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Mrs. Stewart Biology I Honors DNA Structur e

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DNA Structure. Mrs. Stewart Biology I Honors. STANDARDS:. CLE 3210.4.1Investigate how genetic information is encoded in nucleic acids. CLE 3210.4.2Describe the relationships among genes, chromosomes, proteins, and hereditary traits. OBJECTIVES: (today, I will…). - PowerPoint PPT Presentation

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Page 1: Mrs. Stewart Biology I Honors

Mrs. StewartBiology I Honors

DNAStructur

e

Page 2: Mrs. Stewart Biology I Honors

STANDARDS:CLE 3210.4.1 Investigate how

genetic information is encoded in nucleic acids.

CLE 3210.4.2 Describe the relationships among genes, chromosomes, proteins, and hereditary traits.

Page 3: Mrs. Stewart Biology I Honors

OBJECTIVES: (today, I will…)Evaluate the structure of nucleic

acids Determine how genetic information is

“coded” in nucleic acids Create complementary DNA strands

using Chargaff’s rule

Page 4: Mrs. Stewart Biology I Honors

Nucleic AcidsMacromolecules containing :

Carbon HydrogenOxygenNitrogenPhosphorus

Function: Store and transmit genetic/hereditary information

Page 5: Mrs. Stewart Biology I Honors

Two types of Nucleic Acids

DNARNA

Page 6: Mrs. Stewart Biology I Honors

DNA Stands for:

Deoxyribonucleic Acid

Page 7: Mrs. Stewart Biology I Honors

DNA StructureDNA is made up of two strands that are

arranged into a twisted, ladder-like structure called a Double Helix.

A strand of DNA is made up of millions of tiny subunits called Nucleotides.

Each nucleotide consists of 3 parts:1. Phosphate group2. sugar3. Nitrogenous base

Page 8: Mrs. Stewart Biology I Honors

Nucleotides

Phosphate

Pentose

Sugar

Nitrogenous

Base

Page 9: Mrs. Stewart Biology I Honors

DNA sugarThe 5 carbon sugar for DNA is

Deoxyribose

That is where the name (Deoxyribo)nucleic acid comes from

Page 10: Mrs. Stewart Biology I Honors

NucleotidesThe phosphate and sugar form the

backbone of the DNA molecule, whereas the bases form the “rungs”.

There are four types of nitrogenous bases.

Page 11: Mrs. Stewart Biology I Honors

4 different Nitrogen bases

A

AdenineT

Thymine

G

GuanineC

Cytosine

Page 12: Mrs. Stewart Biology I Honors

Purines

A

Adenine

G

Guanine

Page 13: Mrs. Stewart Biology I Honors

Pyrimidines

T

Thymine

C

Cytosine

Page 14: Mrs. Stewart Biology I Honors

Chargaff’s ruleErwin Chargaff observed that the

percentage of adenine equals the percentage of thymine, and the percentage of cytosine equals the percentage of guanine.

Example: in one strand of DNA the following amounts may be found:15% Adenine15% Thymine35% Cytosine35% Guanine

Page 15: Mrs. Stewart Biology I Honors

Complementary base pairing:Each base will only bond with one

other specific base. (Chargaff’s rule)

Adenine (A)Thymine (T)

Cytosine (C)Guanine (G)

Form a base pair.

Form a base pair.

Page 16: Mrs. Stewart Biology I Honors

DNA StructureBecause of this complementary base

pairing, the order of the bases in one strand determines the order of the bases in the other strand.

Page 17: Mrs. Stewart Biology I Honors

G

G

A

T

T

A

A

C

T

G

C

A

T

C

Page 18: Mrs. Stewart Biology I Honors

Practice:Complete the complementary DNA strand for

the following sequence:

G T A A C T C C TC A T A G A G G A

C T C C T A A A CG A G G A T T T G

T A G A A T G C CA T C T T A C G G

Page 19: Mrs. Stewart Biology I Honors

DNA StructureTo crack the genetic code found in

DNA we need to look at the sequence of bases.

The bases are arranged in triplets (sets of 3) called codons.

A G G - C T C - A A G - T C C - T A GT C C - G A G - T T C - A G G - A T C

Page 20: Mrs. Stewart Biology I Honors

DNA StructureA gene is a section of DNA that codes for a

protein.

Each unique gene has a unique sequence of bases.

This unique sequence of bases will code for the production of a unique protein.

It is these proteins and combination of proteins that give us a unique phenotype.

Page 21: Mrs. Stewart Biology I Honors

Protein

DNA

Gene

Trait

Page 22: Mrs. Stewart Biology I Honors

Your TaskDraw a flow chart to

show how to get from:

Page 23: Mrs. Stewart Biology I Honors

Mrs. StewartBiology I Honors

DNA Replicati

on

Page 24: Mrs. Stewart Biology I Honors

STANDARDS:CLE 3210.4.1 Investigate how

genetic information is encoded in nucleic acids.

CLE 3210.4.2 Describe the relationships among genes, chromosomes, proteins, and hereditary traits.

Page 25: Mrs. Stewart Biology I Honors

OBJECTIVES: (today, I will…)Evaluate the structure of DNA and

the need for replicationCreate complementary DNA strands

to simulate replication

Page 26: Mrs. Stewart Biology I Honors

DNA Double HelixMade of 2 strands of nucleotidesThese strands are joined together with the pairing of the Nitrogen bases(A, T, C, G)

The bases are joined by Hydrogen bonds

Page 27: Mrs. Stewart Biology I Honors

Think – Pair - ShareLook at the picture and try to figure

out what “antiparallel” means.

Did you notice that the strands of DNA run in “opposite directions”?

Page 28: Mrs. Stewart Biology I Honors

5’ and 3’ ends of DNARefers to the orientation

of the carbon atoms on the deoxyribose

Strands run in opposite directions

One strand is “upside down”

Page 29: Mrs. Stewart Biology I Honors

Think – pair - shareWhy does DNA need to replicate

itself?

Page 30: Mrs. Stewart Biology I Honors

DNA ReplicationDNA makes an exact copy of itselfOccurs during the S stage of

interphase

Page 31: Mrs. Stewart Biology I Honors

Semi-conservativeEach strand of the double

helix will serve as a template for the new strands that will form

End result is two complete DNA double helixes – each containing one strand from the original molecule and one newly made complementary strand

Page 32: Mrs. Stewart Biology I Honors

HelicaseEnzyme that “unzips” the

DNA double helix by breaking the Hydrogen bonds between the bases to separate the strands in preparation for replication

Creates a “replication fork”

Page 33: Mrs. Stewart Biology I Honors

DNA PolymeraseUses “free-floating” nucleotides in the nucleus to build the complementary strand of DNA

Page 34: Mrs. Stewart Biology I Honors

5‘ to 3‘ directionThe new DNA strands need to form in

the 5 prime to 3 prime direction.

Leading strand: forms continuously because it is forming in the 5’ to 3’ direction

Lagging strand: forms in short segments called Okazaki fragments, so that it can also form in the 5’ to 3’ direction

Page 35: Mrs. Stewart Biology I Honors

http://youtu.be/zdDkiRw1PdU

Page 36: Mrs. Stewart Biology I Honors

This powerpoint was kindly donated to www.worldofteaching.com

http://www.worldofteaching.com is home to over a thousand powerpoints submitted by teachers. This is a completely free site and requires no registration. Please visit and I hope it will help in your teaching.