neutralization – day 1

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Neutralization – Day 1. Neutralization Reactions. A neutralization reaction is a reaction in which an acid and a base react to produce a salt and water Acid + Base  Salt + H 2 O A salt is an ionic compound made up of a cation and an anion. 3 Types of Acid-Base Reactions. - PowerPoint PPT Presentation

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Page 1: Neutralization – Day 1
Page 2: Neutralization – Day 1

A neutralization reaction is a reaction in which an acid and a base react to produce a salt and water

Acid + Base Salt + H2O

A salt is an ionic compound made up of a

cation and an anion

Page 3: Neutralization – Day 1
Page 4: Neutralization – Day 1

HCl + NaOH base

+ H2O water

NaClsaltacid

Page 5: Neutralization – Day 1

Mg(OH)2(aq) + 2HCl(aq) base acid

Write a balanced formula equation for the following acid base neutralization reaction

Nitric acid and sodium hydroxideHNO3 + NaOH NaNO3 + H2O

Salt Water

MgCl2 + H2O

Salt Water

2

Page 6: Neutralization – Day 1

Write a balanced formula equation for the following acid base neutralization reactions:

Barium hydroxide and hydrochloric acidBa(OH)2 + HCl

Sulfuric acid and cesium hydroxideH2SO4 + CsOH

Nitirc acid and potassium hydroxideHNO3 + KOH

H2O + BaCl22 2

H2O + Cs2SO42 2

H2O + KNO3

Page 7: Neutralization – Day 1

What is a neutralization reaction? What is a salt? Where does the cation in the salt come

from? Where does the anion in the salt come

from?

Page 8: Neutralization – Day 1
Page 9: Neutralization – Day 1

Purpose - To find the unknown concentration of a solution.

Procedure – Add a known amount of solution of known concentration to a solution of unknown concentration.

Page 10: Neutralization – Day 1

Buret – A piece of glassware used for dispensing accurate volumes of a solution.

The solution of known concentration is in the buret.

Page 11: Neutralization – Day 1

Analyte/Unknown Solution - The solution that is being analyzed. It is the solution of unknown concentration

Titrant/Standard Solution - The solution of known concentration that is added to the analyte

Page 12: Neutralization – Day 1

Equivalence Point - when the acid and base are mixed and the number of hydrogen ions equal the number of hydroxide ions.◦ [H+] = [OH-]

Page 13: Neutralization – Day 1

Acid–base indicator – A chemical dye whose colors are affected by acidic and basic solutions. A common acid base indicator for titration is phenolphthalein.

End point is the point which the indicator used in titration changes color.

Page 14: Neutralization – Day 1

The equivalence point is when [H+] = [OH-]. You cannot see this.

The end point is when you see a change in color in the indicator.

The equivalence point should be very close to the end point. To make sure this happens, an appropriate indicator needs to be chosen.

Page 15: Neutralization – Day 1

What is the purpose of titration? What is a standard solution? What is

another name for the standard solution? What is the equivalence point? What is phenolphthalein? What is the end point? What is the difference between the

equivalence point and end point

Page 16: Neutralization – Day 1

http://www.youtube.com/watch?v=g8jdCWC10vQ (1min 10 sec)

http://www.youtube.com/watch?v=8UiuE7Xx5l8&feature=related

(3 min 15 sec)

http://www.youtube.com/watch?v=Y-5QJIr7Xm4 (4 min 51 sec)

http://www.youtube.com/watch?v=9DkB82xLvNE (5min 3 sec)

http://www.youtube.com/watch?v=LvXQc0M1grQ (8min 50 sec-student video)

Page 17: Neutralization – Day 1

HC2H3O2 + NaOH H2O + NaC2H3O2

In a titration, the volume of base needed was 9.50mL of 0.500 M NaOH to reach equivalence point. The volume of HC2H3O2 acid titrated was 5.89 mL. Find the molarity of the acid.

Page 18: Neutralization – Day 1

HC2H3O2 + NaOH H2O + NaC2H3O2

9.50mL NaOH

0.00475 mol HC2H3O2

1000 mL

1 L

1000 mL

5.89 mL HC2H3O2

0.00475 mol HC2H3O2

0.500 mol NaOH

=

=

What is the standard solution?(the acid or the base)

1 L NaOH

0.806 M HC2H3O2

1 mol NaOH

1 mol HC2H3O2

1 L0.806 mol HC2H3O2

L

Page 19: Neutralization – Day 1

If you are doing a neutralization where there is more than one hydrogen on the acid, your mole ratio will not be one to one.

Example: H2SO4 + 2RbOH 2H2O + Rb2SO4

43.21mL RbOH

1000 mL

1 L 0.03020 mol NaOH

1 L NaOH 2 mol RbOH

1 mol H2SO4

0.02175 mol H2SO4

Lor 0.02175 M H2SO4

0.0006525 mol H2SO4 1000 mL

30.00 mL H2SO4 1 L

=

0.0006525 mol H2SO4=