11/22 Quiz

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Newton’s First Law of Motion 11/18/13 – 11/22/13. 11/18 Weight vs Mass Textbook p 392-393 11/19 Newton’s 1 st Law of Motion Workbook p 65-68 11/20 Newton’s 1 st Law of Motion Workbook p. 69-72 11/21 Newton’s 1 st Law of Motion WB p. 73-76 11/22 Quiz. - PowerPoint PPT Presentation

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Page 1: Newton’s First Law of Motion 11/18/13 – 11/22/13

Newton’s First Law of Motion11/18/13 – 11/22/13

11/18 Weight vs Mass Textbook p 392-393

11/19 Newton’s 1st Law of Motion Workbook p 65-68

11/20 Newton’s 1st Law of Motion Workbook p. 69-72

11/21 Newton’s 1st Law of Motion WB p. 73-7611/22 Quiz

Page 2: Newton’s First Law of Motion 11/18/13 – 11/22/13

Date: Objective: I can distinguish between mass and weight. I can also calculate weight in Newtons (N)

Bell Ringer:1. As the roller coaster travels from point A to B, how do its potential and kinetic energies change? 2. As the roller coaster travels from point D to E, how do its potential and kinetic energies change?

A

B

C

D

E

Page 3: Newton’s First Law of Motion 11/18/13 – 11/22/13

Date: Objective: I can distinguish between mass and weight. I can also calculate weight in Newtons (N)

Activity Titled : Textbook p. 392Answer Investigate Part A questions 1-5 in your

NotebookAnswer questions with your shoulder partner. Both

partners must write their answers

Page 4: Newton’s First Law of Motion 11/18/13 – 11/22/13

DEFINITIONS

Mass- the amount of matter an object has.

Matter- something that has mass and takes up space.

Weight- is the amount of mass of an object, it is dependent upon gravity.

1 pound (lbs)= .45 kilogram (kg)

Page 5: Newton’s First Law of Motion 11/18/13 – 11/22/13

Look at this figure. The mass of the bowling ball does not change, but the mass of the puppy does. How? Where does the matter come from?

Can the mass of the bowling ball ever change?

Page 6: Newton’s First Law of Motion 11/18/13 – 11/22/13
Page 7: Newton’s First Law of Motion 11/18/13 – 11/22/13

Place these 5 items in the order they would be the most attracted to the Earth due to gravity. Explain why you picked your order.

House fly

Tennis ball

Elephant

Bowling ballpeanut

Page 8: Newton’s First Law of Motion 11/18/13 – 11/22/13

Exit QuestionWhat would happen to your mass and to your weight if you went to the moon?

Explain how you arrived at your answer.

Singing on the moonhttps://www.youtube.com/watch?v=FMnzi8iFnG8Lunar Olympicshttps://www.youtube.com/watch?v=16D0hmLt-S0

Page 9: Newton’s First Law of Motion 11/18/13 – 11/22/13

Date: Objective: I can investigate Newton’s first law of motion

Bell Ringer:1.What would happen to your mass and to

your weight if you went to the moon? Explain how you arrived at your answer.

2.Calculate the weight of a 50kg ball?Fw=mg

Page 10: Newton’s First Law of Motion 11/18/13 – 11/22/13

Place these 5 items in the order they would be the most attracted to the Earth due to gravity. Explain why you picked your order.

House fly

Tennis ball

Elephant

Bowling ballpeanut

Page 11: Newton’s First Law of Motion 11/18/13 – 11/22/13

Activity

Workbook page 65

Read demonstration as a group

Complete workbook p.67 independently

Page 12: Newton’s First Law of Motion 11/18/13 – 11/22/13

Activity

Complete workbook p.68

Page 13: Newton’s First Law of Motion 11/18/13 – 11/22/13

Date: Objective: I can understand Newton’s first law of motion and apply the concept to my daily life

Bell Ringer:Based on our activityYesterday, if the rollerCoaster starts at point BWhat point will the cart Reach? D or E or FExplain why

Page 14: Newton’s First Law of Motion 11/18/13 – 11/22/13

Read Workbook p 69-71 independentlyAnd take cornell notes7 minutes

Page 15: Newton’s First Law of Motion 11/18/13 – 11/22/13

11/6/13 Newton’s 1st Law

Video

Page 16: Newton’s First Law of Motion 11/18/13 – 11/22/13

11/15/12 Newton’s 1st Law

Workbook page 72 complete TEJ

Page 17: Newton’s First Law of Motion 11/18/13 – 11/22/13

Example of a conservative system: The simple pendulum.

• Suppose we release a mass m from rest a distance h1 above its lowest possible point.– What is the maximum speed of the mass and where does

this happen ?– To what height h2 does it rise on the other side ?

v

h1 h2

m

Page 18: Newton’s First Law of Motion 11/18/13 – 11/22/13

Example: The simple pendulum.

y

y=0

y=h1

– What is the maximum speed of the mass and where does this happen ?

E = K + U = constant and so K is maximum when U is a minimum.

Page 19: Newton’s First Law of Motion 11/18/13 – 11/22/13

Example: The simple pendulum.

v

h1

y

y=h1

y=0

– What is the maximum speed of the mass and where does this happen ?

E = K + U = constant and so K is maximum when U is a minimum

E = mgh1 at top

E = mgh1 = ½ mv2 at bottom of the swing

Page 20: Newton’s First Law of Motion 11/18/13 – 11/22/13

Example: The simple pendulum.

y

y=h1=h2

y=0

To what height h2 does it rise on the other side?

E = K + U = constant and so when U is maximum again (when K = 0) it will be at its highest point.

E = mgh1 = mgh2 or h1 = h2

Page 21: Newton’s First Law of Motion 11/18/13 – 11/22/13

Potential Energy, Energy Transfer and Path• A ball of mass m, initially at rest, is released and follows three

difference paths. All surfaces are frictionless 1. The ball is dropped2. The ball slides down a straight incline3. The ball slides down a curved inclineAfter traveling a vertical distance h, how do the three speeds compare?

(A) 1 > 2 > 3 (B) 3 > 2 > 1 (C) 3 = 2 = 1 (D) Can’t tell

h

1 32

Page 22: Newton’s First Law of Motion 11/18/13 – 11/22/13

An experimentTwo blocks are connected on the table as shown. The tablehas a kinetic friction coefficient of k. The masses start at

rest and m1 falls a distance d. How fast is m2 going?

T

m1

m2

m2g

N

m1g

T

fk

Mass 1 Fy = m1ay = T – m1g

Mass 2 Fx = m2ax = -T + fk = -T + k N

Fy = 0 = N – m2g

| ay | = | ay | = a =(km2 - m1) / (m1 + m2)

2ad = v2 =2(km2 - m1) g / (m1 + m2)

K= - km2gd – Td + Td + m1gd = ½ m1v2+ ½ m2v2

v2 =2(km2 - m1) g / (m1 + m2)